Bug? Picture Ring proprty String and Values" returns error 1054 in LV 8.5

Should that propert exist for a Picture Ring?
Ben
Message Edited by Ben on 09-01-2008 07:47 AM
Ben Rayner
I am currently active on.. MainStream Preppers
Rayner's Ridge is under construction
Solved!
Go to Solution.
Attachments:
Error_1054.PNG ‏27 KB

The fact that the error is gone when you don't connect the indicator is good. Even better it is super.
It means the compiler removes that specific node from the execution stack if it isn't needed.
Ton
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Hello,
I'm new here so please let me know if I overstep any of the rules or expectations. I merely want to learn more about Java Programming efficiently, and easily. I can ask and discuss these topics with my online prof, but she doesn't have much time.
So right now I'm trying to solve a problem. It's a typical college level computing problem which I've already turned in. So I'm not looking for someone to do my homework for me or something. It's just that the program didn't work. Even though I probably won't get a very good grade for it, I want to
make it work! I'm kind of slow when it comes to java so just bear with me.
The prof wanted us to write an algorithm that reads a student's name and 6 exam scores. Then it computes the average score for each student, assigns a letter grade, using a rating scale:
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Then we had to use a value-returning method CalculateGrade to determine and return the grade for each student. But it can't output the grade because that must be done in void main.
Finally the class average must be output.
Our prof gave us a list of student names with their 6 scores.
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So all the data had to be read from a file and the results output to a file. Also we couldn't use 'global variables'. We had to use the appropriate parameters to pass values to and from methods.
Question 1: What does she mean by 'no global variables'? Maybe she means: don't use "*double test1, test2, test3, test4, test5*;"
Anyway because I'm a slow learner with Java, I end up looking for sample programs that seem to do a similar job as the problem posed. So with this program I decided to adapt a program called Comparison of Class Averages.
//Program: Comparison of Class Averages.
import java.io.*;
import java.util.*;
import java.text.DecimalFormat;
public class DataComparison
public static void main (String[] args) throws
FileNotFoundException, IOException
//Step 1
String courseId1; //course ID for group 1
String courseId2; //course ID for group 2
int numberOfCourses;
DoubleClass avg1 = new DoubleClass(); //average for a course
//in group 1
DoubleClass avg2 = new DoubleClass(); //average for a course
//in group 2
double avgGroup1; //average group 1
double avgGroup2; //average group 2
String inputGroup1;
String inputGroup2;
StringTokenizer tokenizer1 = null;
StringTokenizer tokenizer2 = null;
//Step 2 Open input and output files
BufferedReader group1 =
new BufferedReader(new FileReader("a:\\group1.txt"));
BufferedReader group2 =
new BufferedReader(new FileReader("a:\\group2.txt"));
PrintWriter outfile =
new PrintWriter(new FileWriter("a:\\student.out"));
DecimalFormat twoDecimal =
new DecimalFormat("0.00"); //Step 3
avgGroup1 = 0.0; //Step 4
avgGroup2 = 0.0; //Step 5
numberOfCourses = 0; //Step 6
//print heading: Step 7
outfile.println("Course No Group No Course Average");
inputGroup1 = group1.readLine(); //Step 8
inputGroup2 = group2.readLine(); //Step 9
while((inputGroup1 != null) &&
(inputGroup2 != null)) //Step 10
tokenizer1 = new StringTokenizer(inputGroup1);
courseId1 = tokenizer1.nextToken(); //Step 10a
tokenizer2 = new StringTokenizer(inputGroup2);
courseId2 = tokenizer2.nextToken(); //Step 10b
if(!courseId1.equals(courseId2)) //Step 10c
System.out.println("Data error: Course IDs "
+ "do not match.");
System.out.println("Program terminates.");
outfile.println("Data error: Course IDs "
+ "do not match.");
outfile.println("Program terminates.");
outfile.close();
return;
else //Step 10d
calculateAverage(group1, tokenizer1, avg1); //Step 10d.i
calculateAverage(group2, tokenizer2, avg2); //Step 10d.ii
printResult(outfile,courseId1,1,avg1); //Step 10d.iii
printResult(outfile,courseId2,2,avg2); //Step 10d.iv
avgGroup1 = avgGroup1 + avg1.getNum(); //Step 10d.v
avgGroup2 = avgGroup2 + avg2.getNum(); //Step 10d.vi
outfile.println();
numberOfCourses++; //Step 10d.vii
inputGroup1 = group1.readLine(); //Step 10e
inputGroup2 = group2.readLine(); //Step 10f
}//end while
if((inputGroup1 != null) && (inputGroup2 == null)) //Step 11a
System.out.println("Ran out of data for group 2 "
+ "before group 1.");
else //Step 11b
if((inputGroup1 == null) && (inputGroup1 != null))
System.out.println("Ran out of data for "
+ "group 1 before group 2.");
else //Step 11c
outfile.println("Avg for group 1: " +
twoDecimal.format(avgGroup1 / numberOfCourses));
outfile.println("Avg for group 2: " +
twoDecimal.format(avgGroup2 / numberOfCourses));
outfile.close(); //Step 12
public static void calculateAverage(BufferedReader inp,
StringTokenizer tok,
DoubleClass courseAvg)
throws IOException
double totalScore = 0.0;
int numberOfStudents = 0;
int score = 0;
if(!tok.hasMoreTokens())
tok = new StringTokenizer(inp.readLine());
score = Integer.parseInt(tok.nextToken());
while(score != -999)
totalScore = totalScore + score;
numberOfStudents++;
if(!tok.hasMoreTokens())
tok = new StringTokenizer(inp.readLine());
score = Integer.parseInt(tok.nextToken());
}//end while
courseAvg.setNum(totalScore / numberOfStudents);
}//end calculate Average
public static void printResult(PrintWriter outp,
String courseId,
int groupNo, DoubleClass avg)
DecimalFormat twoDecimal =
new DecimalFormat("0.00");
if(groupNo == 1)
outp.print(" " + courseId + " ");
else
outp.print(" ");
outp.println("\t" + groupNo + "\t "
+ twoDecimal.format(avg.getNum()));
So my adaptation turned out like this:
//Program: Compute individual and class averages from input file.
import java.io.*;
import java.util.*;
public class Exams
public static void main (String[] args)
throws FileNotFoundException
//Step 1
String nameId; //student name ID for list
int numberOfStudents;
DoubleClass avg = new DoubleClass(); //average for a student
//in list
double avgList; //average for list
//Step 2 Open the input and output files
Scanner group1 = new Scanner(new FileReader("c:\\list.txt"));
PrintWriter outfile = new PrintWriter("c:\\student.out");
avgList = 0.0; //Step 3
numberOfStudents = 0; //Step 5
//print heading: Step 6
outfile.println("NameID List Student Average");
calculateAverage(list, avg); //Step 7d.i
printResult(outfile,nameID, avg); //Step 7d.iii
avgList = avgList + avgList.getNum(); //Step 7d.v
outfile.println();
numberOfStudents++; //Step 7d.vii
outfile.printf("Avg for List: %.2f %n",
(avgList / numberOfStudents));
public static void calculateAverage(Scanner inp,
DoubleClass courseAvg)
double totalScore = 0.0;
int numberOfStudents = 0;
int score = 0;
score = inp.nextInt();
courseAvg.setNum(totalScore / numberOfStudents);
}//end calculate Average
public static void printResult(PrintWriter outp,
String nameId,
int groupNo, DoubleClass avg)
if (list == list)
outp.print(" " + nameId + " ");
else
outp.print(" ");
outp.printf("%9d %15.2f%n", list, avg.getNum());
I guess I was trying to find a shortcut that ended up being a long cut. Here's the algorithm I wrote.
Algorithm
1.) Initialize the variables
2.) Get the student name and his/her accompanying 6 exam scores, limiting the number of scores to 6.
3a.) Calculate score of 6 exams for each student using void method called CalculateAverage.
3b.) Use a loop inside the method to read and sum the six scores.
4.) Use value-returning method CalculateGrade to determine and return each student's grade.
5.) Output each student's grade in void main.
6.) Calculate the average score for all students
7.) Output entire class average
And now I'm trying to piece together code to match each step of the algorithm starting from scratch.
So I got the code for outputting each students grade in void:
public static void printGrade(double testScore)
System.out.print("Line 10: Your grade for "
+ "the course is ");
if (testScore >= 90)
System.out.println("A");
else if (testScore >= 80)
System.out.println("B");
else if (testScore >= 70)
System.out.println("C");
else if (testScore >= 60)
System.out.println("D");
else
System.out.println("F");
This code can read the the file with the scores:
Scanner inFile =
new Scanner(new FileReader("a:\\studentlist.txt"));
PrintWriter outFile =
new PrintWriter("a:\\avg.out");
courseGrade = inFile.nextDouble();
studentName=inFile.nextChar();
while (inFile.hasNext())
studentName= inFile.next().charAt(0);
courseGrade= inFile.nextDouble();
I'm just trying to piece this thing together. Any tips would be appreciated. I will return with more pieces to the puzzle soon. As you can tell it's all kind of disorganized, and scatterbrained. Just trying to find some simplification or distillation, or recommendations.
WR

Hello,
Thanks for your reply. So I take it you are more familiar with Object Oriented Programming more than Procedural Based Programming?
Well the teacher insisted I follow the algorithm instead of trying to adapt another program to the problem. But sometimes that approach saves time I've noticed since many of the code examples we study in Java are like 'the golden oldies'.
The student gradebook problem is repeated over and over in different forms. Maybe if I just approached the problem more linearly:
Algorithm
1.) Initialize the variables
String studentId
int numberOfStudents
DoubleClass avg = new DoubleClass(); //average for a student
double avgGroup: //average for all students2.) Get the student name and his/her accompanying 6 exam scores.
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3a.) Calculate score of 6 exams for each student using void method called CalculateAverage using a loop to read and sum the six scores. The loop must be inside the method. It does not output the average score. The sum and average must be returned and output in void main.
method calculateAverage
double totalScore //to store the sum of all the scores of each student
int numberOfExams; //to store the number of
int score; //to read and store a course score
double totalScore = 0.0
int numberOfExams = 0;
int score = 0;3b.) Use a loop inside the method to read and sum the six scores.
Using psuedocode (since the variables have been declared and initialized)
i)get the next student score
RIght here my approach of adapting another program to my new program becomes problematic
the pseudocode here is:
ii) while (score != -999):
I.) update totalScore by adding course score read in step i.
II.) increment numberOfExams by 1
III.) Get the nex student score
iii) studentAvg.setNum(totalScore / numberOfExams);
*What is the purpose of the statement while (score != -999)?*
I don't see why they picked -999? Will this loop allow me to read an endless number of student names and theri accompanying number of exams and then find the average for each student?
I'll go into the next algorithmic steps later.
4.) Use value-returning method CalculateGrade to determine and return each student's grade.
5.) Output each student's grade in void main.
6.) Calculate the average score for all students
7.) Output entire class average
Thanks ahead of time for any suggestions, tips.

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How about this simple solution? Array of a ring control to Array of string.
/Y
Message Edited by Yamaeda on 04-13-2010 08:36 AM
LabVIEW 8.2 - 2014
"Only dead fish swim downstream" - "My life for Kudos!" - "Dumb people repeat old mistakes - smart ones create new ones."
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CHAR lpszDeviceName, LONG lenDeviceName,
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return ERROR_INV_PARAMETER;
if (lpDeviceList[i].pDeviceName)
WideCharToMultiByte(CP_ACP, 0,
pDeviceList[i].pDeviceName, -1,
lpszDeviceName, lenDeviceName,
NULL, NULL);
if (lpDeviceList[i].pDeviceName)
WideCharToMultiByte(CP_ACP, 0,
pDeviceList[i].pDeviceDescription, -1,
lpszDeviceDesc, lenDeviceDesc,
NULL, NULL);
return NO_ERROR;
Pass the int32 you got from the first parameter of the previous call as
a simple int32 passed by value to this function (and make sure you don't
call this function with a higher index than (plItems - 1) returned from
the first function.
Rolf Kalbermatter
Rolf Kalbermatter
CIT Engineering Netherlands
a division of Test & Measurement Solutions

Compare a string and a binary value

Hi!
I would like to compare two passwords encoded into two different's LDAP directory.
For these two directories, I have not the same libraries, so that the encoded value of the first password returned is a String, and the second one is a binary.
Could you tell me if it is possible to compare them?
Thanks a lot!
Best regards

Hi dwg,
in LDAP directories, there is no encryption. There is
hash coding.
The same method of hashcoding is used in the two
directories, but we do not have (and we cannot)
decode the data.
We only have to compare the two hashcoded values.
About the "binary", you are right. It is a byte
array.
How about this function:
equals (<string parameter>, new String(<array
parameter>, "UTF8"))
do you think it is OK?
Thanks for your help!So you have a hashcode from one directory, and a plaintext String from the other? In that case you have to hash the plain String and then compare the two hashes. You can't turn a hash back into a String, which you seemed to point out when you said "but we do not have (and we cannot) decode the data."

Calling Stored function and showing returned value on the UI screen

I am calling a stored function by using the following steps mentioned as per the below link. The stored function returns a single scalar value
http://download.oracle.com/docs/cd/E1790401/web.1111/b31974/bcadvgen.htm#sm0297_
Please verify if I am putting the code in the classes as required by the ADF framework.
* 1) In class CustomApplicationModuleImpl extends ApplicationModuleImpl*
// Some constants
public static int NUMBER = Types.NUMERIC;
public static int DATE = Types.DATE;
public static int VARCHAR2 = Types.VARCHAR;
protected Object callStoredFunction(int sqlReturnType, String stmt,
Object[] bindVars) {
CallableStatement st = null;
try {
// 1. Create a JDBC CallabledStatement
st = getDBTransaction().createCallableStatement(
"begin ? := "+stmt+";end;",0);
// 2. Register the first bind variable for the return value
st.registerOutParameter(1, sqlReturnType);
if (bindVars != null) {
// 3. Loop over values for the bind variables passed in, if any
for (int z = 0; z < bindVars.length; z++) {
// 4. Set the value of user-supplied bind vars in the stmt
st.setObject(z + 2, bindVars[z]);
// 5. Set the value of user-supplied bind vars in the stmt
st.executeUpdate();
// 6. Return the value of the first bind variable
return st.getObject(1);
catch (SQLException e) {
throw new JboException(e);
finally {
if (st != null) {
try {
// 7. Close the statement
st.close();
catch (SQLException e) {}
With a helper method like this in place, calling the func_with_no_args procedure shown in Example 37-7 would look like this:
*2) In class CustomServiceImpl extends CustomApplicationModuleImpl*
public String callEnvironmentName(){
return (String) callStoredFunction(VARCHAR2, "CAR_UTIL_PK.get_environment_name()", new Object[] {});
3) If I have the first two steps correct, I was to display the value returned by method callEnvironmentName() with scalar values like (Development, Production etc) at the footer of each JSFX page. What is the flow I should follow, should I call callEnvironmentName() from some managed bean? Also I want to store it once on first call to some application variable and use that to populate the JSFX pages. Is there a working example. What is the best practice?
Thanks
Edited by: user5108636 on Apr 5, 2011 11:58 PM

Hi John,
Duplicate alerts are coming for BP_Confirmed as well as one custom event. Earlier I thought there is some issue with my custom event, but when it came for BP_Confirmed also, then i have a doubt something is wrong with the application.
I have also checked that BP_Confirmed is being raised only once inside the method-BP_CONFIRM of class-cl_crmcmp_b_cucobupa_impl.
raise event BPConfirmed
CLASS cl_crm_ic_services DEFINITION LOAD.
CREATE OBJECT event.
event->set_name( if_crm_ic_events_con=>gc_bpconfirmed ).
event_srv = cl_crm_ic_services=>get_event_srv_instance( ).
event_srv->raise( event ).
Are you aware of any other place from where this event is getting triggered?
Thanks for your help!
Regards,
Rohit

Bug? Picture Ring proprty String and Values" returns error 1054 in LV 8.5

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