Capture data from a http request

i am really new learning abap and i just playing around so i looking a way for capture data from a http request giving the request value and submit for respont something like :
put the url "http://www.imdb.com/find?s=all&q=" in some way and way for the data to request by the user
val = 'user_entry'
result =(any_Function)http://www.imdb.com/find?s=all&q=val
write / result.
pd: sorry for my bad english

Welcome to SDN.
If you are saying that you want to read some request from the HTTP page,then you have to do it with BSP instead of ABAP.
Check this link for BSP.
/message/1688265#1688265 [original link is broken]
Regards,
Amit
Reward all helpful replies.

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1. I require to extract the binary data out of a http multipart request,
2. I have a server socket opened up, which can receive connections over tcp( and therefore http.)
3. I will require to read the stream, find out the "request boundary identifier", and then extract the different "request body parts".
4. From there i need to read all of the binary content and put it in a file.
5. I did some implementation to his effect. but i see that the file that i had uploaded initially if its not a text file, gets corrupted.
can you please let me know why is that happening, and a probable solution approach.
please find below the class (with a main method) I have been using to expose a server socket.
package self.services;
import java.io.BufferedReader;
import java.io.ByteArrayOutputStream;
import java.io.FileOutputStream;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.net.ServerSocket;
import java.net.Socket;
public class FileServer {
     public static void main(String[] args) throws Exception {
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               try{
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                    String yourName = null;
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                              continue;
                         if(!postRequest) {
                              System.out.println("NO POST REQ THIS BREAKING FLOW");
                              break;
                         } else {
                              if(currentLine.contains("Content-Type: multipart/form-data; boundary=")) {
                                   System.out.println("found a boundary value header");
                                   dataBoundary = currentLine.substring((currentLine.indexOf("boundary=") + "boundary=".length()), (currentLine.length() -1));
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                                   break;
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                         System.out.println("FileServer.main() dont bother about this" );
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                         PrintWriter pw = new PrintWriter(new OutputStreamWriter(socket.getOutputStream()));
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          String response =
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}{code}
Here is a sample html file which can be used to send multipart requests to the java service.
<html>
     <body>
          <form action="http://localhost:9999" enctype="multipart/form-data" method="POST">
               Enter name :<br/>
               <input type="text" name="yourName"/>
               Enter file :<br/>
               <input type="file" name="sentFile"/>
               <br/>
               <input type="submit" value="Submit"/>
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     </body>
</html>
*Both the form elements are mandatory*
*I hope my requirement is clear. Any help regarding this will be highly appreciated.*
Regards.

MishraC wrote:
1. I require to extract the binary data out of a http multipart request,
2. I have a server socket opened up, which can receive connections over tcp( and therefore http.)
3. I will require to read the stream, find out the "request boundary identifier", and then extract the different "request body parts".
4. From there i need to read all of the binary content and put it in a file.
5. I did some implementation to his effect. but
i see that the file that i had uploaded initially if its not a text file, gets corrupted.
can you please let me know why is that happening,Because you are using a Reader (which translates bytes to chars according to the charset encoding specified).
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