Binary Input to Lifecycle

Hello,
I want to send a PDF to Lifecycle ES via a JavaScript-function inside this PDF (initiated by a button in PDF). This js-function calls a Lifecycle service via WebService. The following methods deliver the byte-code of the current PDF:
var v_documentStream = Collab.documentToStream(event.target);
var v_encodedStream = SOAP.streamEncode(v_documentStream, "base64");
1. The problem is that in Lifecycle ES I only get a Stream with the length of 3 instead of 500.000 My chosen data type for the lifecycle-input-variable is "binary" I'm not sure if that is correct? And on PDF-Site I make the service-call in Document-literal Request-Style.
2. Perhaps it is a problem of encoding (document literal/rpc encoded)? So I tried to call Lifecycle ES via rpc encoded request, but I think that Lifecycle isn't able to handle rpc encoded calls by default, is that correct? Is it possible to enable lifecycle for RPC encoded requests?
Many thanks in advance!

I do not believe that you are getting the whole PDF in that call. You are only getting the commenting layer. AFAIK there is no way to get the whole PDF from inside of a PDF using javascript.

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Binary input in java 5

Hi all, I'm working on a project for class and have come up against a problem and unfortunately my text is not with me... if anyone could help me out I'd be really grateful! My constructor for the MyStudents class looks like this:
public MyStudents(String inF, String outF) throws EOFException, IOException,
          ClassNotFoundException {
          ObjectInputStream fileInput = new ObjectInputStream
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Hmm .. where to start?
First of all it seems that you are using exceptions as a flow control mechanism, not really what they are intended for.
Secondly, when an exception is thrown in a constructor, the constructor does not finish and thus the object does not get constructed. It is never good to have a constructor throw exceptions, just handle the exception internally.
And lastly you're not closing the input stream.
Try replacing
while (true)with
while (fileInput.available() > 0)That said, your reading of objects is assuming that the file is of the correct form. If the file is not a series of UTF string, date object and integer you'll still have the same problem.

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You need to be a bit more specific.
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Hi,
i try to write an implementation of LZW. I need to
read data in binary form from a file. How can i do
that? I cannot find something like "binary input
stream" ...
ThanksInputStream reads bytes. I don't understand your question.

Error in sending a binary outputstream to the browser

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If anyone could tell me what needs to be done to successfully send a binary input stream from a Java application to a JSP page calling it and then successfully sending the outputstream for the client to be read,that would be fantastic.

yes,I did.That sends the data out as junk.The outputstream gets some sort of junk characters with the response.getOutputStream() method.So it errors out when I set the content length.
I tried sending the data as a whole,but does not seem to make a difference.I was grasping at straws when I tried to break it into chunks.

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I've managed to read these from the input file using a byte array that I've converted into char, so I've got the first and last parts as output.
But the other 4 parts aren't ASCII data but character numbers.These have been converted into char,too, but I can't see them in the output..
For these parts the specification tells that for example: there is a part that is contained in 3 bytes and extracted to form a 6 character number...
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I hope it would be clear enough..

String (binary) to boolean conversion problem.

Hello,
Im facing problems converting a string (presumably in the binary format) to turn on LEDs according to its respective weight. ie.binary input = 1010. Thereby it would turn on the first (MSB) and third LEDs while the second and third are left off.
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OK, let's back up a second here. I don't understand what your "boolean to string" VI is doing. Are you starting with a string, a number, or a bunch of Boolean controls? The top part is dealing with Boolean controls and creating a string of characters of "0" and "1". The bottom part you have a numeric control. By the way, it is pointless to take the output of Number to Boolean Array, converting it to an array of 0s and 1s, indexing out each element, and then using the Not Equal to Zero operator. Just take the Boolean array output from Number to Boolean Array directly into an Index Array!
You seem to be saying that you have a string in the binary format. This is somewhat meaningless, so I'm assuming you mean you have a string that consists of a sequence of the ASCII characters "1" and "0" to indicate a numerical 1 or 0. You then want to convert this into something that is programmatically useful. What that is is not clear, so let's assume an array of Booleans. If that's the case, then you can simply take advantage of the fact that you're starting out with ASCII characters, and use the ASCII codes to find out what you have. The ASCII code for the character "0" is 30 (hex) or 48 (decimal). The ASCII code for the character "1" is 31 (hex) or 49 (decimal). Assuming this is what you have and what you want, then you can simply do this:
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Hey
I'm trying to write a importer for the PLY filke format. That file format starts of with a header in ascii and then continues with either the data in ascii or in binary. When the data is in ascii I have no problem reading the file but when the data is in binary I'm noth quite sure how I should do it. Right now I do something like this:
BufferedInputStream stream = new BufferedInputStream(new FileInputStream(file)); // I first create this
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http://www.cs.ucl.ac.uk/staff/Joao.Oliveira/ply.html in the Nbunny.zip.
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Discordia
Message was edited by:
Discordia

DataInputStream is NOT the right class to use for general binary input. It is used only for the specific purpose of reading Java primitives. The input obviously needs to be in the right format for that to work, i.e. it needs to be written using a DataOutputStream.
I would read everything using an InputStream, not a reader. Store the bytes of the header until you reach the end of the header (not sure how to determine that since I don't know the fileformat). Then convert those bytes into a String using the proper charset ("US-ASCII" in this case, if by "ascii" you really mean ASCII).
Then just continue reading the binary data.

Required code to convert binary to decimal

i need the programming logic to convert a binary number into its decimal equivalent. the program should also detect a non binary number.

public class EnterBinary{
   public static void main (String []args){
   int binCheck=0;
   String bins="";
   try {
      bins=args[0];
   catch (Exception e){
      System.out.print("No user input, program will terminate");
      System.exit(0);
   for(int i=0; i<bins.length(); i++)
      if((bins.charAt(i)=='1')||(bins.charAt(i)=='0')) binCheck++;
   if(binCheck==bins.length() ) {
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      binCheck=0;
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}

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Hi there,
I have a program that is reading binary data in as 16 bits per sample. I have some binary input files that were saved as 24 bits per sample. How do I convert my old program to handle this data. I realize that LabView doesn't have built in I24 conversion - how do I do this myself? I found a post that referred to using a boolean array to create your own 24 bit number - but I don't understand what that means... Any help would be appreciated!
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Do you know the format of the saved 24-bit data? Can you share some data with us, along with what you think the values are? If it is I24, then every three bytes represents a 24-bit (signed) integer. The first question to answer is "What is the order of the bytes"? How do you want to represent these data? The obvious choices are as an I32, but since the rest of your data is I16, you might choose I16, instead.
To convert I24 into I16, you can simply return the high two bytes. To convert I24 to I32, you need to set a high byte that replicates the sign (saved in the most significant bit of the third byte). One way to do this is to consider the third byte as an I8 quantity -- if it is positive, set the high byte to 0, and if it is negative, set the high byte to -1.
Bob Schor

What is the best combination of read and write objects to binary files ...

Hi everyone,
what are the best combination of read and write objects to read/write a record of customers from a binary file. I should be able to use StringTokenizer. I am bit confused with all these Stream reader and writers.
abdul

You are, indeed, confused:
o StreamTokenizer works on character input, not binary input.
o Readers and Writers in general work on character streams, not binary.
That leaves you various input streams and output streams for reading binary data.

Help with binary to decimal, binary to hex, and hex to ascii or ascii to hex program

I decided to do a program that will do binary to decimal, binary to hex, and hex to ascii for a project related to a java programming course, which only needs to perform features from chapters 1-6 and 8 of Tony Gaddis's book. The functions work fine as their own main programs out side of this combined effort, so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped. My flowcharts, which have to be revised after discovering that my previous function were logically incorrect after running them in their own main are attached below as the spec sheet.
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii
   public static void main(String[] args)throws IOException
      Scanner input = new Scanner(System.in);
      System.out.println("Enter a binary number: ");
      String binary = input.nextLine(); // store input from user
     if (binary == input.nextLine())
      //int i= Integer.parseInt(hex,2);
      //String hexString = Integer.toHexString(i);
      //System.out.println("Hexa decimal: " + hexString);
      //int finaldecimalvalue = binaryToDecimal(hexString);
      int finaldecimalvalue = binaryToDecimal(hexString);
     if (binary != input.nextLine())
      String hexInput; // The variable Bin Input declared as the datatype int to store the Binary value
      // Create a Scanner object for keyboard input.
      //Scanner keyboard = new Scanner(System.in);
      // Get the number of binary files.
      System.out.print("Enter the Hex value: ");
      hexInput = keyboard.nextLine();
      System.out.println("Original String: "+ hexInput);
      //String hexEquivalent = asciiToHex(demoString);
      String hexEquivalent = asciiToHex(hexInput);
      //Hex value of original String
      System.out.println("Hex String: "+ hexEquivalent);
      String asciiEquivalent = hexToASCII(hexEquivalent);
      //ASCII value obtained from Hex value
      System.out.println("Ascii String: "+ asciiEquivalent);String finalhexOutput = HextoAsciiConverter(hexEquivalent);
     if (binary != input.nextLine() && hexInput != keyboard.nextLine())
         BufferedReader binInput = new BufferedReader(new InputStreamReader(System.in));
         System.out.println("Enter the Binary number:");
         String hex = binInput.readLine();
         //String finaldecimalvalue = binaryToDecimal(decimal);
         //long finalhexvalue = BinaryToHexadecimal(num);
         long finalhexvalue = BinaryToHexadecimal();
   public static String BinaryToHexadecimal(String hex)
      //public static void main(String[] args)throws IOException
         //BufferedReader bf= new BufferedReader(new InputStreamReader(System.in));
         //System.out.println("Enter the Binary number:");
         //String hex = binInput.readLine();
         long num = Long.parseLong(hex);
         long rem;
         while(num > 0)
         rem = num % 10;
         num = num / 10;
         if(rem != 0 && rem != 1)
         System.out.println("This is not a binary number.");
         System.out.println("Please try once again.");
         System.exit(0);
         int i= Integer.parseInt(hex,2);
         String hexString = Integer.toHexString(i);
         System.out.println("Hexa decimal: " + hexString);
      return num.tolong();
//int i= Integer.parseInt(hex,2);
//String hexString = Integer.toHexString(i);
//System.out.println("Hexa decimal: " + hexString);
//} // end BintoDectoHextoAsciil
   //public static String HexAsciiConverter(String hextInput)
      // Get the number of binary files.
      //System.out.print("Enter the Hex value: ");
      //hexInput = keyboard.nextLine();
      //System.out.println("Original String: "+ hexInput);
      //String hexEquivalent = asciiToHex(demoString);
      //String hexEquivalent = asciiToHex(hexInput);
      //Hex value of original String
      //System.out.println("Hex String: "+ hexEquivalent);
      //String asciiEquivalent = hexToASCII(hexEquivalent);
      //ASCII value obtained from Hex value
      //System.out.println("Ascii String: "+ asciiEquivalent);
   //} // End function
   private static String asciiToHex(String asciiValue)
      char[] chars = asciiValue.toCharArray();
      StringBuffer hex = new StringBuffer();
      for (int i = 0; i < chars.length; i++)
         hex.append(Integer.toHexString((int) chars[i]));
      return hex.toString();
   private static String hexToASCII(String hexValue)
      StringBuilder output = new StringBuilder("");
      for (int i = 0; i < hexValue.length(); i += 2)
         String str = hexValue.substring(i, i + 2);
         output.append((char) Integer.parseInt(str, 16));
      return output.toString();
   public static String binaryToDecimal(String binary)
        //Scanner input = new Scanner(System.in);
        //System.out.println("Enter a binary number: ");
        //String binary = input.nextLine(); // store input from user
        int[] powers = new int[16]; // contains powers of 2
        int powersIndex = 0; // keep track of the index
        int decimal = 0; // will contain decimals
        boolean isCorrect = true; // flag if incorrect input
       // populate the powers array with powers of 2
        for(int i = 0; i < powers.length; i++)
            powers[i] = (int) Math.pow(2, i);
        for(int i = binary.length() - 1; i >= 0; i--)
            // if 1 add to decimal to calculate
            if(binary.charAt(i) == '1')
                decimal = decimal + powers[powersIndex]; // calc the decimal
            else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
                isCorrect = false; // flag the wrong input
                break; // break from loop due to wrong input
            } // end else if
            // keeps track of which power we are on
            powersIndex++; // counts from zero up to combat the loop counting down to zero
        } // end for
        if(isCorrect) // print decimal output
            System.out.println(binary + " converted to base 10 is: " + decimal);
        else // print incorrect input message
            System.out.println("Wrong input! It is binary... 0 and 1's like.....!");
        return decimal.toint();
   } // end function
The errors are as follows:
----jGRASP exec: javac BintoDectoHextoAscii.java
BintoDectoHextoAscii.java:65: error: class, interface, or enum expected
   public static String BinaryToHexadecimal(String hex)
                 ^
BintoDectoHextoAscii.java:73: error: class, interface, or enum expected
         long rem;
         ^
BintoDectoHextoAscii.java:74: error: class, interface, or enum expected
         while(num > 0)
         ^
BintoDectoHextoAscii.java:77: error: class, interface, or enum expected
         num = num / 10;
         ^
BintoDectoHextoAscii.java:78: error: class, interface, or enum expected
         if(rem != 0 && rem != 1)
         ^
BintoDectoHextoAscii.java:81: error: class, interface, or enum expected
         System.out.println("Please try once again.");
         ^
BintoDectoHextoAscii.java:83: error: class, interface, or enum expected
         System.exit(0);
         ^
BintoDectoHextoAscii.java:84: error: class, interface, or enum expected
         ^
BintoDectoHextoAscii.java:87: error: class, interface, or enum expected
         String hexString = Integer.toHexString(i);
         ^
BintoDectoHextoAscii.java:88: error: class, interface, or enum expected
         System.out.println("Hexa decimal: " + hexString);
         ^
BintoDectoHextoAscii.java:90: error: class, interface, or enum expected
      return num.tolong();
      ^
BintoDectoHextoAscii.java:91: error: class, interface, or enum expected
   ^
BintoDectoHextoAscii.java:124: error: class, interface, or enum expected
      StringBuffer hex = new StringBuffer();
      ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
      for (int i = 0; i < chars.length; i++)
      ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
      for (int i = 0; i < chars.length; i++)
                      ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
      for (int i = 0; i < chars.length; i++)
                                        ^
BintoDectoHextoAscii.java:128: error: class, interface, or enum expected
      ^
BintoDectoHextoAscii.java:130: error: class, interface, or enum expected
   ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
      for (int i = 0; i < hexValue.length(); i += 2)
      ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
      for (int i = 0; i < hexValue.length(); i += 2)
                      ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
      for (int i = 0; i < hexValue.length(); i += 2)
                                             ^
BintoDectoHextoAscii.java:138: error: class, interface, or enum expected
         output.append((char) Integer.parseInt(str, 16));
         ^
BintoDectoHextoAscii.java:139: error: class, interface, or enum expected
      ^
BintoDectoHextoAscii.java:141: error: class, interface, or enum expected
   ^
BintoDectoHextoAscii.java:144: error: class, interface, or enum expected
   public static String binaryToDecimal(String binary)
                 ^
BintoDectoHextoAscii.java:150: error: class, interface, or enum expected
        int powersIndex = 0; // keep track of the index
        ^
BintoDectoHextoAscii.java:151: error: class, interface, or enum expected
        int decimal = 0; // will contain decimals
        ^
BintoDectoHextoAscii.java:152: error: class, interface, or enum expected
        boolean isCorrect = true; // flag if incorrect input
        ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
        for(int i = 0; i < powers.length; i++)
        ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
        for(int i = 0; i < powers.length; i++)
                       ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
        for(int i = 0; i < powers.length; i++)
                                          ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
        for(int i = binary.length() - 1; i >= 0; i--)
        ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
        for(int i = binary.length() - 1; i >= 0; i--)
                                         ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
        for(int i = binary.length() - 1; i >= 0; i--)
                                                 ^
BintoDectoHextoAscii.java:166: error: class, interface, or enum expected
            else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
            ^
BintoDectoHextoAscii.java:169: error: class, interface, or enum expected
                break; // break from loop due to wrong input
                ^
BintoDectoHextoAscii.java:170: error: class, interface, or enum expected
            } // end else if
            ^
BintoDectoHextoAscii.java:174: error: class, interface, or enum expected
        } // end for
        ^
BintoDectoHextoAscii.java:180: error: class, interface, or enum expected
        else // print incorrect input message
        ^
BintoDectoHextoAscii.java:185: error: class, interface, or enum expected
        return decimal.toint();
        ^
BintoDectoHextoAscii.java:186: error: class, interface, or enum expected
   } // end function
   ^
41 errors
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.

so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped.
Yes - YOU CAN!
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
Excellent! Commenting out code is EXACTLY how you troubleshoot problems like yours.
Comment out sections of code until the problem goes away. Then start adding back ONE SECTION of code at a time until the problem occurs. When it does you have just FOUND the problem.
If you do that you wind up with code that looks like this:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii {
      public static void main(String[] args)throws IOException      {
         Scanner input = new Scanner(System.in);
         System.out.println("Enter a binary number: ");
         String binary = input.nextLine(); // store input from user
              public static String BinaryToHexadecimal(String hex)     {     } // end function
Notice ANYTHING UNUSUAL?
You have a complete CLASS definition followed by a method definition.
Methods have to be INSIDE the class - you can NOT define methods on their own.
Write modular code.
Write EMPTY methods - just the method signature and maybe a RETURN NULL if you need to return something.
Then add calls to those empty methods.
When everything compiles and runs find you can start adding code to the methods ONE METHOD AT A TIME.
Test compile and run after you add the code for each method.

Urgent - 4/16 binary to hexadecimal decoder

Hi...
I have to send an example from multisim to my proffesor assistant, till 28.05.2008...
I have to create a decoder the will 4/16, that will decode binary equivalent digits to hexadecimal digits...
I really have no Idea how to do this with multisim...
Can someone make an example of it or make a tutorial how to do it...
thnx a lot

Multisim has a very easy learning curve, especially for something this simple. Just place the components you want, click on their pins to connect them, and you are set. If you need instructions on placing parts, use the help file. (Hit F1)
Since I can't be doing your school work for you, I'll make a deal with you. You draw up the schematic you want to build and post it, and I'll put it together in multisim. If you weren't introduced to boolean algebra before being given this assignment, then you might be ill-prepared for this. Just stick to the basics: you have AND gates and you know how those work, so just use AND gates to take the inverted and non-inverted binary inputs and give a certain output for a given binary sequence, just like the example your assistant gave you.
Ryan R.
R&D

GUI_DOWNLOAD give 2 bytes for each chinese character - I need fixed length

Due to the Unicode system takes each Chinese character as a byte, the field(10) can take 10 Chinese Characters, not like before only 5 characters allowed.
The problem is when the data is downloaded to a txt file. Some records contains only Western Europe charactes and will fill 10 bytes in the output file and other records contains only Chinese characters and will fill up 20 bytes in the output file.
The data is exported for a system that can upload chinese characters, but only allow fixed record length file (always 10 bytes).
In other words: the records with Western Europe characters should contain 10 characters = 10 bytes but the records with Chinese characters should only contain 5 characters = 10 bytes.
Anyone who can solve this, thanks in advance.
My code:
CALL METHOD CL_GUI_FRONTEND_SERVICES=>GUI_DOWNLOAD
    EXPORTING
      FILENAME                = p_file
      CONFIRM_OVERWRITE       = 'X'
      codepage                = '8400' "Chinese
    CHANGING
      DATA_TAB                = it_output
    EXCEPTIONS

Hi Thomas,
Now I understand.
Pl. check the class CL_ABAP_CONV_X2X_CE.
May it can help u.
Here is it's documentation.
CL CL_ABAP_CONV_X2X_CE
Short Text
Code Page and Endian Conversion Between External Formats
Functionality
Instances of the class CL_ABAP_CONV_X2X_CE allow you to convert text data between different character sets and numeric data between different number formats (byte order).
Using the class corresponds to transforming data from a binary input stream to a binary output stream: The data objects are read from the input buffer sequentially and written to an output buffer.
The class methods are normally used as follows:
CL_ABAP_CONV_X2X_CE=>CREATE
This creates a conversion instance. Among other options, you can specify the following as parameters: The input buffer (that is the binary string that contains the data to be read), the character format at used in the input buffer, the byte order used in the input buffer, the character format to be used in the output buffer, or the byte order to be used in the output buffer.
CONVERT_C, CONVERT_...
This converts the data. Calling this method several times consecutively allows you to read data from the input buffer sequentially and add it to the end of the output buffer.
GET_OUT_BUFFER
This gets the output buffer, making it available for further processing (such as writing to a file, sending using RFC).
RESET
This allows you to reset individual attributes of the conversion instance. (This method is especially designed for restarting on a new input buffer and deleting the output buffer while retaining the remaining attributes.)
Relationships
CL_ABAP_CONV_IN_CE
Converting Binary Data into ABAP Data Objects
CL_ABAP_CONV_OUT_CE
Converting ABAP Data Objects to a Binary Format.
CL_ABAP_CHAR_UTILITIES
Various Attributes and Methods for Character Sets and Byte Order
Example
In the following example, UTF-8 texts are converted to the codepage 1100 (Latin-1) and numbers are converted from little-endian to big-endian format:
DATA:
in_buffer TYPE XSTRING,
out_buffer TYPE XSTRING,
conv TYPE REF TO cl_abap_conv_x2x_ce.
in_buffer = '414220C3B602010000'.
conv = cl_abap_conv_x2x_ce=>create(
         in_encoding = 'UTF-8'
         in_endian = 'L'
         out_encoding = '1100'
         out_endian = 'B'
         input = in_buffer
CALL METHOD conv->convert_c( n = 5 ).
CALL METHOD conv->convert_i( ).
out_buffer = conv->get_out_buffer( ).
The content of the in_buffer variable is made up of 5 bytes (hexadecimal "414220C3B6"), which represent 4 UTF-8 characters (A, B, SPACE, o-Umlaut), and 4 bytes (hexadecimal "02010000"), which represent the value 258 in little-endian format. This data is converted and the out_buffer variable now contains the hexadecimal string "414220F600000102". It is made up of:
4 bytes (hexadecimal "414220F6"), which represent the above 4 characters in codepage 1100 (ISO-8859-1). Note that the length specification n = 5 refers to the number of elementary characters to be converted. For multi-byte codepages like UTF-8 this means that the multi-byte character "C3B6" is counted in length 2.
4 Bytes (hexadecimal "00000102"), which represent the value 258 in big-endian format.
If you have the desired byte order in the old format as expected by TRANSLATE ... NUMBER FORMAT (as an N(4) value), you can proceed as follows:
TYPE-POOLS: ABAP.
CLASS cl_abap_char_utilities DEFINITION LOAD.
DATA:
in_number_format(4) TYPE N VALUE '0101',
out_number_format(4) TYPE N VALUE '0000'.
DATA:
in_endian TYPE ABAP_ENDIAN,
out_endian TYPE ABAP_ENDIAN,
conv TYPE REF TO cl_abap_conv_x2x_ce..
in_endian = cl_abap_char_utilities=>number_format_to_endian(
               in_number_format
out_endian = cl_abap_char_utilities=>number_format_to_endian(
               out_number_format
conv = cl_abap_conv_x2x_ce=>create(
         in_encoding = 'UTF-8'
         in_endian = in_endian
         out_encoding = '1100'
         out_endian = out_endian
         input = in_buffer
Notes
For details refer to the documentation for the individual methods.
Regards,
Joy.

Binary Input to Lifecycle

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