About Tomact's Web.xml file

Starting service Tomcat-Standalone
Apache Tomcat/4.0.1
PARSE error at line 38 column 11
org.xml.sax.SAXParseException: The content of element type "web-app" must match "(icon?,display-name?,description?,
distributable?,context-param*,servlet*,servlet-mapping*,session-config?,mime-mapping*,welcome-file-list?,error-page
*,taglib*,resource-ref*,security-constraint*,login-config?,security-role*,env-entry*,ejb-ref*)".
Starting service Tomcat-Apache
Apache Tomcat/4.0.1
I am getting this message when i keep web.xml file in web-inf folder.that is after starting tomcat.

Hi
The elements in web.xml file must follow a specific order, it the one tomcat prints in the error-message. (It should also tell THIS IS THE REQUESTED ORDER)
I made the same problem before... ;)
Made you have a <servlet-mapping> tag before a <servlet> tag? That is not correct! Hope this solves your problems. :)
/Tobias

Similar Messages

(newbie) Question about replacing .class files and web.xml file

I'm new to servlets and I have two quick questions...
Do I absolutely need a web.xml file to define all my servlets, or can I simply place .class files into the WEB-INF directory and expect them to run?
If my application server (for example Tomcat) is running and I replace a servlet .class file, do I need to restart the server for the new .class file to take effect?
...or are both of these questions specific to the application server I'm using?

Hi,
From an article I read:
With Tomcat 3.x, by default servlet container was set up to allow invoking a servet through a common mapping under the /servlet/ directory.
A servlet could be accessed by simply using an url like this one:
http://[domain]:[port]/[context]/servlet/[servlet full qualified name].
The mapping was set inside the web application descriptor (web.xml), located under $TOMCAT_HOME/conf.
With Tomcat 4.x the Jakarta developers have decided to stop allowing this by default. The <servlet-mapping> tag that sets this mapping up, has been commented inside the default web application descriptor (web.xml), located under $CATALINA_HOME/conf:


A developer can simply map all the servlet inside the web application descriptor of its own web application (that is highly suggested), or simply uncomment that mapping (that is highly discouraged).
It is important to notice that the /servlet/ isn't part of Servlet 2.3 specifications so there are no guarantee that the container will support that. So, if the developer decides to uncomment that mapping, the application will loose portabiliy.
And declangallagher, I will use caution in future :-)

Automate creation of web.xml file for tomcat 4.1.29

hi , this is with ref to Tomcat 4.1.29, if i am correct, each Servlet in the application has to be mentioned in the web.xml file for the Tomcat to know about it. Is there any way to automate the creation of web.xml file , depending on the contents of the Servlet folder of the application. Any way to escape from writing each Servlet name in web.xml file.
rc

Hello,
Maybe you should check if you can use Ant tool to do
that. I am not sure if it can help u.
Zeph.
http://ant.apache.org/
It will, specially if used in conjunction with XDoclets :
http://xdoclet.sourceforge.net/
XDoclet has Ant tasks to generate web.xml files.

Reload web-inf/web.xml file without restarting tomcat

Please help me if any one have a solution .
I am doing development in jsp, servlet. I am using tomcat5 as a webserver.
i want to reload web-inf/web.xml file without restarting tomcat.

From the tomcat admin page you can stop/start and refresh individual applications. See the tomcat documentation. Which, when you have a question about tomcat, you should always do first.

Web.xml file problem in tomcat

Hi i need help in this... its urgent
currently i just subscribe to a web hosting site and i need to start the private tomcat in the web server..
The followings are the instructions and i have follow them but i do not know how to create a web.xml file to store in the folder indicated for example a HelloServlet that im testing :
To setup servlet, you need to configure servlet into the file web.xml which needs to be placed in /var/www/html/WEB-INF directory.
www root directory or webapps:/var/www/htm
Classes directory located in: /var/www/html/WEB-INF/Classes/
There you will need to upload your Java class file.
Our default url-mapping for servlet is: /servlet/*
To check servlet in your browser: www.mydomain.net/servlet/HelloWorld
Jsp Files - Upload anywhere in /var/www/html
all the above steps are follow except the web.xml file which i suppose to write and store in the folder... but i actually try to write one but i still cannot load my servlet on the webpage... test on standalone tomcat works.
pls help its urgent!!!

first sorry about cross posting the subject. i didnt know i am not suppose to do that. i post in a few forums that are related to my topic. sorry
The tomcat on the web server is of version Private J2EE / Tomcat 4.1.29 and the standalone tomcat i am using is also tomcat 4.1
the web.xml in my standalone server in root/web-inf/ is as follows and it is configure for authentication purposes. It works together with the tomcat-users.xml located on conf directory
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/j2ee/dtds/web-app_2_3.dtd">
<web-app>
<security-constraint>
<web-resource-collection>
<web-resource-name>
Restricted Area
</web-resource-name>
<url-pattern>/secure/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>manager</role-name>
<role-name>tomcat</role-name>
</auth-constraint>
</security-constraint>
<login-config>
<auth-method>FORM</auth-method>
<form-login-config>
<form-login-page>/Login.html</form-login-page>
<form-error-page>/Error.html</form-error-page>
</form-login-config>
</login-config>
     <security-role>
     <description>The Secure ROLE</description>
     <role-name>manager</role-name>
          <role-name>tomcat</role-name>
     </security-role>
<security-constraint>
<web-resource-collection>
<web-resource-name>
Restricted Area
</web-resource-name>
<url-pattern>/Customer/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>customer</role-name>
<role-name>tomcat</role-name>
</auth-constraint>
</security-constraint>
<login-config>
<auth-method>FORM</auth-method>
<form-login-config>
<form-login-page>/Login.html</form-login-page>
<form-error-page>/Error.html</form-error-page>
</form-login-config>
</login-config>
     <security-role>
     <description>The Secure ROLE</description>
     <role-name>customer</role-name>
          <role-name>tomcat</role-name>
     </security-role>
</web-app>
using this web.xml, my stanalone web pages works fine for all servlets and jsp. however if i copy this over to the web server, i still cannot load my servlets and jsp. moreover it doesnt work for authentication purpose anymore. i don't know why too
i have try the codes you write before and it also doesnt work
the problem is i cannot get the support form the web hosting site. This is the link that suppose to teach me but it doesn not tell me how to configure my web.xml
https://www.eroute.net/JSPSupport.htm

My sun-web.xml file doesn't seem to be getting processed.

I've made another topic in this forum because my pre-compiled JSPs are not working but I think that I may have found the root of that problem, and it is this...
My sun-web.xml file does not seem to be getting processed (run?) by the web server. I have this theory because I made some changes to it that should have caused an error as the server starts up, but there was nothing. For example, I added some random text as a tag that should have been an error, and there was none.
Now, I did the same thing in my web.xml file, and sure enough, there was an error on start up. So, this coupled with the fact that my "use-precompiled" property seems not to be working makes me think that the sun-web.xml file is not being used by the sever.
Is there anything I need to do other than drop it in the /WEB-INF directory with the web.xml file?
Thanks.

It might be possible that the extra tags in sun-web.xml are just ignored (ie. not validated). I have seen cases where this has occurred.
A simple test you should perform is to enable some obvious setting in sun-web.xml, and see if that takes effect. Ex.
<sun-web-app>
<session-config>
<session-manager persistence-type="mmap"/>
</session-config>
</sun-web-app>
During startup time the logs should indicate that the persistence type has been set to MMAP. Like the following:
[02/Nov/2005:20:21:25] info (12566): WEB3006: Initializing MMapSession Manager to hold a maximum of (1,000) sessions, each of which can store a maximum of (10) values each about (4,096) bytes size, with a timeout value of (1,800) seconds; please ensure that this configuration fits total size of the serialized byte stream of all the attributes of a session

How can I get the context-parm from a web.xml file using struts?

Hello:
I need get the context-param from the web.xml file of my web project using struts. I want configurate the jdbc datasource connection pooling here. For example:
<context-param>
<param-name>datasource</param-name>
<param-value>jdbc/formacion</param-value>
<description>Jdbc datasource</description>
</context-param>
and then from any Action class get this parameter.
Similar using a simple server can be:
/** Initiates new XServlet */
public void init(ServletConfig config) throws ServletException {
          for (Enumeration e = config.getInitParameterNames(); e.hasMoreElements();) {
               System.out.println(e.nextElement());
          super.init(config);
          String str = config.getInitParameter("datasource");
          System.out.println(str);
     public void doPost(HttpServletRequest req, HttpServletResponse res)
          throws ServletException, IOException {
          // res.setContentType( );
          System.out.println("Got post request in XServlet");
          PrintWriter out = res.getWriter();
          out.println("nada");
          out.flush();
          out.close();
but only this works for init-params, if I use
<servlet>
     <servlet-name>MyServlet</servlet-name>
     <display-name>MyServlet</display-name>
     <servlet-class>myExamples.servlet.MyServlet</servlet-class>
     <init-param>
     <param-name>datasource</param-name>
     <param-value>jdbc/formacion</param-value>
</init-param>
</servlet>
inside my web.xml. I need something similar, but using struts inside the action class for that I can get the context-params and call my database.
Thank you

To get context parameters from your web.xml file you can simply get the ActionServlet object from an implementing action object class. In the perform (or execute) method make the following call.
ServletContext context = getServlet().getServletContext();
String tempContextVar =
context.getInitParameter("<your context param >");

Can i run a servlet without a web.xml file for servlet mapping?

Hello everyone.
The code i want to run compiles and everythink looks ok.
It produces the .class file.
I run Tomcat 4.1 and i build my Web site with Dreamweaver.
I have a form in a page and i want to send the data upon form completion to a database i already have build with MySql.
The database is up and running and the server is set-up ok.
I have changed the port in Tomcat to run on port 80.
The directory i have my site is
Tomcat41\webapps\ROOT\se
and the directory where i keep the servlet class is
Tomcat41\webapps\ROOT\se\WEB-INF\servlet
I have a web.xml file to map the servlet and placed it in
Tomcat41\webapps\ROOT\se\WEB-INF
In the Form action i write action:"/servlets/Classes/GroupRegistration"
and I RECEIVE AN 404 ERROR FROM APACHE.
Somethink is wrong .
The following is the code from the GroupRegistration.java file
and follws the web.xml file.
Please Help.
import java.sql.*;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class GroupRegistration extends HttpServlet
Connection con;
public void doPost (HttpServletRequest req, HttpServletResponse res)
                         throws ServletException, java.io.IOException
     handleForm(req, res);
public void init() throws ServletException {
     try{
     /* Loading the driver for the database */
     Class.forName("com.mysql.jdbc.Driver");
     Connection Con = DriverManager.getConnection("jdbc:mysql://localhost/se?user=luser&password=");
     catch (ClassNotFoundException e) {
     throw new UnavailableException("Couldn't load JdbcOdbcDriver");
     catch (SQLException e) {
     throw new UnavailableException("Couldn't get db connection");
     private void handleForm(HttpServletRequest req, HttpServletResponse res)
     throws ServletException {
     //ServletOutputStream out = res.OutputStream();
     //res.setContentType("text/html");
     //Extract the form Data Here
     String group = req.getParameter("GroupNo");
     String Name1 = req.getParameter("Name1");
     String LoginID1 = req.getParameter("LoginID1");
     String Name2 = req.getParameter("Name2");
     String LoginID2 = req.getParameter("LoginID2");
     String Name3 = req.getParameter("Name3");
     String LoginID3 = req.getParameter("LoginID3");
     String Name4 = req.getParameter("Name4");
     String LoginID4 = req.getParameter("LoginID4");
     String URL = req.getParameter("URL");
     String Title2 = req.getParameter("Title2");
     String date = req.getParameter("date");
     String INSERT = "INSERT INTO registration (groupno, name1, loginid1, name2, loginid2, name3, loginid3, name4, loginid4, url, topic, date) VALUES (" + group + "," + Name1 + "," + LoginID2 + "," + Name2 + "," + LoginID2 + "," + Name3 + "," + LoginID3 + "," + Name4 + "," + LoginID4 + "," + URL + "," + Title2 + "," + date + ")";
     PreparedStatement pstmt = null;
     try{
     pstmt = con.prepareStatement(INSERT);
     pstmt.executeUpdate();
     catch (SQLException e) {
     throw new ServletException(e);
     finally {
     try {
     if (pstmt != null)pstmt.close();
     catch (SQLException ignored){
The web.xml file
<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com.xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<servlet>
<servlet-name>GroupRegistration</servlet-name>
<servlet-class>GroupRegistration</servlet-class>
</servlet>
<servlet-maping>
<servlet-name>GroupRegistration</servlet-name>
<url-pattern>/myGroupRegistration</url-patern>
</servlet-mapping>
</web-app>
I apreciate your time.
Thanks for any help.

and the directory where i keep the servlet class is
Tomcat41\webapps\ROOT\se\WEB-INF\servletOthers have pointed out that "servlet" should be "classes", but there is another mistake that hasn't been spotted. If you want your servlet to appear in the root context, you should use:
Tomcat41\webapps\ROOT\WEB-INF\classes
If you want your servlet to appear under the /se context, then you should use:
Tomcat41\webapps\se\WEB-INF\classes
and also, in the latter case, your form action should be /se/myGroupRegistration.

XML Question for web.xml file for LiteWebServer

Hi,
I have no clue of wut tags are required in the web.xml file.
Currently the following code is in my web.xml file and i am trying to run servlets that are located under web-inf/*.class
Pls tell me wuts wrong....
Do i need those mime-mapping tags, session and welcome tags.......... ?
Right now i just want those 2 servlets to work
And wut is this encoding ="UTF-8" in the first line of the xml file. Wut does that do... ? ARe there any others
Any help would b greatly appreciated
Thanks
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app id="WebApp_1">
<display-name>PDMPortal</display-name>
<session-config id="SessionConfig_1">
<session-timeout>60</session-timeout>
</session-config>
<mime-mapping id="MimeMapping_1">
<extension>htc</extension>
<mime-type>text/x-component</mime-type>
</mime-mapping>
<welcome-file-list id="WelcomeFileList_1">
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>HelloWorld</servlet-name>
<servlet-class>HelloWorld</servlet-class>
</servlet>
<servlet>
<servlet-name>HelloWorldExample</servlet-name>
<servlet-class>HelloWorldExample</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>HelloWorld</servlet-name>
<url-pattern>HelloWorld</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>HelloWorldExample</servlet-name>
<url-pattern>HelloWorldExample</url-pattern>
</servlet-mapping>
</web-app>

Try putting your servlets in the WEB-INF\classes directory.

Problem in web.xml file with weblogic server 8.1

Hi frnds,
I was deployed one Enterprise Application,it deploys successfully. But in server side thows Exeception in web.xml file.
Here the actual Exception
<HTTP> <BEA-101248> <[Application:
'G:\bea\user_projects\domains\mydomain\myserver\upload\jasmine.ear', Module: 'Ja
smine']: Deployment descriptor "web.xml" is malformed. Check against the DTD: or
g.xml.sax.SAXParseException: The content of element type "web-app" must match "(
icon?,display-name?,description?,distributable?,context-param*,filter*,filter-ma
pping*,listener*,servlet*,servlet-mapping*,session-config?,mime-mapping*,welcome
-file-list?,error-page*,taglib*,resource-env-ref*,resource-ref*,security-constra
int*,login-config?,security-role*,env-entry*,ejb-ref*,ejb-local-ref*)". (line 61
, column 11).>
My web.xml file as follws....
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.4//EN"
"http://java.sun.com/dtd/web-app_2_4.dtd">
<web-app>
<display-name>Jasmine Applications</display-name>
<description>
Jasmine Applications
</description>
<servlet>
<servlet-name>LoginServlet</servlet-name>
<servlet-class>examples.LoginServlet</servlet-class>
<init-param>
<param-name>java.naming.factory.initial</param-name>
<param-value>weblogic.jndi.WLInitialContextFactory</param-value>
</init-param>
<init-param>
<param-name>java.naming.provider.url</param-name>
<param-value>t3://localhost:7001</param-value>
</init-param>
</servlet>
<servlet>
<servlet-name>ShowQuoteServlet</servlet-name>
<servlet-class>examples.ShowQuoteServlet</servlet-class>
<init-param>
<param-name>java.naming.factory.initial</param-name>
<param-value>weblogic.jndi.WLInitialContextFactory</param-value>
</init-param>
<init-param>
<param-name>java.naming.provider.url</param-name>
<param-value>t3://localhost:7001</param-value>
</init-param>
</servlet>
<servlet>
<servlet-name>CatalogServlet</servlet-name>
<servlet-class>examples.CatalogServlet</servlet-class>
<init-param>
<param-name>java.naming.factory.initial</param-name>
<param-value>weblogic.jndi.WLInitialContextFactory</param-value>
</init-param>
<init-param>
<param-name>java.naming.provider.url</param-name>
<param-value>t3://localhost:7001</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>LoginServlet</servlet-name>
<url-pattern>/login/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>ShowQuoteServlet</servlet-name>
<url-pattern>/showQuote/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>CatalogServlet</servlet-name>
<url-pattern>/catalog/*</url-pattern>
</servlet-mapping>
<security-constraint>
<web-resource-collection>
<web-resource-name>My secure resources</web-resource-name>
<description>Resources to be placed under security control.</description>
<url-pattern>/private/*</url-pattern>
<url-pattern>/registered/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>guest</role-name>
</auth-constraint>
</security-constraint>
<login-config>
<auth-method>FORM</auth-method>
<realm-name>WebApp</realm-name>
<form-login-config>
<form-login-page>/login.jsp</form-login-page>
<form-error-page>/error.jsp</form-error-page>
</form-login-config>
</login-config>

<security-role>
<description>The role allowed to access our content</description>
<role-name>guest</role-name>
</security-role>
</web-app>
pls give me a good solution this exception.. I tried lot..
Thanks in Advance
Regards
Priya

Your DOCTYPE references 2.4, it should be 2.3. WLS 8.1 supports J2EE 1.3 which was servlet 2.3.
Servlet 2.4 is part of J2EE 1.4 and is supported by WLS 9.0/9.1. Also it uses XML Schema not a DTD.
-- Rob
WLS Blog http://dev2dev.bea.com/blog/rwoollen/

How to setup web.xml files in Tomcat 4.0.6

Hi, I'm to new to Java Servlets. i am trying to run my first servlet but it's not showing up..can anyone help me out please!!!
I created a folders like this:
webapps/sumitapps/WEB-INF\classes\Forms\login.class
under sumitapps: i'm puttin all of my .html files(Logins.html)
under WEB-INF: i put web.xml file and classes folder
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<servlet>
<servlet-name>login</servlet-name>
<servlet-class>Forms.login</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>login</servlet-name>
<url-pattern>/Forms.login</url-pattern>
</servlet-mapping>
</web-app>
<Context path="/sumitapps" docBase="webapps/sumitapps" crossContext="true" debug="0" reloadable="true" trusted="false" >
</Context>
under my classes folder i put folder Forms where i'm keeping all of my .class files. my class file name is login.class
can anyone tell me why i cant run my servlets
<FORM method="POST" action="Forms.login"
name=userinfo onsubmit="return checkData()">
please help me out here
i can access my html page like this:
http://lcoalhost:8080/sumitapps/Logins.html
but when i enter userid and password it doesnt show anything..it takes me to http://localhost:8080/sumitapps/Forms.login
and shows cannot be displayed

have a look at www.moreservlets.com. There you can find a free pdf (part of the book, a whole chapter) that explains in deep the use of web.xml.

JSP compiler reading the web.xml file?

Hi,
          I am trying to use the weblogic JSP compiler (weblogic.jspc) to
          pre-compile some JSP that use custom tags. Does the compiler
          read the web.xml file if there is one? In particular the taglib
          elements in that file so that the compiler understands the
          <%@ taglib ... %> directive.
          In the JSP I try to compile I use this statement to declare a taglib:
          <%@ taglib uri="xyz/xyz-taglib" prefix="xyz" %>
          and in my web.xml I have:
          <taglib>
          <taglib-uri>xyz/xyz-taglib</taglib-uri>
          <taglib-location>/WEB-INF/tlds/xyz.tld</taglib-location>
          </taglib>
          When I try to compile the JSP I get the following error:
          Could not parse embedded JSP code: weblogic.utils.ParsingException: nested
          IOException: java.io.IOException: cannot resolve 'xyz/xyz-taglib' into a
          valid tag library.
          Any ideas how I can resolve this?
          In advance thank you for any help.
          Florian


open it in a text editor and modify it.
%

I have some more problem in the web.xml file and url-pattern in my syste

HI ALL!
How can I create and place the web.xml and URL-parrten.Because I run
the tomcat in my computer with ME system.
Hoc

what is the problem? please be more specific and detailed? check a sample web.xml file and make your own one and place it in your <application-context>\WEB-INF folder..

Web.xml file generation problem

Hi,
I am trying to create web.xml file automatically using "java weblogic.marathon.ddinit.WebInit
" command.
I got the following message in the command prompt:
Found Web components. Initializing descriptors
filters=0 servlets=0 tags=0
Above command is creating the web.xml and weblogic.xml files but it is not including
the servlet-mapping information. why?
Thanks,
Prakash

It doesn't look like it found any servlets. You'd have to show me your
files if I'm to understand what's going on.
-- Rob
Prakash wrote:
Hi,
I am trying to create web.xml file automatically using "java weblogic.marathon.ddinit.WebInit
" command.
I got the following message in the command prompt:
Found Web components. Initializing descriptors
filters=0 servlets=0 tags=0
Above command is creating the web.xml and weblogic.xml files but it is not including
the servlet-mapping information. why?
Thanks,
Prakash

Help required in depolying EAR file. web.xml file not recognised.

Hi All,
I have created EAR project using WAR. While I'm trying to deploy the EAR file using SDM tool of J2EE engine. I'm getting the following error: bold com.sap.engine.services.servlets_jsp.server.exceptions.WebDeploymentException: Web application [redirectForm] does not contain "/WEB-INF/web.xml" file or it is spelt incorrectly bold . I have checked the WAR file, it has web.xml file. Please tell me how to resolve this error?
Thanks in advance
Srikant

Hi Srikant,
check the directory entry in your war file if it is woth upper case i.e. WEB-INF
Best regards
Bojidar

About Tomact's Web.xml file

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