Classpath to .jars inside .zip files

I had post something similar to this but this time it's another idea (and another problem) - so, this is not cross-posting.
I have this .zip file with 25 .jar files, I want to use it in my Manifest file, but it seems that when the classes are in the .jars and the .jars are in a zip file they are not reached by the Classloader.
# Archive Libs.zip*
commons-collections-3.1.jar
commons-digester.jar
commons-lang-2.0.jar
commons-logging-1.0.3.jar
commons-logging.jar
commons-logging-api.jar
commons-net-1.4.1.jar
firebirdsql-full.jar
formsrt.jar
itext-1.3.1.jar
jasperreports-1.3.1.jar
jaybird-2.1.1.jar
jaybird-full-2.1.1.jar
jcommon-1.0.0-rc1.jar
jdt-compiler.jar
jfreechart-1.0.0-rc1.jar
Lib.jar
log4j-1.2.14.jar
looks-1.3.1.jar
mail.jar
pop3.jar
substance-lite.jar
swingx-0.8.0.jar
activation.jar
commons-beanutils.jar12670124 10779634 25
The file MANIFEST.MF
Manifest-Version: 1.0
Specification-Version: 3
Implementation-Version: 0 2007
Implementation-Title: SikGraf(Standard)
Specification-Vendor: Kooky
Created-By: Kooky
Main-Class: com.sikgraf.main.Main
SplashScreen-Image: com/sikgraf/imagens/siggraf.jpg
Class-Path: . \SikGrafStandard.jar \C:/Kooky/SigGraf/Libs.zip[/code]
Is is possible to do that? (.jars inside a zip) Or am I dreaming here?

You would have to write your own custom classloader to do this, which is what http://one-jar.sourceforge.net/ tries to do.

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CLASSPATH, Jar file or zip file visibility during compilation and run time

I am using jwsdp-1_0_01 with some success.
However, making my *.jar or *.zip files
visible during ant builds is not working.
Setting a CLASSPATH environment
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</target>
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Calling JAR inside WAR

Dear experts,
I hope this is the right place to post such question. I have a web and desktop app developed using netbeans and to be built into a JAR(J) and WAR (W) file. I would like to know if it is possible for the (J) to call some other JAR (or .class) inside the (W)? Our ultimate goal is to share common classes between two apps, and hopefully no need to re-build the (J) when (W) is modified, or vice-versa. I hope my explaination is clear enough. Any comments and sugguestions is welcomed and appreciated, thanks.

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Remove Zip Files

Hi guys,
I've got a function that extracts a zip file and then extracts two zip files within the newly created folder.
$shell_app = New-Object -com shell.application
$files = Get-ChildItem -Path $path -filter *.zip -recurse
$fileString = $files.toString()
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$directory = $path + "\" + $zipName
New-Item -ItemType Directory -Force -Path $directory
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$copyHere = $shell_app.namespace($directory)
$$copyHere.CopyHere($zip_file.items())
$files = Get-ChildItem -Path $directory -filter *.zip -recurse
foreach($file in $files)
$innerDir = $directory + "\" + $file.name
$zipName = $innerDir.Replace(".zip","")
New-Item -ItemType Directory -Force -Path $zipName
$zip_file = $shell_app.namespace($file.FullName)
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$copyHere.CopyHere($zip_file.items())
This works fine. What I want to do is delete all the .zip files after they have been extracted. I've tried removing the them via the "Remove-Item -Path $path -filter *.zip -recurse" at the end of the function, but it seems to come in too early
and removes them before the files have finished being extracted.
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Hello
KarneeKarnay,
Could you test this and let me know if it worked?
Add-Type -AN System.IO.Compression.FileSystem
$zip = [IO.Compression.ZipFile]::OpenRead("c:\users\User1\desktop\tmp.zip") #my temp zip
$zip.Entries.Count #count inside zip
$files = Get-ChildItem C:\Users\User1\Desktop\tmp
$files.Count #count inside zip
may be a while loop? or could be called separately in a different ps1.?
Regards,
V
Venu

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I've noticed in the installation document of the J9 that if you want to add javax classes it has to be put on the -Xbootclasspath. So I've tried including the zip file using -Xbootclasspath/p:path/to/zipfile/zipfile.zip and I've tried -Xbootclasspath/a:path/to/zipfile/zipfile.zip. I've also tried just including it in the classpath with no luck either. I keep getting a NoClassDefFoundError: javax.units.Unit which is part of the jscience package
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Hi,
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I'm using SWT and here's the code:
lstBread.addListener (SWT.Selection, new Listener () {
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It's working wtihout error on win32 platform. But there is no call on Windows Mobile 5.0 platform. It doesn't run and no exception is throwed on J9 console.
However, when i use the same way for event handling in SWT Button, there is no problem both on WM5 and win32 platform. It's executed as i want.
The code for SWT Button:
btnSView.addListener (SWT.Selection, new Listener () {
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I couldn't find the reason of that. Why doesn't the list#addListener run on WMobile?
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Apache Tomcat 7.0.4 can't recognize the classpath for .jar files

Hiii Everybody,
I have a weird problem. I am trying to develop a simple application where I am trying to pass an excel file name as an argument to a method and the method creates a copy of the specified file. I have used jxl.jar for excel file manipulation. During this I have faced two problems.......
1) I tried to compile the file CopyExcel.java in the command prompt(windows), sometimes the file is not compiled and the error shown indicates that it can't recognize the package jxl. But if I close the command prompt window and open it again.... I could compile the CopyExcel.java succesfully with no error.
2) Even if I have compiled the CopyExcell.java file successfully, whenever I am tryiyng to call a method copyMain() inside it, browser shows....
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
javax.servlet.ServletException: Servlet execution threw an exception
root cause
java.lang.NoClassDefFoundError: jxl/Workbook
     CopyExcel.copy(CopyExcel.java:39)
     CopyExcel.copyMain(CopyExcel.java:81)
     ServicePage.processRequest(ServicePage.java:28)
     ServicePage.doPost(ServicePage.java:73)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:641)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
root cause
java.lang.ClassNotFoundException: jxl.Workbook
     org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1672)
     org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1517)
     java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320)
     CopyExcel.copy(CopyExcel.java:39)
     CopyExcel.copyMain(CopyExcel.java:81)
     ServicePage.processRequest(ServicePage.java:28)
     ServicePage.doPost(ServicePage.java:73)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:641)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
note The full stack trace of the root cause is available in the Apache Tomcat/7.0.4 logs.
--------------------------------------------------------------------------------The code for CopyExcel.java is as folows.............
* To change this template, choose Tools | Templates
* and open the template in the editor.
* @author Administrator
* To change this template, choose Tools | Templates
* and open the template in the editor.
import java.io.File;
import java.io.IOException;
import jxl.Cell;
//import jxl.CellType;
import jxl.Sheet;
import jxl.Workbook;
import jxl.read.biff.BiffException;
import jxl.write.WritableWorkbook;
public class CopyExcel {
     private String inputFile;
     public void setInputFile(String inputFile) {
          this.inputFile = inputFile;
     public void copy() throws IOException {
          File inputWorkbook = new File(inputFile);
          Workbook w;
                try{
                    System.out.println("Before w= Workbook.getWorkbook(inputWorkbook); ");
          w= Workbook.getWorkbook(inputWorkbook);
                 System.out.println("After w= Workbook.getWorkbook(inputWorkbook); ");
          WritableWorkbook copy=Workbook.createWorkbook(new File("CopyPan.xls"), w);
                copy.write();
                copy.close();
                }catch(Exception e){}
/*          try {
               w = Workbook.getWorkbook(inputWorkbook);
               // Get the first sheet
               Sheet sheet = w.getSheet(0);
               // Loop over first 10 column and lines
                    for (int i = 1; i < 6; i++) {
                         Cell cell = sheet.getCell(0, i);
                         //CellType type = cell.getType();
                         //if (cell.getType() == CellType.LABEL) {
                              //System.out.println("I got a label "
                                   //     + cell.getContents());
                         //if (cell.getType() == CellType.NUMBER) {
                              //System.out.println("I got a number "
                                        //+ cell.getContents());
                                                System.out.println(cell.getContents());
          } catch (BiffException e) {
               e.printStackTrace();
     public static String copyMain(String args) throws IOException {
          String str=args;
          CopyExcel test = new CopyExcel();
          test.setInputFile(args);
          test.copy();
                return "Success";
}I have set the "CLASSPATH" environment variables in "user variables for administrator" as follows,
.;%SYSTEM%;C:\Program Files\Apache Software Foundation\apache-tomcat-7.0.4\bin;C:\Program Files\Apache Software Foundation\apache-tomcat-7.0.4\lib\servlet-api.jar;C:\Program Files\Java\jdk1.6.0_11\lib\jxl-2.6.jar Also I have tried editing the startup MS-dos batch file as folows....
set JAVA_HOME=C:\Program Files\Java\jdk1.6.0_11
set CLASSPATH=.;%SYSTEM%;C:\Program Files\Apache Software Foundation\apache-tomcat-7.0.4\bin;C:\Program Files\Apache Software Foundation\apache-tomcat-7.0.4\lib\servlet-api.jar;C:\Program Files\Java\jdk1.6.0_11\lib\jxl-2.6.jar
@echo off
rem Licensed to the Apache Software Foundation (ASF) under one or more
rem contributor license agreements. See the NOTICE file distributed with
rem this work for additional information regarding copyright ownership.
rem The ASF licenses thi..........But the problem remained...........
Plz. help me.
Thank u in advance for any help.

Hiii Everybody,
I have a weird problem. I am trying to develop a simple application where I am trying to pass an excel file name as an argument to a method and the method creates a copy of the specified file. I have used jxl.jar for excel file manipulation. During this I have faced two problems.......
1) I tried to compile the file CopyExcel.java in the command prompt(windows), sometimes the file is not compiled and the error shown indicates that it can't recognize the package jxl. But if I close the command prompt window and open it again.... I could compile the CopyExcel.java succesfully with no error.
2) Even if I have compiled the CopyExcell.java file successfully, whenever I am tryiyng to call a method copyMain() inside it, browser shows....
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
javax.servlet.ServletException: Servlet execution threw an exception
root cause
java.lang.NoClassDefFoundError: jxl/Workbook
     CopyExcel.copy(CopyExcel.java:39)
     CopyExcel.copyMain(CopyExcel.java:81)
     ServicePage.processRequest(ServicePage.java:28)
     ServicePage.doPost(ServicePage.java:73)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:641)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
root cause
java.lang.ClassNotFoundException: jxl.Workbook
     org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1672)
     org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1517)
     java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320)
     CopyExcel.copy(CopyExcel.java:39)
     CopyExcel.copyMain(CopyExcel.java:81)
     ServicePage.processRequest(ServicePage.java:28)
     ServicePage.doPost(ServicePage.java:73)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:641)
     javax.servlet.http.HttpServlet.service(HttpServlet.java:722)
note The full stack trace of the root cause is available in the Apache Tomcat/7.0.4 logs.
--------------------------------------------------------------------------------The code for CopyExcel.java is as folows.............
* To change this template, choose Tools | Templates
* and open the template in the editor.
* @author Administrator
* To change this template, choose Tools | Templates
* and open the template in the editor.
import java.io.File;
import java.io.IOException;
import jxl.Cell;
//import jxl.CellType;
import jxl.Sheet;
import jxl.Workbook;
import jxl.read.biff.BiffException;
import jxl.write.WritableWorkbook;
public class CopyExcel {
     private String inputFile;
     public void setInputFile(String inputFile) {
          this.inputFile = inputFile;
     public void copy() throws IOException {
          File inputWorkbook = new File(inputFile);
          Workbook w;
                try{
                    System.out.println("Before w= Workbook.getWorkbook(inputWorkbook); ");
          w= Workbook.getWorkbook(inputWorkbook);
                 System.out.println("After w= Workbook.getWorkbook(inputWorkbook); ");
          WritableWorkbook copy=Workbook.createWorkbook(new File("CopyPan.xls"), w);
                copy.write();
                copy.close();
                }catch(Exception e){}
/*          try {
               w = Workbook.getWorkbook(inputWorkbook);
               // Get the first sheet
               Sheet sheet = w.getSheet(0);
               // Loop over first 10 column and lines
                    for (int i = 1; i < 6; i++) {
                         Cell cell = sheet.getCell(0, i);
                         //CellType type = cell.getType();
                         //if (cell.getType() == CellType.LABEL) {
                              //System.out.println("I got a label "
                                   //     + cell.getContents());
                         //if (cell.getType() == CellType.NUMBER) {
                              //System.out.println("I got a number "
                                        //+ cell.getContents());
                                                System.out.println(cell.getContents());
          } catch (BiffException e) {
               e.printStackTrace();
     public static String copyMain(String args) throws IOException {
          String str=args;
          CopyExcel test = new CopyExcel();
          test.setInputFile(args);
          test.copy();
                return "Success";
}I have set the "CLASSPATH" environment variables in "user variables for administrator" as follows,
.;%SYSTEM%;C:\Program Files\Apache Software Foundation\apache-tomcat-7.0.4\bin;C:\Program Files\Apache Software Foundation\apache-tomcat-7.0.4\lib\servlet-api.jar;C:\Program Files\Java\jdk1.6.0_11\lib\jxl-2.6.jar Also I have tried editing the startup MS-dos batch file as folows....
set JAVA_HOME=C:\Program Files\Java\jdk1.6.0_11
set CLASSPATH=.;%SYSTEM%;C:\Program Files\Apache Software Foundation\apache-tomcat-7.0.4\bin;C:\Program Files\Apache Software Foundation\apache-tomcat-7.0.4\lib\servlet-api.jar;C:\Program Files\Java\jdk1.6.0_11\lib\jxl-2.6.jar
@echo off
rem Licensed to the Apache Software Foundation (ASF) under one or more
rem contributor license agreements. See the NOTICE file distributed with
rem this work for additional information regarding copyright ownership.
rem The ASF licenses thi..........But the problem remained...........
Plz. help me.
Thank u in advance for any help.

How to get the entries in a jar/zip file contained within a jar/zip file?

If I want to list the jar/zip entries in a jar/zip file contained within a jar/zip file how can I do that?
In order to get to the entry enumeration I need a Zip/JarFile:
ZipFile zip = new ZipFile("C:/java_dev/Java_dl/java_jdk_commander_v36d.zip");
// Process the zip file. Close it when the block is exited.
try {
// Loop through the zip entries and print the name of each one.
for (Enumeration list =zip.entries(); list.hasMoreElements(); ) {
ZipEntry entry = (ZipEntry) list.nextElement();
System.out.println(entry.getName());
finally {
zip.close();
Zip file "java_jdk_commander_v36d.zip" contains two zip entries:
1) UsersGuide.zip
2) JDKcommander.exe
How to list the entries in "jar:file:/C:/java_dev/Java_dl/java_jdk_commander_v36d.zip!/UsersGuide.zip"?
The following code:
URL url = new URL("jar:file:/C:/java_dev/Java_dl/java_jdk_commander_v36d.zip!/UsersGuide.zip");
JarURLConnection jarConnection = (JarURLConnection)url.openConnection();
zipFile = (ZipFile)jarConnection.getJarFile();
would point to "jar:file:/C:/java_dev/Java_dl/java_jdk_commander_v36d.zip", which is no help at all and Class JarURLConnection does not have an enumeration method.
How can I do this?
Thanks.
Andre

I'm not sure I understand the problem. The difference between a zip and jar file is the manifest file; JarFile is extended from ZipFile and is able to read the manifest, other than that they are the same. Your code
for (Enumeration list =zip.entries(); list.hasMoreElements(); ) {
ZipEntry entry = (ZipEntry) list.nextElement();
System.out.println(entry.getName());
}is close to what I've use for a jar, below. Why not use the same approach? I don't understand what you're trying to do by using JarURLConnection - it's usually used to read the jar contents.
String jarName = "";
JarFile jar = null;
try
    jar = new JarFile(jarName);
catch (IOException ex)
    System.out.println("Unable to open jarfile" + jarName);
    ex.printStackTrace();
for ( Enumeration en = jar.entries() ; en.hasMoreElements() ;)
    System.out.println(en.nextElement());
}

Creation of zip file inside another one.

Hi,
I have a problem with the zip file creation.
I have created the zip file but now i can' t
create another zip file inside the first one.
can you suggest me how can i do it ?
thanks Laura.

Hi,
try this Fm..
ISM_GENERATE_ZIP_FILE_NAME
Arunima

Jar files downloaded from SkyDrive are being renamed to jar.zip files

I have cut and pasted the following series of exchanges from when I posted the problem onto SkyDrive's support forum. I hope that someone might be able to propose a better solution to the problem that I have. Thanks for your help.
MDSms asked on
Uploaded jar files convert to jar.zip files when downloaded from SkyDrive
I have uploaded an executable jar file to SkyDrive. (I will call this FILE.jar). The file is intact and indicates that it is a jar file type when the file is viewed by Properties within Skydrive. However, when I download (or others download through a share link) the file, it is being saved onto the local computer's download file with .zip appended to the file name (FILE.jar.zip). The downloaded file can be renamed to remove the .zip appendage and subsequently run successfully. However the folder options for the folder where the downloaded file resides must be changed for disable "Hide known file extensions" prior to being able to remove the .zip appendage. While I have figured out the workaround for this problem, this manual renaming procedure is entirely too cumbersome as a solution for sharing this file with others. How can I prevent or disable the FILE.jar file from being renamed to FILE.jar.zip when it is downloaded from SkyDrive?
All Replies (5)
Audrey_P. replied on
Forum Moderator
Hi,
Thank you for posting. Let me try to assist you with your issue with your files.
In order for us to reproduce the issue on our end. Please provide us with the exact steps that you did when you uploaded the files as well as the steps when you are downloading it.
We will be needing the steps to help us figure put what is causing you this issue.
We look forward to your response.
Thank you.
Audrey P.
MDSms replied on
Reply
The file was uploaded by first logging onto my SkyDrive account using Windows 7 Pro and Firefox browser, then a new folder in my account was created without sharing privileges, then the folder was opened and the FILE.jar was uploaded into the folder using the "Upload" option on skydrive account menu. Sharing privileges for FILE.jar were then created (view only), and the shortened url link was sent to the individuals that I was trying to share the file with. was then turned on. When these people use the link to download the file, it is being saved as FILE.jar.zip.
When I try to download the file through the skydrive account download option, it is being saved onto my computer as FILE.jar.zip and this occurs when I try to download the file while signed into my skydrive account as well as when I am not signed into my skydrive account (using the shared file link).
This PNG shows the information provided by clicking on the download icon (down arrow) within the Firefox browser; note that the file was downloaded as FILE.jar.zip and that the source was live.com. When I use Windows Explorer to look at the same file within the Download folder itself, examining the file's properties details also shows that it is being saved as FILE.jar.zip and is of the file type compressed zip folder.
This PNG shows the information displayed to me from my skydrive account when I view the originally uploaded file's properties; note that the information shows that the file is a jar file type.
When I utilize Internet Explorer 9 to access the file, FILE.jar is being downloaded onto my computer as a jar file type. This PNG shows the information provided by Tools/View Downloads within the IE9 browser. Note that in this instance, the information indicates that the file is being downloaded from yzudea.blu.livefilestore.com.
It appears to me that the problem (the FILE.jar file being renamed to FILE.jar.zip) arises from the fact that a jar file downloaded from skydrive using firefox, is being sent from live.com whereas a jar file downloaded from skydrive using IE9 is being sent from yzudea.blu.livefilestore.com.
I want to make sure that a person receiving a share link from me for FILE.jar is able to download it without modification to the file name regardless of which browser is being using to access the link. How can I make sure that this occurs?
Any help is appreciated. Thanks.
Michelle Anne D. replied on
Forum Moderator Community Star Community Star
Reply
Hi MDSms,
I appreciate you for providing as much information as you can about the issue, as well as for uploading screenshots on what you see from the downloaded file. About your initial concern wherein the file gets renamed with .zip after the original file extension, this is solely dependent on the browser that you are using since they have a different safety/security measure that needs to be implemented.
Moreover, you may see the file servers live.com and yzudea.blu.livefilestore.com to be different with one another, but they actually are sent from the same SkyDrive server. This in turn, depends on the web browser where the file is being downloaded as well. The live.com file where it was downloaded from Firefox simply masks its original server yzudea.blu.livefilestore.com.
As for your last query about your recipients downloading the file without the hassle of renaming it from a .zip file, you can simply tell them to download it through Internet Explorer.
Should you have other queries or additional information that might help in our investigation, I highly encourage you to post them here.
Regards,
Michelle
MDSms replied on
Michelle,
Thanks for your reply. Yes, I could simply tell them to download the file through Internet Explorer, but is there another solution or workaround to the problem I have described here? Am I being punished with the curse of this problem simply because I (or the individuals with which I wish to share FILE.jar with) choose to use Firefox instead of IE? Will the use of any other browser instead of IE (Chrome, Safari, etc., etc.) still result in the same problem?
You stated that it is "solely dependent on the browser that you are using since they have a different safety/security measure that needs to be implemented"........could the problem be overcome by designating one or both of the file server addresses as Trusted Sites within the browser options setting?
I look forward to your response. Thanks in advance.
Joy V. replied on
Forum Moderator Community Star Community Star
Reply
Hi MDSms,
We understand your concern. Since the issue does not occur in Internet Explorer, it has something to do with Firefox's security feature. You might want to verify this concern by contacting Firefox support.
Hope this helps. Let us know if we can further assist you with SkyDrive.
Thanks,
Melanie Joy

Try to delete the mimeTypes.rdf file in the Firefox profile folder to reset all file actions.
*http://kb.mozillazine.org/mimeTypes.rdf
*http://kb.mozillazine.org/File_types_and_download_actions#Resetting_download_actions

I have mountain lion OSX and parallels with Windows. Every time I click on a hyperlink in other applications it opens - some 7 Zip file explorer inside Parallels but doesn't go to Safari. Does anyone know solution?

I have mountain lion OSX and parallels with Windows. Every time I click on a hyperlink in other applications it opens - some 7 Zip file explorer inside Parallels but doesn't go to Safari. Does anyone know solution?

I suggest that you run software update, after which you should have Safari 6.0.5 - then check Safari - Preferences - Privacy & see that 'Block cookies' is not set to Always.
Failing that - switch Safari extensions Off via Safari - Preferences - Extensions & test again

How can I stop Microsoft IE renaming .jar files to .zip files?

I realise this question has been asked before on this forum, but as far as I can tell no answer has yet been posted.
If I put a .jar file on my webserver for people to download, later versions of Internet Explorer will rename the file from xxx.jar to xxx.zip on the client's machine. Is there any way of stopping this from happening?
It looks like the problem is caused by IE examining the contents of the file and realising it uses ZIP compression. As a result, any file that I create (not just jars) that uses Java to zip the contents, when placed on a web server, gets interpreted as a .zip file by IE regardless of its extension.
I realise there are some workarounds such as zipping the .jar file, creating a .exe file from the .jar, telling everyone to use Firefox etc., but none of these are really acceptable or particularly efficient. I am really hoping there is something I can do to the .jar file or the compression process that will tell IE to leave the file alone.
Thanks,
Jo.

You can save any kind of document on iCloud Drive, as long as the file size is smaller than 15GB.
See: iCloud Drive FAQ
Create a new folder for your Office documents on iCloud Drive and drag your documents there, or select iCloud Drive in the File Chooser panel, when you save a document.

Possible trojan .zip file in jar folder

Has anyone heard of the possibility of an infected "jar" file in the
J2SE v.1.4.2_03 application?
I have recently installed Sun during an XP Pro install due to the regulations that don't allow Microsoft to monopolize the Java Machine anymore, and now I have received a message from my Virus software that the demo.jar-2e26db2e-6e6164b1.zip file residing in
C:\Documents and Settings\Owner\Application Data\Sun\Java\Deployment\cache\javapi\v1.0\jar has been detected as an uncleanable trojan. It needs to replaced. Any bulletins about this or help in obtaining another file, (if it's needed to have the application function properly), would be appreciated.

You can certainly remove that file. it's basically the cached applet demo.jar (the JRE caches the downloaded jars so that you don't have to keep re-downloading them each time you visit the web site).
The fact that your Antivirus complains about it just means that it's confused. We're all using the Sun environment, and I have the latest and greatest Norton, and there are no complaints, so it's clear that your Antivirus software needs a fix.

How to extract a folder (and its contents) from inside a zip file?

There is a zip file which contains a folder inside it. The folder itself contains a few files. I would need to know how to extract the folder (with its contents) from inside a zip file.
I have found a few unzipping code samples which show how to handle a folder inside a zip file. An example is shown below:
public static void extract(String workingDirectory, byte[] zipFile)
throws Exception {
ByteArrayInputStream byteStream = new ByteArrayInputStream(zipFile);
ByteArrayOutputStream out = new ByteArrayOutputStream();
ZipInputStream zipStream = new ZipInputStream(byteStream);
ZipEntry zipEntry = null;
String nameZipEntry = null;
byte[] contentZiphttp://forum.java.sun.com/post!default.jspa?forumID=31#
Click for code tagsEntry = null;
boolean isDirectory = false;
int indexFileSeparator = -1;
String directory = null;
String fileName = null;
while ( (zipEntry = zipStream.getNextEntry()) != null )
            nameZipEntry = workingDirectory + File.separator + zipEntry.getName();
            isDirectory = zipEntry.isDirectory();
            if (isDirectory) {
File file = new File(nameZipEntry);
file.mkdirs();
            else
                // read zipEntry
                byte[] buf = new byte[1024];
                int c = 0;
                while ( (c = zipStream.read(buf)) != -1)
                    out.write(buf, 0, c);
                indexFileSeparator = nameZipEntry.lastIndexOf(File.separator);
                directory = nameZipEntry.substring(0, indexFileSeparator);
                fileName = nameZipEntry.substring(indexFileSeparator+1,nameZipEntry.length());
                FileSystemTools.createFile(directory, fileName, out);
                out.reset();
                zipStream.closeEntry();
        zipStream.close();
        byteStream.close();
}The code sample which deals with the part where the zipEntry is a directory creates a directory with the same path and name. (highlighted in bold)
Another similar variation is:
File file = new File(dirDestiny.getAbsolutePath() + File.separator + zipEntry.getName() );
if(zipEntry.isDirectory())
      file.mkdirs();When the code creates a directory for the folder, does it unzip the contents inside the folder as well?
If not, how do I extract the files inside the folder?

Have you already tried to see if the sample code you downloaded works or not? Maybe if you try out the code yourself you can see if it extracts files from a directory within a zip file?
I like to use pkzip. It is a command line compression/uncompression tool that can be used from a batch file. If you assignment involves unzipping large amount of zip files on a regular basis, I recommend taking a look at pkzip.

Classpath to .jars inside .zip files

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