Error parsing XML file from a HttpServletRequest using JAXP

Hi,
I am trying to generate an XML file from an HttpServletRequest. I am actually using file uploading method in JSP to send the XML file. I think the parser isnt able to correctly identify the XML file from the message body and hence it is giving some strange error messages. Has anyone of u managed to solve this problem ?
Code snippet:
//now build an XML document from the requested input stream
InputStream in = myRequest.getInputStream();
try {
myDocRequest = myParser.parse(in);
} catch (Throwable t) {
throw new Exception("Could not build document",t);
Error message is:
[Fatal Error] :1:1: Content is not allowed in prolog.
java.lang.Exception: Could not build document
at XMLUtil.<init>(XMLUtil.java:91)
at WCS.doPost(WCS.java:44)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:252)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:173)
at org.netbeans.modules.web.monitor.server.MonitorFilter.doFilter(MonitorFilter.java:362)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:202)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:173)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:214)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:178)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:126)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:105)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:107)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:148)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:825)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.processConnection(Http11Protocol.java:738)
at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:526)
at org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:80)
at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:684)
at java.lang.Thread.run(Thread.java:534)
Caused by: org.xml.sax.SAXParseException: Content is not allowed in prolog.
at org.apache.xerces.parsers.DOMParser.parse(Unknown Source)
at org.apache.xerces.jaxp.DocumentBuilderImpl.parse(Unknown Source)
at javax.xml.parsers.DocumentBuilder.parse(Unknown Source)
at XMLUtil.<init>(XMLUtil.java:89)
... 20 more
Actually if i just print out the message, it gives something like this:
-----------------------------7d63dc71b06b2
Content-Disposition: form-data; name="W"; filename="C:\work_projects\Capas.xml"
Content-Type: text/xml
<?xml version="1.0" encoding="UTF-8"?>
<GetCapabilities version="1.0.0" service="wcs">
<section>/WCS_Capabilities/Capability</section>
</GetCapabilities>
-----------------------------7d63dc71b06b2--
Cheers.

The ServletInput stream contains this:
-----------------------------7d63dc71b06b2
Content-Disposition: form-data; name="W"; filename="C:\work_projects\Capas.xml"
Content-Type: text/xml
<?xml version="1.0" encoding="UTF-8"?>
i.e., its the HTTP File Upload MIME stuff, followed by the XML. You need to wrap around the input stream something that can decode the HTTP MIME stuff and let you get at the XML itself, i.e., something like: com.orielly.servlet.multipart.MultipartParser (Apache has a similar 'file upload servlet).
Jeremy

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