Add or subtract minutes from any time of day
Hello!
The problem I'm having is that add or subtract minutes related
to a time stamp like e.g.
+ (plus)
17:21 timestamp
minutes to add +80
result -> 18:41
- (minus)
17:21 timestamp
minutes to subtract -20
result -> 17:01
Is any function module existing for such
cases. What would you recommend to me to
solve the problem to get really reliable
time.
THX
ilhan ertas
Hi Ilhan,
as long as you don't leave the limits of a day (i.e. time getting below zero or above 24 hours), ABAP time calculations will get correct results. Type t (time) fields in expressions involving numeric data types are internally converted into the amount of seconds.
So you can add minutes by multiplying by 60 (second per minute) first.
In a type T field 17:21 is represented internally as 172100. Add 4800 (80 minutes times 60 seconds) will result (internally) to 17 * 60 * 60 + 21 * 60 + 4800 = 67260. And this will be converted to time format 184100.
See also this SAP online help:
<a href="http://help.sap.com/saphelp_erp2005vp/helpdata/en/fc/eb334a358411d1829f0000e829fbfe/content.htm">Date and Time Calculations</a>
Regards,
Clemens
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process' Login\ hook 'I/O per process' Mach\ ports kexts Daemons Agents XPC\ cache Startup\ items Admin\ access Root\ access Bundles dylibs Apps Font\ issues Inserted\ dylibs Firewall Proxies DNS TCP/IP Wi-Fi Profiles Root\ crontab User\ crontab 'Global login items' 'User login items' Spotlight Memory Listeners Widgets Parental\ Controls Prefetching SATA Descriptors App\ extensions Lockfiles Memory\ pressure SMC Shutdowns Nets Stylesheet );N3=${#l[@]};for i in {0..3};do l[N3+i]=${p[5+i]};done;N4=${#l[@]};for j in 0 1;do l[N4+j]="Current ${p[29+j]}stream data";done;A0() { id -G|grep -qw 80;v[1]=$?;((v[1]==0))&&sudo true;v[2]=$?;v[3]=`date +%s`;clear >&-;date '+Start time: %T %D%n';};for i in 0 1;do eval ' A'$((1+i))'() { v=` eval "${c1[$1]} ${c2[$2]}"|'${c1[30+i]}' "${s[$3]}" `;[[ "$v" ]];};A'$((3+i))'() { v=` while read i;do [[ "$i" ]]&&eval "${c1[$1]} ${c2[$2]}" \"$i\"|'${c1[30+i]}' "${s[$3]}";done<<<"${v[$4]}" `;[[ "$v" ]];};A'$((5+i))'() { v=` while read i;do '${c1[30+i]}' "${s[$1]}" "$i";done<<<"${v[$2]}" `;[[ "$v" ]];};A'$((7+i))'() { v=` eval sudo "${c1[$1]} ${c2[$2]}"|'${c1[30+i]}' "${s[$3]}" `;[[ "$v" ]];};';done;A9(){ v=$((`date +%s`-v[3]));};B2(){ v[$1]="$v";};for i in 0 1;do eval ' B'$i'() { v=;((v['$((i+1))']==0))||{ v=No;false;};};B'$((3+i))'() { v[$2]=`'${c1[30+i]}' "${s[$3]}"<<<"${v[$1]}"`;} ';done;B5(){ v[$1]="${v[$1]}"$'\n'"${v[$2]}";};B6() { v=` paste -d: <(printf "${v[$1]}") <(printf "${v[$2]}")|awk -F: ' {printf("'"${f[$3]}"'",$1,$2)} ' `;};B7(){ v=`grep -Fv "${v[$1]}"<<<"$v"`;};C0() { [[ "$v" ]]&&sed -E "$s"<<<"$v";};C1() { [[ "$v" ]]&&printf "${f[$1]}" "${l[$2]}" "$v"|sed -E "$s";};C2() { v=`echo $v`;[[ "$v" != 0 ]]&&C1 0 $1;};C3() { v=`sed -E "${s[63]}"<<<"$v"`&&C1 1 $1;};for i in 1 2 7 8;do for j in 0 2 3;do eval D$i$j'(){ A'$i' $1 $2 $3; C'$j' $4;};';done;done;{ A0;D20 0 $((N1+1)) 2;D10 0 $N1 1;B0;C2 27;B0&&! B1&&C2 28;D12 15 37 25 8;A1 0 $((N1+2)) 3;C0;D13 0 $((N1+3)) 4 3;D23 0 $((N1+4)) 5 4;D13 0 $((N1+9)) 59 50;for i in 0 1 2;do D13 0 $((N1+5+i)) 6 $((N3+i));done;D13 0 $((N1+8)) 71 $((N3+3));D13 1 10 7 9;D13 1 11 8 10;B1&&D73 19 53 67 55;D22 2 12 9 11;D12 3 13 10 12;D23 4 19 44 13;D13 5 5 69 1;D13 5 54 30 56;D23 5 14 12 14;D22 6 36 13 15;D22 20 52 66 54;D22 7 37 14 16;D23 8 15 38 17;D22 9 16 16 18;B1&&{ D82 35 49 61 51;D82 11 17 17 20;for i in 0 1;do D82 28 $((N2+i)) 45 $((N4+i));done;};D22 12 44 54 45;D22 12 39 15 21;A1 13 40 18;B2 4;B3 4 0 19;A3 14 6 32 0;B4 0 5 11;A1 17 41 20;B7 5;C3 22;B4 4 6 21;A3 14 7 32 6;B4 0 7 11;B3 4 0 22;A3 14 6 32 0;B4 0 8 11;B5 7 8;B1&&{ A8 18 26 23;B7 7;C3 23;};A2 18 26 23;B7 7;C3 24;D13 4 21 24 26;B4 4 12 26;B3 4 13 27;A1 24 22 29;B7 12;B2 14;A4 39 57 70 14;B2 15;B6 14 15 4;C3 29;A1 24 23 32;B7 13;C3 30;B3 4 0 65;A3 14 6 32 0;B4 0 16 11;A1 26 50 64;B7 16;C3 52;D13 24 24 32 31;D13 25 37 32 33;A2 23 18 28;B2 16;A2 16 25 33;B7 16;B3 0 0 34;B2 21;A6 47 21&&C0;B1&&{ D73 21 0 32 19;D73 10 42 32 40;D82 29 35 46 39;};D23 14 1 62 42;D12 34 43 53 44;D12 22 20 32 25;D22 0 $((N1+10)) 51 32;D13 4 8 41 6;D12 21 28 35 34;D13 27 29 36 35;A2 27 32 39&&{ B2 19;A2 33 33 40;B2 20;B6 19 20 3;};C2 36;D23 38 55 68 57;D23 33 34 42 37;B1&&D83 35 45 55 46;D23 32 31 43 38;D12 36 47 32 48;D13 10 42 32 41;D13 37 2 48 43;A1 4 3 60;B2 30;A1 4 58 60;B2 31;B6 30 31 4;C3 5;D12 21 56 35 58;D12 21 48 49 49;B3 4 22 57;A1 21 46 56;B7 22;B3 0 0 58;C3 47;D22 4 4 50 0;D12 4 51 32 53;D23 22 9 37 7;A9;C2 2;} 2>/dev/null|pbcopy;exit 2>&-
Copy the selected text to the Clipboard by pressing the key combination command-C.
8. Launch the built-in Terminal application in any of the following ways:
☞ Enter the first few letters of its name into a Spotlight search. Select it in the results (it should be at the top.)
☞ In the Finder, select Go ▹ Utilities from the menu bar, or press the key combination shift-command-U. The application is in the folder that opens.
☞ Open LaunchPad and start typing the name.
Click anywhere in the Terminal window and paste by pressing command-V. The text you pasted should vanish immediately. If it doesn't, press the return key.
9. If you see an error message in the Terminal window such as "Syntax error" or "Event not found," enter
exec bash
and press return. Then paste the script again.
10. If you're logged in as an administrator, you'll be prompted for your login password. Nothing will be displayed when you type it. You will not see the usual dots in place of typed characters. Make sure caps lock is off. Type carefully and then press return. You may get a one-time warning to be careful. If you make three failed attempts to enter the password, the test will run anyway, but it will produce less information. In most cases, the difference is not important. If you don't know the password, or if you prefer not to enter it, press the key combination control-C or just press return three times at the password prompt. Again, the script will still run.
If you're not logged in as an administrator, you won't be prompted for a password. The test will still run. It just won't do anything that requires administrator privileges.
11. The test may take a few minutes to run, depending on how many files you have and the speed of the computer. A computer that's abnormally slow may take longer to run the test. While it's running, there will be nothing in the Terminal window and no indication of progress. Wait for the line
[Process completed]
to appear. If you don't see it within half an hour or so, the test probably won't complete in a reasonable time. In that case, close the Terminal window and report what happened. No harm will be done.
12. When the test is complete, quit Terminal. The results will have been copied to the Clipboard automatically. They are not shown in the Terminal window. Please don't copy anything from there. All you have to do is start a reply to this comment and then paste by pressing command-V again.
At the top of the results, there will be a line that begins with the words "Start time." If you don't see that, but instead see a mass of gibberish, you didn't wait for the "Process completed" message to appear in the Terminal window. Please wait for it and try again.
If any private information, such as your name or email address, appears in the results, anonymize it before posting. Usually that won't be necessary.
13. When you post the results, you might see an error message on the web page: "You have included content in your post that is not permitted," or "You are not authorized to post." That's a bug in the forum software. Please post the test results on Pastebin, then post a link here to the page you created.
14. This is a public forum, and others may give you advice based on the results of the test. They speak only for themselves, and I don't necessarily agree with them.
Copyright © 2014 by Linc Davis. As the sole author of this work, I reserve all rights to it except as provided in the Use Agreement for the Apple Support Communities website ("ASC"). Readers of ASC may copy it for their own personal use. Neither the whole nor any part may be redistributed. -
Adding two time periods together, summing it up and misusing 30 minutes from it HELP!
SUPer tricky questions and brownie points for who can solve it!
Column B6 has 11:00 am, Column C6 has 1:00 pm, column D6 has the total hours calculated (i.e. work from 11:00 am to 1:00 pm = 2 hours) and i want column e6 to minus half an hour (.30 hours) and display -.30 OR minus .30 minutes from Colulmn D6... however, only if the total hours/time in column D6 is greater than 5 hours. PLEASE FOR THE LOVE OF GOD TELL ME THE FORMULA FOR THIS!!Hi Chris,
No need to shout.
Formula in column C (calculates the Duration (time elapsed) between two Date and Time values:
=B-A
Formula in column D (Calculates the same Duration as above, but subtracts 30 minutes if the total Duration is greater than 5 hours):
=IF(DUR2HOURS(B-A)>5,B-A-DURATION(,,,30,,),B-A)
Note that any cell displaying a Date or a Time (of day) or both contains a Date and Time value.
If only the Date has been entered, the time part is set to 00:00:00 (midnight, at the beginning of that day).
If only the Time has been entered, the date part is set to the date the entry was made.
In the table above, the values in Row 18, the bottom row of the table are as follows:
A18: March 1, 2012 11:00:00 AM
B18: March 1, 2012 5:00:00 PM
C18: 6h
D18: 5h 30m
The first two are Date and Time values, the second two are Duration values.
Regards,
Barry -
Let's say I have a time like 9:45am in one cell and I want to take that time and add a period of time like 5 minutes from another cell to it so that in the resulting cell I get a later time like 9:50 am.
is that even possible? I'm trying to make a school schedule and it'd just be cool to be able take the end time of one class and add 5 minutes to it and have that be the start time of the next class.
For now I'll just do it manually.Assuming that you time value is in B2,
you may enter, in C2, the formula:
=B+(5/(24*60))
Remember that there is no time item in Numbers but dateTime ones.
I the cell B2 was filled on 2009/06/20
when the displayed time is 9:20, the true cell contents is 2009/06/20 09:20
So, if we add 5 minutes, the result will be: 2009/06/20 09:25
For some uses it may be annoying but for others it is useful.
If the initial value is
23:57 entered today (the cell really contain 2009/06/24 23:57)
adding 5 minutes
we would ge: 2009/06/25 00:02
As you may check, the day would be incremented.
Yvan KOENIG (from FRANCE mercredi 24 juin 2009 20:41:44) -
I installed a security program called Identity Finder whick requires a master password for Firefox on my laptop, which I like. However, even though my settings are to "Show my windows and tabs from last time," I have to manually add each link in a new tab each time. Any suggestions? Thanks in advance.
Pure speculation, but maybe that Identity Finder program is deleting your browsing history which is how Firefox restores tabs and windows from the previous session. Check with technical support for that program or look at the manual.
-
Reg : subtracting weekoff day from the time difference
Hi ,
I have query where I am getting time difference first of all in terms of hours as:
DECLARE @L_TIME_DIFF INT
SET @L_TIME_DIFF= (DATEDIFF(hh, '05/09/2014', '05/12/2014'))
i.e. subtracting 12th may - 9th may and getting diff in hours ..in this case it will be 3*24 = 72 hours
All fine till here. Now next step I need to subtract from this 72 hours if falling any week off day. It can be Friday, it can be Saturday, or Sunday, or Half day Saturday, or Half Day Sunday, or Full 2 days Saturday/Sunday .
The above scenario is decided based on one table [CALENDER_WORKINGDAYS] which looks like below :
CAL_WORKING_DAY
CAL_AM
CAL_PM
CAL_SEQ_NO
Monday
1
1
1
Tuesday
1
1
2
Wednesday
1
1
3
Thursday
1
1
4
Friday
0
0
5
Saturday
1
1
6
Sunday
1
1
7
So in this case, if you look at friday (CAL_AM=0 and CAL_PM=0) this measn friday full day holiday for some country.
Hence I need to : 72 - 24 = 48 Hours should be my output.
In another scenario, let s say some country work half day Saturday and Sunday full day off.
So my output should be : 72 - 36 (because 24 hours for sunday off, and 12 hours for saturday half day off) =
36 should be my output
and so on..
Can you help to build such query based on the above table given ?
ThanksHi Jose Diz,
I am trying the below logic. Seems it should be working:
DECLARE
@L_START_TIME DATETIME,
@L_END_TIME DATETIME,
@L_TIME_DIFF INT, -- Time Difference considering week offs
@W_TIME_DIFF INT ,-- Whole Time Difference,
@PUBLICHOLS INT,
@WEEK_OFF INT
set @L_START_TIME = '5/9/2014';
set @L_END_TIME = '5/12/2014';
/* TO GET THE TIMDIFFERENCE */
SET @L_TIME_DIFF=(DATEDIFF(hh,@L_START_TIME,@L_END_TIME))
SET @W_TIME_DIFF = @L_TIME_DIFF
-- Subtracting day off in the week(i.e. sat/sun or in some case friday) if it is in between start and end
set @WEEK_OFF= 0;
SELECT @WEEK_OFF= @WEEK_OFF + 12 * (abs(CAL_AM -1) + abs(CAL_PM -1))
from CALENDER_WORKINGDAYS
IF DATENAME(WK,@L_END_TIME) > DATENAME(WK,@L_START_TIME)
BEGIN
SET @L_TIME_DIFF= @L_TIME_DIFF - @WEEK_OFF
END
Thanks to confirm -
HTTP response time - From any SAP table.
Hi,
Can we get http response time other than from SMICM u2192 Http log?
Reason for me to ask is we cannot see complete URL in smicm log with response time.
date - "POST /sap/bc/webdynpro/sap/cprojects/?sap-contextid=......................................... HTTP/1.1" 200 325894 9555 h[-]
As per sap help link complete URL after contextID is hidden for security reason.
http://help.sap.com/saphelp_crm70/helpdata/EN/48/442541e0804bb8e10000000a42189b/frameset.htm
u201CFor security reasons the following information is hidden (replaced with points) from the logging procedureu201D
Question: can we access complete URL from any table level with http response time, any input is appreciated.
Thanks,
Venkat.Michael,
First of all, thanks for the reply.
In our environment we have cprojects implemented and have lot of webdynpro request to ECC system.
From http log (SMICM) I can see many webdynpro requests with response time above 30 minutes; I want to automate this monitoring by writing a CCMS data supplier. We already have SAP document to write data supplier.
Scenario: For example if they are doing a task in cprojects.
We will be having a GET webdynpro request and then POST. By looking at GET we can know the task user is trying to do. But it is POST request which will be taking most of the response time and POST URL is show u2026(point) after context ID and as per SAP help this is done for security reason.
HTTP log from SMICMu2026
[DATE] - "GET /sap/bc/webdynpro/sap/cprojects?sap-client=clnt&STARTVIEW=Tasks&OBJECT_TYPE=TTO&GUID=GUIDNUMBER
[DATE] - "GET /sap/bc/webdynpro/sap/cprojects/~ucfLOADING?sap-contextid=....................
[DATE] - "POST /sap/bc/webdynpro/sap/cprojects/?sap-contextid=........................[response time]
I think SAP is displaying as point in http log file, but it should definitely have complete URL is any of the table.
So I am looking If we can find the complete POST URL with response time from table then we can write an ABAP program to send the information to CCMS.
Thanks,
Venkat. -
SUBTRACT TIME FROM DATE & TIME
Hi.
I need FM which will SUBTRACT TIME from DATE & TIME.
Example:
Date = 05.05.2007
Time = 05:00:00
Time_subtract = 48:00:00
Return of FM:
Date = 03.05.2007
Time = 05:00:00
Do you know any FM?
Thanks!Hi, Check these function mod's
SD_DATETIME_DIFFERENCE
HRCM_TIME_PERIOD_CALCULATE
HR_ECM_GET_PERIOD_BETW_DATES
After you execute them in SE37 give the required input and you will get a correct output.
<b>REWARD IF USEFUL</b>
thanks n regards
Dinesh
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