Barcode Reading to next line automatically

Dear Experts.
we implemented Barcode for PO Number in Ecc 6.0.
It is Printing &reading fine.
For reading the Barcode(Bar Text) I designed a module POol Program with Table controll.
But My requirement is while reading , I am getting that bar text in a field.Once After reading one Barcode(One Po), the controll automatically should move to next line.i.e with out touching the Key pad they want to contionuously reading the Barcodes.
And automatiaclly each one bartext come in one line.
Please help to solve this issue.
Thanks in advance,
Regards,
Venkat

Hi
I hope ur reading the BArcodes using RF guns , if so then u have an Option in the RF GUN to move automatically to next field , u have to check with the RF users to configure and change the settings.
surya

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Getting Buffered Reader to read next line and update.

Hello.
I have been trying to get this program to read the next line in a txt file correctly. This is a GUI program
where clicking the button is supposed to bring up the next bit of information for the user to see.
I can get the first line of information to come out correctly, but I am unable to get it to read the next line when I click the next button.
Here is a snippet of my coding...
private JFileChooser fileChoose;
private File openedFile;
private int recordNumber = 0;
FileReader inFile;
String sMaker = new String ( );
else if ( ae.getActionCommand ( ) == "Next Record" )
     if ( openedFile.exists ( ) )
          nextRecord ( );
     else
     JOptionPane.showMessageDialog ( null, "No Files Opened", "No Files Found", JOptionPane.ERROR_MESSAGE );
public void nextRecord ( )
     recordNumber ++; // Increment record number
     fileNumber.setText ( sMaker.valueOf ( recordNumber ) ); // Prints to JTextField for user to see
     BufferedReader inText;
     String lineRead; // Holds line read in
     String [] organizedInfo; // Array to hold info after being split
     try
          inFile = new FileReader ( openedFile );
          inText = new BufferedReader ( inFile );
          lineRead = inText.readLine ( );
          organizedInfo = ( lineRead.split ( "," ) );//.trim ( );
          for ( int i = 0; i < organizedInfo.length; i ++ )
               organizedInfo[i] = organizedInfo.trim ( );
name.setText ( organizedInfo[0] );
city.setText ( organizedInfo[1] );
state.setText ( organizedInfo[2] );
catch ( FileNotFoundException fnfe )
JOptionPane.showMessageDialog ( null, "Selected File was Not Found", "File Not Found", JOptionPane.ERROR_MESSAGE );
catch ( IOException ioe )
JOptionPane.showMessageDialog ( null, "IO Error. Please Try Again.", "IO Error", JOptionPane.ERROR_MESSAGE );
employee.txt
William Wallace,Richmond,VA
Samuel Gompers , San Francisco , California
Andy Smith,Rochester,NY
Sandy Beach,Pittsford,NY
Slim T. None,San Francisco,CA
George Jones, Washington , D.C.
Marvin Martin, Boston , Massachusetts
I. M. Last , Deadmans Gulch, Arizona
Everytime I click the next button, it should go through the list in employee.txt until i reach the end. But it just stops at William Wallace.
I know that this can be recoded to make it more efficient, but before that, I still need to figure out how to get the line read to update to next line.
Thank you in advance.

Your program works perfectly correctly!
Each time you click the button it reads the first line and displays it. Why? Because you create a new reader everytime you enter the nextRecord method and the reader reads the first line. Each new reader has no idea where the last reader was upto in your file. It has to start at the beginning.
<cue response>How do I fix it?

How to read the second line in a .txt file with bufferedReader?

hi,
i am not the best in speaking english and programming java :)
so, just try to make sense of my question:
Im using a BufferedReader to read a .txt file.
the .txt file has 5+ different lines, and each line has 6 tokens (separated with ; )
My java file has 6 textFields and each textfield is filled with one of the 6 different tokens.
and my problem is:
I want my buffered reader to read the next line (with 6 new different tokens) by pressing a button.
if somethings not understandable, just ask :)

maybe its easier to help me, when i publish my code, so here it is:
(its my version, without Thof's code. Sorry, but the comments are the most in german)
/* userdata.java */
import java.awt.*;
import java.awt.event.*;
import java.applet.*;
import javax.swing.*;
import java.util.*;
import java.io.*;
public class userdata extends Frame {
//-----------------------------------KlassenVariablen------------------------------------------------
private JPanel panel = new JPanel ();
String tokId = "";
String tokName= "";
String tokAge= "";
String tokTel= "";
String tokMail= "";
String tokText= "";
BufferedReader br;
String zeile;
StringTokenizer st;
String delim = ";";
//---------Buttons f?r Panel 1-------------------------
Button first = new Button("|< First");
Button back = new Button("< Back");
Button next = new Button("Next >");
Button last = new Button("Last >|");
//---------Buttons f?r Panel 3-------------------------
Button neu = new Button("New");
Button safe = new Button("Safe");
Button refresh = new Button("Refresh");
//--------Labels f?r Panel 2-----------------------------
Label lid = new Label("ID",Label.LEFT);
Label lname = new Label("Name",Label.LEFT);
Label lage = new Label("Age",Label.LEFT);
Label ltel = new Label("Tel.",Label.LEFT);
Label lmail = new Label("E-Mail",Label.LEFT);
Label ltext = new Label("Spruch",Label.LEFT);
Label lub = new Label("Last Button",Label.LEFT);
TextField id = new TextField();
TextField name = new TextField();
TextField age = new TextField();
TextField tel = new TextField();
TextField mail = new TextField();
TextField text = new TextField();
TextField usedbutton = new TextField();
//--------ActionEvent bla sachen eben--------------------
public static void main (String[] args) throws IOException {
userdata wnd = new userdata();
wnd.setVisible(true);
public userdata() throws IOException {
//--------------------------------Layout mit panel bestimmung--------------------------------------
setLayout(new BorderLayout());
JPanel p1 = new JPanel();
JPanel p2 = new JPanel();
JPanel p3 = new JPanel();
add(BorderLayout.NORTH ,p1);
add(BorderLayout.CENTER , p2);
add(BorderLayout.SOUTH , p3);
//-------------------------------Funktionslose Buttons in PANEL 1------------------------------------
p1.add(first);
p1.add(back);
p1.add(next);
p1.add(last);
p1.add(usedbutton);
//--------------------------------Funktionierende Textfelder in PANEL 2------------------------------
Panel labelpanel = new Panel();
p2.setLayout(new GridLayout(7,3));
p2.add(lid);
p2.add(id);
p2.add(lname);
p2.add(name);
p2.add(lage);
p2.add(age);
p2.add(ltel);
p2.add(tel);
p2.add(lmail);
p2.add(mail);
p2.add(ltext);
p2.add(text);
p2.add(lub);
p2.add(usedbutton);
//--------------------------------------Buttons in PANEL 3-----------------------------------------
p3.add(neu);
p3.add(safe);
p3.add(refresh);
//--------------------------------BufferedReader -------------------------------------------------
readData();
//--------------------------------Panel 2 TextField-----------------------------------------------
fillForm();
//================================ActionPerformed==================================================
first.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
System.out.println ("First");
usedbutton.setText("First");
back.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
System.out.println ("Back");
usedbutton.setText("Back");
next.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
System.out.println ("Next");
usedbutton.setText("Next");
last.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
System.out.println ("Last");
usedbutton.setText("Last");
neu.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
System.out.println ("New entry");
usedbutton.setText("New");
safe.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
System.out.println ("Now Saving, do not turn off!");
usedbutton.setText("Save");
//-----------------refresh
refresh.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
try{
readData();
}catch( IOException ioe){
System.out.println("Fehler beim lesen aus Datei");
fillForm();
usedbutton.setText("Refresh");
//=============================================================================Button Funktionen!!!
pack();
//--------------------------------WindowsListener hinzuf?gene--------------------------------------
addWindowListener(
new WindowAdapter() {
public void windowClosing(WindowEvent event)
setVisible(false);
dispose();
System.exit(0);
//-----------------------------------readData() - > Buffered Reader in aktion! --------------------
private void readData() throws IOException{
BufferedReader br = new BufferedReader(new FileReader("My .txt File with path"));
String zeile;
StringTokenizer st;
String delim = ";";
zeile = br.readLine();
st = new StringTokenizer(zeile, delim);
st.hasMoreTokens();
//System.out.println (st.nextToken());
tokId = new String(st.nextToken());
tokName = new String (st.nextToken());
tokAge = new String (st.nextToken());
tokTel = new String (st.nextToken());
tokMail = new String (st.nextToken());
tokText = new String (st.nextToken());
//--------------------------fillForm() - > f?llt die TextFelder aus!--------------------------------
private void fillForm(){
id.setText(tokId);
name.setText(tokName);
age.setText(tokAge);
tel.setText(tokTel);
mail.setText(tokMail);
text.setText(tokText);
}

Reading in a line of text and breaking it up, complicated

Hi all,
At the moment im reading in a few 100 lines of text from a file, each line contains a command and a few variables which need to be set to existing variables I have created shown below;
Int variableA ;
Int variable B ;
Int variable C;
Int Variable D;
However I have no way to know which command will go with which variables,
On every line there will be one command and two variables..
The possible command are; ADD, SUB, TIMES, Divide, COPY, SET
And the text coming in look like this;
SET A10, B15 // set each variable
SET C33, D50 // as above
COPY A, B // which means assign copy what ever in variableA to variableB
ADD C, D // which mean add variableC�s contents to variableD contents
SUB B, C // which is subtract variableC contents by what ever is in variableB
Does anybody know of a way where I can test what the next command is, and assign the correspond variables , so far I have come up with;
But am not sure if this is the best way to go about it, was thinking maybe I should put the text file into an array, which might make it easyer to process.
public static void main (String [] args)
int D = 0 ;
int C = 0 ;
int B = 0 ;
int A = 0 ;
StringTokenizer st ;
String line ;
String buffer = "";
String file ="test2.txt" ;
String name = "";
String billy = "";
try
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BufferedReader inFile = new BufferedReader (fr) ;
//read in one line @ a time
buffer =inFile.readLine() ;
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while(words.hasMoreTokens())
String letter = words.nextToken() ;
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System.out.println(letter) ;
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inFile.close();
catch (FileNotFoundException e)
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hi,
i think that what u r tring to do is "parsing" where u translate these primatin=ve commands to execute them, if so here what u need to do:
Rad a line untell end of file
for each token in the line
if(token="SET" || token="ADD || token=""SUB")
{ //save operation for later use
operation=token;
//now u expect the next token to be an operand
token=nextToken;
if (token!="" and token!=",")//it must be an operand
{operand1=token;
token=next token;
if(token=",")//do nothing just read the nest operand
token=nexttoken;
else //syntax error in file, exit ;
if (token!="" and token!=",")//checking the 2nd operand
operand2=token;
//now check value of operation and call the right method and send operand1,operand2 as arguments to get the result e.g
if(opration=="ADD")
system.println("result of addition is"+addMethod(operand1,operand2));
hope that helps,
Insighter

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When in SAP serial selection screen i scan serial number(barcode) with scanner system should take me to next line after population of serial number in one line is completed.
In delivery in select serial numbers window against serial number field in multiple selection if i scan barcode a single serial number is populated in one field after this system doesnt take me to next field automatically ,I am manually taking the cursor to next line.
If i scan the barcodes with the same scanner in Excel file cursor moves automatically to next line.I want same in SAP
Make of the scanner is TVS electronics made barcode scanner -BS- L 101 Platina U
How to automize it.
Please suggest me solution.
We tried with BDC but it failed.

Hi,
We can set the cursor postion using this statement SET CURSOR FIELD f LINE lin [OFFSET off].
We need to use this in custom Programs.
Please reffer the links below:
[Cursor Position In TABLE CONTROL;
[How to set cursor on next row in TAble control?;
[http://help.sap.com/saphelp_nw70/helpdata/en/9f/dbac9f35c111d1829f0000e829fbfe/content.htm]
I hope this may helpfull.
Thank you,
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AMS

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Hi
Look at this , may be useful
To Create a Bar code prefix:
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<C1> &itab-field& </C1>.
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Which barcode printer are you using ? Can you download this file and see.
http://www.servopack.de/Files/HB/ZPLcommands.pdf.
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Check this link:
http://www.sap-img.com/abap/questions-about-bar-code-printing-in-sap.htm
Check this link:
http://help.sap.com/saphelp_nw04/helpdata/en/d9/4a94c851ea11d189570000e829fbbd/content.htm
Hope this link ll be useful..
http://help.sap.com/saphelp_nw04/helpdata/en/66/1b45c136639542a83663072a74a21c/content.htm
go through these links and cose u r previous threads,
http://www.sap-img.com/abap/questions-about-bar-code-printing-in-sap.htm
smartform - barcode
http://www.erpgenie.com/abap/smartforms.htm
http://sap.ittoolbox.com/groups/technical-functional/sap-basis/print-barcode-with-smartform-634396
http://sap.ittoolbox.com/groups/technical-functional/sap-dev/printing-barcode-733550
Detailed information about SAP Barcodes
A barcode solution consists of the following:
- a barcode printer
- a barcode reader
- a mobile data collection application/program
A barcode label is a special symbology to represent human readable information such as a material number or batch number
in machine readable format.
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<b>Reward points for useful Answers</b>
Regards
Anji

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Hi,
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[http://help.sap.com/saphelp_nw70/helpdata/en/9f/dbac9f35c111d1829f0000e829fbfe/content.htm]
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Hi,
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Thanks,
Ruthra

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Edited by: myway on Mar 29, 2009 3:16 PM

Hi,
Please post your code that raises the problem, I use this simple example and works fine:
Connected to Oracle Database 10g Express Edition Release 10.2.0.1.0
Connected as hr
SQL> select 'line 1' || chr(13) || 'line 2' from dual;
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line 1
line 2
SQL>
SQL> SET SERVEROUTPUT ON
SQL> DECLARE
2     v_string VARCHAR2(4000);
3     v_line1 VARCHAR2(4000) := 'LINE 1';
4     v_line2 VARCHAR2(4000) := 'LINE 2';
5     c_line_break CONSTANT VARCHAR2(1) := CHR(13);
6 BEGIN
7     v_string := v_line1 || c_line_break || v_line2;
8     dbms_output.put_line(v_string);
9 END;
10 /
LINE 1
LINE 2
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jn = 1
if ( st[1] != st[3] )
ml = 1
//dataLine += "\r\n write "
else
ml=2
dataLine += "\r\n"+this.documentFileName
+ "\t" + this.getPageNthWord(i,j)
+ "\t" + pg
+ "\t" + j
+ "\t" + ml
+ "\t" + jn
+ "\t st[0] " + diffx0 + "\t st[1] " + diffx1 + "\t st[2] " + diffx2 + "\t st[3] " + diffx3
+ "\t st[4] " + diffx4 + "\t st[5] " + diffx5 + "\t st[6] " + diffx6 + "\t st[7] " + diffx7
ck=1

If Acrobat is reading each word part as separate words, you have a problem.
The way I approached it in some of my tools was to check if a word ends
with a hyphen, and if so, to check if it's the last on the line. If both
conditions are true, combine with the next word on the next line. This is
not fool proof, of course, as there are documents with columns are other
structural elements that prevent this from working. Better than nothing,
though...
However, it is also possible that Acrobat does see both parts as parts of
the same word. In that case, getPageNthWordQuads() will return multiple
quads arrays. As you know, that method returns an array of quad arrays.
There's usually only one, but in principle there could be more... Something
to check before giving up.

Loop won't increment to next line

My assignment is to do a simple encryption (A-->F,G-->L, etc.) My program will do the encryption, but will only read one line of the text document. How do I get it to read all the lines?
Assigned text doc.:
A long time ago there was a young boy
who went to town 2 buy
some bread? Yes, some bread!
0ne ,abcdefgHIjklmnopq, is this a word?
Fin.
Current output of my program:
F qtsl ynrj flt ymjwj bfx f dtzsl gtdi?
(This is based on a 5 letter incrementation. I'm not sure where the "i?" at the end of the sentance are coming from. They aren't in the text doc.)
//Matthew Bogard - Project 1
   import java.io.*;
   import java.util.*;
   import java.lang.*;
//This program takes a text file and encrypts it using a simple encryption.
//Then it prints the encryption to another text file.
    public class EncryptIt
       public static void main(String[] args)
                           throws FileNotFoundException
         String FileName, OutFileName;
         String AString;
         int numberOfPositions;
         Scanner console = new Scanner(System.in);
         System.out.println("Please enter the File Name to encrypt: ");
         FileName = console.next();
         Scanner InFile = new Scanner(new FileReader(FileName));
         System.out.println("Please enter the File Name that will accept the encrypted file: ");
         OutFileName = console.next();
         PrintWriter OutFile = new PrintWriter(OutFileName);
         System.out.print("Enter an integer for the number of shifts in the encryption: ");
         numberOfPositions = console.nextInt();
         char X;
         int positionNumber = 0;
         int len;
         while (InFile.hasNext()) //I have tried hasNext and hasNextLine
            AString = InFile.nextLine();
            len = AString.length();
            while (positionNumber < len)
               X = AString.charAt(positionNumber);
               if ((X >= 65) && (X <= 90))
                  X += numberOfPositions;
                  if (X > 90)
                     X = (char) ((X - 90) + 65 - 1);
                     OutFile.print(X);
                  else
                     OutFile.print(X);
               else if ((X >= 97) && (X <= 122))
                  X += numberOfPositions;
                  if (X > 122)
                     X = (char) ((X - 122) + 97 - 1);
                     OutFile.print(X);
                  else
                     OutFile.print(X);
               else
                  OutFile.print(X);
               positionNumber++;
         InFile.close();
         OutFile.flush();
         OutFile.close();
   }

Your code is really hard to read. It should be broken down into methods.
I see your problem though.
while (InFile.hasNext()) //I have tried hasNext and hasNextLine
            AString = InFile.nextLine();
            len = AString.length();
            // ADD THESE LINES
            System.out.println("Just read len " + len + " for line: " + AString);
            System.out.println("positionNumber is " + postionNumber);
            while (positionNumber < len)
               X = AString.charAt(positionNumber);
               if ((X >= 65) && (X <= 90Also, "AString" is a really bad variable name. It should start with lowercase, as per the java convention, and it should have a more descriptive name, like "line" or something.

Barcode Reading to next line automatically

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