Column selector for list of values

Hi,
is it possible to use column selector to select list of values of a certain column? I mean similar to dashboard prompts? We may have a situation that the environment we use does not allow us to use dashboard prompts in certain cases. If not, is there a way to separate lov's from each other in pivot tables? Now if we select two columns, lov will look like column1-column2 with all possible combinations and we don't want that.
BR,
Mari

Use a pivot table view to achieve this requirement.
open pivot view properties-->place the required column in the pages--->try the result
It will work like a prompt in the report.
mark if helpful/correct..
thanks,
prassu

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Query for listing several values in same field

Hi,
is there a function for listing more than one value in the same field, only with comma seperation?
For example, I want to group by cardcode from ORDR and list all docnum's like this:
Cardcode    Docnum's
21355          98765, 95498, 95164
21564          95484, 54684, 95654, 98465
21865          95484, 12486
Kind regards
Kjetil Sandvik

HI,
Thank for your replies.
We need to update all old orders for sure, but my idea was to use this query:
Select CardCode, COUNT(Address2) From ORDR Where Docstatus <> 'C' GROUP BY address2, cardcode order by cardcode, address2
The results will give me two lines for each customer and count the addresses, so then I know that the count of one of the lines must me changed. Let's say there is 20 orders with new address and 20 orders with old address, my intention was to manually change the 20 orders that is old. Instead of checking all 40, It would help alot to list all order numbers in a column beside in the query.
BR
Kjetil

Range from columns based on list of values

Hi,
I have a table that has a key_code and a alt_code like this
with values like so.. (has 2 million records in 8.1.7 Database)
KEY_CODE ALT_CODE
0001     AA
0001          AB
0001          AF
0001          G4
0001          G5
0001          G6
0200          BB
0200 BC
0200 BD
0200 Bx
I'm struggling with the concept of how to create a range of these values.
There is one problem I'm running into.
The alt code must be in a valid code list to have a break in the range
An example would be
VALID ALT_CODES TABLE
B1
B2
ZA
ZB
ZC
ZH
ZJ
ZK
WHAT I'M LOOKING FOR IS THE OUTPUT TO BE
KEY_CODE          BEGRANGE               ENDRANGE
10               B1                    B2
10               ZA                    ZK
20               ZA                    ZJ
WHAT I'VE GOT SO FAR IS
SOMETHING THAT LOOKS LIKE
THE PROBLEM IS THAT THE VALID ALT_CODE LIST IS NOT SEQUENTIAL AND THERE ARE GAPS.
SO IF, FOR EXAMPLE THERE IS NO CODE ZD IT WILL BREAK A RANGE ON IT THE VALUE BETWEEN ZC AND ZH
WHEN I DON'T WANT IT TO.
KEY_CODE          BEGRANGE               ENDRANGE
10               B1                    B2
10               ZA                    ZC
10               ZH                    ZH
10               ZJ                    ZK
20               ZA                    ZC
20               ZH                    ZH
20               ZJ                    ZJ
I'd be most grateful for your input.

Ditto.
And where the hell does this row come from (not to mention the 10s and 20s being totally different key codes from the first table)?
KEY_CODE BEGRANGE ENDRANGE
10 B1 B2
10 ZA ZK
20 ZA ZJ <-- ??

How to get count of unique values of column B for each unique value of column A in Excel 2010?

I have an excel sheet containing 72,000 rows in Excel 2010, column A is "site name", column B is category. I want a result that shows number of sites for each category.
Column A Column B
site 1 Category 1
Site 1 Category 1
Site 2 Category 1
site 3 Category 2
site 3 Category 2
site 4 Category 2
site 5 Category 2
I want this result:
Category 1 2
Category 2 3
I tried some formula in a 3rd column and created a pivot table on that column, but it did not give me the result i want.
Any one has an idea ? what is the easiest way to achieve this?
Appreciate any pointer

I tried both formula referenced in these two post (I think they are a little simpler than the one above):
http://stackoverflow.com/questions/11876238/simple-pivot-table-to-count-unique-values
http://stackoverflow.com/questions/18898138/pivot-table-count-unique-values-excel-2010
They both worked! and I got the result for my 72,000 rows!
Thanks for your help!

Display a column with a list of values from DUAL;

Hello, how can I display something like:
COL1
A
B
C
D
E
F

On my planet these are 'words' ;) :
SQL> select dbms_random.string('a', level)
2 from dual
3 connect by level <= 10;
DBMS_RANDOM.STRING('A',LEVEL)
r
BB
pmE
bHri
aZZDC
FzOZBf
fXfPyIP
LOqrQbnK
AYzNgHcGc
lvxRvflHXj
10 rows selected.
SQL> select dbms_random.string('a', dbms_random.value(10, 50))
2 from dual
3 connect by level <= 10;
DBMS_RANDOM.STRING('A',DBMS_RANDOM.VALUE(10,50))
AKExSSzIJOkabCT
VCHHRTcgtnBSlZyRmsITqzWqVNgDnPdnxmt
qLnuyGQErxZvHttRBpWrPoLEiGUra
rcllLkyZXiwvlcGaUoEAeMbEdZSHlZBIgdilgGTQzxlIUW
ftnGzDCzUBEsxKzhDLfgS
aqUmpIzjqkWMZGpbAchhbiqFBUKdRaDwFAgdP
nskqNdzmlAKlsGOJpbKfQHiCfvkDpoFcTkTvKaUcGLFDkgjsX
fwkxBSoVuDSEOFldgDhilvm
iAnSvDMQzamGvIFNydfjhr
lHRPUnKgOxYQwWAltdELJNqqfgMRSmbBpSDnjOsfx
10 rows selected.http://download.oracle.com/docs/cd/B19306_01/appdev.102/b14258/d_random.htm#CDEJAHCB

Set Column Selector Default Value

Hi Gurus,
Does anyone know how to set default value for column selector. In my column selector I have two values let's say employee_name and employee_id. How can I set my column selector always to employee_id as default. Any resolution or workaround would be useful.
Thanks,
Joni

Joni,
You can't achieve this
====
But can i click include column selector on employee_name column and then I add employee_id and use employee_id as default column selector
===
As, I said above whatever is the first column becomes default. Incase, you are getting wrong results then you need to check your report first as I believe EMP ID to EMP NAME shud be 1 to 1 relation.
Hope this was useful..

Dynamic columns in column selector

Hi All,
I have a report with two column selector for X and Y axis . I want to change the columns in the column selector based on the value selected in the dashboard promt.
Please help me ..

Read about Presentation Variables in the Answers documentation. That should do the trick

Finding Columns with only NULL as values

I have a list of tables around 30 in number. Among them i need to generate a report with Table Name and Column Names, for which all values are NULL.
In other words, i need to find all the columns for which all the values are NULL.
I thought of dealing it with cursors, and comparing the total count with null count in each column. But i need to loop "Number of columns" times. Is there any better way to do this?

I think your way is a good solution. It has the advantage that you can check several columns in one select.
select count(*), count(col1), count(col2) ... from mytabAnother approach could be to check statistical information about your table data.
However this will not give you always the correct data.
It depends on the time of the last statistic collection, the sample size and on the detail level.
Here is a sample statement to play with:
select owner, table_name, column_name, num_distinct, num_nulls, num_buckets, sample_size, low_value, high_value
from all_tab_columns
where owner not in ('SYS','SYSTEM')
and nullable = 'Y' -- null values allowed
and num_distinct = 0 -- only nulls found
--and density = 0
;Note that this select would not return tables for which no statistics had been calculated. Num_distinct is NULL in such a case.
Edited by: Sven W. on Feb 11, 2010 2:50 PM

Column display based on Prompt value ( Urgent Please)

Hi Gurus,
I have requirement to create the prompt based on the column, if i selected perticular column heading then i have to see the data of that column otherwise not.
Example.
column names: call attended, call droped, call time, service
Report columns
Region, call attended, call droped, call time, service, Fiscal Month
east 100 10 23 20% Jan
west 230 5 24 30% Jan
east 120 10 23 20% Feb
west 200 5 24 30% Feb
Client want to have a pivot table view and want to have the call attended, call droped, call time as values in the prompt
example if i selected in the prompt Call attended then i should report display like this
______ Jan 2011 : Feb 2011
Region
East 100 120
West 230 200
I am kind a confused and i am looking on web i didnt get any info. Please help me
Regards
Ali

Hi Gurus,
I got my answer. I followed the content of the link and i am able to slove my issue. Thought to share with communite members.
http://www.biconsultinggroup.com/obiee-tips-and-tricks/using-a-dashboard-prompt-as-a-column-selector-for-multiple-r.html
Regards
Ali

OBIEE 11g (11.1.1.5...)Column Selectors and Action Links

All,
I think we have bug - we have a column selector for 3 columns. One of them is configured to navigate to another analyses page (we have only one action link configured) . we have checked the option - "Do not display in a popup if only one action link is available at runtime". The issue is the pop-up still shows up even if there is only one action link. The issue is only for a column group.
Please let us know if anyone has figured out a work around.
Thanks
Edited by: user709926 (Kottresh Kogali) on Sep 13, 2011 2:00 PM

Hi,
Yes, we do face this issue.There is no workaround for this issue as of now.
Rgds,
Dpka

Rest drill on column selector change.

Hi all,
We have a column selector for our table, and a defined dimension. There is a requirement that when the user has drilled down, to any level in the dimension, when he/she changes the column in the column selector it resets the drill to the top level of the dimension.
The current default behaviour is that is does not, and the drill remains in place when changing the column selector.
I have has a play around and couldnt come up with anything. Is this at all possible? Is so, how does one go about achieving such behaviour.
Much appreciated.

i have a workaround..
But this can't use the TITLE view..
1. Add both the columns in your col selector to the criteria
2. Create 2 pivots, first one with your default columns (exclude the col selector one here)
3. Other with the other col selector column (exclude the default one here)
4. Create a View Selector with these two pivots
5. Expose this View Selector as Col Selector in compound layout..
Regards,
Raghu

Lov - List of values

people,
am using jdveeloper11g 11.1.1.4.0
first of fall i want do in input text with List of Values
if i select city means
corresponding state and country must be displayed.
can one guideme or else
paste the link regarding this.

hi..
You can archive that with your VO.
In model project double click on sampleVO --> Attributes --> select relevan field --> press green + button for list of value --> select or Add list data source by pressing green + and Add relevant view accessors to shown state and country,finally edit UI hints as you want with adding state and country.
hope this will helpful..

Column selector addition on drill down.

Hi,,
Problem: Can we dynamically add column selectors for those column which appear after drill down...
Details:
we have a report where we have 3 columns,
A, B
1st & 2nd columns have selectors on them...
1st col -> Select A or B
2nd col -> Select B or A
now if i drill on col 1 i get
A, C , B
Can i some how put a column selector on top of it to slice n dice the report..
I.e. now i get
1st col -> Select A or B Or C
2nd col -> Select B or A or C
3rd col -> Select C or A or B
Thanks,
Dev

No i want it on the report level & dont want to change the navigation path...
For ex: i have a column whihc has a column selector. I click on the data in it & I get the next level on the report.
Year
Year --> Quarter
now I want a column selector for the next level too. Can we manage doing this on drill down.?
Thanks,
Dev

We are trying to do a Quick payment from payment workbench and getting 'FRM-41830: List of values contains no entries' error for payment document column/field. Payment document setup looks good. Not sure what the issue is.

We are trying to do a Quick payment from payment workbench and getting 'FRM-41830: List of values contains no entries' error for payment document column/field. Payment document setup looks good. Not sure what the issue is.

Already gone through following three notes but didn't found resolution.
APXPAWKB: FRM-41830 When Clicking on Payment Document LOV (Doc ID 1081305.1)
R12: APXPAWKB: Payment Document Lov Is Empty When Entering A Payment (Doc ID 857587.1)
R12: Payment Workbench Error: FRM-41830 List Of Values Contains No Entries (APXPAWKB.FMB) (Doc ID 1323875.1)

Validation error message is not displayed for an attribute as an Input List Of Value

Hi everyone,
I use jdev 11.1.1.7.0
In my application I've created an Entity Obj and a View Obj base Employees table.
for the JobId attribute I've taken actions as listed below:
1. in Employees EO I've created a validation for this attribute and in some cases an error message returns (the error message is "the salary is not high"):
     * Validation method for JobId.
    public boolean validateJobId(String jobid) {
        if (...) {
            return false;
        if (...) {
            return false;
        if (...) {
            return false;
        return true;
2. in Employees VO I've created a LOV for this attribute (the view accessor is JobsViewObj ) and I display the attribute as an Input Text with List Of Values.
in jspx page I drag& drop this attribute as below:
          <af:inputListOfValues id="jobIdId"
                                popupTitle="Search and Select: #{bindings.JobId.hints.label}"
                                value="#{bindings.JobId.inputValue}"
                                label="#{bindings.JobId.hints.label}"
                                model="#{bindings.JobId.listOfValuesModel}"
                                required="#{bindings.JobId.hints.mandatory}"
                                columns="#{bindings.JobId.hints.displayWidth}"
                                shortDesc="#{bindings.JobId.hints.tooltip}"
                                autoSubmit="true">
            <f:validator binding="#{bindings.JobId.validator}"/>
          </af:inputListOfValues>
I open the Popup and I select a row from the Popup list and then I click Ok. After that if the validation method(validateJobId) returns false, the error message("the salary is not high") must be show to the user. but the error message doesn't display. I don't understand why this happens.
Can anybody guide me about this problem?
Regards
Habib

yes, you're right, I've tested it in 12.1.3 and error message was displayed.
it seems it's a bug(bad bug ) in both 11.1.1.7 and 12.1.2. and now what can I do? is there any way to display the the error message?
Regards
Habib

Column selector for list of values

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