Arrays[][] - row and column

Evening All...
Just a quick question regarding arrays. My program is working but I am trying to tidy it up.
public class Arrays{
static int firstArray[][]= new int [][] {{8,5},{9,3}};
static int secondArray[][]= new int [][] {{1,7},{4,8}};
static int thirdArray[][]= new int [][] {{0,2,4},{9,6,8}};
     static int fourthArray[][]= new int [][] {{2,1,0},{6,2,3}};
public static void main(String[] args)
     multiply(secondArray,firstArray);
     multiply(firstArray,thirdArray);
     public static void multiply( int[][] x, int[][] z)
     int array2[][] = new int [3][3];
     int 1r = x.length;
     int 1c = x[0].length;
     int 2r = z.length;
     int 2c = z[0].length;
     //for(etc...)
//      (Rest of program)
I want to edit the array.--------int array2[] = new int[3][3]; (up 9 lines)
Instead of specifying it as [3][3] for size.
I would like to say new int - length of row and column - im pretty sure it is similar to
the ints below - but cant seem to get the correct combination.
Thanks in advance for any help folks.

- you can use variables to specify array dimensions
- you can get the (1D) dimension of an array by using the "attribute" theArray.length . Knowing that a 2D-array is indeed an array of arrays, you can indirectky get the size oif the second dimension too:
public static void multiply( int[][] x, int[][] z)
int array2[][] = new int [x.length][x[0].length];
}Of course this shoud be robustified to protect against x or x[0] being null (but in this case the multiplication is probably doomed anyway).
Regards,
J
Edited by: jduprez on Mar 14, 2011 10:45 PM
And please, in the future, use tags around code text, when posting code

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Coato wrote:
                          So ultimately, when i enter a row value of 0.5 and a column value of 0.3, my output will be 1.688.
Sorry, Please explain.
Please make a VI containing a simple 2D aray as diagram constant that contains e.g. 5x5 typical values. Let us know what kind of result you expect from your algorithm..
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