Code to genereate difference between succcessive dates in a table

Question

First create and Insert statements;
create table schedule(iloan_code number , schedule_date date);
insert into schedule values(1001, to_date('01-jun-2012'));
insert into schedule values(1001, to_date('01-jul-2012'));
insert into schedule values(1001, to_date('01-aug-2012'));
insert into schedule values(1001, to_date('01-sep-2012'));
insert into schedule values(1001, to_date('01-oct-2012'));
commit;THe output of the SCHEDULE table shall be now like this:
ILOAN_CODE     SCHEDULE_DATE
1001              01-JUN-12
1001              01-JUL-12
1001              01-AUG-12
1001              01-SEP-12
1001              01-OCT-12we want an extra column by name DAYS along with the existing columns which would be the difference between the dates.
First row should be the difference between sysdate and the date 01-jun-2012 and the successive rows must be the difference between successive schedule dates
For instance in the second row the DAYS column must represent the difference between 01-jul-2012 and 01-jun-2012 and so on for the next rows too.
We need to get the output through a SELECT statement
The output of the SCHEDULE table must be somthing like this.
iloan_code      schedule_date     days     Logic which we need
1001     1-Jun-12     22     sysdate-1st June 2012
1001     1-Jul-12     30     difference between 1st July 2012 and 1st June 2012
1001     1-Aug-12     31     difference between 1st aug 2012  and 1st July 2012
1001     1-Sep-12     31     difference between 1st sep  2012 and 1st aug  2012
1001     1-Oct-12     30     difference between 1st oct 2012 and 1st sep 2012Please advise;

Answer 1

Hi,
sri wrote:
... Could you please let me know the formatting procedure used for the output . I have used (code) (code) (you can consider ( for { ) concept but could not display the
expected results properly.I'm not sure what you're saying.
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