ASCII to binary conversion

Does anyone knows how to convert the ASCII value to binary? For example
ASCII 'U' to 01010101?

Hi,
If I understood you correctly, you want to convert a character eg:'U' to
its ASCII value which is 85 (in binary representation 01010101).
With the following method you can convert the first character of a string to
a one byte long unsigned integer.
method BaseClass.CharToInt(input pStr: Framework.string): Framework.ui1
begin
return *(pointer to ui1)(*(pointer to pointer)(&pStr));
end method;
See also the attached .pex file for some more, usefull little methods...
Regards,
Tamas Deak
-----Message d'origine-----
De: Sing Nyguk Ling [mailto:Thomas.Lingbass.com.my]
Date: dimanche 12 mars 2000 09:49
À: kamranaminyahoo.com
Objet: (forte-users) ASCII to binary conversion
Does anyone knows how to convert the ASCII value to binary? For example
ASCII 'U' to 01010101?
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              System.out.println("The Binary reresentation of "+N+" is = 1"+H1+G1+F1+E1+D1+C1+B1+A1);
         else if(I==0 && N<0){     
              System.out.println("The Binary reresentation of "+N+" is = 1"+I1+H1+G1+F1+E1+D1+C1+B1+A1);
         if(A==0 && N>0){
              System.out.println("The Binary reresentation of "+N+" is = 0"+A1);
         else if(B==0 && N>0){
              System.out.println("The Binary reresentation of "+N+" is = 0"+B1+A1);
         else if(C==0 && N>0){
              System.out.println("The Binary reresentation of "+N+" is = 0"+C1+B1+A1);
         else if(D==0 && N>0){
              System.out.println("The Binary reresentation of "+N+" is = 0"+D1+C1+B1+A1);
         else if(E==0 && N>0){
              System.out.println("The Binary reresentation of "+N+" is = 0"+E1+D1+C1+B1+A1);
         else if(F==0 && N>0){
              System.out.println("The Binary reresentation of "+N+" is = 0"+F1+E1+D1+C1+B1+A1);
         else if(G==0 && N>0){
              System.out.println("The Binary reresentation of "+N+" is = 0"+G1+F1+E1+D1+C1+B1+A1);
         else if(H==0 && N>0){     
              System.out.println("The Binary reresentation of "+N+" is = 0"+H1+G1+F1+E1+D1+C1+B1+A1);
         else if(I==0 && N>0){     
              System.out.println("The Binary reresentation of "+N+" is = 0"+I1+H1+G1+F1+E1+D1+C1+B1+A1);
    }

    String intAsBinaryString(int n){
      String res = "";
      for(int i = 1; i!=0; i *=2){
        res = ((n & i != 0)?"1":"0") + res;
      return res;
    }Pete is right, in order to understand this you need to know how integers are stored.

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