Change integer value to string?

Hi all,
I was wondering if it is possible to change an integer value to a string. I saw in this forum that a string can be changed to an integer using parseInt and I was wondering if there is a similar method for going the other way.
Regards.

try this
Integer.toString(intvalue);
where intvalue is an int like 5.
hope this helps.
Takis

Similar Messages

Change Integer value

please help me...
Integer a = new Integer(10);
how to change a value, without new Integer()..?
thanks

You can't. Integer is an immutable class. It is that way so that you can pass this reference to other classes without worrying about whether that class changed it's value.

How to change the value of subtitution string in a page at runtime

Hi,
I need to change the value of a substitution string which is mentioned in application attributes at runtime.
The value will be fetched from a field in database on load of each screen.
Can anybody help.......
Help will be appriciated........thanx in advance
Sunil

Substitution strings are meant to be static, like global constants.
If you need some variable stuff, use application level items and set them using Application level computations/processes

How to get the value of String in integer type

how to get the value of String in integer

{color:#0000ff}http://java.sun.com/javase/6/docs/api/java/lang/Integer.html#parseInt(java.lang.String)
http://java.sun.com/javase/6/docs/api/java/lang/Integer.html#valueOf(java.lang.String){color}

How to change the value in an Integer object?

Hi,
Is it possible to change the value that is contained in an Integer object.
I know Integer objects are immutable. So it might not be possible to chage to value in an integer object once its been initalized a value @ the time of construction.
Also does autoboxing and unboxing feature of 1.5 help acheive this?
Please let me know of any other alternative
Thanks
Deepak

Tried the autoboxing and unboxing feature doesnt
help.It doesn't help in general. But in this special case it doesn't help because it doesn't anything to do with it. Do you really know what you're doing?
So across the function its not changing the value.
As I have created an object of Integer class and
passed a reference of that object into the chage()
,So any changes should have been reflected
acrosss method calls.?Since you let the newly created parameter-reference a point to a new Integer object: no. Why? You have two references to I(31). Then you move one reference to I(33). Why should 31 get another value?
Does the the java compiler creates a new Integer
object each time it does autoboxing Not necessarily. Some values are pooled. Actualy, the JVM does it. The compiler never creates any object.
so that the value
is lost across method calls?That's not the compiler's or the JVM's fault. It's all a misconception of yours.
Is there any means to achieve this?What for?
int a = 0;
a = change(a);
int change (final int i) {
return i + 12;
}Does exactly what you want, without side-effects.

Showing checkbox that stores string or integer values in db

Dear All I am working on JDev 12c. I tried to show a checkbox in the interface that stores Integer value in database but it raises an error in 12c. Here is the sample that does not work http://husaindalal.blogspot.com/2010/01/displaying-checkbox-based-on-database.html I think it could be a bug in 12c Regards

What does not work?
What error duo you get.
Not all samples from 11g run without changes in 12c. Some samples use code which was activity uses errors in 11g which are now fixed and break the sample under 12c
Timo

Changing A Value Using If Statement in SQL Query

Hello, I have a very rudimentary question that I'm stuck on. I have a query that returns one of 3 different integers. I want to have each integer translate to a string value depending on the number returned. Unfortunately this is the SCCM
database which cannot be changed to provide an additional table with the values.
I have something like this but I'm not getting what I want out of the date - depending on what I do I either get an error, or nothing.
Declare @NewValue nvarchar
Declare @Value nvarchar
If @Value = 1 Set @Value = 'String1'
If @Value = 2 Set @Value = 'String2'
If @Value = 3 Set @Value = 'String3'
Select PrimaryKey,IntegerValue FROM db_Table WHERE @Value=IntegerValue
I know this is a simple thing but I'm new to SQL and not exactly sure what terms I should even be using to search for this. Thanks for the help!

select PrimaryKey, IntegerValue, case IntegerValue when 1 then 'String1'
when 2 then 'String 2' when 3 then 'String3' else 'Unknown Integer Value' end as [Description]
from db_Table
Take a look at
CASE expression in BOL. You may also find the following article helpful
http://social.technet.microsoft.com/wiki/contents/articles/21327.t-sql-simplified-case-expression.aspx
For every expert, there is an equal and opposite expert. - Becker's Law
My blog
My TechNet articles

Read integer values from spreadsheet and display the values in a table

Hi all,
I have integer values to read from a spreadsheet and display them in a table. I am using 'Read from spreadsheet file' in 'integer' mode. I would like to display these values in a table. The problem is that the table takes only 2d-array of string as input but not integer.
It works fine if I change the mode of 'Read from spreadsheet file' from 'integer' to 'string' but I want to read integers and have to use the integer values for further calculations. Please give any suggestions on displaying integers to a table.
Thank you.
Solved!
Go to Solution.

No don't take element by element just convert as a whole. See the attached example
Good luck
The best solution is the one you find it by yourself

Determine which value of string is greater

Hi everybody,
I have a fairly complex problem which i hope you can help me with..
The solution is not probably not very hard (i assume), just hard to explain it but I'll give it a try.
I'm working with arrays. These arrays are "declared" as strings, see below:
                 String[] aa;
              aa= new String[5];
              String[] bb;
              bb=new String [5];
              String [] cc;
              cc=new String[5];The programs asks the "tester" to type in three random numbers (see code below)
System.out.println("First number:");
               aa=TextIO.getWord();
                    System.out.println("Second number:");
                    bb[i]= TextIO.getWord();
                              System.out.println("Third number");
                                   cc[i]=TextIO.getWord();
The program is then supposed to print the greater of the typed values.
eg. First number is greater._
How do i make the program to say which one of the three numbers (the numbers can be anything from 0 - 1000000) is greater?
Since the values are +"Strings,"+ I assume you just can't say
if aa > bb && aa > cc print("first number is greater") etc SO, i tried to write it like this:* (but ended up with the error: +"operator && cannot be applied to boolean,int"+
if (Integer.parseInt(aa) > Integer.parseInt(bb[i]) && Integer.parseInt(aa[i]) > Integer.parseInt(cc[i]))
                    correctanswer = Integer.parseInt(aa[i]);
               else if (Integer.parseInt(bb[i]) > Integer.parseInt(cc[i]) && Integer.parseInt(aa[i]))
                         correctanswer = Integer.parseInt(bb[i]);
                    else { correctanswer = Integer.parseInt(cc[i]); }
So the question is: How can i change the code (without changing the strings to int) so it will work?
I hope i have provided you with enough information, if not, please let me know.
Thanks

First off your array declaration is weird for strings. If you don't know the size of the string you are getting from the user then just declare your array like String aa = new String(). Leave it to an untold size!
Secondly, when you parse you are trying to parse a char. Characters already have an integer value. You need to parse the whole string.
Thirdly, when actaully getting the input from the user dump the parse into another variable...makes it easier.
ex: int firstNum = Integer.parseInt(aa) (when you declare it like I did above).
Fourthly, you need to check each greater than for every instance of the comparison. I.E.
if(a > b && a > c) {...}
if(b > a && b > c) {...}
if(c > a && c > b) {...}
Note: this goal can be accomplished dozens of different ways its up to you.
Quick fix: when you do this:
if (Integer.parseInt(aa) > Integer.parseInt(bb[i]) && Integer.parseInt(aa[i]) > Integer.parseInt(cc[i]))
                    correctanswer = Integer.parseInt(aa[i]);
               else if (Integer.parseInt(bb[i]) > Integer.parseInt(cc[i]) && Integer.parseInt(aa[i]))
                         correctanswer = Integer.parseInt(bb[i]);
                    else { correctanswer = Integer.parseInt(cc[i]); }
do this instead:
if (Integer.parseInt(aa) > Integer.parseInt(bb) && Integer.parseInt(aa) > Integer.parseInt(cc))
                    correctanswer = Integer.parseInt(aa);
               else if (Integer.parseInt(bb) > Integer.parseInt(cc) && Integer.parseInt(aa))
                         correctanswer = Integer.parseInt(bb);
                    else { correctanswer = Integer.parseInt(cc); }

Large integer values

You could use DecimalData with scale 0.
Alexis Hassler
OOsphere France
(33) 4 37 49 01 28
-----Message d'origine-----
De: Kasrul Islam [SMTP:kasrul.islamchordiant.com]
Date: vendredi 3 mars 2000 21:04
A: kamranaminyahoo.com
Objet: (forte-users) Large integer values
Hi,
Can anyone out there help with a little problem, I have string of numbers
that I have extracted out of a file, the numbers are all over 10 digits
when I try to convert this string into a Integer the number gets changed to
something weird for example.
Txt : TextData = new(Value = '12345');
mInt : IntegerData = new(Value = Txt.IntegerValue);
this works fine but when I try a number like this :
Txt : TextData = new(Value = '951475978067');
mInt : IntegerData = new(Value = Txt.IntegerValue);
then I get the following value in my integerdata object : 2147483647 any
help will be appreciated, I really need to get the above value as an
integer because I need to do some calculations with it.
Thanks in advance.
Kasrul Islam.
<< Fichier: ATT00000.html>>

Integer values and decimal values in weblient UI - Display mode

Hello,
i have developed an custom assignmentblock with some custom fields.
Some of this fields are integer values and text values.
Some other fields are decimal values.
I face the issue that this decimal values are in display mode right-aligned all other fields are left-aligned.
In edit mode all values are right-alligned.
How can i change this behaviour? All values left-alligned in display mode!
Otherwise this looks strange.
Thank you
Kind regards
Manfred

Hi,
Decimal values will be displayed right-aligned. To change that you need to modify the GET_M method.
In get_m method, you have to change the attr datatype to string.
Data: attr type string.
Data: dref type ref to data.
Get reference of attr into dref.
Regards,
Arun
Edited by: Arun Kumar on May 14, 2010 3:03 PM

Adding a listener to an integer value?

Hello All
Is there a way of adding a listener to an integer value that produce an event (run a method with the object) when an integer value is changed? (Through a object.setValue(int) for example)
Thanks for any help,
Harold Clements

Can any of the kilo-posters (that's with two o's) say if it's considered
bad form to reuse a class that already exists - albeit for a slighty
different purpose? What I'm thinking is that the SpinnerNumberModel
is rather close to what's being looked for - the differences being that
it'll handle any Numbers and has a "next" functionality that we ignore.
Something like:import java.awt.BorderLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.Random;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.SpinnerNumberModel;
import javax.swing.event.ChangeEvent;
import javax.swing.event.ChangeListener;
public class NumberEg extends JFrame {
     private SpinnerNumberModel intModel;
     private Random rand = new Random();
     private JLabel aLabel;
     public NumberEg() {
               // a thing that responds to changes - there could be
               // many of these
          aLabel = new JLabel("I respond to changes...");
          add(aLabel, BorderLayout.CENTER);
               // the thing which changes
          intModel = new SpinnerNumberModel(0, null, null, 0);
               // a change listener which glues the two previous
               // together - again there could be a number of these
          intModel.addChangeListener(new ChangeListener(){
               public void stateChanged(ChangeEvent evt) {
                    aLabel.setText(intModel.getValue().toString());
               // Meanwhile events like button clicks *cause* the
               // changes
          JButton but = new JButton("Click me!");
          but.addActionListener(new ActionListener(){
               public void actionPerformed(ActionEvent evt) {
                    intModel.setValue(rand.nextInt());
          add(but, BorderLayout.NORTH);
          but = new JButton("Reset");
          but.addActionListener(new ActionListener(){
               public void actionPerformed(ActionEvent evt) {
                    intModel.setValue(0);
          add(but, BorderLayout.SOUTH);
          setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
          pack();
     public static void main(String args[]) {
          NumberEg test = new NumberEg();
          test.setVisible(true);
}

I cannot change the value in about:newtab from "newtab" to "blank." The dialog is displayed but when I click Ok, the value is not changed.

I cannot change the value in about:newtab from "newtab" to "blank." The dialog is displayed but when I click Ok, the value is not changed.
===Answer===
Comment on usual method and solution, by a forum Moderator.
As long as there are no confounding factors, such as certain extensions, or a user.jsfile the procedure is as follows
# Open a new tab and type "about:config" in the address bar.
# In the Search bar type: "newtab"
# Locate and double click "browser.newtab.url"
# In the "Enter String Value" box change "'''about:newtab'''" to "'''about:blank'''" and click OK.
# Verify that the value has changed and now all new tabs will be blank.
See post under by ''pirate048'' [/questions/976589?page=2#answer-509482] ~J99

Have to say that I rather agree with Mark..all we want is a simple, unadorned clean page that doe not track and show usage!! WHY NOT!! Is it too simple for developers..we aren't all (nor do we want to be!) software experts! Come on Mozilla..tidy up and clean up..it might be a quicker programme too!!

Change the value of a variable used in a View query

I am using JDeveloper 11g to develop a simple portlet application which displays data loaded from database. I am displaying the data by dragging the ViewObject from the AppModuleDataControl to the View.jspx page and selecting the option ADF Read-only Table. My ViewObject has a single variable :empId. Now is it possible to change the value of this variable with a value that comes from the request object. On the internet I found the following code:
        FacesContext facesContext = FacesContext.getCurrentInstance();
        Application app = facesContext.getApplication();
        ExpressionFactory elFactory = app.getExpressionFactory();
        ELContext elContext = facesContext.getELContext();
        ValueExpression valueExp =
        elFactory.createValueExpression(elContext, "#{data.AppModuleDataControl.dataProvider}",
        Object.class);
        ApplicationModule am = (ApplicationModule)valueExp.getValue(elContext);
        ViewObject emplVO;
        emplVO = am.findViewObject("EmployeeView1");
        emplVO.setNamedWhereClauseParam("empId", "1");I have put this code in the public void processAction(ActionRequest request, ActionResponse response) method. However this does not work when I deploy it.
Does anyone know if the above code is correct in this case and if there is a better way how I can set this up?

Hi there:
Did you add a break point and debug the code to see what is the value for the :empid parameters passed in to your view object?
If you are sure you have passed in the correct value for ":empid" parameter, then do the following:
String amDef = "yourAmDef";
String config = "yourConfig";
ApplicationModule am =
Configuration.createRootApplicationModule(amDef,config);
ViewObject emplVO;
emplVO = am.findViewObject("EmployeeView1");
emplVO.setNamedWhereClauseParam("empId", "1");
empVO.executeQuery();
which will execute your view object with the new bind variable value and refresh the view.
Please mark my answer as 'Correct' if it solves your problem, or 'Helpful' if it does.
Thanks,
Alex
Edited by: Alexbie on 27-Aug-2010 8:52 AM

Passing multiple integer values as parameter in SSRS

Hello,
I am trying to pass a comma separated multiple integer value parameter in SSRS report and it errors out complaining that it is not able to convert the nvarchar value to datatype int. But it works fine when I pass a single value. Here is the code I am using
for the report and I am stuck at passing multiple values.
SELECT
id,count(*) as cnt
from table
and ID in (@id) group by id
eg: if I pass 10,20,30 then I would get error however if I pass 10 then it works fine
Is there a different method to pass multiple integer values?
Thanks for your help.

A comma is, of course, a textual character and not an integer, thus the error you are getting. Multi-value parameters can be used for this.
Select "Allow multiple values"and set data type to Integer. Multi-value parameters deliver the values as an array. The query interface is smart enough to convert them to the proper syntax (comma-delimited) automatically so a statement like:
WHERE Field IN (@id)
where the parameter has an array of values {1, 2, and 3} is interpreted as:
WHERE Field IN (1,2,3)
You do not need to manually convert it in a transact SQL query. That is not the case for displaying the value array in your report. If you wish to display the array (described above) in your report as "1, 2, 3", you will need to use a join expression:
=Join(@id, ", ")
As DJ described, the other part to a multivalue parameter is the Available values. These can be set explicitly but given your example, I think it would be best to create a new dataset that retrieves a distinct list of the IDs that can be retrieved, perhaps
something like:
SELECT DISTINCT GroupName, GroupID
FROM table
WHERE [criteria]
Set the available values to use this query with GroupName (or whatever user-friendly field you choose for your dataset) as the label and the id as the value. The label field should be something the the target report user can easily identify the correct group
using.
If you don't want to or can't use a multivalue parameter for some reason then you will need to manipulate your parameter value prior to consuming it in your query. When you add the parameter to the TSql query and save the dataset, SSRS adds it to the Parameters
property of the dataset. Open the dataset properties and select the parameters tab. You should see your parameter in the list. click the expression builder (fx) button next to the value and enter this expression:
=Split(@id,",")
Note that the second element of the expression is the delimiter. If your text input has comma-space as a delimiter (1, 2, 3 vs 1,2,3) then that element must include ", ". My example just has comma so if you use that with a string "1, 2, 3"then
the resulting array will still have 3 elements but the 2nd and 3rd elements of the array will have a preceding space which will cause your dataset to error with the same error. As long as there are no non-numeric characters in any of the elements, the split6
will create the text array, SSRS will dynamically generate the correct "IN"syntax (comma separated) and SQL will convert the elements from VARCHAR to INT on the fly.
"You will find a fortune, though it will not be the one you seek." -
Blind Seer, O Brother Where Art Thou
Please Mark posts as answers or helpful so that others may find the fortune they seek.

Change integer value to string?

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