Carriage Return - Regular Expression

Hi guys,
I'm looking for an effective method to speed up the extreme optimization process in my work (finally to not do it manually).
The particulary issue is to find a good regular expression to replace the carriage returns in the source code with nothing.
I searched on the net, and many sources converge on the RegExr tool: http://gskinner.com/RegExr/
I tried to set up an expression to solve my problem but it doesn't work. The expression that was generated by the tool is:
Find: /\r/g Replace: (none)
When i enter the expression in Dreamweaver Find & Replace panel (with regular expression option checked and match case, etc. unchecked), it seems to not produce any valid change on the code.
I'm sure that i'm wrong something.
Anyone have suggestion?
Thanks all for help.

I don't understand the point of this. There's very little to be gained from removing white space from code. And if you do this to JavaScript, you'll very likely break the code.
Safer method, go to Edit > Preferences > Code Format > click on Tag Libraries and define how you want your code formatted. Then apply with Command > Apply Source Formatting.
Nancy O.

Similar Messages

Carriage Return in Expression for Email Address

I have created an SSRS report where one column displays an email address. Since my report is too wide, I need to have the email addresses make two lines where the new line starts at the @ sign. I have this, but its not working.
=Fields!Email.Value +VBCRLF + "@"
I'm not sure how to fix this.

Hi,
hope it helps
=Left("[email protected]",Instr("[email protected]","@")-1) & VBCRLF & Right("[email protected]",Instr("[email protected]","@")+2)
http://gnanadurai.blogspot.in/

Regular Expression. Select Statement. Carriage Return

Oracle 9i
Using SQLPLUS
I've read about regular expression and need some translation/explanation.
I have a large table containing a varchar2 (free text) column. Users may have inserted carriage returns when they entered the data. I need to locate rows that contain carriage returns, select and display them. Later I'll need to update those rows to replace the carriage returns with a space.
Can you assist with syntax. I believe use of a regular expression is required.
Thanks

for single characters like <CR> TRANSLATE() Doh. Never post at the end of a long day.
As the other posters have pointed out, one-for-one single character substitution is normally done with REPLACE(), although TRANSLATE() also works. The more normal role for TRANSLATE() is situations where you want to substitute multiple characters, e.g.
SQL> update <your table> set <your column> = replace (<your column> , chr(13)||chr(10), ' ');This substitutes a space for a carriage return and line feed combination.
Cheers, APC

How can I include a carriage return in a expression

How can I include a carriage return in a expression between text strings eg
Expression 1 = Text1 & text2 & text3 & text4
I need to display it as below
Text1
Text2
Text3
Text4
adjusting the box the size doesn’t work as the text strings are variable lengths

Message Edited by Ryan.S on 01-04-2007 08:17 PM
Ryan Shi
National Instruments
Attachments:
untitled.JPG ‏37 KB

Match Regular Expression not returning submatches.

I am having an issue with Match Regular Expression not returning the appropriate number of submatches. My string is as follows:
DATAM 995000 1.75 0.007 -67.47 24.493 99.072
The spaces are tabs and the length is not fixed so simple string manipulation is out of the question. The regular expression I was trying is as follows:
(?<=\t)[0-9\.\-]*(?=(\t|$))
It successfully returns Whole Match as the first number but no submatches are returned. I've tried simpler expressions which work in Matlab and EditPad Pro such as [0-9.-]* but never got the same answer in Labview.
What is going on?

Here is an image of the VI. The top portion is the input from our Licor 7000. The bottom portion is the bit of code I'm having problems with.
Attachments:
matchregularexpression.jpg ‏336 KB

Cannot get regular expression to return true in String.matches()

Hi,
My String that I'm attempting to match a regular expression against is: value=='ORIG')
My regular expression is: value=='ORIG'\\) The double backslashes are included as a delimiter for ')' which is a regular expression special character
However, when I call the String.matches() method for this regular expression it returns false. Where am I going wrong?
Thanks.

The string doesn't contain what you think it contains, or you made a mistake in your implementation.
public class Bar {
   public static void main(final String... args) {
      final String s = "value=='ORIG')";
      System.out.println(s.matches("value=='ORIG'\\)")); // Prints "true"
}

Convergence and Comm Express missing carriage returns

We have just upgraded our mail sever. We upgraded from Comm suite 5 (mail server 6.3.) on a sparc system to Comm suite 6 update 1 (mail server 7.0 update 1) . We have run into problems with alerts coming from our ERP (Oracle 11.5.9). These alerts are showing as one long line without any carriage returns in UWC and Convergence. The emails look fine in Outlook.
Thanks for any help.
Josh

Coolhands_99 wrote:
We have just upgraded our mail sever. We upgraded from Comm suite 5 (mail server 6.3.) on a sparc system to Comm suite 6 update 1 (mail server 7.0 update 1) . We have run into problems with alerts coming from our ERP (Oracle 11.5.9).
These alerts are showing as one long line without any carriage returns in UWC and Convergence. The emails look fine in Outlook. I know of at least one bug (#6540158 - "javascript error if mailto: link contains encoded newline characters") that was fixed in recent MS6.3 patches and MS7.0 that may be impacting the display of Oracle ERP sourced emails -- it was the display of Oracle ERP source emails that caused the bug to be raised in the first place.
That being said the Oracle ERP emails also had formatting problems which was fixed at the Oracle end.
Please provide a sample of one of the problem emails (the raw *.msg output) that is causing the problem.
Regards,
Shane.

Textarea formatting for carriage returns

Hi all,
I've created a websheet that includes a textarea column and have found that while any text entered in edit mode displays a carriage return, as soon as the data has been entered and the field returns to read-only mode the carriage returns are not retained . . . all of the content is displayed in one continuous string. Is there a way to accomplish this?
Note: Using APEX v4
Thanks.
Edited by: arrowjf on Jan 6, 2012 1:18 PM

* The TextArea control uses UNIX-style line endings, which
means that text data containing Windows-style carriage-return
line-feed (that is, \r\n) formatting for new lines contain extra
line breaks. You can use String.replace() with a regular expression
to convert the text to UNIX-style line endings, as the following
example shows:
private static const windowsCRLF:RegExp = /\r\n/gm;
myTextString = myTextString.replace(windowsCRLF, "\n");
http://www.adobe.com/support/documentation/en/flex/2/releasenotes_flex2_sdk.html

- How do you refer to an HTML carriage return in PHP?

Someone sent me a php script that replaces foul language with
kinder words
in message board postings. I'd like the same script to weed
out carriage
returns, but we can't find the correct syntax for it.
We're using :
$patterns[0] = '/\n\r/';
What's the correct syntax to use in this situation?
Thanks!

"David Powers" <[email protected]> wrote in message
news:[email protected]...
> Reese wrote:
>> "David Powers" <[email protected]> wrote in
message
>>>
>>>$patterns[0] = '/[\n\r]/';
>>>
>>>That searches for either a newline character or a
carriage return.
>>
>> I'm told this will only work in Windows. That Macs
would require a
>> different string. Two, even.
>>
>> Anyone know if this is true?
>
> What you have been told is only partly correct. Windows
uses a carriage
> return followed by a newline character (\r\n). Macs just
use a newline
> character (\n).
>
> The pattern I have given you search for either a newline
character or
> carriage return. So if it's applied in such a way as to
remove all
> instances, it will work on both Windows and Mac. An
alternative pattern
> which would also work on both is this:
>
> $patterns[0] = '/\r?\n/';
>
> It looks for an optional carriage return followed by a
newline character.
> In other words, it still matches if there isn't a
carriage return.
The response of my know-it-all roumanian programmer with an
ego the size of
Texas to that was :
http://www.regular-expressions.info/characters.html
(bottom of the page)
\r\n = windows
\n = Linux (not Mac)
\r = Mac
http://www.regular-expressions.info/optional.html
(tells you what the '?'
does)
(it means that the character before it can be there 0 or 1
times)
\r?\n = \n (Linux) or \r\n (windows)
It leaves out the \r all alone, like added by the Mac.
So, it will not delete the Mac new lines (might delete the
Mac OSX ones
since that one is passed on Linux, but not the older ones.)
Now, you can contradict me all you want and have a busted
code (then you
will say it doesn't work because I made it wrong), or do it
like I told you
and get it working like it should.
To this, I told him I would present this to you for a
rebuttal, but not
before asking him why he used only the '/\r?\n/' model as an
example, and
not the recommended '/[\n\r]/'. Something tells me he has no
idea what [
and ] do in this context, so he's avoiding it altogether --
even though it
may very well solve the problem on its own the way you claim
it does.

Split String value into internal table at Carriage return

Hi All,
I have given a string type context ( text edit box ) to the user to enter the values. The data can have carriage returns also.
My Requirement is that I want to split the data at carriage returns and store it in my tables.
I tired with a constant value of '%CR_LF' as available in CL_ABAP_CHAR_UTILITIES but to no good result.
Can the Experts suggest some solution?/??
Thankx in advance.
Regds,
Srini

Hi Srini,
Have you looked at your string containing the text in the debugger to verify that you really have <CR>+<LF> (i.e. reflecting CL_ABAP_CHAR_UTILITIES=>CR_LF, which should be easily visible when looking at the hex codes of the string)? Maybe it's just a <LF> (i.e. CL_ABAP_CHAR_UTILITIES=>NEWLINE). Might be good to do a REPLACE first using a regular expression for identifying the line feeds and then doing the SPLIT.
Cheers, harald
p.s.: If you still cannot get it to work, provide some more details of what you're doing...

OR ('|') in regular expressions (e.g. split a String into lines)

Which match gets used when you use OR ('|') to specify multiple possible matches in a regex, and there are multiple matches among the supplied patterns? The first one (in the order written) which matches? Or the one which matches the most characters?
To make this concrete, suppose that you want to split a String into lines, where the line delimiters are the same as the [line terminators used by Java regex|http://java.sun.com/javase/6/docs/api/java/util/regex/Pattern.html#lt] :
 A newline (line feed) character ('\n'),
 A carriage-return character followed immediately by a newline character ("\r\n"),
 A standalone carriage-return character ('\r'),
 A next-line character ('\u0085'),
 A line-separator character ('\u2028'), or
 A paragraph-separator character ('\u2029)
This problem has [been considered before|http://forums.sun.com/thread.jspa?forumID=4&threadID=464846] .
If we ignore the idiotic microsoft two char \r\n sequence, then no problem; the Java code would be:
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]");How do we add support for \r\n? If we try
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]|\\r\\n");which pattern of the compound (OR) regex gets used if both match? The
[\\n\\r\\u0085\\u2028\\u2029]or the
\\r\\n?
For instance, if the above code is called when
s = "a\r\nb";and if the first pattern
[\\n\\r\\u0085\\u2028\\u2029]is used for the match when the \r is encountered, then the tokens will be
"a", "", "b"
because there is an empty String between the \r and following \n. On the other hand, if the rule is use the pattern which matches the most characters, then the
\\r\\n
pattern will match that entire \r\n and the tokens will be
"a", "b"
which is what you want.
On my particular box, using jdk 1.6.0_17, if I run this code
String s = "a\r\nb";
String[] lines = s.split("[\\n\\r\\u0085\\u2028\\u2029]|\\r\\n");
System.out.print(lines.length + " lines: ");
for (String line : lines) System.out.print(" \"" + line + "\"");
System.out.println();
if (true) return;the answer that I get is
3 lines: "a" "" "b"So it seems like the first listed pattern is used, if it matches.
Therefore, to get the desired behavior, it seems like I should use
"\\r\\n|[\\n\\r\\u0085\\u2028\\u2029]"instead as the pattern, since that will ensure that the 2 char sequence is first tried for matches. Indeed, if change the above code to use this pattern, it generates the desired output
2 lines: "a" "b"But what has me worried is that I cannot find any documentation concerning this "first pattern of an OR" rule. This means that maybe the Java regex engine could change in the future, which is worrisome.
The only bulletproof way that I know of to do line splitting is the complicated regex
"(?:(?<=\\r)\\n)" + "|" + "(?:\\r(?!\\n))" + "|" + "(?:\\r\\n)" + "|" + "\\u0085" + "|" + "\\u2028" + "|" + "\\u2029"Here, I use negative lookbehind and lookahead in the first two patterns to guarantee that they never match on the end or start of a \r\n, but only on isolated \n and \r chars. Thus, no matter which order the patterns above are applied by the regex engine, it will work correctly. I also used non-capturing groups
(?:X)
to avoid memory wastage (since I am only interested in grouping, and not capturing).
Is the above complicated regex the only reliable way to do line splitting?

bbatman wrote:
Which match gets used when you use OR ('|') to specify multiple possible matches in a regex, and there are multiple matches among the supplied patterns? The first one (in the order written) which matches? Or the one which matches the most characters?
The longest match wins, normally. Except for alternation (or) as can be read from the innocent sentence
The Pattern engine performs traditional NFA-based matching with ordered alternation as occurs in Perl 5.
in the javadocs. More information can be found in Friedl's book, the relevant page of which google books shows at
[http://books.google.de/books?id=GX3w_18-JegC&pg=PA175&lpg=PA175&dq=regular+expression+%22ordered+alternation%22&source=bl&ots=PHqgNmlnM-&sig=OcDjANZKl0VpJY0igVxkQ3LXplg&hl=de&ei=Dcg7S43NIcSi_AbX-83EDQ&sa=X&oi=book_result&ct=result&resnum=1&ved=0CA0Q6AEwAA#v=onepage&q=&f=false|http://books.google.de/books?id=GX3w_18-JegC&pg=PA175&lpg=PA175&dq=regular+expression+%22ordered+alternation%22&source=bl&ots=PHqgNmlnM-&sig=OcDjANZKl0VpJY0igVxkQ3LXplg&hl=de&ei=Dcg7S43NIcSi_AbX-83EDQ&sa=X&oi=book_result&ct=result&resnum=1&ved=0CA0Q6AEwAA#v=onepage&q=&f=false]
If this link does not survive, search google for
regular expression "ordered alternation"
My first hit went right into Friedl's book.
Harald.

Removing new lines and carriage returns

Hi,
SO I am new to regular expressions in java and I want to remove all the new lines and carriage returns from some text, and change them into 
I have tried,
Pattern pat = Pattern.compile("\n");
Matcher mat = pat.matcher(text);
StringBuffer sb = new StringBuffer();
boolean result = mat.find();
while (result){
mat.appendReplacement(sb,"");
result = mat.find();
mat.appendTail(sb);
text=sb.toString();
But it seems to have no effect. Anyone know what I'm doing wrong?
Cheers
Sandra

Hello, i've got the same problem. I want to replace "carriage return" and "new line" from an text file. and i use the replace all function for a String object. The problem is, if i call the replace function like this:
row = row.replaceAll ("\\r", "");
The "carriage return" is replaced, but not with the "" characters, only with nothing.
Lines from my original textfile:
This is an example.
I want to replace.
After replacing with the function call row = row.replaceAll ("\\r", "");
This is an example.I want to replace.
What is wrong. If i insert tab spaces and replace them, everything is fine. it is abug in my Java Version?
I use j2re1.4.2_05
I hope, anybody can help me

Removing Carriage Returns

I have a table with a field that contains data such as this,
and I want to remove all of the carriage returns but I am having
difficultiy. I have tried replacing the chr(13) and the chr(10) but
no such luck. Can anyone help? Thanks!
==== start of code block ====
Part Number: 1307 G9 
Finish Family:
CHROMES 
Finish/Color:
STERLING NICKEL 
Dimensions:
1 1/4 INCH DIAMETER 
Collection:
BRASS & STERLING TRADITIONS 
==== end of code block====

Hi,
For me both database as well as coldfusion worked fine. You
may also please try with small example.
Method 1:
At database side
select
replace(columnname,chr(13)||chr(10),' ') as columnname
from <tablename>
Method 2: Coldfusion
<cfset pageContent = reReplace(pageContent,
chr(10)&chr(13),"", "all" )>
I noticed that the regular expression functions in CF support
the newline character \n Chr(10), carriage return \r Chr(13), and
tab \t Chr(9).
<cfsavecontent variable="data">
here is my
break
</cfsavecontent>
<cfoutput>#ReReplace(data, "\n", " ",
"ALL")#</cfoutput>
Method 3: Coldfusion.
Please go through the below article. Example is mentioned
http://livedocs.macromedia.com/coldfusion/6/CFML_Reference/functions-pt248.htm
Hope this helps. Please try it out.
Satheesh.

"Match Regular Expression" and "Match Pattern" vi's behave differently

Hi,
I have a simple string matching need and by experimenting found that the "Match Regular Expression" and "Match Pattern" vi's behave somewhat differently. I'd assume that the regular expression inputs on both would behave the same. A difference I've discovered is that the "|" character (the "vertical bar" character, commonly used as an "or" operator) is recognized as such in the Match Regular Expression vi, but not in the Match Pattern vi (where it is taken literally). Furthermore, I cannot find any documentation in Help (on-line or in LabVIEW) about the "|" character usage in regular expressions. Is this documented anywhere?
For example, suppose I want to match any of the following 4 words: "The" or "quick" or "brown" or "fox". The regular expression "The|quick|brown|fox" (without the quotes) works for the Match Regular Expression vi but not the Match Pattern vi. Below is a picture of the block diagram and the front panel results:
The Help says that the Match Regular Expression vi performs somewhat slower than the Match Pattern vi, so I started with the latter. But since it doesn't work for me, I'll use the former. But does anyone have any idea of the speed difference? I'd assume it is negligible in such a simple example.
Thanks!
Solved!
Go to Solution.

Yep-
You hit a point that's frustrated me a time or two as well (and incidentally, caused some hair-pulling that I can ill afford)
The hint is in the help file:
for Match regular expression "The Match Regular Expression function gives you more options for matching
strings but performs more slowly than the Match Pattern function....Use regular
expressions in this function to refine searches....
Characters to Find
Regular Expression
VOLTS
VOLTS
A plus sign or a minus sign
[+-]
A sequence of one or more digits
[0-9]+
Zero or more spaces
\s* or * (that is, a space followed by an asterisk)
One or more spaces, tabs, new lines, or carriage returns
[\t \r \n \s]+
One or more characters other than digits
[^0-9]+
The word Level only if it
appears at the beginning of the string
^Level
The word Volts only if it
appears at the end of the string
Volts$
The longest string within parentheses
The first string within parentheses but not containing any
parentheses within it
$[^()]*$
A left bracket
A right bracket
cat, cag, cot, cog, dat, dag, dot, and dag
[cd][ao][tg]
cat or dog
cat|dog
dog, cat
dog, cat cat dog,cat
cat cat dog, and so on
((cat )*dog)
One or more of the letter a
followed by a space and the same number of the letter a, that is, a a, aa aa, aaa aaa, and so
on
(a+) \1
For Match Pattern "This function is similar to the Search and Replace
Pattern VI. The Match Pattern function gives you fewer options for matching
strings but performs more quickly than the Match Regular Expression
function. For example, the Match Pattern function does not support the
parenthesis or vertical bar (|) characters.
Characters to Find
Regular Expression
VOLTS
VOLTS
All uppercase and lowercase versions of volts, that is, VOLTS, Volts, volts, and so on
[Vv][Oo][Ll][Tt][Ss]
A space, a plus sign, or a minus sign
[+-]
A sequence of one or more digits
[0-9]+
Zero or more spaces
\s* or * (that is, a space followed by an asterisk)
One or more spaces, tabs, new lines, or carriage returns
[\t \r \n \s]+
One or more characters other than digits
[~0-9]+
The word Level only if it begins
at the offset position in the string
^Level
The word Volts only if it
appears at the end of the string
Volts$
The longest string within parentheses
The longest string within parentheses but not containing any
parentheses within it
([~()]*)
A left bracket
A right bracket
cat, dog, cot, dot, cog, and so on.
[cd][ao][tg]
Frustrating- but still managable.
Jeff

Textarea has double carriage returns

I have some xml that looks similar to this
<events>
<event>
<title> Event Title</title>
<description>This is the event description
When I have line breaks, like this
the text area will show 2, everywhere
that I only have one.
</description>
</event>
</events>
I have even tried removing the tabs, so that the only extra
characters are CR LF , but I always see extra carriage returns in
my textarea.
Ayone know what is causing this ?

* The TextArea control uses UNIX-style line endings, which
means that text data containing Windows-style carriage-return
line-feed (that is, \r\n) formatting for new lines contain extra
line breaks. You can use String.replace() with a regular expression
to convert the text to UNIX-style line endings, as the following
example shows:
private static const windowsCRLF:RegExp = /\r\n/gm;
myTextString = myTextString.replace(windowsCRLF, "\n");
http://www.adobe.com/support/documentation/en/flex/2/releasenotes_flex2_sdk.html

Carriage Return - Regular Expression

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