Cannot send .zip file

So I'm trying something for Minecraft and I need to send a file that is .zip
I tried to email it to my gmail but here's what it says
Unable to Send Email
A copy has been placed in your outbox. No password provided.
Please go to Mail Account Settings and enter a password.
What do I do? I already entered my password but it still doesn't send and keeps popping up the message above.
Please help me, I'd really appreciate it (by the way I have an iPhone 5c)
-SnowfurandThistleclaw

Since no one has an answer does anyone know where I can find iTunes File Sharing on my PC (computer)?

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How to send zip file as attachment through email

Hi All,
I am having a requirement that I need to download the internal table data into .txt file and I need to zip the text file. And this zip files needs to send to the customer through email.
I am able download the data into .txt and able to zip the file. But I am not able send the .zip file through email.
I know that we can send .xls, .txt, .csv and also .ppt, .doc file types we can send as an attachement through abap program. But I don't know about .zip files. Is there any possibilty to send .zip file as an attachment thorugh email.
Can any one help me how to send a .zip file thorugh email as an attachment.
Regards,
vinod

hi Vinod,
Can you please tell me how you have zipped the file.
I am having a text file in application server. I need to zip that file. Then the middleware moves it to Legacy system.
I used the following code. With this I am having the data in Binary format which my midleware cannot understand.
What I need on the whole is just to reduce the size of the file.
form ZIP_FILE .
DATA: lt_data TYPE TABLE OF x255,
lt_textdata TYPE TABLE OF x255.
DATA: ls_data LIKE LINE OF lt_data.
DATA: lv_dsn1(100) VALUE '/ECD/120/GIS/FTP/IB/DNBPAYDEX.TXT'.
DATA: lv_dsn3(100) VALUE '/ECD/120/GIS/FTP/IB/DNBPAYDEXZIP.zip'.
*DATA: lv_dsn3(100) VALUE '/interfaces/SM5/test.zip'. " Contains sample1.xls and sample2.xls
DATA: lv_file_length TYPE i.
DATA: lv_content TYPE xstring.
DATA: lo_zip TYPE REF TO cl_abap_zip.
CREATE OBJECT lo_zip.
Read the data as a string
clear lv_content .
OPEN DATASET lv_dsn1 FOR INPUT IN BINARY MODE.
READ DATASET lv_dsn1 INTO lv_content .
CLOSE DATASET lv_dsn1.
lo_zip->add( name = 'sample.TXT' content = lv_content ).
lv_content = lo_zip->save( ).
*clear lv_content .
Conver the xstring content to binary
CALL FUNCTION 'SCMS_XSTRING_TO_BINARY'
EXPORTING
buffer = lv_content
IMPORTING
output_length = lv_file_length
TABLES
binary_tab = lt_data.
OPEN DATASET lv_dsn3 FOR OUTPUT IN TEXT MODE ENCODING DEFAULT.
LOOP AT lt_textdata INTO ls_data.
TRANSFER ls_data TO lv_dsn3.
ENDLOOP.
CLOSE DATASET lv_dsn3.
IF sy-subrc EQ '0'.
MESSAGE s999(zfi_ap_gl) WITH text-t10.
ENDIF.
Can you please help.
Thanks Aravind

When I download a page a message says cannot find zip file directory

When I try to download a page a message appears after the download time saying in part that "cannot find zip file directory". This message appears on all downloads I attemp.

Here are typical layouts for the iTunes folders:
If you have upgraded from version 8 (or earlier) to iTunes 9 (or later) at some point, then your media folder (everything inside the red outline) may still be called iTunes Music instead of iTunes Media. The extra Music folder inside the media folder is used if you have allowed iTunes to Upgrade to iTunes Media Organization (iTunes 9) or used File > Library > Organize Library > Reorganize files in the folder "<Media Folder>" (iTunes 10). Depending on your choices for Keep iTunes Media folder organized and Copy files to iTunes Media folder when adding to library plus a little bug in which one build changed the name of the file storing the choice of layout it is quite easy for some of your files to be organized according to one layout and some the other.
It is possible that in the upgrade to Lion iTunes has been installed with the current default options while your library is based on an older structure. Use Get Info. on a missing track, click cancel when asked to locate it and look at the path given on the summary tab. Now look for the actual file with Finder. Post both paths back here and we can try to make sense of the problem.
tt2

Cannot send a file to mobile phone ????

I have connected to my phone and browse the device.
I can get the the files from my phone but cannot send any file to it
What is the problems???? How can i fix it?
My phone is W350i
My mac is 10.4.11
Thanks you
Message was edited by: SM0715

Hi,
I am sorry to tell you that there is no such functionality. But of course, you could send URLs to the document locations via smartSync.
Cheers, Stefan

"Cannot send this file" for conversion/download for Word editing

Cannot send this file is response for conversion/download for Word editing

As you speak to "sending" a file you'd be using one of Adobe's online subscription services.
The "umbrella" user forum for this is at:
https://forums.adobe.com/community/acrobatdotcom
Of course a paid subscription is required.
Note that accessing the online service of interest through Adobe Reader can be bumpy sometimes.
Best is to just go to online and have your browser take you to the service.
A starting point:
https://www.acrobat.com/en_us.html
Select your service and then sign in.
Be well...

Please help!!!!!! i filled out a job application using adobe reader but i cannot send the file back via email because the file is protected with a lock. how do i unlock this file to send it?!!!!!!!!!

please help!!!!!! i filled out a job application using adobe reader but i cannot send the file back via email because the file is protected with a lock. how do i unlock this file to send it?!!!!!!!!!

Hi kevinv1987,
It doesn't sound like the PDF was password protected (or Adobe Reader would prompt you for a password). Instead, it sounds like that file may be marked locked by your operating system. Are you on Mac OS or Windows? In either case, here are instructions for removing the lock icon from the file:
Remove the Lock Icon from a Folder in Windows 7 (check Microsoft's website if you have a different version of Windows)
On Mac OS, select the file in the Finder, and choose File > Get Info. Then, just deselect the Lock checkbox.
Please let us know how it goes.
Best,
Sara

Bypassing SOA MANAGER , Consume a stateless Webservice and send Zip file

Hello,
I have question around consuming web service via ABAP program.The scenario is consume a operation of a web-service and get the information, based on this information put the data in flat files and send it back in another operation of this web-service. Due to way web-service is implemented I cannot generate proxy class and use SOA manager the reason is web-service is using complex data type
1) Is it possible to consume a web-service via ABAP program directly
I have explored the SAP documentation and came up with this link
Appendix C - SOAP Runtime for the SAP Web AS - SAP Library
Few Links I found are
Manual HTTP POST from ABAP
WebService 4.7 / WAS 620 XSTRING BASE 64
Using any of the above approaches can SAP program consume a web-service bypassing the SOA manager & send the zipped files in one of the operations.
Thank you

Appreciate if some one can answer the question above

Cannot extract Zip file with Winzip after zipping with java.util.zip

Hi all,
I write a class for zip and unzip the text files together which can be zip and unzip successfully with Java platform. However, I cannot extract the zip file with Winzip or even WinRAR after zipping with Java platform.
Please help to comment, thanks~
Below is the code:
=====================================================================
package myapp.util;
import java.io.* ;
import java.util.TreeMap ;
import java.util.zip.* ;
import myapp.exception.UserException ;
public class CompressionUtil {
public CompressionUtil() {
    super() ;
public void createZip(String zipName, String fileName)
      throws ZipException, FileNotFoundException, IOException, UserException {
    FileOutputStream fos = null ;
    BufferedOutputStream bos = null ;
    ZipOutputStream zos = null ;
    File file = null ;
    try {
      file = new File(zipName) ; //new zip file
      if (file.isDirectory()) //check if it is a directory
     throw new UserException("Invalid zip file ["+zipName+"]") ;
      if (file.exists() && !file.canWrite()) //check if it is readonly
     throw new UserException("Zip file is ReadOnly ["+zipName+"]") ;
      if (file.exists()) //overwrite the existing file
     file.delete();
      file.createNewFile();
      //instantiate the ZipOutputStream
      fos = new FileOutputStream(file) ;
      bos = new BufferedOutputStream(fos) ;
      zos = new ZipOutputStream(bos) ;
      this.writeZipFileEntry(zos, fileName); //call to write the file into the zip
      zos.finish() ;
    catch (ZipException ze) {
      throw ze ;
    catch (FileNotFoundException fnfe) {
      throw fnfe ;
    catch (IOException ioe) {
      throw ioe ;
    catch (UserException ue) {
      throw ue ;
    finally {
      //close all the stream and file
      if (fos != null)
     fos.close() ;
      if (bos != null)
     bos.close();
      if (zos != null)
     zos.close();
      if (file != null)
     file = null ;
    }//end of try-catch-finally
private void writeZipFileEntry(ZipOutputStream zos, String fileName)
      throws ZipException, FileNotFoundException, IOException, UserException {
    BufferedInputStream bis = null ;
    File file = null ;
    ZipEntry zentry = null ;
    byte[] bArray = null ;
    try {
      file = new File(fileName) ; //instantiate the file
      if (!file.exists()) //check if the file is not exist
     throw new UserException("No such file ["+fileName+"]") ;
      if (file.isDirectory()) //check if the file is a directory
     throw new UserException("Invalid file ["+fileName+"]") ;
      //instantiate the BufferedInputStream
      bis = new BufferedInputStream(new FileInputStream(file)) ;
      //Get the content of the file and put into the byte[]
      int size = (int) file.length();
      if (size == -1)
     throw new UserException("Cannot determine the file size [" +fileName + "]");
      bArray = new byte[(int) size];
      int rb = 0;
      int chunk = 0;
      while (((int) size - rb) > 0) {
     chunk = bis.read(bArray, rb, (int) size - rb);
     if (chunk == -1)
       break;
     rb += chunk;
      }//end of while (((int)size - rb) > 0)
      //instantiate the CRC32
      CRC32 crc = new CRC32() ;
      crc.update(bArray, 0, size);
      //instantiate the ZipEntry
      zentry = new ZipEntry(fileName) ;
      zentry.setMethod(ZipEntry.STORED) ;
      zentry.setSize(size);
      zentry.setCrc(crc.getValue());
      //write all the info to the ZipOutputStream
      zos.putNextEntry(zentry);
      zos.write(bArray, 0, size);
      zos.closeEntry();
    catch (ZipException ze) {
      throw ze ;
    catch (FileNotFoundException fnfe) {
      throw fnfe ;
    catch (IOException ioe) {
      throw ioe ;
    catch (UserException ue) {
      throw ue ;
    finally {
      //close all the stream and file
      if (bis != null)
     bis.close();
      if (file != null)
     file = null ;
    }//end of try-catch-finally
}

Tried~
The problem is still here~ >___<
Anyway, thanks for information sharing~
The message is:
Cannot open file: it does not appear to be a valid archive.
If you downloaded this file, try downloading the file again.
The problem may be here:
if (fos != null)
fos.close() ;
if (bos != null)
bos.close();
if (zos != null)
zos.close();
if (file != null)
file = null ;
The fos is closed before bos so the last buffer is not
saved.
zos.close() is enough.

How to send Zip files as attachments !! Very urgent, Please help!

I am sending PDF files as attachments using java mail (it works fine). But now my requirement is to zip the PDFs and send them as attachments instead of actual PDF's. But i don't know how to achieve that. does java mail API support zip attachment facilities? I have looked in activation API also, but i couldn't find anything helpful. even i searched the forums, but no clue. Please, anybody help me about this, it's very urgent.
thanks
sri

Check the first "if". If I specify an attachment, then a myme multipart doby is created: one for text and the other for the attachemnt I use this myme ovbject only for attachemnts, because some ISPs have problems and report error in email format if the attachemnet is missing and it contains only text and no attachment.
static public void send(String to,
     String from,
     String host,
     String smtpPort,
     String subject,
     String body,
     String fileAttachment,
     String attachmentMimeType,
     String username,
     String password,
     String debug)
throws Exception
     // create some properties and get the default Session
     Properties props = new Properties();
     props.put("mail.smtp.host", host);
     props.put("mail.smtp.port", smtpPort);
     props.put("mail.smtp.timeout","5000");
     props.put("mail.debug", debug);
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     if (username != null && password != null)
          props.put("mail.smtp.auth", "true");
          MyPasswordAuthenticator auth = new MyPasswordAuthenticator(username, password);
          session = Session.getDefaultInstance(props,auth);
     else
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     //session.setDebug(true);
     // create a message
     MimeMessage message = new MimeMessage(session);
     message.setFrom(new InternetAddress(from));
     InternetAddress[] address = InternetAddress.parse(to, false);
     message.setRecipients(Message.RecipientType.TO, address);
     message.setSubject(subject);
     message.setSentDate(new Date());
     // create the message part
     if ( fileAttachment != null && fileAttachment != "NO" )
          MimeBodyPart messageBodyPart = new MimeBodyPart();
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          messageBodyPart.setText(body);
          //Multipart multipart = new MimeMultipart();
          Multipart multipart = new MimeMultipart("alternative");
          multipart.addBodyPart(messageBodyPart);
          // Part two is attachment
          System.out.println("----->fileAttachment DISTINTO de NULL");
          messageBodyPart = new MimeBodyPart();
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          messageBodyPart.setDataHandler( new DataHandler(fds));
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          multipart.addBodyPart(messageBodyPart);
          //EN DESARROLLO el envio de attachment!!
          // Put parts in message
          message.setContent(multipart);
     } else { //Envio es solamente TEXTO
          message.setText(body);
     // send the message
     Transport.send(message);
Regards,
Vladimir

Cannot see zipped files in Windows Explorer

I used the code below to create a zip file. When I use Winzip to open a zip file named test.zip, I can see all the files (a.txt, b.class, etc.) that have been zipped. But, when I double-click on the test.zip in Windows Explorer (Windows XP Professional), I cannot see any of the zipped files.
Can someone give me some pointers?
import java.util.*;
import java.util.zip.*;
import java.io.*;
public class CreateZip
     public CreateZip()
     public void createZipFile(String[] all_array, String zipfilename)
          FileOutputStream pout; // declare a file output object
PrintStream p;
          String file_path = "D:\\Docs\\FedPlanner\\";
try
pout = new FileOutputStream(file_path + "FedPlanner_Zip_log.txt");
p = new PrintStream( pout );
               for (int i = 0; i < all_array.length; i++)
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                    p.println (all_array[i]);
p.close();
catch (Exception e)
System.err.println ("Error writing to file");
          byte[] buf = new byte[1024];
          try
               String outFilename = file_path + zipfilename;
          ZipOutputStream out = new ZipOutputStream(new FileOutputStream(outFilename));
               for (int i=0; i< all_array.length; i++) //
               FileInputStream in = new FileInputStream(file_path + all_array[i]);//filenames
               out.putNextEntry(new ZipEntry(file_path +all_array[i]));//filenames
               int len;
               while ((len = in.read(buf)) > 0)
               out.write(buf, 0, len);
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               in.close();
          out.close();
          catch (IOException e)
               e.printStackTrace();
     public static void main(String args[])
          for(int i=0; i < all_array.length; i++)
               System.out.println("x = " + all_array[i]);
          CreateZip create = new CreateZip();
          create.createZipFile(all_array);

I have never created a zip file using Java . But from what i know about Winzip and Window Explorer, here's my takes on it:
1. Winzip works with severals different compression algorithm 9including their own)
2. Winzip has the ability to display the content of the zip file (if the zip file happens to be one of the compression algorithm they supported....otherwise, it's highly unlikely, winzip can even open the file)
3. Window Explorer does not call Winzip to display the content of Winzip file. rather, Window Explorer has its own utility to look into the Winzip for files and display them. Note: they probably only do this for the popular compression algorith (such as Winzip .zip, probably .tar...but highly doubtful of the one that Java use to make a zip file).
So..it's probably Window Explorer does not supports display that compression algorithm (the one Java use) for a Winzip file.
Example...you created a new format for an image call .mypics
Window Explorer can display a thumb nail for .bmp, .jpeg, and quite a few other
You created an application to display the image. Now..in Window Explorer, when you click on the icon, the thumbnail of the pic is not display...this is because Window Explorer does not have a util to do thumbnail for that format.

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