Binary/bit-operation

Question

hi folks,
i would like to do the following:
i have a byte and split it up to get the left and right half of the byte. then i xor the left with the right and replace the right with the result of the xor.
how can i do this ?
here some code to get the half bytes:
byte temp = (byte)140; // or any other byte-value
int left = (temp & 0xF0) / 16; // get the left half-byte
int right = temp & 0x0F; // get the right half-byte
int xor = left ^ right; // xor the left with the right
// how shall i go on to replace the right with the xor-result ?thanks a lot,
tobias

Answer 1

Is this what you want?
byte result = (byte)((temp & 0xF0) | xor);