Canvas Hierarchy to BitmapData

Question

I'm trying to capture the graphic contents of a hierarchy of Canvases to a BitmapData. I'm using BitmapData.draw and passing it the Canvas that contains the hierarchy. However I am only capturing the contents of the root Canvas's Graphics object. None of the contained objects are showing up in the BitmapData. I am creating a hierarchy of Canvases in order to get graphics effects (drawing with a hierarchy of clipping paths) that I can't do in a single Graphics object. Is there any way to flatten this out to a single bitmap?
David

Answer 1

Hi,
Although I dont understand your problem properly,but still trying to Resolve it.
Below is the code in which I am having a canvas inside canvas and so on.
Then I am capturing the bitmapdata of the outer canvas, and creating a new Image
with that bitmapdata.It is creating the same childeren heerarchy as is in the
oringional Canvas.The code is below.
Main.MXML
<?xml version="1.0" encoding="utf-8"?>
<mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="horizontal">
<mx:Script>
<![CDATA[
import mx.core.UIComponent;
public function CreateBitmapImage() : BitmapData
var bitmapData:BitmapData = getBitmapData( UIComponent( sourceCanvas ) );
targetImage.source = new Bitmap( bitmapData );
return bitmapData;
private function getBitmapData( target : UIComponent ) : BitmapData
var bitmapData : BitmapData = new BitmapData( target.width, target.height,true, 0x00000000);
bitmapData.draw( target );
return bitmapData;
]]>
</mx:Script>
<mx:Canvas id="sourceCanvas" width="500" height="500" backgroundColor="0xFFFFFF">
<mx:Canvas width="400" height="400" backgroundColor="0xFF0000">
<mx:Canvas width="300" height="300" backgroundColor="0x000FF00">
<mx:Canvas width="200" height="200" backgroundColor="0x0000FF"/>
</mx:Canvas>
</mx:Canvas>
</mx:Canvas>
<!--This will be the Image Created by the BitmapData of the 'sourceCanvas'.-->
<mx:Image id="targetImage" creationComplete="CreateBitmapImage()"/>
</mx:Application>
Pls let me know if you have any problem,or i am unable to understand ur problem.
Shardul Singh Bartwal