Comma separated output into columns

Hi,
I've the following Query :
select ParameterValue
FROM Event.vEvent
join event.vEventParameter on event.vEventParameter.EventOriginId=event.vEvent.EventOriginId
where EventNumber=0
which gives the following output in a single column:
VSSDATA_FS,171423,106013,142420,11,248433,Wed Jun 4 03:40:58 EDT 2014
DATAGRP_FS,2302724,1074283,2208370,39,3282653,Wed Jun 4 07:54:26 EDT 2014
DATAPUB_FS,100837,5998,36688,49,42686,Wed Jun 4 03:04:42 EDT 2014
SHT_APT_FS,1008350,651,3906,84,4557,Mon Jun 2 03:12:35 EDT 2014
SHT_GER_FS,806699,809987,747788,52,1557775,Thu Jun 5 03:55:33 EDT 2014
DATAGRP1_FS,151256,24805,120496,33,145301,Tue Jun 3 05:11:31 EDT 2014
I need to separate the above output in different columns using separators as ',' (comma).
Please help me in achieving this as I'm a newbie in SQL.

pass it through a parameter
DECLARE @p varchar(max) = 'VSSDATA_FS,171423,106013,142420,11,248433,Wed Jun 4 03:40:58 EDT 2014
DATAGRP_FS,2302724,1074283,2208370,39,3282653,Wed Jun 4 07:54:26 EDT 2014
DATAPUB_FS,100837,5998,36688,49,42686,Wed Jun 4 03:04:42 EDT 2014
SHT_APT_FS,1008350,651,3906,84,4557,Mon Jun 2 03:12:35 EDT 2014
SHT_GER_FS,806699,809987,747788,52,1557775,Thu Jun 5 03:55:33 EDT 2014
DATAGRP1_FS,151256,24805,120496,33,145301,Tue Jun 3 05:11:31 EDT 2014'
SELECT Val
FROM dbo.ParseValues(@p,',')
ParseValues can be found here
http://visakhm.blogspot.in/2010/02/parsing-delimited-string.html
Please Mark This As Answer if it helps to solve the issue Visakh ---------------------------- http://visakhm.blogspot.com/ https://www.facebook.com/VmBlogs

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Inserting the Comma Separated Strings into Table

Hi Seniors,
i had two string and i want to insert the records in the Table COMMENT . In this way.
would u please give some programe to insert the records.
The Data and the Table
( 901,902,903,904 )
( 'hai','nice','good & mail is [email protected] ','excellent and the phone 011-235323' )
comm_id loc_id company_name comments
1      10 901      Hai
2      10 902      nice
3 10      903      good & mail is [email protected]
4      10 904      excellent and the phone 011-235323
Thanks
Seenu

Hi, Seenu,
In Oracle 10 (and up) you can easily split a comma-delimited list using REGEXP_SUBSTR.
INSTR and SUBSTR can do the same thing in any version, but it's more complicated.
See the general instructions below:
/*     How to Split a Delimited String
This shows how to take a single row with a delimited string, such as
     Animal     amoeba,bat,cedusa,dodo
and transform it into multiple rows:
     Animal     1     amoeba
     Animal     2     bat
     Animal     3     cedusa
     Animal     4     dodo
PROMPT     ========== -1. sep_char parameter ==========
VARIABLE     sep_char     VARCHAR2 (10)
EXECUTE     :sep_char := ',';
SELECT     :sep_char     AS sep_char
FROM     dual;
PROMPT     ========== 0. string_test table ==========
DROP TABLE     string_test;
CREATE TABLE     string_test
(     grp_name     VARCHAR2 (10)
,     list_txt     VARCHAR2 (50)
INSERT INTO string_test (grp_name, list_txt) VALUES ('Animal',     'amoeba,bat,cedusa,dodo');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Date',     '15-Oct-1582,16-Oct-2008');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Nothing',     NULL);
INSERT INTO string_test (grp_name, list_txt) VALUES ('Place',     'New York');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Skip',     'Hop,,Jump');
SELECT     *
FROM     string_test
ORDER BY     grp_name;
PROMPT     ========== Q1. Oracle 11 Query ==========
WITH     cntr     AS          -- Requires Oracle 9
(     -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
     SELECT     LEVEL     AS n     -- Requires Oracle 9
     FROM     dual
     CONNECT BY     LEVEL     <= 1 +     (
                         SELECT     MAX ( REGEXP_COUNT (list_txt, :sep_char) )     -- Requires Oracle 11
                         FROM     string_test
)     -- End sub-query cntr, to generate n (1, 2, 3, ...)
SELECT     grp_name
,     n
,     REGEXP_SUBSTR     ( list_txt     -- Requires Oracle 10
               , '[^' || :sep_char || ']'     -- Anything except sep_char ...
                    || '+'               -- ... one or more times
               , 1
               , n
               )     AS item_txt
FROM     string_test
JOIN     cntr                                   -- Requires Oracle 9
ON     n     <= 1 + REGEXP_COUNT (list_txt, :sep_char)     -- Requires Oracle 11
ORDER BY     grp_name
,          n;
/*     Notes:
     REGEXP_SUBSTR (s, '[^,]+', 1, n)
returns the n-th item in a comma-delimited list s.
If there are fewer than n items, it returns NULL.
One or more consecutive characters other than comma make an item, so
'Hop,,Jump' has two items, the second one being 'Jump'.
The sub-query cntr produces a list of integers 1, 2, 3, ..., w
where w is the worst-case (the largest number of items in any list).
This actually counts separators, not items, (e.g., it counts both
commas in 'Hop,,Jump', even though), so the w it produces may be
larger than is really necessary. No real harm is done.
PROMPT     ========== Q2. Possible Problems Fixed ==========
WITH     cntr     AS
(     -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
     SELECT     LEVEL     AS n
     FROM     dual
     CONNECT BY     LEVEL     <= 1 +     (
                         SELECT     MAX ( REGEXP_COUNT (list_txt, :sep_char) )
                         FROM     string_test
)     -- End sub-query cntr, to generate n (1, 2, 3, ...)
SELECT     grp_name
,     n
,     REGEXP_SUBSTR     ( list_txt
               , '[^' || :sep_char || ']'     -- Anything except sep_char ...
                    || '+'               -- ... one or more times
               , 1
               , n
               )     AS item_txt
FROM     string_test
JOIN     cntr          ON n     <= 1 + NVL     ( REGEXP_COUNT (list_txt, :sep_char)     -- Problem (1)
                              , 0
WHERE     REGEXP_SUBSTR     ( list_txt     -- Problem (2)
               , '[^' || :sep_char || ']'     -- Anything except sep_char ...
                    || '+'               -- ... one or more times
               , 1
               , n
               )     IS NOT NULL
OR     list_txt     IS NULL          -- Problems (1) and (2) together
ORDER BY     grp_name
,          n;
     (Possible) Problems and Fixes
(1) If list_txt IS NULL, then REGEXP_COUNT (list_txt, :sep_char)
     returns NULL, the join condition fails, and the output
     contains nothing corresponding to the row from string_test.
     If you want a NULL item to appear in the results, use
     NVL to make sure the expression returns 0 instead of NULL.
(2) If list_txt contains multiple consecutive sep_chars (or if it
     begins or ends with sep_char, then the original query
     will return NULL items. To suppress these, add a WHERE
     clause to test that the item_txt to be displayed IS NOT NULL.
PROMPT     ========== Q3. Oracle 8.1 Query ===========
SELECT     grp_name
,     n
,     SUBSTR     ( list_txt
          , begin_pos
          , end_pos - begin_pos
          )     AS item_txt
FROM     (     -- Begin sub-query to compute begin_pos and end_pos
     SELECT     grp_name
     ,     n
     ,     list_txt
     ,     INSTR     ( :sep_char || list_txt
               , :sep_char
               , 1
               , n
               )     AS begin_pos
     ,     INSTR     ( list_txt || :sep_char
               , :sep_char
               , 1
               , n
               )     AS end_pos
     FROM     string_test
     ,     (     -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
          SELECT     ROWNUM     AS n
          FROM     all_objects
          WHERE     ROWNUM     <= 1 +     (
                         SELECT     MAX     ( LENGTH (list_txt)
                                   - LENGTH (REPLACE (list_txt, :sep_char))
                         FROM     string_test
          )     -- End sub-query cntr, to generate n (1, 2, 3, ...)
          cntr
     WHERE     n     <= 1 +     ( LENGTH (list_txt)
                    - LENGTH (REPLACE (list_txt, :sep_char))
     )     -- End sub-query to compute begin_pos and end_pos
ORDER BY     grp_name
,          n;
/*     Version-Dependent Features and Work-Arounds
The code above, Q3, runs in Oracle 8.1.
The following changes were made to Q1:
(11) REGEXP_COUNT was introduced in Oracle 11.
     In earlier versions, to find the number of sep_chars in list_txt,
     see how much the LENGTH changes when sep_chars are removed.
(10) REGEXP_SUBSTR was introduced in Oracle 10.
     In earlier versions, use INSTR to find where the sep_chars are,
     and use SUBSTR to get the sub-strings between them.
     (Using this technique, 'Hop,,Jump' still contains three items,
     but now item 2 IS NULL and item 3 is 'Jump'.)
(9.a) The WITH-clause was introduced in Oracle 9
     In earlier versions, use in-line views.
(9.b) "CONNECT BY LEVEL < constant" doesn't work in Oracle 8.
     Use ROWNUM from any sufficiently large table or view instead.
(9.c) ANSII join notation (JOIN table_name ON ...) was introduced in Oracle 9
     In earlier versions, join condition go in a WHERE-clause.
*/

Comma separated output using report builder

Hi Experts,
I am working with EBS 11.5.10, database 9i, and report builder 6i. I have a XML Publisher report, with output type EXCEL, which is working fine. But if i get huge data like 1million, 2million, it's not able accommodate the output in EXCEL. Since it's EXCEL 2003, it can't handle data more than it's capacity(i think 60,000 rows).
So we thought, if we can generate the output in CSV file with comma separte, then we can open the file in EXCEL 2007. Could somebody help me how to generate the CSV output using report builder 6i.
or is there any work around to our problem, kindly help me, it's urgent.

Hi,
Not sure if report builder can be made to generate csv output.
But you can create a PLSQL Report. Just use the query of Report Builder and write a Plsql procedure based on this query
-Idris

Comma separated data into IN clause in oracle report query

i have a field on form as order number it takes more than one value as 1,2,3
now i want to fetch data in report query for where order no in 1,2 and 3...
but field takes value as 1,2,3...
how can i separte the comma from value and how can i pass value in IN clause...or
how can i get all records with order no 1,2,3...
please suggest how can i achieve the same....

Hi Maddy....
Try this :
declare
var varchar2(10);
v1 varchar2(5);
v2 varchar2(5);
v3 varchar2(5);
vRegExp varchar2(5);
begin
var:='1,2,3';
vRegExp:='[^,]+';
FOR i IN 1..length (regexp_replace (var,vRegExp)) + 1
LOOP
            v1 := REGEXP_SUBSTR (var,vRegExp);
            v2 := REGEXP_INSTR(var,vRegExp,1,2);
            var := substr(var,v2);
           // here fetch you data from report by passing v1 as a parameter;
      EXIT WHEN v2 = 0;
END LOOP;
end;
Hope this will resolve your question..
Thanks

Comma separated output

4.we have employee table with Empname empno and deptnum
tabel name:emp
deptno name
10 A
10 B
10 C
i need output like this
deptno name
10 A,B,C

Hi,
See this link
http://www.dba-oracle.com/t_converting_rows_columns.htm
There I did find query what should do what you are looking
select
   deptno,
   rtrim (xmlagg (xmlelement (e, ename || ',')).extract ('//text()'), ',') enames
from
   emp
group by
   deptno
;Regards,
Jari

Comma separated values into MV

Hi,
I'm importing FIM data via a SQL agent and I have a column with this data:
00E704CB-40AE-0616-5B5A-6E0965BD5616,018F1801-34AE-FEE9-F98D-86E484F1812D
when the import runs, I see in the CS Object Properties that the new value is
00E704CB-40AE-0616-5B5A-6E0965BD5616\,018F1801-34AE-FEE9-F98D-86E484F1812D
Whats appenning and how can I tell FIM not to do this?
Many, many thanks,
DD

Is the attribute configured as a DN or reference attribute?
What's happening is it is escaping a dn.
David Lundell, Get your copy of FIM Best Practices Volume 1 http://blog.ilmbestpractices.com/2010/08/book-is-here-fim-best-practices-volume.html

Converting comma separated string into rows

for my procedure varchar2 is i/p paramter. i will get this i/p from java. this string value is like 'VTP,VR','VM'.
i want to split taht string into rows ie o/p will be
VTR
VR
VM.
how to do this.

Hi,
As always, the solution depends on your data, your requirements, and you Oracle version.
Here's one way:
-- Simulating Java input with a bind variable:
VARIABLE str VARCHAR2 (100)
EXEC     :str := 'VTP,VR,VM';
SELECT LEVEL AS n
,       REGEXP_SUBSTR ( :str
                      , '[^,]+'
                      , 1
                      , LEVEL
                      ) AS str_part
FROM     dual
CONNECT BY LEVEL <= 1 + REGEXP_COUNT (:str, ',')
I'm just guessing that your original string doesn't include single-quotes after VR or before VM. If it does, you can use TRIM to remove them from the string passed back by REGEXP_SUBSTR.

Comma separated output i need

Hi, am new to oracle pls help me with the below query.....
i have below table
empname deptno
ssss 10
aaaa 10
www 10
qqqq 20
eeee 20
i need a output like this
deptno empname
10 ssss ,aaaa ,www
20 qqqq ,eeee
thanks in advance

In 11gR2:
SQL> select deptno, listagg(ename, ',') within group (order by ename) enames from emp
group by deptno
         DEPTNO ENAMES
             10 CLARK,KING,MILLER
             20 ADAMS,FORD,JONES,SCOTT,SMITH
             30 ALLEN,BLAKE,JAMES,MARTIN,TURNER,WARD
3 rows selected.

SSRS Report : Comma Separated Hyperlinks

Hello,
I want to display Comma Separated Hyperlinks in SSRS Report. I am not sure what should I change here to get this working.
Below is the flow of data.
1. Extracting value from the SharePoint List using SSIS Package Script component and filling data in SQL Table.
I have used this Table and created below view to stuff all these three links together.
SELECT ID, STUFF
((SELECT ', ' + BCM.BCMProgramDocument
FROM BCMProgramDocumentation BCM
WHERE BCM.Risk = R.ID FOR XML PATH('')), 1, 1, '') AS BCMDoc
FROM Risk R
which gives me below output, not sure why.
"<a href='http://yahoo.com'>YAHOO</a>", "<a href='http://gmail.com'>GMAIL</a>", "<a href='http://hotmail.com'>HOTMAIL</a>"
Then in the SSRS Reporting, I have placed a PlaceHolder with HTML View selected and gave above field value in the expression.
They are not appearing as comma separated Hyperlinks.
Can anyone please help me on this ? What are the changes required in above steps ?
Thank you,
Mittal.

Hi Mittal,
According to your description, you want to show three links together with comma separated from BCMProgramDocument column to a report table. After testing the issue in my environment, we can refer to the following steps to achieve your requirement:
Use the following query create a dataset:
select * from BCMProgramDocumentation
Click Fields in the left pane, add a Calculated Field as below:
Field Name: ID2 Field Source: 1
Drag a table to design surface, then insert the expression below in the detail row:
=JOIN(lookupset(Fields!ID2.Value,Fields!ID2.Value,Fields!BCMProgramDocument.Value,"DataSet1"),",")
Right-click the Placeholder to open Placeholder Properties, then select ‘HTML-Interpret HTML tags as styles’ as Markup type.
The following screenshot is for your reference:
If there are any other questions, please feel free to ask.
Thanks,
Katherine Xiong
Katherine Xiong
TechNet Community Support

Comma separated data to array

I am looking for a method to translate a string with comma separated data into an array or vector.

Hello rolivawdaneel, I hope this help you, this takes the string a returns a vector.
import java.util.StringTokenizer;
import java.util.Vector;
public class stringConverter {
    public static Vector toVector( String s ) {
        Vector result = new Vector();
        StringTokenizer st = new StringTokenizer( s, "," );
        while( st.hasMoreTokens() ) {
            String aTokenizedString = st.nextToken();
            result.addElement( aTokenizedString );
        return result;
}

Need to Convert Comma separated data in a column into individual rows from

Hi,
I need to Convert Comma separated data in a column into individual rows from a table.
Eg: JOB1 SMITH,ALLEN,WARD,JONES
OUTPUT required ;-
JOB1 SMITH
JOB1 ALLEN
JOB1 WARD
JOB1 JONES
Got a solution using Oracle provided regexp_substr function, which comes handy for this scenario.
But I need to use a database independent solution
Thanks in advance for your valuable inputs.
George

Go for ETL solution. There are couple of ways to implement.
If helps mark

When I import a text file(comma separated )into a numbers spread sheet all the data goes into one column. Why does the text not go into separate columns based on the commas.

When I import a text file(comma separated) into a numbers spreadsheet all the data goes into one column instead of individual columns based on the comma separators. Excel allows you to do this during the import.. Is there a way to accomplish this in numbers without opening it in Excel and the importing into Numbers.

Your user info says iPad. This is the OS X Numbers forum. Assuming you are using OS X… Be sure the file is named with a .csv suffix.
(I don't have an iPad, so I don't know the iOS answer.)

SQL - Multiple Fetch into Single Column with Comma Separator

Hello Experts,
Good Day to all...
I need your help on following scenarios. The below query returns set of titleID strings. Instead of printing them one below the other as query output, I want the output to be in batch of 25 values.i.e each row should have 25 values separated by comma. i.e If there are 100 titles satisfying the output, then there should be only four rows with and each row having 25 titles in comma separated manner.
SELECT DISTINCT title_id
           FROM pack_relation
          WHERE package_id IN (      SELECT DISTINCT fa.package_id
                                                FROM annotation fa
                                            GROUP BY fa.package_id
                                              HAVING COUNT
                                                        (fa.package_id) <100);I tried with the PL/SQL block; whereas it is printing all the values continously :(
I need to stop with 25 values and display.
If its possible with SQL block alone; then it would be of great help
DECLARE
   v_str   VARCHAR2 (32767) := NULL;
   CURSOR c1
   IS
     SELECT DISTINCT title_id
           FROM pack_relation
          WHERE package_id IN (      SELECT DISTINCT fa.package_id
                                                FROM annotation fa
                                            GROUP BY fa.package_id
                                              HAVING COUNT
                                                        (fa.package_id) <100);
BEGIN
   FOR i IN c1
   LOOP
      v_str := v_str || ',' || i.title_id;
   END LOOP;
   v_str := SUBSTR (v_str, 2);
   DBMS_OUTPUT.put_line (v_str);
EXCEPTION
   WHEN OTHERS
   THEN
      DBMS_OUTPUT.put_line ('Error-->' || SQLERRM);
END;Thanks...

You can use CEIL
Sample code
SELECT
    nt,
    LTRIM(MAX(SYS_CONNECT_BY_PATH(val,',')) KEEP (DENSE_RANK LAST ORDER BY curr),',') AS concat_val
FROM
        SELECT
            val,
            nt,
            ROW_NUMBER() OVER (PARTITION BY nt ORDER BY val)    AS curr,
            ROW_NUMBER() OVER (PARTITION BY nt ORDER BY val) -1 AS prev
        FROM
                SELECT
                    level                          AS val,
                    ceil(rownum/3) as nt /* Grouped in batches of 3 */
                FROM
                    dual
                    CONNECT BY level <= 10
GROUP BY
    nt
    CONNECT BY prev = PRIOR curr
AND nt              = PRIOR nt
    START WITH curr = 1;
        NT CONCAT_VAL
         1 1,2,3
         2 4,5,6
         3 7,8,9
         4 10Your code
SELECT
    nt,
    LTRIM(MAX(SYS_CONNECT_BY_PATH(title_id,',')) KEEP (DENSE_RANK LAST ORDER BY curr),',') AS concat_val
FROM
        SELECT
            title_id,
            nt,
            ROW_NUMBER () OVER (PARTITion BY nt ORDER BY title_id)   AS curr,
            ROW_NUMBER() OVER (PARTITION BY nt ORDER BY title_id) -1 AS prev
        FROM
                SELECT
                    title_id,
                    ceil(rownum/25) AS nt /* Grouped in batches of 25 */
                FROM
                    pack_relation tdpr
                JOIN annotation fa
                ON
                    tdpr.package_id = fa.package_id
                GROUP BY
                    title_id,
                    fa.package_id
                HAVING
                    COUNT (fa.package_id) < 500
GROUP BY
    nt
    CONNECT BY prev = PRIOR curr
AND nt              = PRIOR nt
    START WITH curr = 1;

Comma separated column into rows for each value

experts,
I have a two column table. The second column has comma separated string values. How can I put the values separate for each comma separated and make one row for each value?
example,
column1 |   StringColumn
s1          |   test, joy, happy
s2          | USA, England, India
I want the result to be like below
column1   |    StringColumn
s1            |      test
s1            |      joy
s1            |      happy
s2            |     USA
s2            |     England
s2            |     India
thanks in advance
ebro

Hello ebro,
See the following for a possible solution:
http://gallery.technet.microsoft.com/scriptcenter/Convert-Small-CSV-Value-to-ffc142ff
Olaf Helper
[ Blog] [ Xing] [ MVP]

Obtaining comma-separated list of text values associated with bitwise flag column

In the table msdb.dbo.sysjobsteps, there is a [flags] column, which is a bit array with the following possible values:
0: Overwrite output file
2: Append to output file
4: Write Transact-SQL job step output to step history
8: Write log to table (overwrite existing history)
16: Write log to table (append to existing history)
32: Include step output in history
64: Create a Windows event to use as a signal for the Cmd jobstep to abort
I want to display a comma-separated list of the text values for a row. For example, if [flags] = 12, I want to display 'Write Transact-SQL job step output to step history, Write log to table (overwrite existing history)'.
What is the most efficient way to accomplish this?

Here is a query that gives the pattern:
DECLARE @val int = 43
;WITH numbers AS (
   SELECT power(2, n) AS exp2 FROM (VALUES(0), (1), (2), (3), (4), (5), (6)) AS n(n)
), list(list) AS (
   SELECT
   (SELECT CASE WHEN exp2 = 1 THEN 'First flag'
WHEN exp2 = 2 THEN 'Flag 2'
WHEN exp2 = 4 THEN 'Third flag'
WHEN exp2 = 8 THEN 'IV Flag'
WHEN exp2 = 16 THEN 'Flag #5'
WHEN exp2 = 32 THEN 'Another flag'
WHEN exp2 = 64 THEN 'My lucky flag'
   END + ', '
FROM   numbers
WHERE exp2 & @val = exp2
ORDER BY exp2
FOR XML PATH(''), TYPE).value('.', 'nvarchar(MAX)')
SELECT substring(list, 1, len(list) - 1)
FROM   list
Here I'm creating the numbers on the fly, but it is better to have a table of numbers in your database. It can be used in many places, see here for a short discussion:
http://www.sommarskog.se/arrays-in-sql-2005.html#numbersasconcept
(Only read down to the next header.)
For FOR XML PATH thing is the somewhat obscure way we create concatenated lists. There is not really any using trying to explain how it works; it just works. The one thing to keep in mind is that it adds an extra comma at the end and the final query strips
it off.
This query does not handle that 0 has a special meaning - that is left as an exercise to the reader.
Erland Sommarskog, SQL Server MVP, [email protected]

Comma separated output into columns

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