Accessing an URL from Forms Java Bean

Dear Oracle Gurus,
Please help me
I have an Oracle Application Server 10g Rel1 in production. I have oracle forms running with a java bean. I am passing an URL to this java bean to fetch and display an image.
This url belongs to another web server (IIS server running a ASP.net application). If i call this url in internet explorer window it is displaying the image. If the same URL if i am calling from forms applet it is not working. When i checked in the java console by setting up trace level to 5 no error message.
I have checked in the midtier/j2ee/home/log/home_default_island_1 folder in the log file no error messages. I have setup the internet explorer --> internet options --> security --> custom level --> miscellaneous --> access data across domain --> enable.
Please give me a solution.
Best Regards
Syed Jalal

Hello,
I don't know how we can help you, because you use a Java Bean and did not tell us anything about this bean. A bean is like a "black box", so we cannot give you any help at all without the code.
Francois

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|#]
[#|2006-10-02T13:52:55.390+0200|INFO|sun-appserver-pe8.0.0_01|javax.enterprise.system.stream.out|_ThreadID=11;|2006-10-02 13:52:55 [8080-Processor4] INFO .va.ejb.testrh.sb.TestRemoteEjbBean - RemoteException when getting BrickFacade. Message:Invalid URL or IOR: corbaloc:iiop://161.90.176.213:3700
javax.naming.ConfigurationException: Invalid URL or IOR: corbaloc:iiop://161.90.176.213:3700 [Root exception is org.omg.CORBA.BAD_PARAM:   vmcid: SUN minor code: 603 completed: No]
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     at com.sun.jndi.url.iiop.iiopURLContextFactory.getUsingURLIgnoreRest(iiopURLContextFactory.java:56)
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     at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:263)
     at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:210)
     at javax.servlet.http.HttpServlet.service(HttpServlet.java:861)
     at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
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     at org.apache.catalina.security.SecurityUtil.execute(SecurityUtil.java:268)
     at org.apache.catalina.security.SecurityUtil.doAsPrivilege(SecurityUtil.java:162)
     at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:236)
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     at org.apache.catalina.core.ApplicationFilterChain$1.run(ApplicationFilterChain.java:145)
     at java.security.AccessController.doPrivileged(Native Method)
     at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:141)
     at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:220)
     at org.apache.catalina.core.StandardValveContext.invokeNext(StandardValveContext.java:109)
     at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:522)
     at org.apache.catalina.core.StandardContextValve.invokeInternal(StandardContextValve.java:214)
     at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:168)
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     at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:522)
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     at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.processConnection(Http11Protocol.java:604)
     at org.apache.tomcat.util.net.TcpWorkerThread.runIt(PoolTcpEndpoint.java:542)
     at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:647)
     at java.lang.Thread.run(Thread.java:534)
Caused by: org.omg.CORBA.BAD_PARAM: vmcid: SUN minor code: 603 completed: No
     at com.sun.corba.ee.impl.logging.NamingSystemException.insBadAddress(NamingSystemException.java:148)
     at com.sun.corba.ee.impl.logging.NamingSystemException.insBadAddress(NamingSystemException.java:166)
     at com.sun.corba.ee.impl.naming.namingutil.CorbalocURL.badAddress(CorbalocURL.java:104)
     at com.sun.corba.ee.impl.naming.namingutil.CorbalocURL.handleColon(CorbalocURL.java:140)
     at com.sun.corba.ee.impl.naming.namingutil.CorbalocURL.handleIIOPColon(CorbalocURL.java:115)
     at com.sun.corba.ee.impl.naming.namingutil.CorbalocURL.<init>(CorbalocURL.java:67)
     at com.sun.corba.ee.impl.naming.namingutil.INSURLHandler.parseURL(INSURLHandler.java:41)
     at com.sun.corba.ee.impl.resolver.INSURLOperationImpl.operate(INSURLOperationImpl.java:103)
     at com.sun.corba.ee.impl.orb.ORBImpl.string_to_object(ORBImpl.java:774)
     at com.sun.jndi.cosnaming.CNCtx.setOrbAndRootContext(CNCtx.j|#]

Problem solved:
configuration in jndi-name was wrong:
<jndi-name>corbaname:iiop:161.90.176.213:3700#ejb/BrickFacade</jndi-name>

How to get an XML string from a Java Bean without wrting to a file first ?

I know we can save a Java Bean to an XML file with XMLEncoder and then read it back with XMLDecoder.
But how can I get an XML string of a Java Bean without writing to a file first ?
For instance :
My_Class A_Class = new My_Class("a",1,2,"Z", ...);
String XML_String_Of_The_Class = an XML representation of A_Class ?
Of course I can save it to a file with XMLEncoder, and read it in using XMLDecoder, then delete the file, I wonder if it is possible to skip all that and get the XML string directly ?
Frank

I think so too, but I am trying to send the object to a servlet as shown below, since I don't know how to send an object to a servlet, I can only turn it into a string and reconstruct it back to an object on the server side after receiving it :
import java.io.*;
import java.net.*;
import java.util.*;
class Servlet_Message        // Send a message to an HTTP servlet. The protocol is a GET or POST request with a URLEncoded string holding the arguments sent as name=value pairs.
public static int GET=0;
public static int POST=1;
private URL servlet;
// the URL of the servlet to send messages to
public Servlet_Message(URL servlet) { this.servlet=servlet; }
public String sendMessage(Properties args) throws IOException { return sendMessage(args,POST); }
// Send the request. Return the input stream with the response if the request succeeds.
// @param args the arguments to send to the servlet
// @param method GET or POST
// @exception IOException if error sending request
// @return the response from the servlet to this message
public String sendMessage(Properties args,int method) throws IOException
    String Input_Line;
    StringBuffer Result_Buf=new StringBuffer();
    // Set this up any way you want -- POST can be used for all calls, but request headers
    // cannot be set in JDK 1.0.2 so the query string still must be used to pass arguments.
    if (method==GET)
      URL url=new URL(servlet.toExternalForm()+"?"+toEncodedString(args));
      BufferedReader in=new BufferedReader(new InputStreamReader(url.openStream()));
      while ((Input_Line=in.readLine()) != null) Result_Buf.append(Input_Line+"\n");
    else
      URLConnection conn=servlet.openConnection();
      conn.setDoInput(true);
      conn.setDoOutput(true);
      conn.setUseCaches(false);
      // Work around a Netscape bug
      conn.setRequestProperty("Content-Type","application/x-www-form-urlencoded");
      // POST the request data (html form encoded)
      DataOutputStream out=new DataOutputStream(conn.getOutputStream());
      if (args!=null && args.size()>0)
        out.writeBytes(toEncodedString(args));
//        System.out.println("ServletMessage args: "+args);
//        System.out.println("ServletMessage toEncString args: "+toEncodedString(args));
      BufferedReader in=new BufferedReader(new InputStreamReader(conn.getInputStream()));
      while ((Input_Line=in.readLine()) != null) Result_Buf.append(Input_Line+"\n");
      out.flush();
      out.close(); // ESSENTIAL for this to work!
    return Result_Buf.toString();               // Read the POST response data
// Encode the arguments in the property set as a URL-encoded string. Multiple name=value pairs are separated by ampersands.
// @return the URLEncoded string with name=value pairs
public String toEncodedString(Properties args)
    StringBuffer sb=new StringBuffer();
    if (args!=null)
      String sep="";
      Enumeration names=args.propertyNames();
      while (names.hasMoreElements())
        String name=(String)names.nextElement();
        try { sb.append(sep+URLEncoder.encode(name,"UTF-8")+"="+URLEncoder.encode(args.getProperty(name),"UTF-8")); }
//        try { sb.append(sep+URLEncoder.encode(name,"UTF-16")+"="+URLEncoder.encode(args.getProperty(name),"UTF-16")); }
        catch (UnsupportedEncodingException e) { System.out.println(e); }
        sep="&";
    return sb.toString();
}As shown above the servlet need to encode a string.
Now my question becomes :
<1> Is it possible to send an object to a servlet, if so how ? And at the receiving end how to get it back to an object ?
<2> If it can't be done, how can I be sure to encode the string in the right format to send it over to the servlet ?
Frank

Opening an URL from a JAVA application

hi,
iam new to Java.
Currently iam designing a simle GUI which takes input(URL) from user in a test field and has a button.Upon clicking button i want to open the webPage specified by that URL in a default webBrowser.
How can i do that(opening webPage)?
advanced thanks for your help.
vd.rach

getting an error on that line as follows: "unreported
exception; must be caught or declared to be thrown".exec() throws IOException so catch it.
try {
Runtime.getRuntime.exec(...);
catch(IOException e) {
System.err("Cannot launch the browser: " + e.getMessage());
}On the side note: I found javaworld's [url http://www.javaworld.com/javatips/jw-javatip66_p.html]solution most useful in serving this purpose in a project, even though its a little bit platform specific.

Accessing Sql Server from AS400 Java program

Hi everybody,
I am trying to access Sql Server from an AS400 Java program. I have tried various Sql Server JDBC drivers including the Microsoft one but no luck yet. When i try to compile my Java program (with driver file in the classpath) it gives some errors on the driver jar file and also it throws out lots of unreadable text characters. This gave me a feeling that probably its a character coding issue with the jar file, so i tried ftp the file in binary mode as well as copying through the Operations Navigator. But still compilation is giving the same kind of errors.
Do I need to have some special JDBC Drivers compiled for AS400 specifically. My understanding was that Java is platform independent so any JDBC Type 4 driver will work.
We are running Java 1.3 on the AS400. Any help on this issue would be great.
Thanks
Inder

Thanks for the help. I am writing a Java program after a long time that's why was making that mistake. Now the program gets compiled correctly but on running the program i am getting the following error message:
java 001-0070: Exception JVAB544 not expected
/myjava/test/msbase.jar: 001-0050 Syntax error on Line 1: token ')' not expected
/myjava/test/msutil.jar: 001-0050 Syntax error on Line 1: token ')' not expected
/myjava/test/mssqlserver.jar: 001-0050 Syntax error on Line 1: token ')' not expected
I have no idea what is this error about. Though the same driver files don't give any error when running on a Windows machine.
Thanks

JMS: can I access SAP messages from extenal Java

- Can I access SAP Messages from an external (non-SAP) java program?
- Do I use JNDI or can I call using a jar file from my java invocation?
- Do I have to define a queue (or does SAP JMS have queues)
- What port do I use?
Thanks

Hi John,
> - Can I access SAP Messages from an external
> (non-SAP) java program?
>
Yes, you can use the JMS provider on the Web AS from a standalone java program.
> - Do I use JNDI or can I call using a jar file from
> my java invocation?
You connect your remote java client to the server by getting an InitialContext. The you lookup the JMS resources (such as Topic- or Queue ConnectionFactory, etc.) from the JNDI. You can have a look at <a href="http://help.sap.com/saphelp_nw04/helpdata/en/25/bf8f44540c469abc19fb6ac3ac7885/frameset.htm">this</a> page for more info.
>
> - Do I have to define a queue (or does SAP JMS have
> queues)
>
The JMS Provider on the Web AS provides default connection factories that you can use to create a topic ot queue. The lookup strings you have to use are
jmsfactory/default/TopicConnectionFactory
for topics and
jmsfactory/default/QueueConnectionFactory
for queues.
> - What port do I use?
>
You use the P4 port (50004 by default for instance number 00) when obtaining the InitialContext with this code:
java.util.Properties properties = new Properties();
// set the properties of the connection
properties.put("Context.INITIAL_CONTEXT_FACTORY", "com.sap.engine.services.jndi.InitialContextFactoryImpl");
properties.put(Context.PROVIDER_URL, "<Server_Host>:<p4_port>");
properties.put("Context.SECURITY_PRINCIPAL", "Administrator");
properties.put("Context SECURITY_CREDENTIALS", "admin_password");
// start initial context with the properties specified
InitialContext context = new InitialContext(properties);
Hope that helps!

Calling a url from forms

Hi!
i have created a website using ARCIMS - (if you are not familiar with ARCIMS it is software that is used to create maps) I now want to call URL (website) from a button on my form. I have tried to use web.show_docuement and I am getting errors such as 'register failk'.
I was able to run this same URL succesfuly from my browser. any ideas please?!?

Kayla.
web.show_document() is the right buit-in to do this and it works the same as calling a URL from a Browser. if it says "register failed" (not sure if I am correctimng your error message the right way) then this does not look like a Forms error message but one coming from teh program you call. Please check teh URL that is composed before calling web.show_document(). Check for invisible characters added to it.
Frank

Accessing env-entry from out side bean

Hi,
          I have my env-entry element declared in ejb-jar.xml like this
          <env-entry>
          <env-entry-name>ConfigFile</env-entry-name>
          <env-entry-type>java.lang.String</env-entry-type>
          <env-entry-value>centaur</env-entry-value>
          </env-entry>
          and if I access that value from the EJB(MDB) of that ejb-jar.xml, it is giving the right value. But when I am trying to retrieve the same from a java class, that is throwing exception "javax.naming.NameNotFoundException: Unable to resolve 'ConfigFile' Resolved ; remaining name 'ConfigFile'"
          I think this is because env-entry has access to only EJB or MDB to maintain security?
          or can env-entry elemenets cab be accessed outside the EJB and some thing I am doing wrong here?
          can some one help me here?

The java:comp/env namespace is local to the J2EE component (ie the EJB).
          You could certainly have a business method that returned the value and call the business method from a java class.
          Or your EJB could lookup the env-entry in JNDI and store it in another data structure.
          -- Rob
          WLS Blog http://dev2dev.bea.com/blog/rwoollen/

Accessing an URL from Forms Java Bean

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