Adding a button to each row of a tabular form

Hi,
I'm new to APEX. I've searched the forums high and low for a couple days, but no go on a solution to my problem. Perhaps I'm not phrasing my search right.
I have a tabular form. The columns in each row save to a table called STORE. At the end of each row, I'd like to have a button/hyperlink that takes you to another page wherein, for that store, you can check/uncheck the items they carry. So, here's the main tabular form:
The Hardware Shop -- Col1 Col2 Col3 Col4 Col5 Link
Bob's Nuts and Bolts -- Col1 Col2 Col3 Col4 Col5 Link
Suppose you click on the link for The HW Shop. Now you're in a screen where you have a list of 20 items (coming from another table). From that list, you can check/uncheck the items carried by that store, save changes, and return to the tabular form. Checking/unchecking would insert/delete records from a junction table (using a trigger I guess).
Back in the tabular form, you should still be able to save data at that level (i.e. the col1, col2, etc., above). I have this latter part working, and I know how to write triggers, it's just the button link concept that I can't understand.
I'd be much obliged if somebody could point me to some sort of reference/example.
Thanks,
Max

Hi again,
I'd like to add some functionality to this, and would appreciate any input. I can't post this app for security reasons, and it would require a lot of reworking to 'genericize' it, so I'll just devote that same energy to being as detailed as possible in my explanation of the issue.
Part of my app has 2 pages that interact with each other. Page 1 is a tabular form, and at the end of each row there is a link column, which I created with Arie's help. This link opens up page 2, which is also a tabular form.
Clicking 'Save' in page 2 should launch a javascript function to do some calculation, and then this calculation should be sent back to page 1, and stored in a text field located on the same row as the link column that was clicked in page 1.
There's a lot of different ideas floating in the forums regarding javascript calls via buttons, and I'm currently researching that. More important to me is understanding what row number was clicked on page 1 (i.e. f01, f02, etc.).
I think this posting is similar to what I'm trying to do: Re: Trying to attach onclick event to a pagination link But, the replies went a bit over my head. I managed to create a row selector, which added a checkbox column to my form. But the downside to that is I don't want to force the user to click a checkbox to activate a row, and then do the additional step of clicking the link column.
Thanks,
max

Similar Messages

Adding radio button to each row of an interactive report: possible or not?

First of all let me explain what the point of this application is.
I'm making an application that allows a user to select something out of a drop-down select list. This list is a list of categories for food. Let's say the user selects "Fruit".
Then the page refreshes and shows an interactive report with a list of food that belongs to the category of fruit.
Here's where I want to change things:
I want the user to see the interactive report, but in this interactive report I want to add a radio button for each row.
Then, when a certain type of food is selected (let's say "Strawberry") via the radio button, a text field should appear underneath the interactive report. In this textfield, the user can then add the weight of the food item, and then it will calculate how many carbs there are in the strawberry.
All I really want to know is:*
How do I add a radio button to each row of the interactive report, and how do I link this radio button to the value of that particular row?*
Additional information:
The item "P17_FOOD_CATEGORY" contains the following LOV:
select FOODCATEGORYNAME as display_value, FOODCATEGORYID as return_value
from FOODCATEGORY
order by 1
The "Food" region contains the following source:
select a.FOODID, a.NAME, b.FOODCATEGORYNAME, c.STANDARDAMOUNT, c.NAME Unit
from FOOD a inner join FOODCATEGORY b
on a.FOODCATEGORYID = b.FOODCATEGORYID join FOODUNIT c
on a.FOODID = c.FOODID
where a.FOODCATEGORYID = :P17_SET_CATEGORY
EDIT:
PLEASE! Even if you don't know a good answer or if you are unsure about your answer, do post! Even suggestions would be welcome! I really need all the help I could get, even if it's not much.
Edited by: 917169 on Feb 29, 2012 12:25 AM

Hi there!
I tried to change my code to your version, but then I get an error message:
Error Unable to change Interactive Report query.
ORA-12899: value too large for column "APEX_040100"."WWV_FLOW_WORKSHEET_COLUMNS"."DB_COLUMN_NAME" (actual: 32, maximum: 30)
I don't quite know what this means. After doing a quick search on the internet, I know that this message should mean that the length of the value for the columns named "APEX_040100", "WWV_FLOW_WORKSHEET_COLUMNS" and "DB_COLUMN_NAME" is too long. But, I don't have these columns. I searched for them in my object browser, and they can't be found in any table related to my application.
I'm sure your answer is the solution, but do you perhaps have an idea on how to solve this error? I checked the allowed maximum length for any column value that is related to my application, but they all have "50" set as the maximum value...
Thank you for your reply. ;)

Adding a button in each row of table view

Hi.
In my application i have to add a button in each row of table view. i have done this by using UICatalog example. now problem is how I can handle the click events of these buttons.
suppose i have 5 buttons in 5 rows ... now one of them is clicked(suppose button in 3rd row). how would i know that button in 3rd row is clicked.
Muhammad Usman Aleem

- (UITableViewCell)tableView:(UITableView)tableView
cellForRowAtIndexPath:(NSIndexPath*)indexPath {
static NSString *CellTableIdentifier = @"CellTableIdentifier ";
static NSUInteger nTag = 100;
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:
CellTableIdentifier];
if (cell == nil) {
CGRect cellFrame = CGRectMake(0, 0, 300, 65);
cell = [[[UITableViewCell alloc] initWithFrame:cellFrame
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CGRect labelRect = CGRectMake(10, 26, 190, 15);
UILabel *label = [[UILabel alloc] initWithFrame:labelRect];
label.textAlignment = UITextAlignmentLeft;
label.font = [UIFont boldSystemFontOfSize:12];
// set all label tags to 10 so the label can be found in the subviews
label.tag = 10;
[cell.contentView addSubview:label];
[label release];
CGRect buttonRect = CGRectMake(210, 25, 65, 25);
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button.frame = buttonRect;
// set the button title here if it will always be the same
[button setTitle:@"Action" forState:UIControlStateNormal];
button.tag = nTag++;
[button addTarget:self action:@selector(myAction:) forControlEvents:UIControlEventTouchUpInside];
// make sure the button is the lowest subview so it's easy to find
[cell.contentView insertSubview:button atIndex:0];
// button will be autoreleased so don't release it here
// the label text and button title come from an array of NSDictionary in this example
NSUInteger row = [indexPath row];
NSDictionary *rowData = [self.data objectAtIndex:row];
UILabel *thisLabel = (UILabel*)[cell.contentView viewWithTag:10];
thisLabel.text = [rowData objectForKey:@"Text"];
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[thisButton setTitle:[rowData objectForKey:@"Button"] forState:UIControlStateNormal];
return cell;
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UIButton *theSender = sender;
UITableViewCell *cell;
NSUInteger row = 0;
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if (thisButton.tag == theSender.tag) {
row = [[theTableView indexPathForCell:cell] row];
break;
NSLog(@"myAction: row=%d", row);

Add Button to each row

Hi all,
Sorry about my english!!!
My problem is that i'm trying to add a column to my report (tabular).
That column has a button for each row and when this button is pressed is called a new page with the details of the record for that line.
example:
ID NAME BUTTON
1 qwerty ver
2 ASDFG ver
"ver" is the button.
Problem: how do i build a report with that button and after that how do i call in the pl/sql of the button the detail page?
Thanks everyone.
Using Release 2 9ias

mail me i will send u demo file
[email protected]

Add a radio button to each row on output (not selection-screen)

its a normal interacitve report...
we need to add a radio button to each row on output (not selection-screen) and when user selects the radio button of a particular row and clicks on the user defined menu 'Execute' the report has to fetch the records from a table corresponding to the selected row on the second list.
all this has to be done in normal interactive list.
please let me know your suggetions as soon as possible.
thanks,
usha.

Hi , try this
TABLES: spfli.
TYPE-POOLS:slis.
PARAMETERS: p_col TYPE i ,
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            p_color(4) TYPE c .
DATA: t_fieldcat TYPE slis_t_fieldcat_alv,
      fs_fieldcat LIKE LINE OF t_fieldcat,
      fs_layout TYPE slis_layout_alv ,
      w_color(4) ,
      w_row TYPE i,
      w_fieldname(20),
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TYPES : BEGIN OF ty_spfli ,
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          connid TYPE spfli-connid,
          cityfrom TYPE spfli-cityfrom,
          cityto TYPE spfli-cityto,
          distance TYPE spfli-distance,
       END OF ty_spfli.
DATA : wa_spfli TYPE ty_spfli ,
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DATA: fs_cell LIKE LINE OF wa_spfli-cell.
SELECT carrid connid cityfrom cityto distance
FROM spfli
INTO CORRESPONDING FIELDS OF TABLE t_spfli.
w_color = p_color.
fs_fieldcat-fieldname = 'CARRID'.
fs_fieldcat-ref_tabname = 'SPFLI'.
fs_fieldcat-col_pos = 1.
fs_fieldcat-key = 'X'.
APPEND fs_fieldcat TO t_fieldcat.
CLEAR fs_fieldcat .
fs_fieldcat-fieldname = 'CONNID'.
fs_fieldcat-ref_tabname = 'SPFLI'.
fs_fieldcat-col_pos = 2.
fs_fieldcat-key = 'X'.
APPEND fs_fieldcat TO t_fieldcat.
CLEAR fs_fieldcat .
fs_fieldcat-fieldname = 'DISTANCE'.
fs_fieldcat-ref_tabname = 'SPFLI'.
fs_fieldcat-col_pos = 3.
fs_fieldcat-key = ' '.
fs_fieldcat-edit = 'X'.
APPEND fs_fieldcat TO t_fieldcat.
CLEAR fs_fieldcat.
fs_fieldcat-fieldname = 'CITYFROM'.
fs_fieldcat-ref_tabname = 'SPFLI'.
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fs_fieldcat-key = ' '.
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LOOP AT t_fieldcat INTO fs_fieldcat.
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ENDLOOP.
fs_layout-info_fieldname = 'COLOR'.
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fs_layout-coltab_fieldname = 'CELL'.
fs_layout-f2code = '&ETA'.
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CALL FUNCTION 'REUSE_ALV_LIST_DISPLAY'
EXPORTING
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TABLES
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EXCEPTIONS
    program_error      = 1
    OTHERS             = 2.
IF sy-subrc <> 0.
* MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
* WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
Regards,
Aby

How can i add rows in a tabular form

Hi,
How can i add rows in a tabular form with out updating in database and after adding the rows one by one and after filling the data then iwant to submit them all at once.Please help me on this.
Thanks

Hello Leandro,
In the Add_Rows page process, there is a box for "Number Of Rows". Change that value and you change the number of rows that get added. The default is 1.
Don.
You can reward this reply by marking it as either Helpful or Correct :)

Link column from an interactive report to insert a row in a tabular form

Hi, I need your help, i'm new on APEX and i really need to make a "link column" from an "interactive report" to insert a row into a "tabular form".
I mean that when you click the "link column" instantly create a new row in the Tabular form with the information of the linked row on the interactive report. Its something like that.
I really appreciate your help.
Ricardo Capuz

Hi Ricardo,
You can use the following code as per your requirement (this is just an example),
(In this case IR report is in Page#1 and Tabular form is in Page#2),
On Page#1, Create a hidden item (i.e 'P1_ID')
IR Report query as like the below,
select empno,
ename,
job,
mgr,
hiredate,
sal,
comm,
deptno,
empno "copy"
from empUse the below JS code in Page HTML Header section,
function f_insert_row(pSub)
$s('P1_ID',pSub);
doSubmit('ADD');
Edit Report Attribute -> copy column -> Under Column Link
Link Text: Select your column name (i.e. #EMPNO#)
Target: URL
URL: javascript:f_insert_row(#EMPNO#);
Then create a process to insert like below,
BEGIN
insert into emp_test (select * from emp where empno=:P1_ID);
END;Process condition as * Request=Expression1* in Expression1 as 'ADD'.
At last, create a branch to Page#2, Check 'include process success message' and with the same condition as * Request=Expression1* in Expression1 as 'ADD'.
Thanks,
Lakshmi

Unable to delete row(s) from tabular form

Hi!
I created report with row selector, when I select one row I get tabular form regarding to the selected row from report. I can insert and update data from tabular form, but I have problem with deleting them. Error I get is ORA-01403: no data found (Row 207589)My tabular form is created by wizard and primary key is managed by database rowid, I use apex 4.1 an 10g database.
Do you know for any solution for my problem?
Regards,
drama9346
Add:
For creating report and tabular form I use code and suggestion from this thread: {thread:id=2490862}
Edited by: drama9346 on 28.1.2013 1:51

Hi,
I tried everything I know and I didn't solve my problem.
Can anyone give me some clue?
Regards,
drama9346
Add:
I solve my problem.
Edited by: drama9346 on 29.1.2013 1:52

Adding the Checkbox for each row in classic report

Hello,
I have created classic report with checkboxes in each row and added the On-Submit process, BUTTON CONDITIONAL, to determine the behavior of the checkboxes. The PL/SQL process is suppose to delete the selected row from database.
I am getting the Success message, but When I check the database, the row still persist in the database.
PLSQL CODE:
FOR i IN 1..apex_application.g_f01.count LOOP
DELETE
FROM
registry
WHERE
reg_id = apex_application.g_f01(i);END LOOP;
ORACLE APEX: 4.2
Thank you

Hi ApexNewLearner,
Try this
DECLARE
j number;
BEGIN
FOR i IN 1..apex_application.g_f01.count LOOP
j := apex_application.g_f01(i);
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WHERE reg_id = apex_application.g_f01(j);
END LOOP;
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Regards,
Jitendra

Help: Link buttons to each row in JTable

Here is the story: a JTable contains many entries/rows. I want to have a small "edit" button next to each row, once user click the "edit" button, another GUI will be loaded, and the new GUI is filled with the row of data where that clicked button is corresponding to.
Question:
1.How to link a button to a specific row in the JTable?
2.Can I put the buttons inside the JTable? How?(eg. button at the end of each row).
3.If it's not possible to put the button inside the JTable, then I want to make 5 buttons next to the JTable area(only 5 rows are visible in JTable at any given time). Now, assume we have 20 rows, 1-5 are visible, if I scroll down to 10-15, what can I do to make that once user click the top button of the five, row 10 is loaded with the GUI?
plz help, thx.

Ok, what i want to do is:
user search the database, I display the search result on to the screen(use JTable).
The search result will contain many rows of data, I want to allow user to choose a row, and edit that row with an editor. The editor is another GUI, that GUI will first be filled with data from the row that user chose, then user can edit those data with that editor.
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Apex 4.0 how to add a button to each row of a report

Hi Everyone
I have to a requirement where i need to add a button or link to each row of report dynamically and when a user clicks on it region has to display a region below.
For example displaying report in region 1 and when a user clicks the link or button the region 2 has to appear based on the condition.
Report display details of employee , employeename, emp no, manager, depto, sal,feedback and if the feedback is filled then the link should not appear and if feedback is not filled and the link or button should appear beside that row and allow the user to click and when it is clicked it has to show region 2 .
I am new to Apex, please help me out how to do this.
Thanks in advance
Regards
Sandeep

Step 1:
Add a new item to set ID principal in report 2. ex. "P2000_ID" (maybe hidden item)
Step 2:
in report 1 section "report Attributes" section "Link Column"
-> Link Column = Link to Custom Target
-> Link Icon: Select some Icon link.
-> Target: Page in this Application
-> Page: same page ex. 2000.
-> Item 1: "Name" = select Item created (step 1) "P200_ID" "Value" = #NAME_OF_ID_COLUMN_IN_REPORT_1#
-> Apply Changes
Step 3:
Create query to report 2
Ex.
select *
from
TABLE2
where
ID=:P2000_ID
-> In Report2 condition
* Condition Type = Value of item in Expression 1 Is NOT NULL
* Expression1 = P2000_ID

Extra buttons on each row of a report?

Hi,
I would like to add multiple buttons in front of each row in a report.
When a button is pressed a Pl/SQL statement should run with access to the PK ID of that row.
Also, it is important that I can add other buttons as well (edit, delete etc)
What I want to accomplish, for example:
I want to have an add event button on each line of a scheduled production run, this should then branch to a new page on which first a hidden item (set to pk id) and visible item (pk info) is set to those of the row on which the button was pressed.
I hope that makes sense.
Please let me know how I can to do this,
Thank you so much for any help!!!

open the page, click the RPT link to the report column attributes of that region. choose the field you wish to alter (click the edit icon) then change under the "column link" section to an href. I have used a call to a javascript function in the URL box e.g. "javascript:show_the_page(#ADD#);" and included a javascript function within my app to handle this (read in PK and open a page in a new window with the PK as a variable)

Two radio button in each row of Table view

Hi,
I have a issue like two radio button should come in each row of the tableview and any one only can be selected and selected value should be assigned to a variable.
Kindly help with coding in methods RENDOR_CELL_START AND RENDER_ROW_START.
Thanks in Advance.
Saravanan.

Saravanan,
If you keep the Radiobutton in 2 different column then it wil difficult to put it in one Radiobuttong Group. I am not sure its possible or not. I would suggest you do keep both the "Approved" & "Rejected" radio button in single column as shown below so that the memont "Rejected" is selected, "Approved" will be unchecked.
WHEN 'Your Column'.
        DATA: RAD_GRP TYPE REF TO CL_HTMLB_RADIOBUTTONGROUP,
                 RAD_BTN TYPE REF TO CL_HTMLB_RADIOBUTTON,
                 COL_BEE TYPE REF TO CL_BSP_BEE_TABLE.
          CREATE OBJECT COL_BEE.
          RAD_GRP = CL_HTMLB_RADIOBUTTONGROUP=>FACTORY(
                  ID = P_CELL_ID COLUMNCOUNT = '2' ).
          COL_BEE->ADD( ELEMENT = RAD_GRP LEVEL = 1 ).
          RAD_BTN ?= CL_HTMLB_RADIOBUTTON=>FACTORY( ID = '1' TEXT = 'Approved' ).
          COL_BEE->ADD( ELEMENT = RAD_BTN LEVEL = 2 ).
          RAD_BTN ?= CL_HTMLB_RADIOBUTTON=>FACTORY( ID = '2' TEXT = 'Rejected' ).
          COL_BEE->ADD( ELEMENT = RAD_BTN LEVEL = 2 ).
          P_REPLACEMENT_BEE ?= COL_BEE.
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Again to get the selected radiobutton, use method REQUEST->GET_FORM_FIELDS
DATA: GT_TIHTTPNVP TYPE TIHTTPNVP.
REFRESH GT_TIHTTPNVP.
CALL METHOD REQUEST->GET_FORM_FIELDS
CHANGING
    FIELDS = GT_TIHTTPNVP.
For example, suppose your 3r column has 2 radio buttons & In 1st Row if you've selected the radiobutton 2. THen get_form_fields return the below value.
TV1_1_3 = 2. Here TV1 is tableview name & 1 - Row 1 & 3 -Column three. value 2 indicates that 2nd radio button is selected.
DO 10 TIMES. "Here 10, stands for number of visible rows in tableview
concantenate 'TV1' '_' sy-tabix '_' '3' into v_cell_id. "Here now v_cell_id will have TV1_1_3 for 1st row & etc..
Read table GT_TIHTTPNVP into wa with key name = v_cell_id.
if sy-subrc = 0.
v_selected_rad_btn = wa-value. " THis will give you the selected radio button.
endif.
enddo.
Hope this will solve your problem.
Raja T
Message was edited by:
        Raja Thangamani

Add row button is not working in manual tabular form

Hi,
I have created a tabular form by using collections. In the same page there is a wizard tabular form also.
Here my problem is whenever i giving request to the add row button its showing nothing. there is no any new row got added.
IF :REQUEST ='ADD'
THEN
apex_collection.add_member(
p_collection_name => l_collection_name
END IF;
END;
Thanks.

Hi,
Thanks for ur reply.
My problem got solved after deleting the tabular form wizard from the page then add row button is working.
But i think its not the solution.
Thanks.

Adding a dummy row in the tabular form

Hi
'm an ApEX newbie.
I'm in need to add a dummy row in between a tabular form to make it more appealing at the user end.
A representation of my Tabular Form having 3 columns (i.e Sr No & Skill is of display only format and Remarks column is of text area) is depicted below:
Sr No Skill Remarks
1     Java Language
2     Oracle Database
3     Oracle DBA
4     Oracle Pl Sql
5     Communication
6     Analytical Thinking
7     Logical Thinking
8     Attitude     Remarks
9     Leadership Qualities
10     Business Understanding
i need to add a dummy row (which will act as display only) between Sr No 5 & Sr No 6 as "General Evaluation". As shown below...
Sr No Skill Remarks
1     Java Language
2     Oracle Database
3     Oracle DBA
4     Oracle Pl Sql
5     Communication
"General Evaluation"
6     Analytical Thinking
7     Logical Thinking
8     Attitude     Remarks
9     Leadership Qualities
10     Business Understanding
It would be of great help if any of you could help me out with this (with an detailed answer)
Thanks in advance :)
'm using ApEX 4.1

901720 wrote:
Hi
'm an ApEX newbie.Welcome to the forum: please read the FAQ and forum sticky threads (if you haven't done so already), and ensure you have updated with your profile with a real handle instead of "901720".
You'll get a faster, more effective response to your questions by including as much relevant information as possible upfront. This should include:
<li>Full APEX version
<li>Full DB/version/edition/host OS
<li>Web server architecture (EPG, OHS or APEX listener/host OS)
<li>Browser(s) and version(s) used
<li>Theme
<li>Template(s)
<li>Region/item type(s)
(In particular it is essential to make it clear whether a "report" is a standard report, an interactive report, or in fact an "updateable report" (i.e. a tabular form) and if so, whether the tabular form is declarative—using only report attributes and a wizard generated MRU process—or manual—using <tt>apex_item</tt> calls in the query and custom processing—or some hybrid approach.)
I'm in need to add a dummy row in between a tabular form to make it more appealing at the user end.
A representation of my Tabular Form having 3 columns (i.e Sr No & Skill is of display only format and Remarks column is of text area) is depicted below:
Sr No Skill Remarks
1     Java Language
2     Oracle Database
3     Oracle DBA
4     Oracle Pl Sql
5     Communication
6     Analytical Thinking
7     Logical Thinking
8     Attitude     Remarks
9     Leadership Qualities
10     Business Understanding
i need to add a dummy row (which will act as display only) between Sr No 5 & Sr No 6 as "General Evaluation". As shown below...
Sr No Skill Remarks
1     Java Language
2     Oracle Database
3     Oracle DBA
4     Oracle Pl Sql
5     Communication
"General Evaluation"
6     Analytical Thinking
7     Logical Thinking
8     Attitude     Remarks
9     Leadership Qualities
10     Business UnderstandingIt's not clear from the above what the required layout is: please see the information in the FAQ about posting code/formatted output.
It would be of great help if any of you could help me out with this (with an detailed answer)With APEX we're fortunate to have a great resource in apex.oracle.com where we can reproduce and share problems. Reproducing things there is the best way to troubleshoot most issues, especially those relating to layout and visual formatting. If you expect a detailed answer then it's appropriate for you to take on a significant part of the effort by getting as far as possible with an example of the problem on apex.oracle.com before asking for assistance with specific issues. We can then see exactly what you're really talking about.

Adding a button to each row of a tabular form

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