Arguments in function passed through shell script

Question

HI all,
I have a shell script test.sh
it contains the following
A=$1
B=$2
C=$3
D=$4
sqlplus usr/pwd<<eof
a varchar2(10);
b varchar2(10);
c date;
d date;
a:='$A';
b:='$B';
c:='$C';
d:='$D';
func(a,b,c,d(;
eof
func() defbn
func(name varchar2,trc varchar2,dt1 date,dt2 date)
end;
When icall test.sh as
./test.sh xyz 0100 01-NOV-09 06-NOV-09
It appneds dt1 with 06-NOV-09 and dt2 remains null.
It should be like:
dt1=01-NOV-09
dt2=06-NOV-09
inside function
Thanks

Answer 1

Are you sure there is no problem in SQL function *"func"* that you are calling?
You haven't pasted the function code so can't really comment on that.
Below test shows that it works really fine:
kallo:DZHLHFC1> cat 1.ksh
A=$1
B=$2
C=$3
D=$4
echo "Shell vars = $A,$B,$C,$D"
sqlplus -s username/pass<<eof
alter session set nls_date_format='DD-MON-YY';
set serverout on size 10000
declare
a varchar2(10);
b varchar2(10);
c date;
d date;
begin
a:='$A';
b:='$B';
c:='$C';
d:='$D';
dbms_output.put_line('');
dbms_output.put_line('SQL vars =' ||a||',' ||b||',' ||c||',' ||d);
end;
eof
kallo:DZHLHFC1> ./1.ksh xyz 0100 01-NOV-09 06-NOV-09
Shell vars = xyz,0100,01-NOV-09,06-NOV-09
Session altered.
SQL vars =xyz,0100,01-NOV-09,06-NOV-09
PL/SQL procedure successfully completed.