Cannot set alarm between 2:00 am and 2:59 am

Question

iPhone 4 with iOS 4.3
I cannot set an alarm between 2:00 am and 2:59 am. The alarm actually sets itself as 1:xx am. It's only 11:30 pm eastern as I write this and I'm guessing as the clock ticks over to March 14th this will go away but what the heck?
Guess I should sleep till 3.

Answer 1

The reason you get the exception is right there in the message. You are trying to insert a datetime value that is out of range. The valid SQL Server datetime range is between 1/1/1753 12:00:00 AM and 12/31/9999 11:59:59 PM. If you send in a datetime outside
of this range, you will get the exception you mention.
Now, there is a thing or two to know about this. First off, the .net datetime has a different range than the SQL datetime and ranges from the year 0001 up to year 9999. That means that while the .Net datetime is valid, it might break when you try to send
it to SQL Server.
In order to get around this, you have several options, depending on your preference and how your code is structured.
One idea is to change the datatype in the SQL Server column to datetime2 which has the same range as the .Net datetime.
Another is to catch the exception and handle it in your code after it has occured using a try/catch.
Most likely you want to validate the data BEFORE sending it to SQL Server though, and you can check that your datetime variable is in the valid range by comparing it to the max and min values in SQL Server datetime type using System.Data.SqlTypes.SqlDateTime.MinValue
and .MaxValue respectively. If your variable is outside of these, you can alert the user or whatever you need to do.
(Yet another option is to declare your variable as a System.Data.SqlTypes.SqlDateTime and use that, but I would not go that route, but rather use the native .Net datatypes and validate the range).