ASCII for checkmark
Is there an ASCIi replacment for this? I googled for it but I
cant seem to find anything consistent or specifically stating its
supported in CF. An alternate solution is acceptable, but using the
letter x seems a little cheesy.
keep in mind however, that different OS's and languages use
different character sets.
You will not get a checkmark on a Mac or Unix/Linux system
with that code, and if the user is from another country or using a
different default OS language like French or Spanish etc, it will
also have a different character in many cases.
The only foolproof way to relay something like that to any
user, is to use a graphic.
Similar Messages
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Problem with java, ASCII and Linux
Hi Friends,
I has a Linux RedHat 9.0 with a jre1.5.0_04 (rpm package of Sun).
I has a problem with ASCII , for example :
import java.io.*;
public class HolaMundo
public static void main (String[] args)
System.out.println("Hol� M�ndo");
this programs runs ok on my windows jdk so it prints "Hol� M�ndo", but when i run the same HolaMundo.class program on my linux redhat it prints "Hol�� M��ndo"
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I think the most efficient way in my thinking is XSLT and Java mapping.
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byte [] msg = .. // whatever
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Edited by: Aashish Sinha on Mar 25, 2008 6:07 PM -
Appleworks won't save DB file as ASCII
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Paul -
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Help with binary to decimal, binary to hex, and hex to ascii or ascii to hex program
I decided to do a program that will do binary to decimal, binary to hex, and hex to ascii for a project related to a java programming course, which only needs to perform features from chapters 1-6 and 8 of Tony Gaddis's book. The functions work fine as their own main programs out side of this combined effort, so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped. My flowcharts, which have to be revised after discovering that my previous function were logically incorrect after running them in their own main are attached below as the spec sheet.
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii
public static void main(String[] args)throws IOException
Scanner input = new Scanner(System.in);
System.out.println("Enter a binary number: ");
String binary = input.nextLine(); // store input from user
if (binary == input.nextLine())
//int i= Integer.parseInt(hex,2);
//String hexString = Integer.toHexString(i);
//System.out.println("Hexa decimal: " + hexString);
//int finaldecimalvalue = binaryToDecimal(hexString);
int finaldecimalvalue = binaryToDecimal(hexString);
if (binary != input.nextLine())
String hexInput; // The variable Bin Input declared as the datatype int to store the Binary value
// Create a Scanner object for keyboard input.
//Scanner keyboard = new Scanner(System.in);
// Get the number of binary files.
System.out.print("Enter the Hex value: ");
hexInput = keyboard.nextLine();
System.out.println("Original String: "+ hexInput);
//String hexEquivalent = asciiToHex(demoString);
String hexEquivalent = asciiToHex(hexInput);
//Hex value of original String
System.out.println("Hex String: "+ hexEquivalent);
String asciiEquivalent = hexToASCII(hexEquivalent);
//ASCII value obtained from Hex value
System.out.println("Ascii String: "+ asciiEquivalent);String finalhexOutput = HextoAsciiConverter(hexEquivalent);
if (binary != input.nextLine() && hexInput != keyboard.nextLine())
BufferedReader binInput = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter the Binary number:");
String hex = binInput.readLine();
//String finaldecimalvalue = binaryToDecimal(decimal);
//long finalhexvalue = BinaryToHexadecimal(num);
long finalhexvalue = BinaryToHexadecimal();
public static String BinaryToHexadecimal(String hex)
//public static void main(String[] args)throws IOException
//BufferedReader bf= new BufferedReader(new InputStreamReader(System.in));
//System.out.println("Enter the Binary number:");
//String hex = binInput.readLine();
long num = Long.parseLong(hex);
long rem;
while(num > 0)
rem = num % 10;
num = num / 10;
if(rem != 0 && rem != 1)
System.out.println("This is not a binary number.");
System.out.println("Please try once again.");
System.exit(0);
int i= Integer.parseInt(hex,2);
String hexString = Integer.toHexString(i);
System.out.println("Hexa decimal: " + hexString);
return num.tolong();
//int i= Integer.parseInt(hex,2);
//String hexString = Integer.toHexString(i);
//System.out.println("Hexa decimal: " + hexString);
//} // end BintoDectoHextoAsciil
//public static String HexAsciiConverter(String hextInput)
// Get the number of binary files.
//System.out.print("Enter the Hex value: ");
//hexInput = keyboard.nextLine();
//System.out.println("Original String: "+ hexInput);
//String hexEquivalent = asciiToHex(demoString);
//String hexEquivalent = asciiToHex(hexInput);
//Hex value of original String
//System.out.println("Hex String: "+ hexEquivalent);
//String asciiEquivalent = hexToASCII(hexEquivalent);
//ASCII value obtained from Hex value
//System.out.println("Ascii String: "+ asciiEquivalent);
//} // End function
private static String asciiToHex(String asciiValue)
char[] chars = asciiValue.toCharArray();
StringBuffer hex = new StringBuffer();
for (int i = 0; i < chars.length; i++)
hex.append(Integer.toHexString((int) chars[i]));
return hex.toString();
private static String hexToASCII(String hexValue)
StringBuilder output = new StringBuilder("");
for (int i = 0; i < hexValue.length(); i += 2)
String str = hexValue.substring(i, i + 2);
output.append((char) Integer.parseInt(str, 16));
return output.toString();
public static String binaryToDecimal(String binary)
//Scanner input = new Scanner(System.in);
//System.out.println("Enter a binary number: ");
//String binary = input.nextLine(); // store input from user
int[] powers = new int[16]; // contains powers of 2
int powersIndex = 0; // keep track of the index
int decimal = 0; // will contain decimals
boolean isCorrect = true; // flag if incorrect input
// populate the powers array with powers of 2
for(int i = 0; i < powers.length; i++)
powers[i] = (int) Math.pow(2, i);
for(int i = binary.length() - 1; i >= 0; i--)
// if 1 add to decimal to calculate
if(binary.charAt(i) == '1')
decimal = decimal + powers[powersIndex]; // calc the decimal
else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
isCorrect = false; // flag the wrong input
break; // break from loop due to wrong input
} // end else if
// keeps track of which power we are on
powersIndex++; // counts from zero up to combat the loop counting down to zero
} // end for
if(isCorrect) // print decimal output
System.out.println(binary + " converted to base 10 is: " + decimal);
else // print incorrect input message
System.out.println("Wrong input! It is binary... 0 and 1's like.....!");
return decimal.toint();
} // end function
The errors are as follows:
----jGRASP exec: javac BintoDectoHextoAscii.java
BintoDectoHextoAscii.java:65: error: class, interface, or enum expected
public static String BinaryToHexadecimal(String hex)
^
BintoDectoHextoAscii.java:73: error: class, interface, or enum expected
long rem;
^
BintoDectoHextoAscii.java:74: error: class, interface, or enum expected
while(num > 0)
^
BintoDectoHextoAscii.java:77: error: class, interface, or enum expected
num = num / 10;
^
BintoDectoHextoAscii.java:78: error: class, interface, or enum expected
if(rem != 0 && rem != 1)
^
BintoDectoHextoAscii.java:81: error: class, interface, or enum expected
System.out.println("Please try once again.");
^
BintoDectoHextoAscii.java:83: error: class, interface, or enum expected
System.exit(0);
^
BintoDectoHextoAscii.java:84: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:87: error: class, interface, or enum expected
String hexString = Integer.toHexString(i);
^
BintoDectoHextoAscii.java:88: error: class, interface, or enum expected
System.out.println("Hexa decimal: " + hexString);
^
BintoDectoHextoAscii.java:90: error: class, interface, or enum expected
return num.tolong();
^
BintoDectoHextoAscii.java:91: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:124: error: class, interface, or enum expected
StringBuffer hex = new StringBuffer();
^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
for (int i = 0; i < chars.length; i++)
^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
for (int i = 0; i < chars.length; i++)
^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
for (int i = 0; i < chars.length; i++)
^
BintoDectoHextoAscii.java:128: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:130: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
for (int i = 0; i < hexValue.length(); i += 2)
^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
for (int i = 0; i < hexValue.length(); i += 2)
^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
for (int i = 0; i < hexValue.length(); i += 2)
^
BintoDectoHextoAscii.java:138: error: class, interface, or enum expected
output.append((char) Integer.parseInt(str, 16));
^
BintoDectoHextoAscii.java:139: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:141: error: class, interface, or enum expected
^
BintoDectoHextoAscii.java:144: error: class, interface, or enum expected
public static String binaryToDecimal(String binary)
^
BintoDectoHextoAscii.java:150: error: class, interface, or enum expected
int powersIndex = 0; // keep track of the index
^
BintoDectoHextoAscii.java:151: error: class, interface, or enum expected
int decimal = 0; // will contain decimals
^
BintoDectoHextoAscii.java:152: error: class, interface, or enum expected
boolean isCorrect = true; // flag if incorrect input
^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
for(int i = 0; i < powers.length; i++)
^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
for(int i = 0; i < powers.length; i++)
^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
for(int i = 0; i < powers.length; i++)
^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
for(int i = binary.length() - 1; i >= 0; i--)
^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
for(int i = binary.length() - 1; i >= 0; i--)
^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
for(int i = binary.length() - 1; i >= 0; i--)
^
BintoDectoHextoAscii.java:166: error: class, interface, or enum expected
else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
^
BintoDectoHextoAscii.java:169: error: class, interface, or enum expected
break; // break from loop due to wrong input
^
BintoDectoHextoAscii.java:170: error: class, interface, or enum expected
} // end else if
^
BintoDectoHextoAscii.java:174: error: class, interface, or enum expected
} // end for
^
BintoDectoHextoAscii.java:180: error: class, interface, or enum expected
else // print incorrect input message
^
BintoDectoHextoAscii.java:185: error: class, interface, or enum expected
return decimal.toint();
^
BintoDectoHextoAscii.java:186: error: class, interface, or enum expected
} // end function
^
41 errors
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped.
Yes - YOU CAN!
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
Excellent! Commenting out code is EXACTLY how you troubleshoot problems like yours.
Comment out sections of code until the problem goes away. Then start adding back ONE SECTION of code at a time until the problem occurs. When it does you have just FOUND the problem.
If you do that you wind up with code that looks like this:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii {
public static void main(String[] args)throws IOException {
Scanner input = new Scanner(System.in);
System.out.println("Enter a binary number: ");
String binary = input.nextLine(); // store input from user
public static String BinaryToHexadecimal(String hex) { } // end function
Notice ANYTHING UNUSUAL?
You have a complete CLASS definition followed by a method definition.
Methods have to be INSIDE the class - you can NOT define methods on their own.
Write modular code.
Write EMPTY methods - just the method signature and maybe a RETURN NULL if you need to return something.
Then add calls to those empty methods.
When everything compiles and runs find you can start adding code to the methods ONE METHOD AT A TIME.
Test compile and run after you add the code for each method. -
Greetings,
I'v got a Problem
At my report (generated with CR 11) is a formularfield located, witch calculates a string used for barcode-font. For our customers we use some applications once with the runtimefiles and viewes from Crystal 8.5 and on the other hand crystal 11. It works without problems. But this formularfield formatted with the barcode-font works different on using viewer CR 11 in contrast using CR 85. By viewing this report, generated with the engine of CR 11, the Ascii-sign 129 is missing. So the barcode can no be read from the scanner. Using the same formularfield with same dates on CR 85-report viewing with the 8.5 viewer - all works. We swap the font, printers, drivers for printers repeatedly always the same result. If the barcodefont isn't installed, you can see the string but in the preview and printout of the report generated with cr 11 is missing Ascii-sign 129. But only at one costumer. Using the same Report (Cr 11) with exact the similar dates at our environment or at our other customers it works. What should be the problem? All our costomers using the same runtimfiles for the 11 and 8.5 crystal with the latest updates, patches and monthly hotfixes. The formluar functioned definitively. What is the differnt between Cr 85 an Cr 11 by using fonts? I'm deeply grateful for any tip.
MarkusHi Markus
You might like to see the Service Pack3 read me that fixed some issues for ASCII for CR 11.
Here is the [link|http://ftp1.businessobjects.com/outgoing/CMS/crXIwin_en_sp3.pdf]
Please also provide some more details about the exact version of Crystal 11.
Regards
Sourashree -
Problems with string encoding - need the text content in char* format.
The problem is non ASCII-characters, which comes out as some sort of unicode I need to desipher.
Here's what I got:
A text frame object with the TextString "Agnartjørna"
I get the text content of this object into an ai::UnicodeString the following way:
AIErr
VMGetTextOfTextArt( AIArtHandle textArt, ai::UnicodeString &ucStr)
ASUnicode *textBuffer = NULL;
AITRY {
TextFrameRef ateTextRef;
AIX( sAITextFrame->GetATETextFrame( textArt, &ateTextRef));
ATE::ITextFrame ateText( ateTextRef);
ATE::ITextRange ateRange = ateText.GetTextRange( true);
ASInt32 textLen = ateRange.GetSize();
AIX( sSPBlocks->AllocateBlock( (textLen+2) * sizeof( ASUnicode), nil, (void**) &textBuffer));
ateRange.GetContents( textBuffer, (ASInt32) textLen+1);
/* trim off trailing newlines */
if ((textBuffer[textLen] == '\n') || (textBuffer[textLen] == '\r'))
textBuffer[textLen] = 0;
ucStr.clear();
ucStr.append( ai::UnicodeString( textBuffer, textLen));
sSPBlocks->FreeBlock( textBuffer);
textBuffer = NULL;
AIRETURN;
AICATCH {
if (textBuffer) sSPBlocks->FreeBlock( textBuffer);
AIPROPAGATE;
Now, the next step is to convert it into a form that I can use to call regexp.
Baiscally, I want to detect the ending "tjørna" (meaning small lake) on a map label, and apply a standard abbevriation "tj^a" (with "a" superscripted).
So the problem is to obtain the regexp pattern and the text content in same encoding. And since the regexp library is old *char based, I would like to convert the text content in to plain old *char.
Hence the following code:
static AIErr
VMAbbreviateTextArt( AIArtHandle textArt,
vmTextAbbrevEffectParams *params)
AITRY {
/* first obtain the text contents of the textArt */
ai::UnicodeString ucText;
const int kTextLen = 256;
char textContent[kTextLen];
AIX( VMGetTextOfTextArt( textArt, ucText));
ucText.as_Roman( textContent, kTextLen);
But textContent now has the value "Agnartj\xbfnna" (According to XCode),
which will not get a match on the pattern "tj([øe][rn])na\\" (with backslash matching the end of the string)
Any other ways to convert the textContent to a plain *char string?Thank you very much, your method will work fine. with
the "UTF-8" parameter the byte[].length is double,
cause every valid byte is preceeded by an -62, but I
will just filter the valid bytes into a new array.
Thanks again,
StefanActually what you need to do is to find the character encoding that your device expects, and then you can code your strings in Arabic.
That's the way Java does things; Strings and char values are always in UNICODE (see www.unicode.org) (which means \u600 to \u6ff for arabic) and uses a specified character encoding when translating these to and from a byte stream.
Each national character encoding has a name. Most of them are identical to ASCII for 0-127 and code their national characters in 128-255.
Find the encoding name for your display and, odds are, the JRE has it in the library.
BTW the character encoding ISO-8859-1 simply maps UNICODE characters 0-255 on to bytes. -
How can i store values from my String into Array
Hi guys
i wants to store all the values from my string into an array,,,, after converting them into intergers,,,, how i can do this becs i have a peice of code which just give me a value of a character at time,,,,charat(2)...BUT i want to the values from String to store in an Array
here is my peice of code which i m using for 1 char at time
int[] ExampleArray2 = new int[24];
String tempci = "Battle of Midway";
for(int i=0;i>=tempci.length();i++)
int ascii = tempci.charAt(i); //Get ascii value for the first character.public class d1
public static final void main( String args[] )
int[] ExampleArray2 = new int[24];
String tempci = "Battle of Midway";
for(int i=0;i<tempci.length();i++)
int ascii = tempci.charAt(i);
ExampleArray2=ascii;
for(int i=0;i<ExampleArray2.length;i++)
System.out.println(ExampleArray2[i]); -
I want to write an arraylist to a text file and have the file encoded in ansi. I have found the only way to have the file encoded in ansi is to write strings to the file. I can't figure out how to cast my arraylist to strings, (which is what i think I must do).
Any help/suggestions are appreciated. Below is my code:
import java.io.*;
//This class writes the status to the Master.txt file upon radio button press
class Writer1{
public Writer1(){
System.out.println("writer1 has been called");
try {
OutputStream bout = new BufferedOutputStream(fout);
OutputStreamWriter out = new OutputStreamWriter(bout,"ASCII");
for(int i = 0; i < Chat6.arrList.size(); i++) {
//out.write(Chat6.arrList.get(i)) + "\n");//need to convert to string
System.out.println("writing array loop " +Chat6.arrList);
out.flush();
out.close();
} catch (IOException e) {
}FileWriter? I've written it before -- FileWriter is just a convenient subclass
of OutputStreamWriter that folds in a FileOutputStream. Here is its
complete source code, minus comments:
package java.io;
public class FileWriter extends OutputStreamWriter {
public FileWriter(String fileName) throws IOException {
super(new FileOutputStream(fileName));
public FileWriter(String fileName, boolean append) throws IOException {
super(new FileOutputStream(fileName, append));
public FileWriter(File file) throws IOException {
super(new FileOutputStream(file));
public FileWriter(File file, boolean append) throws IOException {
super(new FileOutputStream(file, append));
public FileWriter(FileDescriptor fd) {
super(new FileOutputStream(fd));
}What's missing from FileWriter that exists in OutputStreamWriter is
the ability to choose a charset! And the OP (perhaps mistakenly) seems
hellbent on choosing ASCII. -
How to open file system file from Apex?
Hi,
Can someone help me to find how to open a pdf file e.g. test.pdf from apex when someone click on a button ABC?
The file is located in /C/
Thanks in advance
DipYou can use the Onclick event and window.location to show the file when the user clicks a button.
<input type=button onClick="window.location= 'file:///C:/Documents%20and%20Settings/rchamarthi/Desktop/test.pdf' + document.form1.cmuds.value;" value="Open File">The actual location of the file is "C:/Documents and Settings/rchamarthi/Desktop/test.pdf"
Since the location is treated as a URL, remember that it should be URL encoded.
Hence all spaces should be replaced by '%20' (32 being the ASCII for space and 20 in hex -> 32). -
We are using MS Outlook 2010 as our mail client. But we have noticed that whenevr we sent a mail to any other internet mail recipient all the "apostrophe", "single" and "double quotes" have automatically converted to ?. We have
done almost all the workaround found in this site such as
1.New a message and focus on the message window > click File > Options > Mail > Spelling and Autocorrect… > Proofing > AutoCorrect Options… > AutoFormat > clear the box before “Straight quotes” with “smart quotes”
2. Used different encoding. We presently using US-ASCII for outgoing message. etc.
Need your help to sort out these issues urgently.
Waiting for a solution.Hi,
What is your account type? IMAP, POP or Exchange?
Send an email from the webmail, ask the recipient if this issue persists.
As far as I know, this problem is always related to the encoding for outgoing messages, and here I suggest you try UTF-8:
Go to File -> Options -> Advanced -> International options -> Uncheck "Automatically select encoding for outgoing messages", then select "Unicode (UTF-8)" beside "Preferred encoding for outgoing messages" -> OK.
Hope this helps.
Regards,
Melon Chen
TechNet Community Support
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