Calculate the difference between two dates times in infopath form 2013
Hi,
I have an infopath 2013 form that contains three fields:
2 date time and the 3rd contains the difference between the two in hours
how I can make the difference between the two so that the display will be like this:
Date Time1 08/21/2014 22:00
Date Time2 08/22/2014 1:00
Diff Field 3:00
Hi,
Please refer to the following article which matches your requirement exactly.
Calculate the difference between two date picker controls in InfoPath using rules and formulas - no code!
Please mark it answered, if your problem resolved.
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Calculate the Difference Between two dates excluding weekends and Holidays
Hi,
We need to calculate the difference between the two dates by excluding the Local public holidays (It is global and varies across countries) and weekends should not be included in calculation for a business day in OBIEE.
We have two dates: Open date and close date when ever close date is null we are calculating age based on taking the current timestamp and need to exclude the weekends and Holidays when ever the close date is null.
Ex:
Col1 col2 Total
11/9/2010 2:46:38 PM Null 13
11/2/2010 8:06:26 PM 11/3/2010 5:37:03 PM 1
(In the Total we shouldn't include the weekends,holidays)
Please let me know how to calculate the difference between two dates by excluding the weekends and holidays.
Thanks
Edited by: user10441472 on Nov 22, 2010 3:14 PMYou already asked this question and I answered it...
Re: calculation of Business day in OBIEE -
Calculate the difference between two dates
I would like to calculate the difference between two dates in PL/SQL and return the result as a number of days expressed as an integer value.
Denes,
A fair point, I should really have posted this on the SQL forum (I'm new to the forum as well as PL/SQL) but thanks for responding anyway. It does raise a question as to how to implement this in ApEx though.
I have created the function and am calling it as shown below from the source window of a form. The source type is 'PL/SQL expression or function' and the expression in the source window of the form is:
calc_date_difference (:p26_c_payment, :p26_c_rec)
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Is it possible to do it this way or am I taking completely the wrong approach?
Regards
Sandy
This is not ApEx related but SQL related:
CREATE OR REPLACE FUNCTION calc_date_difference (
p_date_1 VARCHAR2,
p_date_2 VARCHAR2
RETURN NUMBER
v_difference NUMBER;
v_sql_err VARCHAR2 (4000);
BEGIN
v_difference := TRUNC (TO_DATE (p_date_1)) - TRUNC
(TO_DATE (p_date_2));
RETURN v_difference;
CEPTION
WHEN OTHERS
THEN
v_sql_err := SQLERRM || CHR (10) || CHR (10) ||
SQLCODE;
ND calc_date_difference;and
SQL> SELECT calc_date_difference ('23.01.2007',
'20.01.2007') diff
2 FROM DUAL;
DIFF
3
Denes Kubicek -
How to calculate the difference between two dates?
Hello,
I would like to write some code which figures out how many days are between the Date_of_change (which is of datatype DATE, length 7 and of format DD-MON-YY) and the current date today. Then if the difference between Date_of_change and the current date is greater that 30 days for example then I would like to delete that record from the database.
Thanks
DougSomething like this should work:
SQL> select * from emp order by hiredate ;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7934 MILLER CLERK 7782 21-OCT-2005 1300 10
7902 FORD ANALYST 7566 22-OCT-2005 3000 20
7900 JAMES CLERK 7698 23-OCT-2005 950 30
7876 ADAMS CLERK 7788 24-OCT-2005 1100 20
7844 TURNER SALESMAN 7698 25-OCT-2005 1500 0 30
7839 KING PRESIDENT 26-OCT-2005 5000 10
7788 SCOTT ANALYST 7566 27-OCT-2005 3000 20
7782 CLARK MANAGER 7839 28-OCT-2005 2450 10
7698 BLAKE MANAGER 7839 29-OCT-2005 2850 30
7654 MARTIN SALESMAN 7698 30-OCT-2005 1250 1400 30
7566 JONES MANAGER 7839 31-OCT-2005 2975 20
7521 WARD SALESMAN 7698 01-NOV-2005 1250 500 30
7499 ALLEN SALESMAN 7698 02-NOV-2005 1600 300 30
7369 SMITH CLERK 7902 03-NOV-2005 800 20
14 rows selected.
SQL> delete from emp where hiredate < sysdate - 30 ;
10 rows deleted.
SQL> select * from emp order by hiredate ;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7566 JONES MANAGER 7839 31-OCT-2005 2975 20
7521 WARD SALESMAN 7698 01-NOV-2005 1250 500 30
7499 ALLEN SALESMAN 7698 02-NOV-2005 1600 300 30
7369 SMITH CLERK 7902 03-NOV-2005 800 20
4 rows selected.
SQL> -
Java code to get the difference between two dates in days
Hi ppl,
I need to write a user defined function to get the difference between two date nodes, in days.Please help me out
regards,
PrashanthHi,
have a look at those two:
(How do I calculate the difference between two dates?)
http://joda-time.sourceforge.net/faq.html
Calculating the Difference Between Two Datetime Stamps
http://www.xmission.com/~goodhill/dates/deltaDates.html
Get difference in days
http://javaalmanac.com/egs/java.util/CompDates.html
Regards,
michal -
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Hi all,
Is there any function module to calculate difference between two dates/times which are in TIMESTAMPL format.
I need to know how many millisconde(second,minutes, hours... )there is between these two times.
Please, It is urgent
Thank you all.
Karimhi,
try the following function
CALL FUNCTION 'CCU_TIMESTAMP_DIFFERENCE'
EXPORTING
timestamp1 = timestamp1
timestamp2 = timestamp2
IMPORTING
difference = diff
EXCEPTIONS
OTHERS = 1.
the above function gives the difference in seconds...
try the following code to set the resolution to milliseconds..
SET RUN TIME CLOCK RESOLUTION LOW
check the thread for details:
SET RUN TIME CLOCK RESOLUTION?
all the best!!!
Regards,
Aparna -
To calculate the difference between two periods in SSM
Hi,
I have two questions need to be clarified.
Question 1: I have KPI named Revenue growth and the formula to calculate is (current year revenue - previous year revenue).I am using data entry& approval.Is that technically possible to calculate the revenue difference between two periods in SSM?
Question 2: Is that possible to enter the date as input for the variable?for example i want find the difference between two dates and the difference value is output for my variable.
Regards
BalaHi:
Question 1:
We have same problem, and what we did is to create:
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R1 = Revenue current year
R2 = Revenue previous year
- 1 virtual KPI
R3 = R2-R1
Question 2:
I don't know.
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Calculate the Difference between 2 dates
Please let me know how to Calculate the Difference between 2 dates in Time Management. I have a hire date(U1) and adjusted Service Date(B2)
I need to Find out the number of Years, Days and Months between these 2 dates
Thanks a lot in AdvanceHi Rahul,
You can take a look at the standard function 'HR_HK_DIFF_BT_2_DATES' and see if it suits your need.
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Francis -
As to the data type of the data type of the difference between two date type of datas
Hi,
I have a question about the data type of the difference between two date type of datas.
There are two date type of datas as:
SSHIPMENTS.RECEIVEDATETIME
SSHIPMENTS.PROMISEDATETIME
I try to use the following SQL Script in Oracle SQL*Plus as:
SELECT CASE
WHEN (SSHIPMENTS.RECEIVEDATETIME - SSHIPMENTS.PROMISEDATETIME) < '000 01:00:00.000' THEN 'OnTime'
WHEN (SSHIPMENTS.RECEIVEDATETIME - SSHIPMENTS.PROMISEDATETIME) < '000 01:30:00.000' THEN '60-89 Minutes'
ELSE '3+ Hours'
END
FROM SSHIPMENTS;
The error message of "Invalid Number" for the '000 01:30:00.000' happens.
I don't know if the data type of the interval is wrong.
Many Thanks,
CathySELECT CASE
WHEN (to_char(SSHIPMENTS.RECEIVEDATETIME,'hhmiss') - to_char(SSHIPMENTS.PROMISEDATETIME,'hh24miss')) < '010000' THEN 'OnTime'
WHEN (to_char(SSHIPMENTS.RECEIVEDATETIME,'hhmiss') - to_char(SSHIPMENTS.PROMISEDATETIME,'hh24miss'))< '000 01:30:00.000' THEN '60-89 Minutes'
ELSE '3+ Hours'
END
FROM SSHIPMENTS;
just try it out.. -
How to get the difference between two date
Hello,
I want to know how to write a code the tell me the difference between two date, I am using
oracle.jbo.domain.Date
i have a rent date and return date so my code is
Date rent=(Date)nr.getAttrbute("RentDate"),ret=(Date)nr.getAttrbute("ReturnDate");
is there a way to know the difference in days between those two dates ?
Thankshi,
try this.....
DateFormat formatter = new SimpleDateFormat("E MMM dd HH:mm:ss Z yyyy");
Date date = (Date)formatter.parse(dateStr); //// dateStr <- from date value (that is string value)
Date dateto = (Date)formatter.parse(datetostr); //// datetostr <- to date value (to date getting from as a string)
Calendar cal = Calendar.getInstance();
cal.setTime(date);
Calendar calto = Calendar.getInstance();
calto.setTime(dateto);
fromDate = cal.get(Calendar.DATE) + "/" + (cal.get(Calendar.MONTH) + 1) + "/" + cal.get(Calendar.YEAR);
toDate = calto.get(Calendar.DATE) + "/" + (calto.get(Calendar.MONTH) + 1) + "/" + calto.get(Calendar.YEAR);
// System.out.println("from Date : " + fromDate);
if ((fromDate != null && toDate != null) && (date.compareTo(dateto) > -1) ) {
fc.addMessage("VacationQueryComponent", new FacesMessage(FacesMessage.SEVERITY_ERROR, "From Date cannot be lower than To Date", "From Date cannot be lower than To Date"));
fc.renderResponse();
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Calculate the difference between Creation date and key date
Hello
I want to calculate the difference between creation date of the document with key date(todays date). How can i do that in the query designer. Also then I want to restrict my key figure on this difference if it is =10..please can someone suggest what can be done
thanksHi Grame...
For the days calculation ..
I suggest you to use replacement path ..
I have the reference that you can see the sample. The case of samples is also about day calculation.
http://www.sd-solutions.com/documents/SDS_BW_Replacement%20Path%20Variables.html
Hopefully it can help you a lot.
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Niel. -
Hi,
I am new to Labview. This question might be a joke to some of you here, but any help would be greatly appreciated. I have a spreadsheet with time stamps and power outputs from a generator. I am supposed to calculate the difference between consecutive time stamps, which will act as a delay for the next power output update that needs to be sent. For example, lets say that I have to following data:
Time Stamp Power Output
11:00:00 AM 3kW
11:00:02 AM 2.9kW
11:00:04 AM 3.2kW
11:00:06 AM 3.1kW
The above data doesn't make any sense, but it is just for the purpose of this question.
So, I have to read 11:00:00 AM and 3kW initially - 3kW is the initial request thatHello
you can simple subtract one time from the other one and so you get the difference. -> Example
Mike
Attachments:
Unbenannt 2.vi 8 KB -
How do I calculate the difference between two times?
I am so embarrassed by the fact that I can't figure this out.
Cell B2- 8:00 am
Cell C2- 10:50 am
Cell D2- (How do I get this cell to calculate the difference and say 2:50?)
I know this is probably one of the most basic operations, but for the life of me I can't figure it out. Cells B2 & C2 are formatted for 24 hour clock. But if I tell the system to just subtract the two, I get "0.118". Everything I find on the forum search goes beyond what I need. Can anyone help me?
Thank you.KOENIG Yvan wrote:
Numbers states clearly in the Help and the PDF Users Guide that it doesn't know a "duration" object but a time one which is restricted to the range 00:00:0 to 23:59:59.
When I search the U.S. language Numbers User Guide for the word "duration," it is not found.
What may be more clear: _duration is not available but time is_?
Once again your response resemble to a rant againt the Help and the User Guide.
In the Help:
+date-time Any Numbers date/time value. _While you can choose to display only date or time in a cell, all Numbers date or time values contain both the date and time._+
Which wording would be more clear and precise?
TIMEVALUE
+The TIMEVALUE function converts a date, a time, or a text string to _a decimal fraction of a 24-hour day._+
Which wording would be more clear and precise?
TIME
+The TIME function converts hours, minutes, and seconds into a time format.+
+TIME(hours, minutes, seconds)+
+hours: The number of hours _(using a 24-hour clock)._+
+minutes: The number of minutes.+
+seconds: The number of seconds.+
Notes
+You can specify hour, minute, and second values greater than 23, 59, and 59, respectively. _If the hours, minutes, and seconds add up to more than 24 hours, Numbers subtracts 24 hours repeatedly until the sum is less than 24 hours._+
Which wording would be more clear and precise?
In the User Guide:
page 190
+date-time Any Numbers date/time value. _While you can choose to display_+
+_only date or time in a cell, all Numbers date or time values contain_+
+_both the date and time._+
+TIME (page 277) Converts a time to a decimal fraction of a 24-hour day.+
+TIMEVALUE (page 278) Converts a time in a string to a decimal fraction of a 24-hour day.+
TIME
+The TIME function converts the specified time to a decimal fraction of a 24-hour day.+
+TIME(hours, minutes, seconds)+
+• hours: The number of hours _(using a 24-hour clock)_.+
+• minutes: The number of minutes.+
+• seconds: The number of seconds.+
Notes
+You can specify hour, minute, and second values greater than 23, 59, and 59,+
+respectively. _If the hours, minutes, and seconds add up to more than 24 hours,_+
+_Numbers subtracts 24 hours repeatedly until the sum is less than 24 hours._+
+You can also specify fractional values for hours, minutes, or seconds.+
TIMEVALUE
+The TIMEVALUE function converts a time in a string to a decimal fraction of a 24-hour+
day.
TIMEVALUE(date-time)
+• date-time: A date, a time, or a string in any of the Numbers date and time formats.+
As you may check, the infos are exactly the same in the Help and in the Guide.
And I really don't understand how you may find them unclear.
Yvan KOENIG (from FRANCE lundi 4 août 2008 14:57:36) -
Find the difference between two dates for the specific month and year
Hi,
I have two dates, start date is 30/12/2012 and end date is 04/01/2013. Using datediff I found the difference of days between two dates. But I find the no of days in January 2013. ie output is 4 instead of 6. I input month and year to find the no of days
for that date. In this case I input Jan 2013. How can I sql this ?I don't understand how most of the answers provided here not analytically solving the problem with many cases possible.
First let me understand you:
You have 2 dates range and you want to calculate day range for specific month and year between the original date range.
declare @for_month int = 1 --January
declare @for_year int = 2013
declare @StartDate date = '2012-12-20'
declare @EndDate date = '2013-01-04'
SELECT
CASE
WHEN (DATEPART(MONTH, @StartDate) = @for_month and DATEPART(MONTH, @EndDate) = @for_month) and ((DATEPART(YEAR, @StartDate) = @for_year or DATEPART(YEAR, @EndDate) = @for_year)) THEN
DATEDIFF(DAY, @StartDate,@EndDate)
WHEN (@StartDate < cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (@EndDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, DATEADD(MONTH, DATEDIFF(MONTH, -1, @EndDate)-1, 0),@EndDate)
WHEN (@EndDate > cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) and (@StartDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, @StartDate,DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, @StartDate) + 1, 0))) + 1
WHEN ((DATEDIFF(DAY, @StartDate, cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) >= 0) and (DATEDIFF(DAY, cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date), @EndDate) >= 0)) THEN
DATEDIFF(DAY, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime), DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime)) + 1, 0))) + 1
ELSE
0
END as [DD]
I don't know how you calculate day range between 01/01/2013 and 04/01/2013
is 4, it is actually is 3 but if that is the case, you can add 1 from the condition. -
How to get the difference between two dates???
HI I have two dates and I want to test if there is an hour between them.
Is there a way to compare two dates like mySQL can with dateDiff(date1,date2);
Thanks alot.
GrahamThis link is now out of date as they have revamped the structure. Yep. Here it is again: http://forum.java.sun.com/thread.jsp?forum=31&thread=502686
I've also noticed that my comment regarding daylight saving was misleading. The demonstrated method for calculating difference between Dates is reliable. However, one needs to be careful when interpreting Dates in a daylight saving timezone.
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