Possible trojan .zip file in jar folder

Has anyone heard of the possibility of an infected "jar" file in the
J2SE v.1.4.2_03 application?
I have recently installed Sun during an XP Pro install due to the regulations that don't allow Microsoft to monopolize the Java Machine anymore, and now I have received a message from my Virus software that the demo.jar-2e26db2e-6e6164b1.zip file residing in
C:\Documents and Settings\Owner\Application Data\Sun\Java\Deployment\cache\javapi\v1.0\jar has been detected as an uncleanable trojan. It needs to replaced. Any bulletins about this or help in obtaining another file, (if it's needed to have the application function properly), would be appreciated.

You can certainly remove that file. it's basically the cached applet demo.jar (the JRE caches the downloaded jars so that you don't have to keep re-downloading them each time you visit the web site).
The fact that your Antivirus complains about it just means that it's confused. We're all using the Sun environment, and I have the latest and greatest Norton, and there are no complaints, so it's clear that your Antivirus software needs a fix.

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Saved presentation as .zip file or a folder. Presentation gone?

Hello, I really need some help. Yesterday, I worked with a presentation which took about 10 hours, I'm not really that experienced with computers, but I think I saved it as a .zip file or simply as a folder. I cannot find the presentation and open it anymore, and the .zip file and the folder simply contains:
All the images i used in the presentation.
A folder named "Quicklook".
A folder named "Thumbnails", with all the thumbnails of each slide, but they are too small to read, and it doesn't help to zoom in, too bad quality.
The frontpage of my presentation.
A file named "Index", not sure about the filetype.
I really need help on how to fix this, if it is possible. I don't understand where the main file for the presentation is, it seems like this folder only contains all the materials and parts for the presentation.
Any ideas?
Thanks in advance.

Welcome to the discussions, Maryam222.
Keynote "files" are actually .zip files or folders with the difference being that their name has .key on the end. As long as you haven't moved any of the items/objects out of OR to different positions in that folder, you should be able to...
1) Select the icon that you think is your presentation (not the stuff on the inside, the folder that it's all in, select the folder)
2) Do "command-I" to "Get Info" for that icon.
3) In the "Name & Extension" area, you should see the name of the folder
4) I'm guessing that your problem is that it doesn't have .key at the end. So, add .key to the end of the filename (If it has .zip at the end, change .zip to .key)
5) OSX will tell you something about changing the file, click the button to confirm the change
Now, it should open in Keynote when you double click on it. If not, post back to report what you're seeing.

Zipping files in a folder using java.util.zip

hi guys,
does any body has the java code for
zipping files in a folder
hi guys,
actually i want to zip no of files in a folder .the folder can also have sub folder
and after zipping when i extract the files manually i should
maintain the same folder structure
does any body has the code
please reply me soon its a bit urgent

hi smeee
i tried running ur code but its not working
here the command
java c:\abc\ zzz.zip
its saying
no files or directories even though there's the
directory present
what's the solution Hi,
Oops that was because of the error check added at the last moment..
Anyway, You need to use the following command to run it :
java ZipUtility c:\abc c:\zzz.zip
Please use the following corrected code:
     Class to zip file(s).
     Requires jdk1.3.1.
     To run use the following command:
     java ZipUtility <directory or file to be zipped> <name of zip file to be created>
     Please specify absolute path names as its parameters while running this program.
import java.util.zip.*;
import java.io.*;
public class ZipUtility {
     ZipOutputStream cpZipOutputStream = null;
     String strSource = "";
     String strTarget = "";
     String strSubstring = "";
     public static void main(String args[]) {
          if(     args == null || args.length < 2) {
               System.out.println("Usage: java ZipUtility <directory or file to be zipped> <name of zip file to be created>");
               return;
          ZipUtility udZipUtility = new ZipUtility();
          udZipUtility.strSource = args[0];
          udZipUtility.strTarget = args[1];
          udZipUtility.zip();
     private void zip(){
                    try
                         File cpFile = new File (strSource);
                         if (!cpFile.isFile() && !cpFile.isDirectory() ) {
                              System.out.println("\nSource file/directory Not Found!");
                              return;
                         if (cpFile.isDirectory()) {
                              strSubstring = strSource;;
                         } else {
                              strSubstring = "";
                         cpZipOutputStream = new ZipOutputStream(new FileOutputStream(strTarget));
                         cpZipOutputStream.setLevel(9);
                         zipFiles( cpFile);
                         cpZipOutputStream.finish();
                         cpZipOutputStream.close();
                         System.out.println("\n Finished creating zip file " + strTarget + " from source " + strSource);
                    }catch (Exception e){
                         e.printStackTrace();
     private void zipFiles(File cpFile) {
               if (cpFile.isDirectory()) {
                    File [] fList = cpFile.listFiles() ;
                    for (int i=0; i< fList.length; i++){
                         zipFiles(fList) ;
               } else {
                    try {
                         String strAbsPath = cpFile.getAbsolutePath();
                         String strZipEntryName ="";
                         if (!strSubstring.equals("") ){
                              strZipEntryName = strAbsPath.substring(strSource.length()+1, strAbsPath.length());
                         } else {
                              strZipEntryName = cpFile.getName();
                         byte[] b = new byte[ (int)(cpFile.length()) ];
                         FileInputStream cpFileInputStream = new FileInputStream (cpFile) ;
                         int i = cpFileInputStream.read(b, 0, (int)cpFile.length());
                         ZipEntry cpZipEntry = new ZipEntry(strZipEntryName);
                         cpZipOutputStream.putNextEntry(cpZipEntry );
                         cpZipOutputStream.write(b, 0, (int)cpFile.length());
                         cpZipOutputStream.closeEntry() ;
                    } catch (Exception e) {
                         e.printStackTrace();

Pickup and process zip file in watch folder

Hi,
Could someone refer me to an example where it shows me how to use Java script in the Execute Script service to do the following:
- Pickup the zip file from the Watch Folder
- Unzip the zip file
- Loop through all the folders, look for the documents and store them in the list document variable in the process
Thank you in advance for the help!
Hai

You can certainly remove that file. it's basically the cached applet demo.jar (the JRE caches the downloaded jars so that you don't have to keep re-downloading them each time you visit the web site).
The fact that your Antivirus complains about it just means that it's confused. We're all using the Sun environment, and I have the latest and greatest Norton, and there are no complaints, so it's clear that your Antivirus software needs a fix.

JFileChooser interpreting zip file as a folder

I have an app that reads and writes data to zip files. When opening one, I use a JFileChooser with a file filter for zips and directories.
This works fine except except on XP. If the zip file is on a remote (Novell) file server, the JFileChooser treats the zip file as a directory. You can't open the zip file itself.
If the client is W2k, there is no problem.
I'm using JRE 1.4.1.
Anyone know if there's a tweak to XP to fix this?

JResourceBrowser is a swing component similar to the javax.swing.JFileChooser but letting the user navigating into a set of directories bound to various protocols or containers. For an usage sample, listing an ftp directory, creating a new file and editing it inside your application. JResourceBrowser is provided by default with a set of "managers" dedicated to ZIP and JAR, FTP and WebDAV.
http://www.swingall.com/jrb/index.html
Features :
* JavaBeans
* Built with a GridBagLayout
* Create your own plugins for navigating
* User Interface delegate for rendering a file
* Cutomize the set of actions
* Default actions for creating a new file, deleting, renaming or locking/unlocking
* Extracting or putting a file content
* Save/restore the user interface state
* ZIP, JAR support
* FTP support
* WebDAV support
* JDK 1.4 and 1.5 compatibility

Zip files in AdobePatchFiles folder

I have 2 GB of zip files in Applications/Adobe/AdobePatchFiles generated by Creative Cloud (Mac OSX 10.9.2). Can I delete them?

you need those files for future patches.
in general, before deleting files you're not certain you can delete, rename them. (i like to prefix the file name with a dollar sign, $. that moves the file to the top of the directory listings and makes it easy to rename back to the original if there's a problem.)

Reading ZIP files

Is it possible to read content of ZIP files.
Iam using ORACLE forms 6i.
In our company, we are creating a zip file with two folder src and lib, where SRC contains FMB files abd LIB contains PLLfiles.Now i want to know whether instead of us seeing the contents, is it possible to check whether fmx and plx are present in correspoding folder using some api methods.
If u can find any please tell me .. it will be of great use

I dont about the api's, but one way cud be unzipping the files in temp folder thru winzip command line and then checking the files existence.

Zip file created in Snow Leopard can't be opened on a PC

Hi,
I've created a zip file of a folder containing Word and pdf files using File>Compress in Snow Leopard.
After emailing to clients, they cannot open the zip file on their PCs.
Any help? I thought zip was supposed to be universal.
Thanks in advance!

All clients, or some clients? How big are the zip files?
Usually when this happens, one of two things is going on: one of your mail servers is truncating the message (cutting off part of the attachment) because the message exceeds some pre-determined maximum message size (or the mailbox goes over a quota), OR one of you is running a virus/malware scanner on your mail server that objects to certain file types (it's not uncommon to strip .ZIP, .COM, and .EXE files).
There's also the possibility that a Windows client just doesn't understand the file's type. While that shouldn't be, it does happen sometimes (I've seen it with Lotus Notes, for example). In that case, the recipient should save the attachment as a file on their desktop and open it from the desktop.

How to create a Web Dynpro Project from Downloaded zip file?

Hi,
I have been working in Java Web Dynpro for last 1 month but not able
to create any Web Dynpro from Downloaded zip file?
Can anybody tell me how to create a Java Web Dynpro Project from
Donloaded zip code?
Regards
Kaushik Banerjee

Hi Kaushik,
You can add the existing zip file into your workspace by the following way -
First open the NWDS and create a new project by clicking file -> new -> Project -> Simple -> Project
and then File -> Import -> zipfile and then browse the zip file into the newly created project.
or else you can also unzip the zip file into a folder and then Use the option of Import an exisitng project into workspace. You can find this in the File-> import -> Existing project into workspace. and then use the Browse option to browse to the existing folder.
After importing the project you need to rebuild the project
Regards,
Raju Bonagiri.

Error while extracting zip file

I am using the following code to extract zip files from jar file
source = "zip/test.zip"
destination = "c:\\"
public void unzip(String source,String destination){
          try{
               ZipInputStream in = new ZipInputStream( this.getClass().getResourceAsStream(source));
               FileOutputStream fos = null;
               ZipEntry ze = null;
               File ff = null;
               while ( (ze=in.getNextEntry() ) != null ){
                    System.out.println( "name=" + ze.getName() );
                    ff = new File( destination + ze.getName() );
                    if ( ze.isDirectory() ){
                         System.out.println("making "+ze.getName()+" dir ("+ ff.mkdirs() +")");
                    else{
                         fos = new FileOutputStream( ff );
                         byte[] buf = new byte[1024];
                         int len;
                         while ((len = in.read(buf)) > 0){
                              fos.write(buf, 0, len);
                         fos.close();
                         System.out.println("wrote file "+ff.getPath()+" success=" + ff.exists() );
               in.close();
          }catch(Exception e){
               e.printStackTrace();
     }     But i found error in extracting zip file
java.io.FileNotFoundException: C:\eclipse\.eclipseproduct (The system cannot find the path specified)
I need some quick response on it.

Nothing to do with the resource path....thats fine. Use the code below.....most likely this will fix it.......
Added a check for directories that start with a ".". The File utility probably thinks its a file, also added a try....check it does make the "." directories.........dont forget the dukes.
    ZipInputStream zis = null;
    FileOutputStream fos = null;
    try
      zis = new ZipInputStream( new FileInputStream( "C:\\your_path\\your_zipfile_or_jar.zip" ) );
      ZipEntry ze = null;
      File ff = null;
      while ( ( ze = zis.getNextEntry() ) != null )
        System.out.println( "name=" + ze.getName() );
        ff = new File( "C:\\your_path\\" + ze.getName() );
        if ( ze.isDirectory() || ze.getName().startsWith("."))
          try{ System.out.println( "making " + ze.getName() + " dir (" + ff.mkdirs() + ")" ); }catch(Exception e2){}
        else
          fos = new FileOutputStream( ff );
          byte[] buf = new byte[1024];
          int len;
          while ( ( len = zis.read( buf ) ) > 0 )
            fos.write( buf, 0, len );
          fos.close();
          System.out.println( "wrote file " + ff.getPath() + " success=" + ff.exists() );
      zis.close();
    catch( Exception ex )
      ex.printStackTrace();
    finally
      try { zis.close(); }catch(Exception ex){}
      try { fos.close(); }catch(Exception ex){}
    }

How do I open a pw protected zip file?

This question appears to be different from similar questions asked because I HAVE the password. I really don't want to download extra safe-cracker's-anonymous software to hack into it. The file just never gives me the option of entering it. I have the zip file, I double-click on it, it gives me an error message. I right-click on it but no options there either. How do I open it such that it gives me a chance to unlock it?
Appreciate the help. (and yeah, I have no idea if I'm in the right community - sorry about that if I'm in the wrong place)

The zip file format is not a nice, standardized format. You could have a weird zip file that is technically not bad, but isn't supported by the built-in software on Mac OS X. In some cases, when zip files won't open, I've had success opening them with The Unarchiver, which is available both in the App Store and outside it:
https://itunes.apple.com/us/app/the-unarchiver/id425424353?mt=12
http://unarchiver.c3.cx
(I don't know if there's a difference in functionality between the two... there could be, but if there is, I am not aware of it.)
It's also possible the zip file is corrupted, and won't be openable by anything.

Problem in unzipping the zip files

Hi,
I have created a program to unzip the zip files. But when i try to zip it is creating the zipped files outside the folder where it is to be zipped.
what is wrong with my code.
if the zip file is migration.zip
if the path inside the zip file shows
and the path inside says this
/codebase/scripts/
it would create migration folder and create codebase folder outside the migration folder
what is wrong with my code
//Unzip the zip files to the folder with their name
import java.io.BufferedReader;
import java.io.File;
import java.io.FileOutputStream;
import java.io.FilenameFilter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
// Getting the path to find the type of files
public class zipper implements FilenameFilter{
          String ext;
          public zipper(String ext)
               this.ext="." + ext;
          public boolean accept(File dir,String name)
               return name.endsWith(ext);
public static void main(String args[]) throws IOException
          try
                    String dir = "D:/a/";
                    File f2 = new File(dir);
                    FilenameFilter fn= new zipper("zip");
                    String ss[]=f2.list(fn);
               for ( int j = 0; j < ss.length; j++)
                    System.out.println(" Extracting ...." + ss[j]) ;
                    String zipFile = dir + ss[j];
                    ZipFile zf = new ZipFile(zipFile);
                    Enumeration entries = zf.entries();
                    String directoryName = zf.getName();
                    directoryName = directoryName.substring(0, (directoryName.indexOf(":" + File.separator) + 2));
                         String folderName = zf.getName();
                         folderName = folderName.substring(0, folderName.lastIndexOf("."));
                         File file1 = new File(folderName);
                         //File file1 = new File(entries.getName());
                         file1.mkdir();
               while (entries.hasMoreElements())
                         ZipEntry ze = (ZipEntry) entries.nextElement();
                         String path = directoryName + ze.getName() ;
                         String path1 = folderName + ze.getName();
                         //System.out.println(" : " + path);
                         if (ze.getName().endsWith("/"))
                                   File file = new File(path);
                                   file.mkdir();
                                   continue;
                                   //break;
                    BufferedReader bReader = new BufferedReader(new InputStreamReader(zf.getInputStream(ze)));
     StringBuffer fileBuffer = new StringBuffer(" ");
     String line ;
                    while ((line = bReader.readLine()) != null)
                              fileBuffer.append(line);
                              fileBuffer.append("\r\n");
                              //line = line + "\r\n";
                              //byte[] b = new byte[line.length()];
                              //b =line.getBytes();
                              //out.write();
                    String fileData = fileBuffer.toString();
     File f1 = new File(path);
                    f1.createNewFile();
                    //FileOutputStream out = new FileOutputStream(folderName + "/" + ze.getName());
                    FileOutputStream out = new FileOutputStream(path);
                    long size = ze.getSize();
                    byte[] data1 = new byte[fileData.length()];
                    for (int i = 0; i < fileData.length(); i++)
                              data1[i] = (byte) fileData.charAt(i);
     out.write(data1);
     out.close();
                    bReader.close();
               } catch (Exception e)
                         e.printStackTrace();
Thanks in Advance
Avinash

String path = directoryName + ze.getName();
String path1 = folderName + File.separator+ ze.getName();
File f1 = new File(path); // pass path1 instead of path
f1.createNewFile();
FileOutputStream out = new FileOutputStream(path); // pass path1 instead of path

Problem in Unzipping the zip file

Hi
I have created a program to unzip the zip files in the folder named after the zip file
it is working well well when u try to zip zip files put in a directory
i.e u create a folder name contents and put files into that and then zip it
but when u directly create a zip file , without putting in a folder
it creates the folder and zip the files outside the folder
Another problem is that with the path
for e.g. suppose the zip file name is contents and path should show
contents/filename.txt but there are some other files whose path shows
res/file.txt. In this case it creates a folder of res and put it outside the
folder with the name of zip file
I have pasted my code :
//Unzip the zip files to the folder with their name
import java.io.BufferedReader;
import java.io.File;
import java.io.FileOutputStream;
import java.io.FilenameFilter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
// Getting the path to find the type of files
public class zipper implements FilenameFilter{
          String ext;
          public zipper(String ext)
               this.ext="." + ext;
          public boolean accept(File dir,String name)
               return name.endsWith(ext);
public static void main(String args[]) throws IOException
          try
                    String dir = "D:/";
                    File f2 = new File(dir);
                    FilenameFilter fn= new zipper("zip");
                    String ss[]=f2.list(fn);
               for ( int j = 0; j < ss.length; j++)
                    System.out.println(" Extracting ...." + ss[j]) ;
                    String zipFile = dir + ss[j];
                    ZipFile zf = new ZipFile(zipFile);
                    Enumeration entries = zf.entries();
                    String directoryName = zf.getName();
                    directoryName = directoryName.substring(0, (directoryName.indexOf(":" + File.separator) + 2));
                         String folderName = zf.getName();
                         folderName = folderName.substring(0, folderName.lastIndexOf("."));
                         File file1 = new File(folderName);
                         //File file1 = new File(entries.getName());
                         file1.mkdir();
               while (entries.hasMoreElements())
                         ZipEntry ze = (ZipEntry) entries.nextElement();
                         String path = directoryName + ze.getName() ;
                         String path1 = folderName + ze.getName();
                         //System.out.println(" : " + path);
                         if (ze.getName().endsWith("/"))
                                   File file = new File(path);
                                   file.mkdir();
                                   continue;
                                   //break;
                    BufferedReader bReader = new BufferedReader(new InputStreamReader(zf.getInputStream(ze)));
     StringBuffer fileBuffer = new StringBuffer(" ");
     String line ;
                    while ((line = bReader.readLine()) != null)
                              fileBuffer.append(line);
                              fileBuffer.append("\r\n");
                              //line = line + "\r\n";
                              //byte[] b = new byte[line.length()];
                              //b =line.getBytes();
                              //out.write();
                    String fileData = fileBuffer.toString();
     File f1 = new File(path);
                    f1.createNewFile();
                    //FileOutputStream out = new FileOutputStream(folderName + "/" + ze.getName());
                    FileOutputStream out = new FileOutputStream(path);
                    long size = ze.getSize();
                    byte[] data1 = new byte[fileData.length()];
                    for (int i = 0; i < fileData.length(); i++)
                              data1[i] = (byte) fileData.charAt(i);
     out.write(data1);
     out.close();
                    bReader.close();
               } catch (Exception e)
                         e.printStackTrace();
Thanks in Advance
Avinash

String path = directoryName + ze.getName();
String path1 = folderName + File.separator+ ze.getName();
File f1 = new File(path); // pass path1 instead of path
f1.createNewFile();
FileOutputStream out = new FileOutputStream(path); // pass path1 instead of path

Is there a way to add a password to either a zipped file or a m4v file?

Either using the apps that are included or any FREE app thanks

Well, first, there are a couple caveats. If you want to compress your home folder into an encrypted .zip file, you wouldn't want to place that .zip file on the desktop. There could be problems with trying to put the .zip file inside the folder you are zipping! I would put it at the root level of the hard drive instead. Second, if this is something you want to do regularly, as a means for creating an encrypted backup of the home folder or something similar, this isn't a very efficient or easy method. Creating such a large .zip file will take a long time, and it will have to be re-created from scratch every time you want to update the backup. It would be better to use a specific tool for that task.
However, all that said, to create a zip archive named cool.zip at the root level of the hard drive, containing the entire home folder, you would execute the following command:
zip -e /cool.zip /Users/yourusername
You should also be able to substitute '~' for your home folder path:
zip -e /cool.zip ~
If you wanted to create an archive of your Documents folder and place it on the desktop, to give another example, here's the command you would use:
zip -e ~/Desktop/cool.zip ~/Documents
Hope all that helps!

How many files that JAR can bundle into a single file?

How many files that JAR can bundle into a single file?

The are no limitations inherent in the ZIP file format (jar files are basically just zip files).
The only limitations I can think of are;
available disk space
maximum file size (for some filesystems)

Possible trojan .zip file in jar folder

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