Bypassing function argument without changing default value

Question

Hi there
I’m having some problems understanding how I can bypass function arguments without changing its default value. Here are some examples:
 function myFunction ( arg1:Boolean, arg2:String="default string", arg3:Number=3 ):Array
    return new Array (arg1, arg2, arg3);
trace(myFunction(true, "new string", 5));
// true,new string,5
trace(myFunction(true, undefined, 5));
// true,,5
trace(myFunction(true, null, 5));
// true,,5
trace(myFunction(true));
// true,default string,3
trace(myFunction(true, null));
// true,,3
My question is: Shouldn't I be able to call a function bypass the second argument (that has a default value), change third argument and on result second argument maintains its default value?
Example:
trace(myFunction(true, null, 5));
// not desired: true,,5
// desired: true,default string,5
I know that applying a defult value to the argument allows one to bypass it. But it will always be redefined or to null or to undefined. At the moment I only see one solution.
function myFunction ( arg1:Boolean, arg2:String="default string", arg3:Number=3 ):Array
     if (!arg2)arg2 = "deafult string";
     return new Array (arg1, arg2, arg3);
It just seems like too much code repeated
Regards

Answer 1

Hi dmennenoh,
Yup, this was just an example to show that the use of a default value only helps you to bypass the need to simulate a MouseEvent Object for an onRollOver MouseEvent argument. Other than that you can never bypass it without changing its value. You must always apply a null or undefined value and work with that.
Thanks anyway