%age Entry in Data Form

Question

Hi,
In our data form,we are having a member of percntage type. Percentages values are displayed correctly but input has to be done in values between 0 and 1. Is there a way to input the % values between 0 and 100?
As an example,if we want to input 50%,we need to input 0.5 instead of 50.But our requirement is to input 50 in place of 0.5.
If we give the input with % sign then it is working fine. As an exaple if we put the input as 5% then it is working fine.
But our requirement is to put 5 instead of 5%.Is there any other way(like changes in setting) to meet the requirement.
Thanks in advance

Answer 1

I use these functions to set and get item values in my Portal
forms. These functions are in a user interface template used by
the forms. You don't need to know the full name of the field
when using these functions. The functions find the field based
on the base name (usually database column name).
This Java Script example would set the value of BILLING_ADDRESS
the same as SHIPPING_ADDRESS:
set_item_value("BILLING_ADDRESS", get_item_value
("SHIPPING_ADDRESS"));
functions:
function set_item_value(p_field_name, p_value)
var v_index, v_full_name;
for(v_index=0; v_index<document.forms[0].length; v_index++)
v_full_name = document.forms[0].elements[v_index].name.split
if (v_full_name[2] == p_field_name)
document.forms[0].elements[v_index].value = p_value;
function get_item_value(p_field_name)
var v_index, v_full_name, v_return="";
for(v_index=0; v_index<document.forms[0].length; v_index++)
v_full_name = document.forms[0].elements[v_index].name.split
if(v_full_name[2] == p_field_name)
if(document.forms[0].elements[v_index].type != "radio")
v_return = document.forms[0].elements[v_index].value;
else
if(document.forms[0].elements[v_index].checked)
v_return = document.forms[0].elements[v_index].value;
if(v_return == " ")
v_return = "";
return v_return;