About interface and class[Please read this]

Question

I writing what I found out:
myinterface.java
interface myinterface
class A
A()
{System.out.println("A()
of interface");}
A.java
class A implements
myinterface
A(){System.out.println("A()
of A.java");}
public static void main
(String args[])
A a=new A();
//this calls A() of interface
//myinterface.java
//how come the output of
// this code is like this

Answer 1

how come this is possible?Well, it had to pick one or the other, since they
have the same symbol name. Why are you choosing to
make up goofy names that collide in the first place?
If you want to explicitly use one or the other, you
need to also choose a package name, and fully-qualify
the class name that you are trying to instantiate.For example:
package test;
interface MyInterface // renamed to follow standard naming convention
  class A
    A() { System.out.println("A() of interface"); }
class A implements MyInterface
  A() {System.out.println("A() of A.java"); }
  public static void main(String args[])
    test.A a = new test.A(); // prints A() of A.java
    MyInterface.A a1 = new MyInterface.A(); // prints the other one
}