BUG IN SimpleDateFormat ?

Question

hi all,
i want to get the difference between 2 dates (time), so i use the following code:
java.text.SimpleDateFormat format = new java.text.SimpleDateFormat("hh:mm:ss");
String time1 = "12:48:10";
String time2 = "12:48:09";
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
lTotalTime = date1.getTime() - date2.getTime();
System.out.println( "Time diff :" + format.format(new Date(lTotalTime)));
but the result is ==> Time diff :01:00:01
why do i get 1 hour too much????
the result should be 00:00:01
any idea what goes wrong?
thanx,
andi

Answer 1

Hi!
try the following, and u will see, it's ok!
import java.util.*;
public class Test
public static void main(String[] args)
try
java.text.SimpleDateFormat format = new java.text.SimpleDateFormat("hh:mm:ss");
java.text.SimpleDateFormat formatlong = new java.text.SimpleDateFormat("dd.MM.yyyy hh:mm:ss");
String time1 = "12:48:10";
String time2 = "12:48:09";
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
long lTotalTime = date1.getTime() - date2.getTime();
System.out.println( "Time1: " + time1 +
" " + date1.getTime() +
" " + formatlong.format(new Date(date1.getTime())));
System.out.println( "Time2: " + time2 +
" " + date2.getTime() +
" " + formatlong.format(new Date(date2.getTime())));
System.out.println( "Time diff long: " + lTotalTime);
System.out.println( "Time diff: " + format.format(new Date(lTotalTime)));
System.out.println( "Time zero: " + format.format(new Date(0)));
catch (Throwable thr) {thr.printStackTrace();}
result:
Time1: 12:48:10 -710000 01.01.1970 12:48:10
Time2: 12:48:09 -711000 01.01.1970 12:48:09
Time diff long: 1000
Time diff: 01:00:01
Time zero: 01:00:00
The time difference is 1000 milliseconds, and this is right!
The only problem here is, that a Date initialized with zero is 01:00:00!
So you get the right difference to this date!
regards,
Martin