CE function to get distinct values from Column table

Question

Hi All,
Could you please let me know the appropriate CE function to get the distinct values from column table.
IT_WORK = SELECT DISTINCT AUFNR FROM :IT_WO_DETAILS;
Thank you.

Answer 1

Hi,
If you have 10g, you can use Model( with model performance is better than connect by )
Solution
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WITH t AS
(SELECT '0989.726332, 1234.567432, 3453.736379, 3453.736379, 0989.726332, 3453.736379, 1234.567432, 1234.567432, 0989.726332'
txt
FROM DUAL)
SELECT DISTINCT TRIM(CHAINE)
FROM T
MODEL
RETURN UPDATED ROWS
DIMENSION BY (0 POSITION)
MEASURES (CAST( ' ' AS VARCHAR2(50)) AS CHAINE ,txt ,LENGTH(REGEXP_REPLACE(txt,'[^,]+',''))+1 NB_MOT)
RULES
(CHAINE[FOR POSITION FROM  1 TO NVL(NB_MOT[0],1) INCREMENT 1] =
CASE WHEN NB_MOT[0] IS NULL THEN TXT[0] ELSE REGEXP_SUBSTR(txt[0],'[^,]+',1,CV(POSITION)) END );
=========================================================================
Demo
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SQL> WITH t AS
2 (SELECT '0989.726332, 1234.567432, 3453.736379, 3453.736379, 0989.726332, 3453.736379, 123
4.567432, 1234.567432, 0989.726332'
3 txt
4 FROM DUAL)
5 SELECT DISTINCT TRIM(CHAINE)
6 FROM T
7 MODEL
8 RETURN UPDATED ROWS
9 DIMENSION BY (0 POSITION)
10 MEASURES (CAST( ' ' AS VARCHAR2(50)) AS CHAINE ,txt ,LENGTH(REGEXP_REPLACE(txt,'[^,]+',''))+1 NB_MOT)
11 RULES
12 (CHAINE[FOR POSITION FROM  1 TO NVL(NB_MOT[0],1) INCREMENT 1] =
13 CASE WHEN NB_MOT[0] IS NULL THEN TXT[0] ELSE REGEXP_SUBSTR(txt[0],'[^,]+',1,CV(POSITION)) END );
TRIM(CHAINE)
3453.736379
1234.567432
0989.726332
SQL>
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