Applying Style1 to all paragraph with Style2

Hi,
I would like to apply a new style to all paragraph with a particular style. For example, change all paragraph with style Style2 to style Style1. How can I proceed?
Thanks for any help.
Hervé Soulard.

Kenneth's solution
(1. In a content file, find one of your Style 1 paras.
2. Copy Special > Paragraph Style
3. Use Find&Replace to Find Style 2 and Replace By Pasting. )
... works best for book level replacements.
You can also, for a single file...
In the Paragraph Designer with Style 1 open, use the Global Updates drop down menu to select Style 2 as "Apply to..."
Art

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{/,}L*/{A*d,Ca*/*/Ex,Co{mpon,reM},Ex,In{p,ter},iTu*/*P,Keyb,Mail/B,Pr*P,Qu*T,Scripti,Sec,Servi,Spo,Widg}* -path \\*s/Resources -prune -o -type f -name Info.plist' '/usr/lib -type f -name *.dylib' `awk "${s[31]}"<<<${p[23]}` "/e*/{auto,{cron,fs}tab,hosts,{[lp],sy}*.conf,mach_i*/*,pam.d/*,ssh{,d}_config,*.local} {,/usr/local}/etc/periodic/*/* /L*/P*{,/*}/com.a*.{Bo,sec*.ap}*t {/S*/,/,}L*/Lau*/*t .launchd.conf" list getenv /Library/Preferences/com.apple.alf\ globalstate --proxy '-n get default' -I --dns -getdnsservers\ "${p[N5]}" -getinfo\ "${p[N5]}" -P -m\ / '' -n1 '-R -l1 -n1 -o prt -stats command,uid,prt' '--regexp --only-files --files com.apple.pkg.*|sort|uniq' -kl -l -s\ / '-R -l1 -n1 -o mem -stats command,uid,mem' '+c0 -i4TCP:0-1023' com.apple.dashboard\ layer-gadgets '-d /L*/Mana*/$USER&&echo On' '-app Safari WebKitDNSPrefetchingEnabled' "+c0 -l|awk '{print(\$1,\$3)}'|sort|uniq -c|sort -n|tail -1|awk '{print(\$2,\$3,\$1)}'" -m 'L*/{Con*/*/Data/L*/,}Pref* -type f -size 0c -name *.plist.???????|wc -l' kern.memorystatus_vm_pressure_level '3>&1 >&- 2>&3' " -F '\$Time \$Message' -k Sender kernel -k Message CSeq 'n Cause: -' " );N1=${#c2[@]};for j in {0..9};do c2[N1+j]=SP${p[j]}DataType;done;N2=${#c2[@]};for j in 0 1;do c2[N2+j]="-n ' syscall::'${p[33+j]}':return { @out[execname,uid]=sum(arg0) } tick-10sec { trunc(@out,1);exit(0);} '";done;l=(Restricted\ files Hidden\ apps 'Elapsed time (s)' POST Battery Safari\ extensions Bad\ plists 'High file counts' User Heat System\ load boot\ args FileVault Diagnostic\ reports Log 'Free space (MiB)' 'Swap (MiB)' Activity 'CPU per process' Login\ hook 'I/O per process' Mach\ ports kexts Daemons Agents XPC\ cache Startup\ items Admin\ access Root\ access Bundles dylibs Apps Font\ issues Inserted\ dylibs Firewall Proxies DNS TCP/IP Wi-Fi Profiles Root\ crontab User\ crontab 'Global login items' 'User login items' Spotlight Memory Listeners Widgets Parental\ Controls Prefetching SATA Descriptors App\ extensions Lockfiles Memory\ pressure SMC Shutdowns );N3=${#l[@]};for i in 0 1 2;do l[N3+i]=${p[5+i]};done;N4=${#l[@]};for j in 0 1;do l[N4+j]="Current ${p[29+j]}stream data";done;A0() { id -G|grep -qw 80;v[1]=$?;((v[1]==0))&&sudo true;v[2]=$?;v[3]=`date +%s`;clear >&-;date '+Start time: %T %D%n';};for i in 0 1;do eval ' A'$((1+i))'() { v=` eval "${c1[$1]} ${c2[$2]}"|'${c1[30+i]}' "${s[$3]}" `;[[ "$v" ]];};A'$((3+i))'() { v=` while read i;do [[ "$i" ]]&&eval "${c1[$1]} ${c2[$2]}" \"$i\"|'${c1[30+i]}' "${s[$3]}";done<<<"${v[$4]}" `;[[ "$v" ]];};A'$((5+i))'() { v=` while read i;do '${c1[30+i]}' "${s[$1]}" "$i";done<<<"${v[$2]}" `;[[ "$v" ]];};A'$((7+i))'() { v=` eval sudo "${c1[$1]} ${c2[$2]}"|'${c1[30+i]}' "${s[$3]}" `;[[ "$v" ]];};';done;A9(){ v=$((`date +%s`-v[3]));};B2(){ v[$1]="$v";};for i in 0 1;do eval ' B'$i'() { v=;((v['$((i+1))']==0))||{ v=No;false;};};B'$((3+i))'() { v[$2]=`'${c1[30+i]}' "${s[$3]}"<<<"${v[$1]}"`;} ';done;B5(){ v[$1]="${v[$1]}"$'\n'"${v[$2]}";};B6() { v=` paste -d: <(printf "${v[$1]}") <(printf "${v[$2]}")|awk -F: ' {printf("'"${f[$3]}"'",$1,$2)} ' `;};B7(){ v=`grep -Fv "${v[$1]}"<<<"$v"`;};C0() { [[ "$v" ]]&&sed -E "$s"<<<"$v";};C1() { [[ "$v" ]]&&printf "${f[$1]}" "${l[$2]}" "$v"|sed -E "$s";};C2() { v=`echo $v`;[[ "$v" != 0 ]]&&C1 0 $1;};C3() { v=`sed -E "${s[63]}"<<<"$v"`&&C1 1 $1;};for i in 1 2 7 8;do for j in 0 2 3;do eval D$i$j'(){ A'$i' $1 $2 $3; C'$j' $4;};';done;done;{ A0;D20 0 $((N1+1)) 2;D10 0 $N1 1;B0;C2 27;B0&&! B1&&C2 28;D12 15 37 25 8;A1 0 $((N1+2)) 3;C0;D13 0 $((N1+3)) 4 3;D23 0 $((N1+4)) 5 4;D13 0 $((N1+9)) 59 50;for i in 0 1 2;do D13 0 $((N1+5+i)) 6 $((N3+i));done;D13 1 10 7 9;D13 1 11 8 10;B1&&D73 19 53 67 55;D22 2 12 9 11;D12 3 13 10 12;D23 4 19 44 13;D23 5 54 12 56;D23 5 14 12 14;D22 6 36 13 15;D22 20 52 66 54;D22 7 37 14 16;D23 8 15 38 17;D22 9 16 16 18;B1&&{ D82 35 49 61 51;D82 11 17 17 20;for i in 0 1;do D82 28 $((N2+i)) 45 $((N4+i));done;};D22 12 44 54 45;D22 12 39 15 21;A1 13 40 18;B2 4;B3 4 0 19;A3 14 6 32 0;B4 0 5 11;A1 17 41 20;B7 5;C3 22;B4 4 6 21;A3 14 7 32 6;B4 0 7 11;B3 4 0 22;A3 14 6 32 0;B4 0 8 11;B5 7 8;B1&&{ A8 18 26 23;B7 7;C3 23;};A2 18 26 23;B7 7;C3 24;D13 4 21 24 26;B4 4 12 26;B3 4 13 27;A1 4 22 29;B7 12;B2 14;A4 14 6 52 14;B2 15;B6 14 15 4;B3 0 0 30;C3 29;A1 4 23 27;B7 13;C3 30;B3 4 0 65;A3 14 6 32 0;B4 0 16 11;A1 26 50 64;B7 16;C3 52;D13 24 24 32 31;D13 25 37 32 33;A2 23 18 28;B2 16;A2 16 25 33;B7 16;B3 0 0 34;B2 21;A6 47 21&&C0;B1&&{ D73 21 0 32 19;D73 10 42 32 40;D82 29 35 46 39;};D23 14 1 62 42;D12 34 43 53 44;D12 22 20 32 25;D22 0 $((N1+8)) 51 32;D13 4 8 41 6;D12 21 28 35 34;D13 27 29 36 35;A2 27 32 39&&{ B2 19;A2 33 33 40;B2 20;B6 19 20 3;};C2 36;D23 33 34 42 37;B1&&D83 35 45 55 46;D23 32 31 43 38;D12 36 47 32 48;D13 10 42 32 41;D13 37 2 48 43;D13 4 5 32 1;D13 4 3 60 5;D12 21 48 49 49;B3 4 22 57;A1 21 46 56;B7 22;B3 0 0 58;C3 47;D22 4 4 50 0;D12 4 51 32 53;D23 22 9 37 7;A9;C2 2;} 2>/dev/null|pbcopy;exit 2>&-
    Copy the selected text to the Clipboard by pressing the key combination command-C.
    8. Launch the built-in Terminal application in any of the following ways:
    ☞ Enter the first few letters of its name into a Spotlight search. Select it in the results (it should be at the top.)
    ☞ In the Finder, select Go ▹ Utilities from the menu bar, or press the key combination shift-command-U. The application is in the folder that opens.
    ☞ Open LaunchPad. Click Utilities, then Terminal in the icon grid.
    Click anywhere in the Terminal window and paste by pressing command-V. The text you pasted should vanish immediately. If it doesn't, press the return key.
    9. If you see an error message in the Terminal window such as "Syntax error" or "Event not found," enter
    exec bash
    and press return. Then paste the script again.
    10. If you're logged in as an administrator, you'll be prompted for your login password. Nothing will be displayed when you type it. You will not see the usual dots in place of typed characters. Make sure caps lock is off. Type carefully and then press return. You may get a one-time warning to be careful. If you make three failed attempts to enter the password, the test will run anyway, but it will produce less information. In most cases, the difference is not important. If you don't know the password, or if you prefer not to enter it, press the key combination control-C or just press return  three times at the password prompt. Again, the script will still run.
    If you're not logged in as an administrator, you won't be prompted for a password. The test will still run. It just won't do anything that requires administrator privileges.
    11. The test may take a few minutes to run, depending on how many files you have and the speed of the computer. A computer that's abnormally slow may take longer to run the test. While it's running, there will be nothing in the Terminal window and no indication of progress. Wait for the line
    [Process completed]
    to appear. If you don't see it within half an hour or so, the test probably won't complete in a reasonable time. In that case, close the Terminal window and report what happened. No harm will be done.
    12. When the test is complete, quit Terminal. The results will have been copied to the Clipboard automatically. They are not shown in the Terminal window. Please don't copy anything from there. All you have to do is start a reply to this comment and then paste by pressing command-V again.
    At the top of the results, there will be a line that begins with the words "Start time." If you don't see that, but instead see a mass of gibberish, you didn't wait for the "Process completed" message to appear in the Terminal window. Please wait for it and try again.
    If any private information, such as your name or email address, appears in the results, anonymize it before posting. Usually that won't be necessary.
    13. When you post the results, you might see an error message on the web page: "You have included content in your post that is not permitted," or "You are not authorized to post." That's a bug in the forum software. Please post the test results on Pastebin, then post a link here to the page you created.
    14. This is a public forum, and others may give you advice based on the results of the test. They speak only for themselves, and I don't necessarily agree with them.
    Copyright © 2014 by Linc Davis. As the sole author of this work, I reserve all rights to it except as provided in the Use Agreement for the Apple Support Communities website ("ASC"). Readers of ASC may copy it for their own personal use. Neither the whole nor any part may be redistributed.

  • How do I find all pictures with no (empty) keyword ?

    I have decided to import all my pictures into LightRoom.
    A lot of my older pictures are not registered with any keywords :(
    - only with IPTC location information.
    My plan is to systematic go through all my pictures and add relevant keywords to all pictures - so my old pictures become as searchable as my newest pictures.
    Some of my old pictures has keywords some has not.
    How do I in Lightroom - find all pictures with no keywords?
    I have tried to use the Find tool - but don't see any options to search for "Empty/missing" keywords.
    Also I would like to find all pictures with few keywords and in step II add additional keywords to these pictures.
    Any ideas on how to make a find all pictures where number of keywords is less than X inside or outside LightRoom.
    Henrik Bach
    Denmark

    > I also did think of the SQL idea.
    > If I find a way of doing this I will repost my findings.
    Well, being a tech geek, I found this challenge kind of irresistible,
    and I'm happy to report I have a solution for you.
    STEP 1
    First, make a copy of your "Lightroom Database.lrdb" file (we'll work
    off the copy to be safe)
    STEP 2
    Next, you need to be able to browse the database. The database is in
    SQLite3 format. I tried installiing an SQLite3 ODBC driver and accessing
    it through MS Access 2003. While Access was able to see all of the
    tables in the database, every time I tried to link to one I got:
    "Reserved error (-7748); there is no message for this error"
    I found a few tips for this but wasn't able to work around it and get it
    to work. Which is a shame, since Access would be the easiest way for
    browsing and querying tables.
    Instead I found an open source tool called SQLite Database Browser.
    http://sourceforge.net/project/showfiles.php?group_id=87946&package_id=91778&release_id=41 4746
    I used the Windows version. There appears to be a version for MacOSX on
    PowerPC. It doesn't look like there is a version for Intel based Macs
    (though if you know how, you could always try downloading the source and
    compiling it yourself).
    STEP 3
    After you install the browser, open it up, choose "Open Database" and
    select the COPY of the lightroom database we made in step 1
    STEP 4
    go to the Execute SQL tab and issue the following command
    SELECT A.idx_filename, count(C.name)
    FROM Adobe_imageFiles A, AGLibraryTagImage B, AGLibraryTag C
    WHERE A.image=B.image AND B.tag=C.id_local AND C.kindName='AgKeywordTagKind'
    GROUP BY A.idx_filename
    HAVING count(C.name) <= 3
    That will give you all images with 3 or fewer keywords applied.
    Of course, theres no guarantee that this wont break in future versions.
    Now an explanation of the data.
    Adobe_imageFiles - contains data about image files:
    1) idx_filename is the filename
    2) absolutePath is the full file path
    3) image is a unique ID for the image which you can cross reference in
    other image related tables
    AGLibraryTag - contains info about "tags" applied to images:
    1) id_local is a unique ID for this "tag", which you can use to cross
    reference in other tag tables
    2) kindName is the kind of tag you are looking at. Available values
    appear to be:
    AgCaptionTagKind
    AgCollectionTagKind
    AgCopyrightTagKind
    AgEnumeratedMetadataTagKind
    AgFolderTagKind
    AgImportTagKind
    AgKeywordTagKind
    AgMissingFileTagKind
    AgQuickCollectionTagKind
    AgSpecialContentOwningTagKind
    AgTempImagesTagKind
    3) name is the value for that tag (the collection name, the keyword, etc)
    AGLibraryTagImage - Use this to connect the images and tags tables

  • Problems when trying to move a paragraph with a heading to the next page

    When i try to move a paragraph with a heading (generally style 2) to the next page by pressing the enter key, rather than the whole paragraph moving to the top of the next page it moves to pretty well every where but the top. i have attached a video because im sure what i have said doesn't make much sense.
    http://www.youtube.com/watch?v=MrlnsmLIDGk&feature=youtubegdataplayer
    i have talked to an apple technician through apple care and we came to the conclusion after reseting iwork to default settings still with no changes all i could do was completely remove iwork from my computer and try to start over. Or come to the forums to see if there is a work around.

    Hi Jared,
    Without commentary, or other explanation, it's difficult to determine what actions you are taking to produce the results in the video.
    In the first instance, it appears that you have placed the insertion point at the beginning of the line following the header, then pressed and held return. this action pushes that line (and anything below it) down until it crosses the page boundary and jumps to a second page. That's expected behaviour.
    At approximately 0:57, you have deleted the return characters, returning the first and second lines after the header to a position immediately following the header. The insertion point is then moved to the point at the beginning of the header line, and returns are inserted as before. About 1:04, a number of unreadable alert boxes appear. At 1:07, the second line below the heading moves to the second page, followed by the first line, then by the heading itself at about 1:10. Again this is expected behaviour.
    Only after that are there any 'odd' behaviours, and without knowing what actions you are taking to produce those oddities, it's (at least) difficult to say what is causing the results you see.
    Regards,
    Barry

  • InDesign CS3 crashes when applying styles to pasted text with formatting.

    Running InDesign CS3, v. 5.0.2 on Windows XP, SP2
    InDesign is crashing whenever I do the following:
    1. Paste or place text from Microsoft Word -- with existing formatting preserved.
    2. Apply any character or paragraph style to that text.
    This happens 100% of the time when I try to recreate the error. It happens on more than one computer. It never used to happen in IDCS2. It's not a missing font issue.
    I've tried recreating the InDesign preference files, but it didn't work. (See help file at http://kb.adobe.com/selfservice/viewContent.do?externalId=kb400616&sliceId=1)
    Any suggestions would be hugely appreciated! This is slowing down my work a ton, and manually adding things like underline is killing me. If it persists, I'll have to roll back to CS2. :(

    We had exactly the same issue - but it only seemed to happen when a "Hyperlink" character style came in with the pasted text. In fact, the crash only happened when we tried to apply a paragraph style to a paragraph that had a hyperlink in it.
    Our solution: before we try to do anything else, we delete the "Hyperlink" character style. I can't guarantee that this will solve your issue, but it has worked for us (so far!) in those rare cases when we cut & paste Word text.
    We have never had this issue when we import ("Place") the Word file - that's generally a better workflow anyway.
    -Bill

  • How do I save a style of paragraphs with a numbered list in Pages 05?

    I wish to save a style of paragraph with a numbered list. Is it possible to save them at the same time in Pages 5 as it was in Pages 09'?
    Where are the shortcuts?
    Thanks.

    Yes, I know but there is no real list preset. The format command, when opened, shows a menu and I think you are using the word Style differently. A Style in 09 allowed one to save present formatting for several text appearance options, which is no longer possible in 05 "styles." Styles in text edting for applications like Word, OpenOffice, iBooks, and Pages 09 referred to a way to save a set of formatting command together and apply them with one click. That's the rub here in 5.
    Yes, you can apply a bullet as a "style" to a paragraph, bui you cannot save that formatting as a preset in any way to do it in one click. The issue is consistency and one click capability for multiple formatting features for a paragraph of text.
    Separating bullets and lists from the ability to maintain them in the Paragraph style removed the one click paragraph formatting option which is helpful for anyone who uses it more than a few times in a document.
    The need is for people who want to use common formatting for paragraphs and maintain a one-click option to apply text, indent, spacing, and bullets in one click, not spread out in several menus and lists. 
    If you can explain how to do this in Pages 5 I will be very happy and you will have saved me many clicks. Otherwise I will continue to use the bullet "style" list drop down menu.

  • How can I find paragraph with hyphens?

    Hi community,
    I received a document with left-aligned text AND ugly hyphenation. No paragraph styles applied.
    I thought it would be easy to search for hyphenated paragraphs with the search and replace window, but can find this option anywhere.
    Am I blind or isn't there such an option?
    Thanks for your help
    Vinny

    it's possible with script.
    I suggest you to ask that in the section indesign scripting
    InDesign Scripting

  • All Joins with Example

    Hi Experts,
    Pls let me know what are all joins available in ABAP??
    One example program for each for better understanding...
    Any useful inputs on this will be highly rewarded.
    Thanks in advance
    Rgds ~ Lakshmiraj

    Hi,
    Joins are used to fetch data fast from Database tables:
    Tables are joined with the proper key fields to fetch the data properly.
    If there are no proper key fields between tables don't use Joins;
    Important thing is that don't USE JOINS FOR CLUSTER tableslike BSEG and KONV.
    Only use for Transparenmt tables.
    You can also use joins for the database VIews to fetch the data.
    JOINS
    ... FROM tabref1 [INNER] JOIN tabref2 ON cond
    Effect
    The data is to be selected from transparent database tables and/or views determined by tabref1 and tabref2. tabref1 and tabref2 each have the same form as in variant 1 or are themselves Join expressions. The keyword INNER does not have to be specified. The database tables or views determined by tabref1 and tabref2 must be recognized by the ABAP Dictionary.
    In a relational data structure, it is quite normal for data that belongs together to be split up across several tables to help the process of standardization (see relational databases). To regroup this information into a database query, you can link tables using the join command. This formulates conditions for the columns in the tables involved. The inner join contains all combinations of lines from the database table determined by tabref1 with lines from the table determined by tabref2, whose values together meet the logical condition (join condition) specified using ON>cond.
    Inner join between table 1 and table 2, where column D in both tables in the join condition is set the same:
    Table 1 Table 2
    A
    B
    C
    D
    D
    E
    F
    G
    H
    a1
    b1
    c1
    1
    1
    e1
    f1
    g1
    h1
    a2
    b2
    c2
    1
    3
    e2
    f2
    g2
    h2
    a3
    b3
    c3
    2
    4
    e3
    f3
    g3
    h3
    a4
    b4
    c4
    3
    |--|||--|
    Inner Join
    A
    B
    C
    D
    D
    E
    F
    G
    H
    a1
    b1
    c1
    1
    1
    e1
    f1
    g1
    h1
    a2
    b2
    c2
    1
    1
    e1
    f1
    g1
    h1
    a4
    b4
    c4
    3
    3
    e2
    f2
    g2
    h2
    |--||||||||--|
    Example
    Output a list of all flights from Frankfurt to New York between September 10th and 20th, 2001 that are not sold out:
    DATA: DATE LIKE SFLIGHT-FLDATE,
    CARRID LIKE SFLIGHT-CARRID,
    CONNID LIKE SFLIGHT-CONNID.
    SELECT FCARRID FCONNID F~FLDATE
    INTO (CARRID, CONNID, DATE)
    FROM SFLIGHT AS F INNER JOIN SPFLI AS P
    ON FCARRID = PCARRID AND
    FCONNID = PCONNID
    WHERE P~CITYFROM = 'FRANKFURT'
    AND P~CITYTO = 'NEW YORK'
    AND F~FLDATE BETWEEN '20010910' AND '20010920'
    AND FSEATSOCC < FSEATSMAX.
    WRITE: / DATE, CARRID, CONNID.
    ENDSELECT.
    If there are columns with the same name in both tables, you must distinguish between them by prefixing the field descriptor with the table name or a table alias.
    Note
    In order to determine the result of a SELECT command where the FROM clause contains a join, the database system first creates a temporary table containing the lines that meet the ON condition. The WHERE condition is then applied to the temporary table. It does not matter in an inner join whether the condition is in the ON or WHEREclause. The following example returns the same solution as the previous one.
    Example
    Output of a list of all flights from Frankfurt to New York between September 10th and 20th, 2001 that are not sold out:
    DATA: DATE LIKE SFLIGHT-FLDATE,
    CARRID LIKE SFLIGHT-CARRID,
    CONNID LIKE SFLIGHT-CONNID.
    SELECT FCARRID FCONNID F~FLDATE
    INTO (CARRID, CONNID, DATE)
    FROM SFLIGHT AS F INNER JOIN SPFLI AS P
    ON FCARRID = PCARRID
    WHERE FCONNID = PCONNID
    AND P~CITYFROM = 'FRANKFURT'
    AND P~CITYTO = 'NEW YORK'
    AND F~FLDATE BETWEEN '20010910' AND '20010920'
    AND FSEATSOCC < FSEATSMAX.
    WRITE: / DATE, CARRID, CONNID.
    ENDSELECT.
    Note
    Since not all of the database systems supported by SAP use the standard syntax for ON conditions, the syntax has been restricted. It only allows those joins that produce the same results on all of the supported database systems:
    Only a table or view may appear to the right of the JOIN operator, not another join expression.
    Only AND is possible in the ON condition as a logical operator.
    Each comparison in the ON condition must contain a field from the right-hand table.
    If an outer join occurs in the FROM clause, all the ON conditions must contain at least one "real" JOIN condition (a condition that contains a field from tabref1 amd a field from tabref2.
    Note
    In some cases, '*' may be specified in the SELECT clause, and an internal table or work area is entered into the INTO clause (instead of a list of fields). If so, the fields are written to the target area from left to right in the order in which the tables appear in the FROM clause, according to the structure of each table work area. There can then be gaps between table work areas if you use an Alignment Request. For this reason, you should define the target work area with reference to the types of the database tables, not simply by counting the total number of fields. For an example, see below:
    Variant 3
    ... FROM tabref1 LEFT [OUTER] JOIN tabref2 ON cond
    Effect
    Selects the data from the transparent database tables and/or views specified in tabref1 and tabref2. tabref1 und tabref2 both have either the same form as in variant 1 or are themselves join expressions. The keyword OUTER can be omitted. The database tables or views specified in tabref1 and tabref2 must be recognized by the ABAP-Dictionary.
    In order to determine the result of a SELECT command where the FROM clause contains a left outer join, the database system creates a temporary table containing the lines that meet the ON condition. The remaining fields from the left-hand table (tabref1) are then added to this table, and their corresponding fields from the right-hand table are filled with ZERO values. The system then applies the WHERE condition to the table.
    Left outer join between table 1 and table 2 where column D in both tables set the join condition:
    Table 1 Table 2
    A
    B
    C
    D
    D
    E
    F
    G
    H
    a1
    b1
    c1
    1
    1
    e1
    f1
    g1
    h1
    a2
    b2
    c2
    1
    3
    e2
    f2
    g2
    h2
    a3
    b3
    c3
    2
    4
    e3
    f3
    g3
    h3
    a4
    b4
    c4
    3
    |--|||--|
    Left Outer Join
    A
    B
    C
    D
    D
    E
    F
    G
    H
    a1
    b1
    c1
    1
    1
    e1
    f1
    g1
    h1
    a2
    b2
    c2
    1
    1
    e1
    f1
    g1
    h1
    a3
    b3
    c3
    2
    NULL
    NULL
    NULL
    NULL
    NULL
    a4
    b4
    c4
    3
    3
    e2
    f2
    g2
    h2
    |--||||||||--|
    Example
    Output a list of all custimers with their bookings for October 15th, 2001:
    DATA: CUSTOMER TYPE SCUSTOM,
    BOOKING TYPE SBOOK.
    SELECT SCUSTOMNAME SCUSTOMPOSTCODE SCUSTOM~CITY
    SBOOKFLDATE SBOOKCARRID SBOOKCONNID SBOOKBOOKID
    INTO (CUSTOMER-NAME, CUSTOMER-POSTCODE, CUSTOMER-CITY,
    BOOKING-FLDATE, BOOKING-CARRID, BOOKING-CONNID,
    BOOKING-BOOKID)
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    ORDER BY SCUSTOMNAME SBOOKFLDATE.
    WRITE: / CUSTOMER-NAME, CUSTOMER-POSTCODE, CUSTOMER-CITY,
    BOOKING-FLDATE, BOOKING-CARRID, BOOKING-CONNID,
    BOOKING-BOOKID.
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    If there are columns with the same name in both tables, you must distinguish between them by prefixing the field descriptor with the table name or using an alias.
    Note
    For the resulting set of a SELECT command with a left outer join in the FROM clause, it is generally of crucial importance whether a logical condition is in the ON or WHERE condition. Since not all of the database systems supported by SAP themselves support the standard syntax and semantics of the left outer join, the syntax has been restricted to those cases that return the same solution in all database systems:
    Only a table or view may come after the JOIN operator, not another join statement.
    The only logical operator allowed in the ON condition is AND.
    Each comparison in the ON condition must contain a field from the right-hand table.
    Comparisons in the WHERE condition must not contain a field from the right-hand table.
    The ON condition must contain at least one "real" JOIN condition (a condition in which a field from tabref1 as well as from tabref2 occurs).
    Note
    In some cases, '*' may be specivied as the field list in the SELECT clause, and an internal table or work area is entered in the INTO clause (instead of a list of fields). If so, the fields are written to the target area from left to right in the order in which the tables appear in the llen in der FROM clause, according to the structure of each table work area. There can be gaps between the table work areas if you use an Alignment Request. For this reason, you should define the target work area with reference to the types of the database tables, as in the following example (not simply by counting the total number of fields).
    Example
    Example of a JOIN with more than two tables: Select all flights from Frankfurt to New York between September 10th and 20th, 2001 where there are available places, and display the name of the airline.
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    FLIGHT TYPE SFLIGHT,
    PFLI TYPE SPFLI,
    CARR TYPE SCARR,
    END OF WA.
    SELECT * INTO WA
    FROM ( SFLIGHT AS F INNER JOIN SPFLI AS P
    ON FCARRID = PCARRID AND
    FCONNID = PCONNID )
    INNER JOIN SCARR AS C
    ON FCARRID = CCARRID
    WHERE P~CITYFROM = 'FRANKFURT'
    AND P~CITYTO = 'NEW YORK'
    AND F~FLDATE BETWEEN '20010910' AND '20010920'
    AND FSEATSOCC < FSEATSMAX.
    WRITE: / WA-CARR-CARRNAME, WA-FLIGHT-FLDATE, WA-FLIGHT-CARRID,
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    Syntax
    ... [(] {dbtab_left [AS tabalias_left]} | join
    {[INNER] JOIN}|{LEFT [OUTER] JOIN}
    {dbtab_right [AS tabalias_right] ON join_cond} [)] ... .
    Effect
    The join syntax represents a recursively nestable join expression. A join expression consists of a left-hand and a right- hand side, which are joined either by means of [INNER] JOIN or LEFT [OUTER] JOIN . Depending on the type of join, a join expression can be either an inner ( INNER) or an outer (LEFT OUTER) join. Every join expression can be enclosed in round brackets. If a join expression is used, the SELECT command circumvents SAP buffering.
    On the left-hand side, either a single database table, a view dbtab_left, or a join expression join can be specified. On the right-hand side, a single database table or a view dbtab_right as well as join conditions join_cond can be specified after ON. In this way, a maximum of 24 join expressions that join 25 database tables or views with each other can be specified after FROM.
    AS can be used to specify an alternative table name tabalias for each of the specified database table names or for every view. A database table or a view can occur multiple times within a join expression and, in this case, have various alternative names.
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    At least one comparison must be specified after ON.
    Individual comparisons may be joined using AND only.
    All comparisons must contain a column in the database table or the view dbtab_right on the right-hand side as an operand.
    The following language elements may not be used: BETWEEN, LIKE, IN.
    No sub-queries may be used.
    For outer joins, only equality comparisons (=, EQ) are possible.
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    In outer joins, all comparisons that contain columns as operands in the database table or the view dbtab_right on the right-hand side must be specified in the corresponding join condition. In the WHERE condition of the same SELECT command, these columns are not allowed as operands.
    Resulting set for inner join
    The inner join joins the columns of every selected line on the left- hand side with the columns of all lines on the right-hand side that jointly fulfil the join_cond condition. A line in the resulting set is created for every such line on the right-hand side. The content of the column on the left-hand side may be duplicated in this case. If none of the lines on the right-hand side fulfils the join_cond condition, no line is created in the resulting set.
    Resulting set for outer join
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    Example
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    PARAMETERS: p_cityfr TYPE spfli-cityfrom,
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    DATA: BEGIN OF wa,
    fldate TYPE sflight-fldate,
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    connid TYPE spfli-connid,
    END OF wa.
    DATA itab LIKE SORTED TABLE OF wa
    WITH UNIQUE KEY fldate carrname connid.
    SELECT ccarrname pconnid f~fldate
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    FROM ( ( scarr AS c
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    INNER JOIN sflight AS f ON fcarrid = pcarrid
    AND fconnid = pconnid ).
    LOOP AT itab INTO wa.
    WRITE: / wa-fldate, wa-carrname, wa-connid.
    ENDLOOP.
    Example
    Join the columns carrid, carrname and connid of the database tables scarr and spfli using an outer join. The column connid is set to the null value for all flights that do not fly from p_cityfr. This null value is then converted to the appropriate initial value when it is transferred to the assigned data object. The LOOP returns all airlines that do not fly from p_cityfr.
    PARAMETERS p_cityfr TYPE spfli-cityfrom.
    DATA: BEGIN OF wa,
    carrid TYPE scarr-carrid,
    carrname TYPE scarr-carrname,
    connid TYPE spfli-connid,
    END OF wa,
    itab LIKE SORTED TABLE OF wa
    WITH NON-UNIQUE KEY carrid.
    SELECT scarrid scarrname p~connid
    INTO CORRESPONDING FIELDS OF TABLE itab
    FROM scarr AS s
    LEFT OUTER JOIN spfli AS p ON scarrid = pcarrid
    AND p~cityfrom = p_cityfr.
    LOOP AT itab INTO wa.
    IF wa-connid = '0000'.
    WRITE: / wa-carrid, wa-carrname.
    ENDIF.
    ENDLOOP.
    Cheers,
    vasavi.
    kindly reward if helpful.

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