Can't open the Zipped file

Question

Hi
I am making a zip file using GZIPOutputStream. But I am not able to open the zip file that is created using win zip.The size of the zipped file is 81 KB and the input file is 3,245 KB.I have closed all the streams still I am not able to figure out the problem.Any idea where I am going wrong ? Any help would be greatly appreciated.
Here my code goes:
import java.util.zip.*;
import java.io.*;
public class ZipFile
     public static void main(String[] args) throws FileNotFoundException,IOException
          ZipFile("D:\\Java\\Test\\INPUTXML_bkp_1.xml");
     public static String ZipFile(String fileName) throws FileNotFoundException,IOException
          String name = fileName.substring(fileName.lastIndexOf('\\') +1 ,fileName.lastIndexOf('.'));
          String filePath = fileName.substring(0,fileName.indexOf(name));
          String newFileName = new StringBuffer(name).append(".zip").toString();
          FileOutputStream outputStream = new FileOutputStream(newFileName);
          GZIPOutputStream zipOutputStream = new GZIPOutputStream(outputStream);
          FileInputStream inputStream = new FileInputStream(fileName);
          byte[] temp = new byte[10000000];
          int counter = inputStream.read(temp,0,temp.length);
          zipOutputStream.write(temp,0,counter);
          inputStream.close();
          zipOutputStream.finish();
          zipOutputStream.close();
          return newFileName;
Thanks
Ritesh

Answer 1

Thanks for the reply.
I changed my code to look like this:
import java.util.zip.*;
import java.io.*;
public class ZipFile
     public static void main(String[] args) throws FileNotFoundException,IOException
          ZipFile("D:\\Java\\Test\\INPUTXML_bkp_1.xml");
     public static String ZipFile(String fileName) throws FileNotFoundException,IOException
          String name = fileName.substring(fileName.lastIndexOf('\\') +1 ,fileName.lastIndexOf('.'));
          String filePath = fileName.substring(0,fileName.indexOf(name));
          String newFileName = new StringBuffer(name).append(".zip").toString();
          FileOutputStream outputStream = new FileOutputStream(newFileName);
          ZipOutputStream zipOutputStream = new ZipOutputStream(outputStream);
          ZipEntry zipEntry = new ZipEntry(fileName);
          zipOutputStream.putNextEntry(zipEntry);
          zipOutputStream.finish();
          zipOutputStream.close();
          return newFileName;
Now I can atleast open the zip file. But the problem is the size of the file is 0 kb. Probably because, I am not populating the Zip entry. Can u pls let me know how do I do that.
Thanks
Ritesh