Am I bottlenecked? Can't figure out where...

Looking at resource monitor, I'm not using my hardware to it's full potential.
Here's what I got:
Intel i7 870 2.93Ghz (4 real cores + 4HT)
16GB of DDR3 1600MHz
Nvidia GT 430 (1GB, 96 CUDA Cores, 700MHz)
Windows 7 64bit.
So, I've configured AE CS6 according to this tutorial: http://tv.adobe.com/watch/digital-video-cs6/how-to-optimize-after-effects-cs6-for-high-per formance/?go=
I've enabled Render Multiple Frames Simultaneously, set CUPs reserved to other Applications to 4 (giving 4 real CPUs to AE) with 3GB of RAM Allocation per CPU (for a total of 12GB) leaving a healthy 4GB of RAM for other applications.
The system disk is a 64Gb SSD and I've got another similar one set up as the scratch.
GPU rendering is enabled and so is harware accelerated Fast Previews.
I've got a single FullHD composition (from pre-processed defished TIF stills) and I'm running 3 filters in the following order:
a) - Warp Stabilizer (Synthesize Edges, just 0.2s for Synthesis Input Range and 25pixels Feather)
b) - Color Finesse (just a shadow boost through curves)
c) - Noise reduction (3 passes IIRC, 60% opacity)
I'm rendering to uncompressed.
From enabling/disabling those effects, I'd say a) takes 40% of the time, b) less than 10% and c) over 50%.
Each video frame takes about 9s to process.
I'm not running "anything else" and the issue I'm facing is that CPU frequency only oscilates between 1200MHz minimum and 1600MHz maximum as if AE wasn't pushing the CPUs.
4 CPU's are being used at ~60% each, with the virtual cores parked as expected, as can be seen from the attached capture. The source footage is on a regular 1.5TB disk but disk usage is dismall 1.2MB read and 600K writes...
GPU usage is also NULL.
Shouldn't the CPUs be at 100% and full clock? I could understand if it's not in the nature of Warp Stabilizer to be parallel friendly but those regular spikes on CPU 2 (which are consistent with 9s per frame) show that neither Noise Reduction is taxing the CPU...
What gives?
Thanks in advance.
Duarte Bruno.
(edit) This disk where the footage lies easily breaks 50MB/s so it can't be the culprit and I've tried a small compression job on VirtualDub that easily sends the CPU flying to full speed.

There are two things going on here. Some filters take better advantage of your system's power than others. Some are not MP friendly, some are. Until the developers have the time (and it takes a bunch of time) and the resources (it costs a bunch of money) to make every program call completely aware of an unlimited variety of plug-ins, system configurations, and background processes so each read/calculate/write process uses 100% of every possible data path, you'll never get an app as complex as AE 100% efficient.
The second thing going on here is that the system can process data faster than the data can be move on and off a drive. Grab frame info, process it, be done with it, then write it and grab it again before you can grab another frame. When the process requires this kind of analysis the bottle neck is the data transfer rate on and off a drive or in and out of memory. That's the linear progression that Mylenium is talking about. Temporal effects do this kind of processing. Things have to wait for read, calculate, write cycles. We'll just have to wait until developers have the resources to change that. AE gets better at doing most things with each new build. Sometimes bugs pop up, sometimes things that shouldn't slip past QA/QC do, but I clearly remember when just rendering a simple key took 20 or 30 seconds a frame.
BTW, Virtual dub can run your CPU's to 100% easily because it's just doing a single set of calculations.

Similar Messages

Can't figure out where NullPointerException is coming from

I will attach the code I have below. It is almost entirely done but i am getting a NullPointerException that is driving me nuts, and I can't figure out were it is coming from.
Help is greatly appreciated.
First code:
import java.util.Scanner;
import java.io.*;
import java.util.Random;
import java.util.Collection;
public class DistributionPlagiarist
 public static void main(String[] args) throws IOException
 Scanner keyboard = new Scanner(System.in);
 int keyLength=0, phraseLength=0, numberOfPhrases=0;
 String inputFileName="", keepReadingFromFile="", theFile="";
 FrequencyLibrary text = new DenseFrequencyLibrary();
 if(args.length != 4)
 System.out.println("The command line arguments you entered do not match what is needed. Please try again.");
 System.exit(0);
 for(int count=0; count<args.length; count++)
 keyLength = Integer.parseInt(args[0]);
 phraseLength = Integer.parseInt(args[1]);
 numberOfPhrases = Integer.parseInt(args[2]);
 inputFileName = args[3];
 if(keyLength < 0)
 while(keyLength < 0)
 System.out.print("The length of the key (" + keyLength + ")" + " you entered is less than zero.\nPlease enter another key length: ");
 keyLength = keyboard.nextInt();
 System.out.println();
 if(phraseLength < 0)
 while(phraseLength < 0)
 System.out.print("The desired length of the phrase (" + phraseLength + ")" + " you entered is less than zero.\nPlease enter another phrase length: ");
 keyLength = keyboard.nextInt();
 System.out.println();
 if(numberOfPhrases <= 0)
 while(numberOfPhrases <= 0)
 System.out.print("The desired number of phrases (" + keyLength + ")" + " you entered is not applicable.\nPlease choose another number: ");
 keyLength = keyboard.nextInt();
 System.out.println();
 File file=new File(inputFileName);
 boolean exists = file.exists();
 if (exists == false)
 while(exists == false)
 System.out.println("The file you are searching for does not exist. Please place it in this programs directory.");
 System.out.print("Please re-enter the file name: ");
 inputFileName = keyboard.nextLine();
 file=new File(inputFileName);
 exists = file.exists();
 int count=keyLength, start=0, stop=0;
 FileReader freader = new FileReader(inputFileName);
 BufferedReader inputFile = new BufferedReader(freader);
 while(keepReadingFromFile != null)
 keepReadingFromFile = inputFile.readLine();
 if(keepReadingFromFile == null)
 break;
 else
 theFile = theFile + keepReadingFromFile;
 while(count < theFile.length())
 String name = theFile.substring(start, keyLength+stop);
 char singleCharacter = theFile.charAt(count);
 text.add(name, singleCharacter);
 start++;
 stop++;
 count++;
 int countNumberOfPhrases=0;
 while(numberOfPhrases > 0)
 countNumberOfPhrases++;
 String phrase = randomphrase(text, phraseLength, keyLength);
 System.out.println("Phrase " + countNumberOfPhrases + ":\n" + phrase);
 numberOfPhrases--;
 private static String randomphrase(FrequencyLibrary textLibrary, int phraseLengthToMake, int startLength)
 String startString="";
 char characterToAdd=' ';
 startLength++;
 Random generator = new Random();
 int sizeOfLibrary=textLibrary.size()/2, randomInt = generator.nextInt(sizeOfLibrary+1), value=0;
 Collection<String> stringNames = textLibrary.makeStringCollection();
 for(String stringFromCollection : stringNames)
 if(randomInt == value)
 startString = stringFromCollection;
 value++;
 String thePhrase = new String(startString);
 System.out.println("INITIAL START:" + startString + "TTTT");
 int substringStart=1;
 while(startLength < phraseLengthToMake)
 characterToAdd = textLibrary.randomUniformChoose(startString);
 thePhrase = thePhrase + characterToAdd;
 System.out.println("CHARACTER:" + characterToAdd + "TTTT");
 System.out.println("PHRASE:" + thePhrase + "TTTT");
 startString = thePhrase.substring(substringStart, thePhrase.length());
 boolean answer = textLibrary.contains(startString);
 System.out.println(answer);
 System.out.println("NEW STRING:" + startString + "TTTT");
 startLength++;
 substringStart++;
 return thePhrase;
}Second code:
import java.util.Collection;
import java.util.HashMap;
public class DenseFrequencyLibrary implements FrequencyLibrary
 private HashMap<String, MultiSetOfChar> bookTitleAndCharacterAndIntegerHashMap = new HashMap<String, MultiSetOfChar>();
 private MultiSetOfChar keyAndValuePairs = new DenseMultiSetOfChar();
 * Creates a new DenseFrequencyLibrary with all the essential things clear;
 DenseFrequencyLibrary()
 bookTitleAndCharacterAndIntegerHashMap.clear();
 * Input the value from the creation of the DensneMultiSetOfChar into a HashMap. If the key
 * already exists then the value associated with it is updated by one.
 * @param character a char to be used in forming the HashMap
 * @return characterMap
 private HashMap<String, MultiSetOfChar> inputIntoMap(String name, char character)
 if(!bookTitleAndCharacterAndIntegerHashMap.containsKey(name))
 keyAndValuePairs = new DenseMultiSetOfChar(character);
 else
 keyAndValuePairs.add(character);
 this.bookTitleAndCharacterAndIntegerHashMap.put(name, keyAndValuePairs); //input character and value
 return bookTitleAndCharacterAndIntegerHashMap; //return the new HashMap
 * Returns the number of books in the library.
 * @return |b|, ie the number of books in b
 public int size()
 int numberOfBooks=bookTitleAndCharacterAndIntegerHashMap.size();
 return numberOfBooks;
 * Searches the library for an occurrence of a given book
 * @param target the name of a book to be searched for in the library
 * @return true if and only if the argument is already a book title in the library.
 public boolean contains(String target)
 boolean bookIsInLibrary=false;
 if(bookTitleAndCharacterAndIntegerHashMap.containsKey(target))
 bookIsInLibrary = true;
 return bookIsInLibrary;
 * Returns the MultiSetOfChar that represents the occurrences of the individual characters
 * in the text of the book indicated by the argument.
 * @param target
 * @return MultiSetOfChar
 public MultiSetOfChar getFrequencies(String target)
 MultiSetOfChar frequencyMultiSetOfChar = bookTitleAndCharacterAndIntegerHashMap.get(target);
 return frequencyMultiSetOfChar;
 * Modifies the character occurrences associated with name to include one more occurrence of element.
 * @param name string of the name of the book
 * @param element character to add to the specified book
 public void add(String name, char element)
 bookTitleAndCharacterAndIntegerHashMap = inputIntoMap(name, element);
 * Modifies the character occurrences associated with name to include one less occurrence of element.
 * @param name string of the name of the book
 * @param element character to be removed from the specified book
 * @return true if and only if the book is modified.
 public boolean remove(String name, char element)
 boolean characterWasRemovedFromBook=false;
 //if the target character is in the map then remove it
 if(bookTitleAndCharacterAndIntegerHashMap.containsKey(name))
 MultiSetOfChar keyAndValuePairs = bookTitleAndCharacterAndIntegerHashMap.get(name);
 keyAndValuePairs.remove(element);
 characterWasRemovedFromBook = true; //set answer to true because the HashMap was changed
 else //target does not exist in the HashMap
 characterWasRemovedFromBook = false; //set answer to false because the HashMap was not changed
 return characterWasRemovedFromBook;
 * Returns a random character, chosen from the same distribution as the characters appear in the book.
 * For example, if 5% of the characters in "Alice in Wonderland" are an 'A', then this method should
 * return an 'A' about 5% of the time.
 * @param name string of the name of the book to search through and remove a character
 * @return true if and only if the argument is already a book title in the library.
 public char randomUniformChoose(String name)
 MultiSetOfChar keyAndValuePairs = bookTitleAndCharacterAndIntegerHashMap.get(name);
 char randomCharacter = keyAndValuePairs.randomUniformChoose();
 return randomCharacter; //return the random character pulled out
 public Collection<String> makeStringCollection()
 Collection<String> stringCollection = bookTitleAndCharacterAndIntegerHashMap.keySet();
 return stringCollection;
}Third code:
import java.util.HashMap;
import java.util.Set;
import java.util.Collection;
import java.util.Random;
* DenseMultiSetOfChar implements MultiSetOfChar.
* @mathmodel b is a finite multiset
* @mathdef
* |b| is the cardinality of b
* ||c,b|| is the number of occurrences of element c in b
* @author Kyle Hiltner
public class DenseMultiSetOfChar implements MultiSetOfChar
 private char characterInput=' ';
 private HashMap<Character, Integer> characterMap = new HashMap<Character, Integer>();
 * Create a new DenseMultiSetOfChar with zero argument
 DenseMultiSetOfChar()
 characterMap.clear(); //clear static HashMap
 * Create a new DenseMultiSetOfChar with the passed in value.
 * @param newChar character input to be added to the HashMap
 DenseMultiSetOfChar(char newChar)
 this.characterInput = newChar; //set characterInput to the value passed in
 characterMap = inputIntoMap(this.characterInput); //call private procedure to add characterInput to HashMap
 * Input the value from the creation of the DensneMultiSetOfChar into a HashMap. If the key
 * already exists then the value associated with it is updated by one.
 * @param character a char to be used in forming the HashMap
 * @return characterMap
 private HashMap<Character, Integer> inputIntoMap(char character)
 //if the character is not in the HashMap then add it with the starting value of 1
 if(!characterMap.containsKey(character))
 characterMap.put(character, 1); //input character and value
 else //character does exist
 int value = characterMap.get(character); //get the value for the specified key
 value++; //increase the value so as to show that another character was added
 characterMap.put(character, value); //place the character and new value in the HashMap
 return characterMap; //return the new HashMap
 * Returns the number of elements in this multiset (ie its cardinality).
 * Note that since multisets can include duplicates, the cardinality may be
 * larger than the number of distinct elements. Also, the total number of
 * items in the multiset is bounded above by Integer.MAX_VALUE.
 * @return |b|, ie the cardinality of b
 public int getCardinality()
 int totalElementsInMap=0;
 Collection<Integer> integerCollection = characterMap.values(); //create a collection for easy iteration
 //iterate through each value in the HashMap and compute the total number of elements in the HashMap
 for(Integer valueFromCollection : integerCollection)
 totalElementsInMap = totalElementsInMap + valueFromCollection; //compute new value of total values
 return totalElementsInMap; //return the final total value
 * Returns the number of occurrences of a given element in the multiset. A
 * simple identity relating getElementCount and getCardinality is that the
 * sum of getElementCount for each char is equal to the cardinality of the
 * set.
 * @param target
 * char to be counted in the multiset
 * @return ||target,b||, ie the number of occurrences of target in b
 public int getElementCount(char target)
 int numberOfGivenCharacters=0; //set initial value
 //if the HashMap contains the target character then numberOfGivenCharacters is set to the value
 if(characterMap.containsKey(target))
 numberOfGivenCharacters = characterMap.get(target); //set numberOfGivenCharacters to the value assigned to the target character
 return numberOfGivenCharacters; //return the value for the target character
 * Returns a set such that every element in the multiset is in the set (but
 * no duplicates). The cardinality of the returned set must be less than or
 * equal to |b|. The cardinality of the two are equal if and only if b
 * contains no duplicate elements.
 * @return a set of Character, s, such that: 
 * (for all (Character)i in s : (char)i in b) and 
 * (for all (char)i in b : (Character)i in s)
 public Set<Character> getElementSet()
 Set<Character> characterSet = characterMap.keySet(); //create a Set from the keys of characters in the HashMap
 return characterSet; //return the character Set
 * Adds a single element to the multiset. This operation always increases
 * the cardinality of the multiset by 1, assuming that the maximum capacity
 * of Integer.MAX_VALUE has not been reached.
 * @param item
 * the char to be added to b
 * @requires |b| < Integer.MAX_VALUE
 * @alters b
 * @ensures b = #b union {item}
 public void add(char item)
 characterMap = inputIntoMap(item); //call the private method to add new character (item) to the HashMap
 * Removes the target, if it is present in the multiset. The method returns
 * true if and only if it changes the multiset.
 * @param target
 * the char to be removed
 * @alters b
 * @ensures (target not in #b) ==> (b = #b) 
 * (target in #b) ==> (b union {target} = #b)
 * @return target in #b
 public boolean remove(char target)
 boolean answer=false; //set initial value to false
 //if the target character is in the map then remove it
 if(characterMap.containsKey(target))
 int value = characterMap.get(target); //find the value associated with the target character
 //if the value is 1 call remove from the HashMap and remove key and value
 if(value == 1)
 characterMap.remove(target); //remove key and value from the HashMap
 else //value is greater than 1
 value--; //decrease value to show removal
 characterMap.put(target, value); //replace target character with new value back into the HashMap
 answer = true; //set answer to true because the HashMap was changed
 else //target does not exist in the HashMap
 answer = false; //set answer to false because the HashMap was not changed
 return answer; //return answer
 * Returns a char chosen randomly based on the contents of the multiset.
 * This operation does not remove the char from the multiset or change the
 * multiset in any way. In particular, the cardinality of the multiset is
 * the same before and after this method.
 * 
 * Characters should be returned with a random distribution equal to the
 * distribution of characters in the multiset. That is, for a character that
 * appears N times in a multiset of cardinality M, the probability of that
 * character being returned is N / M. For example, a multiset that contains
 * only the character 'a', possibly many times, would always result in an
 * 'a' being generated. On the other hand, a multiset with an equal number
 * of 'a' and 'b' elements would return an 'a' approximately half the time
 * and a 'b' the other half.
 * @requires |b| >= 1
 * @return char c with probability p, where: 
 * p = ||c,b|| / |b|
 public char randomUniformChoose()
 char randomCharacter=' ';
 Random generator = new Random();
 int totalElementsInMap=0;
 Collection<Integer> integerCollection = characterMap.values(); //create a collection for easy iteration
 //iterate through each value in the HashMap and compute the total number of elements in the HashMap.
 //Do this in case a remove call was made
 for(Integer valueFromCollection : integerCollection)
 totalElementsInMap = totalElementsInMap + valueFromCollection; //compute new value of total values
 int randomInt = generator.nextInt(totalElementsInMap+1), lowerValue=0, upperValue=0;
 Collection<Character> keyCollection = characterMap.keySet();
 //iterate through each value in the HashMap and compute the total number of elements in the HashMap
 for(Character keyFromCollection : keyCollection)
 upperValue = upperValue + characterMap.get(keyFromCollection);
 if(randomInt == upperValue)
 randomCharacter = keyFromCollection;
 if(randomInt >= lowerValue && randomInt <= upperValue)
 randomCharacter = keyFromCollection;
 lowerValue = upperValue + 1;
 return randomCharacter; //return the random character pulled out
}The Error:
Exception in thread "main" java.lang.NullPointerException
 at DenseFrequencyLibrary.randomUniformChoose(DenseFrequencyLibrary.java:137)
 at DistributionPlagiarist.randomphrase(DistributionPlagiarist.java:146)
 at DistributionPlagiarist.main(DistributionPlagiarist.java:112)I will attempt to explain what this does in as few words as possible. For a breakdown of the lab go urlhttp://www.cse.ohio-state.edu/~paolo/teaching/494MJ/labs/lab8.shtml{url}. If you don't feel like reading that: THe program reads in some command line arguments. From there it reads from the file provided in the command line and creates "keys" from the specified length. From there I need to create a phrase of the specified length. If i am supposed to create more then one then i do. That is pretty much it. I can't figure out where (really why) the NullPointerException error is coming from.
Help is appreciated!!

Post the actual error text (copy and paste, don't "interpret" it) here.
It should include a stack trace which references a line number of the program -
unless you suppressed the trace, in which case change your error handling
so that the trace is produced.
Identify which program line in your post the error is pointing to so that we can match
the error with your program, since your post doesn't have line numbers..
Edited by: ChuckBing on Nov 16, 2007 7:19 PM
Also - posting large amounts of code (as you did) will reduce the chance of anyone helping

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Thanks. I'm working with different hosts and I guess thats where the confusion for me is coming in. In bluehost, I simply submit my form through form action to http://www.bluehost/bluemail. With the php form construction it 's form action is contact.php. Does this mean that the server I'm working with will uinderstand how to process contact.php and where to send it based on paramaters previously submitted? Or do I instruct the server via the php form? Thanks again
Date: Wed, 8 Feb 2012 13:50:11 -0700
From: [email protected]
To: [email protected]
Subject: Newbie for the life of me can't figure out where in contact.php you tell it where to send form?
 Re: Newbie for the life of me can't figure out where in contact.php you tell it where to send form?
 created by mhollis55 in Dreamweaver - View the full discussion
The reason why this is done in php is because php is server-side scripting. It's telling your server to do stuff. HTML doesn't tell your server anything, it tells the client (the web browser loading it) to do things. Only your server can send an email.
 Replies to this message go to everyone subscribed to this thread, not directly to the person who posted the message. To post a reply, either reply to this email or visit the message page: http://forums.adobe.com/message/4194407#4194407
 To unsubscribe from this thread, please visit the message page at http://forums.adobe.com/message/4194407#4194407. In the Actions box on the right, click the Stop Email Notifications link.
 Start a new discussion in Dreamweaver by email or at Adobe Forums
For more information about maintaining your forum email notifications please go to http://forums.adobe.com/message/2936746#2936746.

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Hi,
According to your post, my understanding is that to paste 270,000 cells data into the Datashet view to use in a list.
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http://clintoncherry.wordpress.com/2008/02/27/bulk-copy-and-paste-into-a-sharepoint-list/
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Linda Li
Linda Li
TechNet Community Support

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First thing to try is to reset your device. Press and hold the Home and Sleep buttons simultaneously until the Apple logo appears. Let go of the buttons and let the device restart. See if that fixes your problem.
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The storage space taken up by "Other" can be made up of, notes or files of any kind you've added to the iPod whilst using it as a hard disk or album artwork. Or sometimes when the iPod data base has become corrupt.
There will always be a few MBs of used space under "other" but if it's more than that it often happens when the iPod data base becomes corrupt.
If the iPod is enabled for disk use, you can look at the folders on the iPod through Explorer or Finder and delete anything you don't want.
If it's a corruption it will probably need to be restored, see how to restore the iPod to factory settings which will erase the iPods contents and reclaim the used space.
Then reload the music from iTunes.

One of my kids submitted their friends email as our verification email if anything needs changed so now I am not getting emails about my questions. I can not figure out where to find it to edit it

Somehow my security answers are not correct. So, I submitted to have the answers send to me and they are going to another e-mail address that I don't have access to. I can't find it in my account to edit it though. Anyone know where I can find it to change it?

From a Kappy post
The Three Best Alternatives for Security Questions and Rescue Mail
1. Use Apple's Express Lane.
Go to https://expresslane.apple.com ; click 'See all products and services' at the
bottom of the page. In the next page click 'More Products and Services, then
'Apple ID'. In the next page select 'Other Apple ID Topics' then 'Forgotten Apple
ID security questions' and click 'Continue'. Please be patient waiting for the return
phone call. It will come in time depending on how heavily the servers are being hit.
2. Call Apple Support in your country: Customer Service: Contact Apple support.
3. Rescue email address and how to reset Apple ID security questions.
A substitute for using the security questions is to use 2-step verification:
Two-step verification FAQ Get answers to frequently asked questions about two-step verification for Apple ID.

HT1390 I have completed the download of a rented movies on iTunes on my iPad but can't figure out where it is so I can start watching it? Help?

I have completed the download of a rental movies on iTunes on my iPad but can't find where the movie so I can start playing it on my iPad? Help?

Since you make no mention of where you have looked, then I suggest looking in the videos app.

I have 2008 microsoft office with three license keys. i bought my daughter a new make and wiped her older mac. question is when i did this it says there are too many users for program how can i figure out where product key is

I have microsoft officemac w 3 licenses. I have one key on one computer and the second key on another. Problem I bought daughter new mac (3rd computer) and put on key on her new computer. With her old computer we wiped it to back to factory etc. Then I added a product key for officemac on old
est computer. Now when I use my wiped computer it comes up saying that all product keys are taken. How do I check to see if she has the same key number as the old one I have? I have paid for three but her computer and my old one must have the same key number. I need help in checking key numbers so I can set it right. Thanks

Office 2008 for Mac error: "Microsoft Office 2008 ... - Microsoft Support

Am I bottlenecked? Can't figure out where...

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