A view from a table.. with cursors?

Question

i have a table with this:
contract - date de execução - action
3034 - 01012006 -72
3034 - 10022006 -73
2011 - 05012006 -74
2011- 10012006 -73
and I want a view with this:
3034 - 01012006 - 72 - 10022006 - 73
2011 - 05012006 - 74 - 10012006 - 73
how can I extract this fastly?
thanks

Answer 1

There can be too many interpretations of your data and what you want to get -
do you want for example to have last and first values amongth particular group
ordered by date - for example:
SQL> select * from t order by 1,2;
CONTRACT   DATE#            ACTION
2011       05012006             74
2011       07012006             70
2011       10012006             73
3034       01012006             72
3034       05012006             71
3034       10022006             73
6 rows selected.
SQL> select unique contract,
  2  first_value(date#) over(partition by contract order by date#) date1,
  3  first_value(action) over(partition by contract order by date#) action1,
  4  last_value(date#) over(partition by contract order by date#
  5  range between unbounded preceding and unbounded following) date2,
  6  last_value(action) over(partition by contract order by date#
  7  range between unbounded preceding and unbounded following) action2
  8  from t
  9  /
CONTRACT   DATE1           ACTION1 DATE2           ACTION2
2011       05012006             74 10012006             73
3034       01012006             72 10022006             73Please, make your task clear.
Rgds.