Are Java Interfaces 'free'?

From a performance point of view, are Java interfaces free?
That is, if I have:
class Foo
public void bar() { ... // some code }
}and I change it to:
interface Foo
public void bar();
class FooImpl implements Foo
public void bar() { ... // some code }
}And I call one or other of the Foos like
Foo foo // A parameter, field or local variable.
foo.bar();Does calling foo through an interface add any overhead that calling it direct in the first example not? As I understand it, all methods are 'virtual' in Java, so it should perform the same in either case.
Thanks for any of your thoughts.
Rupert

rupertlssmith wrote:
YoungWinston wrote:
The Second Rule of Program Optimization (for experts only!): Don't do it yet.”
- Michael A. Jackson
Basically, don't worry about it. Worry about writing clear, correct, object-oriented code.
Wierdly enough, in the long run, that is more likely to help than anything else you can do, should (and if) you ever need to worry about optimization in the future.
WinstonThanks for the advice. I can write good clear OO code. I am now at the future and worrying about optimization, so have made it past the second rule!Then you exactly know where your bottleneck is from the profiler you've used. Did it tell you that your interfaces are the bottleneck? If so, why do you even bother to ask here?

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