Batch File Search and Replace a String

Question

I've written a batch file to handle the copying of files.  I'm trying to reduce the number of parameters that I pass to the batch file.
I want the batch file to perform a string replace on the directory path that is passed as a parameter to the batch file.
Here is how I run the batch file:
COPY_FILE.BAT C:\DATA\FTP_DATA\ACME\IN      (I'm passing directory path "C:\DATA\FTP_DATA\ACME\IN" as parameter %1)
So my batch file will copy a file to the directory path represented by parameter %1.
But then I want the file copied to a second directory.  I want the batch file to replace string "FTP_DATA" in the directory path with string "FTP_DATA\ARCHIVE"
I know I could pass this path as a second parameter, but I want to limit the number of parameters so figured I could have the batch file perform a search and replace on string "FTP_DATA".
After searching the internet, I thought I found the answer by using the following command in the batch file:
set ARCHIVE_PATH=%1:FTP_DATA=FTP_DATA\ARCHIVE
But it doesn't perform a search and replace.  It just appends to the directory path with the following result:
C:\DATA\FTP_DATA\ACME\IN:FTP_DATA=FTP_DATA\ARCHIVE
What I want is the this:
C:\DATA\FTP_DATA\ARCHIVE\ACME\IN
Any suggestions?

Answer 1

Your syntax is not correct. Example:
@echo off
setlocal enableextensions
set ARCHIVE_PATH=C:\DATA\FTP_DATA\ACME\IN
echo %ARCHIVE_PATH%
set ARCHIVE_PATH=%ARCHIVE_PATH:FTP_DATA=FTP_DATA\ARCHIVE%
echo %ARCHIVE_PATH%
endlocal
-- Bill Stewart [Bill_Stewart]