Can any body tell me why this program works?!! It shouldn't work!

Question

I wrote this program in a different long way, but it worked...I got the code i just posted below, it works well as well, but i dont know how this works. It seems more effeciant as well.....Q:
Write a program to read lines of text containing names and print each on a separate line.
Eliminate duplicate names.
Input lines may contain any number of names.
import java.util.Scanner;
public class Tut1P3 {
     //Write a program to read lines of text containing names and print each on a separate line.
     //Eliminate duplicate names.
     //Input lines may contain any number of names.
     public static void main(String args[]) {
         Scanner sc = new Scanner(System.in);
         String a[] = new String[ 1000 ];     // string to hold up to 1000 names        
         int i,     // loop control variable
         n = 0;      // number of names in array so far
                    //how hasNext works in memory?
         while ( sc.hasNext() ) {     //reads the next name
                String next = sc.next();
                for(i = n-1; i >= 0; i--){
                     System.out.println(a);
          if ( a[i].equals(next) ) //we have nothing in the array! it checks nothing!
               break;
          if ( i < 0 ){
               //this part doesn't make sense. Any quick help please..
               System.out.println( a[ n++ ] = next );

Answer 1

The line in question can be split up into 3 different lines.
a[n] = next;
System.out.println(a[n]);
n++;