BufferedReader/FileWriter - read in a line and store it in a file

Question

hi, I'm new in programming java, so I hope somebody can help me with the following question:
I've got a file that contains parameters, which change every second (the file updates itself every second)
Now I have to write a java Programm, that reads in a certain parameter of that file, and store it in another file, so that the file lists every read-in parameter (to show the changes of the parameter).
the following source shows a programm, that reads in the content of a text file and stores it in another file - every second. Please, could anyone be so kind, and help me to change the programm?
import java.io.*;
import java.util.Date;
public class readIn {
public static void main(String[] args) throws IOException {
for (int i = 1; i <= 5; ++i) {
System.out.println("Sleep at: " + new Date());
try
// ask currently executing Thread to sleep for 1000ms
Thread.sleep(1000);
catch(InterruptedException e)
System.out.println("Sleep interrupted:"+e);
if (args.length != 2)
System.err.println ("usage: pattern file");
System.exit (1);
String patt = args [0];
String fileIn = args [1];
try
LineNumberReader reader = new LineNumberReader
(new FileReader (fileIn));
String str;
while ((str = reader.readLine()) != null)
if (str.indexOf (patt) != -1)
int ln = reader.getLineNumber();
File inputFile = new File("logfile.txt");
File outputFile = new File("history.txt");
FileReader in = new FileReader(inputFile);
FileWriter out = new FileWriter(outputFile);
int c;
while ((c = in.read()) != -1)
out.write(c);
in.close();
out.close();
reader.close();
catch (IOException e)
System.err.println ("IO-Fehler beim Filtern");
e.printStackTrace();
System.out.println("Awoke at: " + new Date());
the logfile.txt contains words which change every second. I want to permanently read in the third line.
anatomy
animation
applet
application
argument
bolts
class
communicate
component
container
development
environment
exception
graphics
image
input
integrate
interface
Thank you very much for your immediate answer!!

Answer 1

RandomAccessFile ??
aha, I took a look at the API but I have no idea how to work with it. If its quite easy, could you please be so kind and tell me ?? thanks ;)