Biztalk WCF-SQL polling sample using a FOR XML Path

I've been searching in the web for a sample that uses FOR XML "PATH" to poll the SQL database . The result returned from my query is a parent child data and FOR XML PATH is the best choice to structure it in that way . I guess I'm missing something while
generating the schemas from this stored procedure.
I guess Dan Rosanova has touched on this concept (http://social.technet.microsoft.com/wiki/contents/articles/3480.aspx)
, but its using XML Auto. Again there is no sample available so makes things a bit difficult.
Can someone point to a sample walkthrough , generating the schemas and then later using it in the application.
Thanks
Anthstone

I used XMLPolling and it worked for me. you can go for XMLPolling. Steps to be followed:
1) Create the SP which will have the SELECT query similar to below:
;WITH XMLNAMESPACES (default 'http://yourcustomnamespace')
 Select * from Employee FOR XML PATH('YourCustomRootNode') 
2) Create a schema out of the table using the following query
Select * from Employee for
xml
auto,
xmlschema 
3) Re-name the root name and namespace as per you mentioned in point#1 (YourCustomRootNode)
4) Create an Envelope Schema and refer the schema from point#3. Also make a note of the root node name and namespace that we need to specify
in the admin console.
5) Assign the Body XPath to debatch. Refer
this.  Deploy the solution.
6) In the Admin console, add the Root Node Name and namespace mentioned in point#4 under "XmlStoredProcedureRoodNodeName" and "XmlStoredProcedureRoodNodeNamespace"
There you go. I did this for debatching. You can do for nomarl batch message instead of Envelope create a normal document schema.
Thanks
SKGuru

Similar Messages

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    Hi all,
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    SQL Server 2012 Management Studio:
    --Coles12_8.sql // saved in C:/Documemnts/SQL Server Management Studio
    -- Coles Listing 12-8 FOR XML PATH Using XPATH Node Tests
    -- Retrieving Name and E-mail Addresses with FOR XML PATH in AdvantureWorks
    -- 16 March 2015 0935 AM
    USE AdventureWorks;
    GO
    SELECT
    p.NameStyle AS "processing-instruction(nameStyle)",
    p.BusinessEntityID AS "Person/@ID",
    p.ModifiedDate AS "comment()",
    pp.PhoneNumber AS "test()",
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    MiddleName AS "Person/Name/Middle",
    LastName AS "Person/Name/Last",
    EmailAddress AS "Person/Email"
    FROM Person.Person p
    INNER JOIN Person.EmailAddress e
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    INNER JOIN Person.PersonPhone pp
    ON p.BusinessEntityID = pp.BusinessEntityID
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    Msg 6850, Level 16, State 1, Line 2
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    I have no ideas why I got this error message.  Please kindly help and advise me how to resolve this error.
    Thanks in advance,  Scott Chang

    Hi Michelle, Thanks for your nice response.
    I corrected the mistake and executed the revised code. It worked nicely.
    I just have one question to ask you about the appearance of the xml output of my Co;les12_8.sql:
    <row>
    <?nameStyle 0?>
    <Person ID="1" />
    <!--2003-02-08T00:00:00-->697-555-0142<Person><Name><First>Ken</First><Middle>J</Middle><Last>Sánchez</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    <?nameStyle 0?>
    <Person ID="2" />
    <!--2002-02-24T00:00:00-->819-555-0175<Person><Name><First>Terri</First><Middle>Lee</Middle><Last>Duffy</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    <?nameStyle 0?>
    <Person ID="3" />
    <!--2001-12-05T00:00:00-->212-555-0187<Person><Name><First>Roberto</First><Last>Tamburello</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    <?nameStyle 0?>
    <Person ID="4" />
    <!--2001-12-29T00:00:00-->612-555-0100<Person><Name><First>Rob</First><Last>Walters</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    <?nameStyle 0?>
    <Person ID="5" />
    <!--2002-01-30T00:00:00-->849-555-0139<Person><Name><First>Gail</First><Middle>A</Middle><Last>Erickson</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    <?nameStyle 0?>
    <Person ID="6" />
    <!--2002-02-17T00:00:00-->122-555-0189<Person><Name><First>Jossef</First><Middle>H</Middle><Last>Goldberg</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    <?nameStyle 0?>
    <Person ID="7" />
    <!--2003-03-05T00:00:00-->181-555-0156<Person><Name><First>Dylan</First><Middle>A</Middle><Last>Miller</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    <?nameStyle 0?>
    <Person ID="8" />
    <!--2003-01-23T00:00:00-->815-555-0138<Person><Name><First>Diane</First><Middle>L</Middle><Last>Margheim</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    <?nameStyle 0?>
    <Person ID="9" />
    <!--2003-02-10T00:00:00-->185-555-0186<Person><Name><First>Gigi</First><Middle>N</Middle><Last>Matthew</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    <?nameStyle 0?>
    <Person ID="10" />
    <!--2003-05-28T00:00:00-->330-555-2568<Person><Name><First>Michael</First><Last>Raheem</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    <?nameStyle 0?>
    <Person ID="11" />
    <!--2004-12-29T00:00:00-->719-555-0181<Person><Name><First>Ovidiu</First><Middle>V</Middle><Last>Cracium</Last></Name><Email>[email protected]</Email></Person></row>
    <row>
    I feel this xml output is not like the regular xml output.  Do you know why it is diffrent from the regular xml xml output?  Please comment on this matter.
    Thanks,
    Scott Chang
    What do you mean by regular xml document? Are you referring to fact that its missing a root element? if yes it can be added as below
    USE AdventureWorks;
    GO
    SELECT
    p.NameStyle AS "processing-instruction(nameStyle)",
    p.BusinessEntityID AS "Person/@ID",
    p.ModifiedDate AS "comment()",
    pp.PhoneNumber AS "text()",
    FirstName AS "Person/Name/First",
    MiddleName AS "Person/Name/Middle",
    LastName AS "Person/Name/Last",
    EmailAddress AS "Person/Email"
    FROM Person.Person p
    INNER JOIN Person.EmailAddress e
    ON p.BusinessEntityID = e.BusinessEntityID
    INNER JOIN Person.PersonPhone pp
    ON p.BusinessEntityID = pp.BusinessEntityID
    FOR XML PATH('ElementName'),ROOT('RootName');
    replace ElementName and RootName with whatever name you need to set for element as well as the root element
    Please Mark This As Answer if it solved your issue
    Please Vote This As Helpful if it helps to solve your issue
    Visakh
    My Wiki User Page
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  • "for XML path "  Oracle equivalent of this SQL expression

    SELECT TheID,
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    Works perfectly in SQL.
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    Hi,
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    Other than using dynamic sql (which we don't want to use) is there a way to use a variable in For XML Path, e.g.
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    TIA,
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    In terms of general XML design this is poor.  An element is normally a 'thing', and the attributes are normally the properties of that thing.  Therefore in your case you would have a Book property with a 'name' attribute.  It would be impossible
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  • Generate xml using FOR XML PATH from table with hierarchy

    I need to create xml from a table like:
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    E10,E1020,    ,a,b,c,d
    E10,E1020,E102010,a,b,c,d
    E20,    ,    ,a,b,c,d
    E20,E2010,    ,a,b,c,d
    E20,E2010,E201010,a,b,c,d
    E20,E2020,    ,a,b,c,d
    E20,E2020,E202010,a,b,c,d
    E20,E2020,E202020,a,b,c,d
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          <E101030 Attr01="a" Attr02="b" Attr03="c" Attr04="d" />
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          <E102010 Attr01="a" Attr02="b" Attr03="c" Attr04="d" />
        </E1020>
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          <E201010 Attr01="a" Attr02="b" Attr03="c" Attr04="d" />
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        <E2020 Attr01="a" Attr02="b" Attr03="c" Attr04="d">
          <E202010 Attr01="a" Attr02="b" Attr03="c" Attr04="d" />
          <E202020 Attr01="a" Attr02="b" Attr03="c" Attr04="d" />
        </E2020>
      </E20>
    </root>
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    EL1 VARCHAR(10),
    EL2 VARCHAR(10),
    EL3 VARCHAR(10),
    Attr01 VARCHAR(10),
    Attr02 VARCHAR(10),
    Attr03 VARCHAR(10),
    Attr04 VARCHAR(10)
    GO
    INSERT INTO Src
    (EL1,EL2,EL3,Attr01,Attr02,Attr03,Attr04
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     UNION SELECT 'E10','E1010','','a','b','c','d'
     UNION SELECT 'E10','E1010','E101010','a','b','c','d'
     UNION SELECT 'E10','E1010','E101020','a','b','c','d'
     UNION SELECT 'E10','E1010','E101030','a','b','c','d'
     UNION SELECT 'E10','E1020','','a','b','c','d'
     UNION SELECT 'E10','E1020','E102010','a','b','c','d'
     UNION SELECT 'E20','','','a','b','c','d'
     UNION SELECT 'E20','E2010','','a','b','c','d'
     UNION SELECT 'E20','E2010','E201010','a','b','c','d'
     UNION SELECT 'E20','E2020','','a','b','c','d'
     UNION SELECT 'E20','E2020','E202010','a','b','c','d'
     UNION SELECT 'E20','E2020','E202020','a','b','c','d'
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    I tried to use FOR XML PATH to generate xml for the sample data. When the records increase to a few hundreds, it's not a good idea.
    Here is my script:
    SELECT
    (SELECT Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    FROM Src
    WHERE EL3 = 'E101010'
    FOR XML PATH('E101010'),TYPE
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    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    FROM Src
    WHERE EL3 = 'E101020'
    FOR XML PATH('E101020'),TYPE
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    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    FROM Src
    WHERE EL3 = 'E101030'
    FOR XML PATH('E101030'),TYPE
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    FROM Src
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    FOR XML PATH('E1010'),TYPE
    ) AS 'node()'--1010
    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    FROM Src
    WHERE EL3 = 'E102010'
    FOR XML PATH('E102010'),TYPE
    ) AS 'node()'
    FROM Src
    WHERE EL2 = 'E1020' AND (EL1 <>'' AND EL3 ='')
    FOR XML PATH('E1020'),TYPE
    ) AS 'node()'--1020
    FROM Src
    WHERE EL1 = 'E10' AND (EL2 ='' AND EL3 ='')
    FOR XML PATH('E10'),TYPE) 'node()'
    ,(SELECT Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    FROM Src
    WHERE EL3 = 'E201010'
    FOR XML PATH('E201010'),TYPE
    ) AS 'node()'
    FROM Src
    WHERE EL2 = 'E2010' AND (EL1 <>'' AND EL3 ='')
    FOR XML PATH('E2010'),TYPE
    ) AS 'node()'--2010
    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    FROM Src
    WHERE EL3 = 'E202010'
    FOR XML PATH('E202010'),TYPE
    ) AS 'node()'
    ,( SELECT
    Attr01 AS '@Attr01'
    ,Attr02 AS '@Attr02'
    ,Attr03 AS '@Attr03'
    ,Attr04 AS '@Attr04'
    FROM Src
    WHERE EL3 = 'E202020'
    FOR XML PATH('E202020'),TYPE
    ) AS 'node()'
    FROM Src
    WHERE EL2 = 'E2020' AND (EL1 <>'' AND EL3 ='')
    FOR XML PATH('E2020'),TYPE
    FROM Src
    WHERE EL1 = 'E20' AND (EL2 ='' AND EL3 ='')
    FOR XML PATH('E20'),TYPE) AS 'node()'
    FOR XML PATH(''),ROOT('root')
    If I get a few hundreds of rows, how huge the script should be. Does anyone have better solution for this? Thanks.
    Tao

    wBob,
    Thanks! And sorry for late feedback.
    The XSD requires the xml structures like the following
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    <School02>Some other school</School02>
    </Schools>
    I have to use the number in the element name. 
    Right now I just use the nested FOR XML PATH, although I have to write thousand lines code.
    Thanks anyway.
    Tao
    Tao

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    Thanks,
    Nimit

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    Copyright (c) Microsoft Corporation
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    FROM Sales.SalesOrderDetail sod2
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    FROM Sales.SalesOrderDetail sod2
    WHERE sod1.SalesOrderID = sod2.SalesOrderID
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    FROM
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    GROUP BY
    sod1.SalesOrderID
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    Thanks,
    Jason
    Jason Long

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    parFactorNames := SUBSTR(parFactorNames,Pos + 1);
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    The answer is NO.
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    A snippet quoted below.
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