Building big XML file from scratch - Urgent

Oracle 8.1.7.3 on windows NT platform
What is the best way to generate a quiet big XML file from multiple tables ?
I have information stored in many relational tables from which I need to generate a XML flat file either stored in a CLOB field or in a text file in a system directory. This XML file will be then used
as an input to generate a report either in HTML using XSLT, or in a PDF file using apache-fop or in a MS Excel file using SoftArtisan ExcelWriter.
My XML file has many levels in it structure, I mean that it is composed of one root element with 2 children, each children has a 3 children. One on these 3 children has 2 children and so on. Actually there are more or less 10 nested levels.
To generate this XML file, I tried to use XSU for PL/SQL with the nested cursor() feature plus XSLT to transform the raw XML file to my requirements.
But obviously there are some limitations using this method. Particularly, if the inner cursor returns an empty set I get exhausted resultset java error... A TAR confirmed that limitation.
So I had to give up this method to use basic nested PL/SQL cursors. Each fetched row is then inserted into a table (varchar2) with a sequence number so that with a cursor like select xml_chunk from my_table order by sequence, I get the whole XML file that I save either in a flat file or in a CLOB (using append method).
This method works fine, but it takes time and it's not flexible at all as I have to construct each XML tag. I guest this way of proceeding is not the more efficient...
Using DOM method won't be better as I still need PL/SQL cursor to select each level of my XML structure and in addition I might for sure encounter a problem of memory.
So what solutions would you suggest to generate this XML file. It must be quiet fast. The XML file can be up to 2Mo big. My system is actually a kind of on-the-fly reports generation. I mean that the XML file needs to be created with up-to-date data many times during the working hours !
Quick answers or suggestions would be greatly appreciated. It's very urgent !!
Thanks

I looks like the best way is to using the SAX processing for your application? Do you know the DTD or XML schema of your output XML document?
Would you send me the sample code for the method "to use XSU for PL/SQL with the nested cursor() feature plus XSLT to transform the raw XML file" to reproduce the problem?

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    >
    > David
    >

  • Load XML file from different location?

    Hi All,
    I've been going through an exercise by Karl Matthews to load XML data into an AIR App:
    http://www.adobe.com/devnet/air/flex/articles/xml_viewer_on_air.html
    but I would like to change where the XML file used in the project is retrieved from.
    Currently the XML file is loaded from here:
    <!-- Set up the HTTP service from where we get the source XML data -->
    <mx:HTTPService id="srcData" url="
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    but I would like to load the XML file from one of these locations instead:
    File.userDirectory:
    File.documentsDirectory:
    Can someone please show me how I should change the above code to accomplish this, as my efforts to date have not been successful :-(
    I am using Flex Builder 3 and Air 1.5.
    Thanks heaps!
    Tim

    Hi Bhasker,
    Thank you for replying.
    I am not very good at all this coding, but I am assuming I should now be doing entering the following:
    =======================
    <?xml version="1.0" encoding="utf-8"?>
    <mx:WindowedApplication 
    xmlns:mx="http://www.adobe.com/2006/mxml" layout="vertical"width="
    800" height="660"xmlns:comp="
    *" xmlns:fmtComp="fmtComps.*"creationComplete="srcData.send()"
    paddingLeft="
    0" paddingRight="0" paddingTop="0" paddingBottom="0">
    <mx:Script>
    <![CDATA[
    import mx.utils.ObjectProxy; 
    import mx.rpc.events.ResultEvent; 
    Bindable] 
    private var userManualObj:ObjectProxy; 
    private function loadModelData(event:ResultEvent):void
    userManualObj=event.result.UserManual;
    private function readXMLContent(xmlFile:File,objContentView:Object):Array{
    var reportDir:File = File.userDirectory.resolvePath("assets"); 
    var xmlFile:File; 
    var fileStream:FileStream = new FileStream(); xmlFile = reportDir.resolvePath(
    "UserGuide.xml"); 
    if(xmlFile.exists && xmlFile.size > 0)// Checking if the impressions.xml file already exists and the file is not empty
    var stream:FileStream = new FileStream(); 
    var xml:XML = new XML();stream.open(xmlFile, FileMode.READ);
    xml = XML(stream.readUTFBytes(stream.bytesAvailable));
    stream.close();
    ]]>
    </mx:Script>
    <!-- Set up the HTTP service from where we get the source XML data<mx:HTTPService id="srcData"
    url="assets/UserGuide.xml"
    result="loadModelData(event)"/> -->
    <mx:VBox width="100%" horizontalAlign="left" height="100%" paddingBottom="
    0" paddingLeft="0" paddingRight="0" paddingTop="0">
    <mx:TabNavigator width="100%" height="100%"paddingBottom="
    0" paddingLeft="0" paddingRight="0" paddingTop="0">
    <mx:Repeater id="modelsRep" dataProvider="{userManualObj.Product.Model}">
    <mx:VBox label="{modelsRep.currentItem.Name}" width="100%" height="100%">
    <comp:ModelDesc model="{modelsRep.currentItem}"/>  
    </mx:VBox>
    </mx:Repeater>
    <mx:VBox label="Troubleshooting" width="100%" height="100%"paddingBottom="
    0" paddingLeft="0" paddingRight="0" paddingTop="0">
    <comp:Troubleshooting issues="{userManualObj.Product.Troubleshooting.Issue}" />
    </mx:VBox>
    </mx:TabNavigator>
    </mx:VBox></mx:WindowedApplication>
    =======================
    and create and "assets" folder in my user directory placing the XML file in there?
    However when I do all that, I get this error when I try to compile:
      Encountered errors or warnings while building project main.mxml.
        main.mxml: Function does not return a value.
    Any thoughts?
    Many thanks,
    Tim

  • How to Generate XML File from Java Code.

    I want to generate the xml file from the java code.
    Could you plz suggest any webSite address with example?

    Here is the code
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    import javax.xml.parsers.DocumentBuilderFactory;
    import javax.xml.parsers.FactoryConfigurationError;
    import javax.xml.parsers.ParserConfigurationException;
    import javax.xml.transform.Transformer;
    import javax.xml.transform.TransformerConfigurationException;
    import javax.xml.transform.TransformerException;
    import javax.xml.transform.TransformerFactory;
    import javax.xml.transform.dom.DOMSource;
    import javax.xml.transform.stream.StreamResult;
    import org.w3c.dom.Document;
    import org.w3c.dom.Element;
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         public void saveDocument(Document document){
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                   System.out.println("XML Created !!");
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  • Help with creating a new XML file from an existing DOM tree!!

    i want to create a new XML file from an existing DOM tree
    i used this code to create a new document:
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    Cross-post: http://forum.java.sun.com/thread.jspa?threadID=784467&messageID=4459240#4459240

  • Re-Using XML file from decode barcode + extract xml process

    I was hoping someone could put me in the right direction here. I am decodeing the information stored in a 2D Bar code and sending this information to an XML file, then I am trying to combine that xml file with a blank PDF template but the process is failing beacuse there are some additional tag fields the XML data from the  Decode->Extract XML process.
    The XML file from the decode process gives the structure below..notice therer some extra tags (lines 2- 4)
    <?xml version="1.0" encoding="UTF-8"?>
    <xdp:xdp xmlns:xdp="http://ns.adobe.com/xdp/" xmlns:xfa="http://www.xfa.org/schema/xfa-data/1.0/">
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    <?xml version="1.0" encoding="UTF-8"?>
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    So the xml output of the Decode barcode + Extract XML process has three extra lines of tag. Is there a way I could use a process within liveCycle to clean out those three lines in real-time before sending the xml to be recombined with the PDF template.
    Thanks

    Hi,
    What you may do is to use the SetValue and its xpath builder functions to "serialize" the xml into string, "substring" to remove the extra tags, and "concat" to add the extra tags and then "deserialize" it again to an xml to be merged with your form.
    Greetings,
    Yasser

  • Can I load xml file from SWC without using @embed

    I'm developing a mobile application in which I need to load xml files from File.applicationDirectory. This works great if the xml files are part of the main application swf. But I would like to move these xml files into a SWC so they could be shared across multiple applications.
    Using FlashBuilder 4.5, when a SWC is built, I can specify files to embed in the library that are not assets (Assets Tab of Flex Library Build Path). For various design reasons, I do NOT want to embed the xml files via @embed.
    When the swc is built and I open it up using a zip utility, I see the xml files in there just fine. So they are being bundled with the SWC. But how can I load these files in my main application that does not involve using @embed? When the main application is built, the swc setting for link type is "merged into code".
    I wouldn't expect the application to automatically pull out the xml files from the swc and place them in the File.applicationDirectory on the mobile device. I've tried loading from there just in case but file.exists is false (as expected).
    I've searched the web (and continue to do so) and all the answers seem to be to use @embed. Is there another way?
    Randy

    It's actually a lot easier than you think.
    Just reference the file like any'ol URL using a path relative to the SWC's src directory.
    So if you include the file "assets/xml/some.xml", just use that same string like you would any remote resource.
    For example:
    var loader:URLLoader = new URLLoader( new URLRequest("assets/xml/some.xml"));
    I believe it would also work like this "/assets/xml/some.xml", but I prefer relative paths so the link doesnt break if moved out of the SWC...

  • Error parsing XML file from a HttpServletRequest using JAXP

    Hi,
    I am trying to generate an XML file from an HttpServletRequest. I am actually using file uploading method in JSP to send the XML file. I think the parser isnt able to correctly identify the XML file from the message body and hence it is giving some strange error messages. Has anyone of u managed to solve this problem ?
    Code snippet:
    //now build an XML document from the requested input stream
    InputStream in = myRequest.getInputStream();
    try {
    myDocRequest = myParser.parse(in);
    } catch (Throwable t) {
    throw new Exception("Could not build document",t);
    Error message is:
    [Fatal Error] :1:1: Content is not allowed in prolog.
    java.lang.Exception: Could not build document
    at XMLUtil.<init>(XMLUtil.java:91)
    at WCS.doPost(WCS.java:44)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:252)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:173)
    at org.netbeans.modules.web.monitor.server.MonitorFilter.doFilter(MonitorFilter.java:362)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:202)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:173)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:214)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:178)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:126)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:105)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:107)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:148)
    at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:825)
    at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.processConnection(Http11Protocol.java:738)
    at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:526)
    at org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:80)
    at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:684)
    at java.lang.Thread.run(Thread.java:534)
    Caused by: org.xml.sax.SAXParseException: Content is not allowed in prolog.
    at org.apache.xerces.parsers.DOMParser.parse(Unknown Source)
    at org.apache.xerces.jaxp.DocumentBuilderImpl.parse(Unknown Source)
    at javax.xml.parsers.DocumentBuilder.parse(Unknown Source)
    at XMLUtil.<init>(XMLUtil.java:89)
    ... 20 more
    Actually if i just print out the message, it gives something like this:
    -----------------------------7d63dc71b06b2
    Content-Disposition: form-data; name="W"; filename="C:\work_projects\Capas.xml"
    Content-Type: text/xml
    <?xml version="1.0" encoding="UTF-8"?>
    <GetCapabilities version="1.0.0" service="wcs">
    <section>/WCS_Capabilities/Capability</section>
    </GetCapabilities>
    -----------------------------7d63dc71b06b2--
    Cheers.

    The ServletInput stream contains this:
    -----------------------------7d63dc71b06b2
    Content-Disposition: form-data; name="W"; filename="C:\work_projects\Capas.xml"
    Content-Type: text/xml
    <?xml version="1.0" encoding="UTF-8"?>
    i.e., its the HTTP File Upload MIME stuff, followed by the XML. You need to wrap around the input stream something that can decode the HTTP MIME stuff and let you get at the XML itself, i.e., something like: com.orielly.servlet.multipart.MultipartParser (Apache has a similar 'file upload servlet).
    Jeremy

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