Converting comma separated string into rows

for my procedure varchar2 is i/p paramter. i will get this i/p from java. this string value is like 'VTP,VR','VM'.
i want to split taht string into rows ie o/p will be
VTR
VR
VM.
how to do this.

Hi,
As always, the solution depends on your data, your requirements, and you Oracle version.
Here's one way:
-- Simulating Java input with a bind variable:
VARIABLE str VARCHAR2 (100)
EXEC     :str := 'VTP,VR,VM';
SELECT LEVEL AS n
,       REGEXP_SUBSTR ( :str
                      , '[^,]+'
                      , 1
                      , LEVEL
                      ) AS str_part
FROM     dual
CONNECT BY LEVEL <= 1 + REGEXP_COUNT (:str, ',')
I'm just guessing that your original string doesn't include single-quotes after VR or before VM. If it does, you can use TRIM to remove them from the string passed back by REGEXP_SUBSTR.

Similar Messages

Convert comma separated string in rows

Dear Gurus,
I want to convert comma separated string in rows so as to insert in collection.
e.g. string 1234,2323,23232,2343,34234
Above string should be converted in rows so as to insert in table or collection
Thanks in advance
Sanjeev

Or slight variation...
SQL> ed
Wrote file afiedt.buf
1 with t as (select '1234,2323,23232,2343,34234' as txt from dual)
2 --
3 select REGEXP_SUBSTR (txt, '[^,]+', 1, level)
4 from t
5* connect by REGEXP_SUBSTR (txt, '[^,]+', 1, level) is not null
6 /
REGEXP_SUBSTR(TXT,'[^,]+',
1234
2323
23232
2343
34234... so it doesn't have to work out how many levels it needs to do, it just keeps going until it get's a no-value (of course that assumes that there is always a value between each comma)

Comma separated column into rows for each value

experts,
I have a two column table. The second column has comma separated string values. How can I put the values separate for each comma separated and make one row for each value?
example,
column1 |   StringColumn
s1          |   test, joy, happy
s2          | USA, England, India
I want the result to be like below
column1   |    StringColumn
s1            |      test
s1            |      joy
s1            |      happy
s2            |     USA
s2            |     England
s2            |     India
thanks in advance
ebro

Hello ebro,
See the following for a possible solution:
http://gallery.technet.microsoft.com/scriptcenter/Convert-Small-CSV-Value-to-ffc142ff
Olaf Helper
[ Blog] [ Xing] [ MVP]

Comma separated string in rows

Hi All,
I have one table
select * from abcd;
No err
1    rishi,rahul
2    rishi,ak
I want output like:
No ERR
1 rishi
1 rahul
2 rishi
2 ak
i am using the below query for this:
select no,regexp_substr(err,'[^,]+', 1, level) from abcd
connect by regexp_substr(err, '[^,]+', 1, level) is not null
but this query is giving me output:
1
rishi
1
rahul
2
ak
2
rishi
1
rahul
2
ak
if i am using distinct then only desired output is coming.
select distinct no,regexp_substr(err,'[^,]+', 1, level) from abcd
connect by regexp_substr(err, '[^,]+', 1, level) is not null
but i don't want to use distinct because my table has millions of rows and err contains comma separated varchar(6000);
please help me.

Something like this?
SQL> ed
Wrote file afiedt.buf
1 WITH table_x AS(
2    SELECT 1 id, 'rishi,rahul' str FROM dual UNION ALL
3    SELECT 2 id, 'rishi,ak' str FROM dual
4 )
5 SELECT id,
6             REGEXP_SUBSTR (str,
7                            '[^,]+',
8                            1,
9                            LEVEL)
10             --LEVEL,
11             --SYS_GUID ()
12        FROM table_x
13 CONNECT BY     LEVEL <= LENGTH (REGEXP_COUNT (str, ',')) +1
14             AND PRIOR id = id
15             AND PRIOR Sys_Guid() IS NOT NULL
16*   ORDER BY id, LEVEL
SQL> /
        ID REGEXP_SUBS
         1 rishi
         1 rahul
         2 rishi
         2 ak
Trick here is: the usage of SYS_GUID() i.e. System Global Unique Identifier.
Alternative to this, can also use DBMS_RANDOM.value() here.
Read more here - https://forums.oracle.com/thread/2526535
HTH
-- Ranit

Inserting the Comma Separated Strings into Table

Hi Seniors,
i had two string and i want to insert the records in the Table COMMENT . In this way.
would u please give some programe to insert the records.
The Data and the Table
( 901,902,903,904 )
( 'hai','nice','good & mail is [email protected] ','excellent and the phone 011-235323' )
comm_id loc_id company_name comments
1      10 901      Hai
2      10 902      nice
3 10      903      good & mail is [email protected]
4      10 904      excellent and the phone 011-235323
Thanks
Seenu

Hi, Seenu,
In Oracle 10 (and up) you can easily split a comma-delimited list using REGEXP_SUBSTR.
INSTR and SUBSTR can do the same thing in any version, but it's more complicated.
See the general instructions below:
/*     How to Split a Delimited String
This shows how to take a single row with a delimited string, such as
     Animal     amoeba,bat,cedusa,dodo
and transform it into multiple rows:
     Animal     1     amoeba
     Animal     2     bat
     Animal     3     cedusa
     Animal     4     dodo
PROMPT     ========== -1. sep_char parameter ==========
VARIABLE     sep_char     VARCHAR2 (10)
EXECUTE     :sep_char := ',';
SELECT     :sep_char     AS sep_char
FROM     dual;
PROMPT     ========== 0. string_test table ==========
DROP TABLE     string_test;
CREATE TABLE     string_test
(     grp_name     VARCHAR2 (10)
,     list_txt     VARCHAR2 (50)
INSERT INTO string_test (grp_name, list_txt) VALUES ('Animal',     'amoeba,bat,cedusa,dodo');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Date',     '15-Oct-1582,16-Oct-2008');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Nothing',     NULL);
INSERT INTO string_test (grp_name, list_txt) VALUES ('Place',     'New York');
INSERT INTO string_test (grp_name, list_txt) VALUES ('Skip',     'Hop,,Jump');
SELECT     *
FROM     string_test
ORDER BY     grp_name;
PROMPT     ========== Q1. Oracle 11 Query ==========
WITH     cntr     AS          -- Requires Oracle 9
(     -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
     SELECT     LEVEL     AS n     -- Requires Oracle 9
     FROM     dual
     CONNECT BY     LEVEL     <= 1 +     (
                         SELECT     MAX ( REGEXP_COUNT (list_txt, :sep_char) )     -- Requires Oracle 11
                         FROM     string_test
)     -- End sub-query cntr, to generate n (1, 2, 3, ...)
SELECT     grp_name
,     n
,     REGEXP_SUBSTR     ( list_txt     -- Requires Oracle 10
               , '[^' || :sep_char || ']'     -- Anything except sep_char ...
                    || '+'               -- ... one or more times
               , 1
               , n
               )     AS item_txt
FROM     string_test
JOIN     cntr                                   -- Requires Oracle 9
ON     n     <= 1 + REGEXP_COUNT (list_txt, :sep_char)     -- Requires Oracle 11
ORDER BY     grp_name
,          n;
/*     Notes:
     REGEXP_SUBSTR (s, '[^,]+', 1, n)
returns the n-th item in a comma-delimited list s.
If there are fewer than n items, it returns NULL.
One or more consecutive characters other than comma make an item, so
'Hop,,Jump' has two items, the second one being 'Jump'.
The sub-query cntr produces a list of integers 1, 2, 3, ..., w
where w is the worst-case (the largest number of items in any list).
This actually counts separators, not items, (e.g., it counts both
commas in 'Hop,,Jump', even though), so the w it produces may be
larger than is really necessary. No real harm is done.
PROMPT     ========== Q2. Possible Problems Fixed ==========
WITH     cntr     AS
(     -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
     SELECT     LEVEL     AS n
     FROM     dual
     CONNECT BY     LEVEL     <= 1 +     (
                         SELECT     MAX ( REGEXP_COUNT (list_txt, :sep_char) )
                         FROM     string_test
)     -- End sub-query cntr, to generate n (1, 2, 3, ...)
SELECT     grp_name
,     n
,     REGEXP_SUBSTR     ( list_txt
               , '[^' || :sep_char || ']'     -- Anything except sep_char ...
                    || '+'               -- ... one or more times
               , 1
               , n
               )     AS item_txt
FROM     string_test
JOIN     cntr          ON n     <= 1 + NVL     ( REGEXP_COUNT (list_txt, :sep_char)     -- Problem (1)
                              , 0
WHERE     REGEXP_SUBSTR     ( list_txt     -- Problem (2)
               , '[^' || :sep_char || ']'     -- Anything except sep_char ...
                    || '+'               -- ... one or more times
               , 1
               , n
               )     IS NOT NULL
OR     list_txt     IS NULL          -- Problems (1) and (2) together
ORDER BY     grp_name
,          n;
     (Possible) Problems and Fixes
(1) If list_txt IS NULL, then REGEXP_COUNT (list_txt, :sep_char)
     returns NULL, the join condition fails, and the output
     contains nothing corresponding to the row from string_test.
     If you want a NULL item to appear in the results, use
     NVL to make sure the expression returns 0 instead of NULL.
(2) If list_txt contains multiple consecutive sep_chars (or if it
     begins or ends with sep_char, then the original query
     will return NULL items. To suppress these, add a WHERE
     clause to test that the item_txt to be displayed IS NOT NULL.
PROMPT     ========== Q3. Oracle 8.1 Query ===========
SELECT     grp_name
,     n
,     SUBSTR     ( list_txt
          , begin_pos
          , end_pos - begin_pos
          )     AS item_txt
FROM     (     -- Begin sub-query to compute begin_pos and end_pos
     SELECT     grp_name
     ,     n
     ,     list_txt
     ,     INSTR     ( :sep_char || list_txt
               , :sep_char
               , 1
               , n
               )     AS begin_pos
     ,     INSTR     ( list_txt || :sep_char
               , :sep_char
               , 1
               , n
               )     AS end_pos
     FROM     string_test
     ,     (     -- Begin sub-query cntr, to generate n (1, 2, 3, ...)
          SELECT     ROWNUM     AS n
          FROM     all_objects
          WHERE     ROWNUM     <= 1 +     (
                         SELECT     MAX     ( LENGTH (list_txt)
                                   - LENGTH (REPLACE (list_txt, :sep_char))
                         FROM     string_test
          )     -- End sub-query cntr, to generate n (1, 2, 3, ...)
          cntr
     WHERE     n     <= 1 +     ( LENGTH (list_txt)
                    - LENGTH (REPLACE (list_txt, :sep_char))
     )     -- End sub-query to compute begin_pos and end_pos
ORDER BY     grp_name
,          n;
/*     Version-Dependent Features and Work-Arounds
The code above, Q3, runs in Oracle 8.1.
The following changes were made to Q1:
(11) REGEXP_COUNT was introduced in Oracle 11.
     In earlier versions, to find the number of sep_chars in list_txt,
     see how much the LENGTH changes when sep_chars are removed.
(10) REGEXP_SUBSTR was introduced in Oracle 10.
     In earlier versions, use INSTR to find where the sep_chars are,
     and use SUBSTR to get the sub-strings between them.
     (Using this technique, 'Hop,,Jump' still contains three items,
     but now item 2 IS NULL and item 3 is 'Jump'.)
(9.a) The WITH-clause was introduced in Oracle 9
     In earlier versions, use in-line views.
(9.b) "CONNECT BY LEVEL < constant" doesn't work in Oracle 8.
     Use ROWNUM from any sufficiently large table or view instead.
(9.c) ANSII join notation (JOIN table_name ON ...) was introduced in Oracle 9
     In earlier versions, join condition go in a WHERE-clause.
*/

Need to Convert Comma separated data in a column into individual rows from

Hi,
I need to Convert Comma separated data in a column into individual rows from a table.
Eg: JOB1 SMITH,ALLEN,WARD,JONES
OUTPUT required ;-
JOB1 SMITH
JOB1 ALLEN
JOB1 WARD
JOB1 JONES
Got a solution using Oracle provided regexp_substr function, which comes handy for this scenario.
But I need to use a database independent solution
Thanks in advance for your valuable inputs.
George

Go for ETL solution. There are couple of ways to implement.
If helps mark

MODEL clause to process a comma separated string

Hi,
I'm trying to parse a comma separated string using SQL so that it will return the parsed values as rows;
eg. 'ABC,DEF GHI,JKL' would return 3 rows;
'ABC'
'DEF GHI'
'JKL'
I'm thinking that I could possibily use the MODEL clause combined with REGULAR expressions to solve this as I've already got a bit of SQL which does the opposite ie. turning the rows into 1 comma separated string;
select id, substr( concat_string, 2 ) as string
from (select 1 id, 'ABC' string from dual union all select 1, 'DEF GHI' from dual union all select 1, 'JKL' from dual)
model
return updated rows
partition by ( id )
dimension by ( row_number() over (partition by id order by string) as position )
measures ( cast(string as varchar2(4000) ) as concat_string )
rules
upsert
iterate( 1000 )
until ( presentv(concat_string[iteration_number+2],1,0) = 0 )
( concat_string[0] = concat_string[0] || ',' || concat_string[iteration_number+1] )
order by id;
Can anyone give me some pointers how to parse the comma separated string using regexp and create as many rows as needed using the MODEL clause?

Yes, you could do it without using ITERATE, but FOR ... INCREMENT is pretty much same loop. Couple of improvements:
a) there is no need for CHAINE measure
b) there is no need for CASE in RULES clause
c) NVL can be applies on measures level
with t as (select 1 id, 'ABC,DEF GHI,JKL,DEF GHI,JKL,DEF GHI,JKL,DEF,GHI,JKL' string from dual
   union all
    select 2,'MNO' string from dual
    union all
   select 3,null string from dual
SELECT id,
         string
FROM   T
   MODEL
    RETURN UPDATED ROWS
    partition by (id)
    DIMENSION BY (0 POSITION)
    MEASURES(
             string,
             NVL(LENGTH(REGEXP_REPLACE(string,'[^,]+','')),0)+1 NB_MOT
    RULES
     string[FOR POSITION FROM 1 TO NB_MOT[0] INCREMENT 1] = REGEXP_SUBSTR(string[0],'[^,]+',1,CV(POSITION))
SQL> with t as (select 1 id, 'ABC,DEF GHI,JKL,DEF GHI,JKL,DEF GHI,JKL,DEF,GHI,JKL' string from dual
2     union all
3      select 2,'MNO' string from dual
4      union all
5     select 3,null string from dual
6      )
7   SELECT id,
8           string
9    FROM   T
10     MODEL
11      RETURN UPDATED ROWS
12      partition by (id)
13      DIMENSION BY (0 POSITION)
14      MEASURES(
15               string,
16               NVL(LENGTH(REGEXP_REPLACE(string,'[^,]+','')),0)+1 NB_MOT
17              )
18      RULES
19      (
20       string[FOR POSITION FROM 1 TO NB_MOT[0] INCREMENT 1] = REGEXP_SUBSTR(string[0],'[^,]+',1,CV(POSITION))
21      )
22 /
        ID STRING
         1 ABC
         1 DEF GHI
         1 JKL
         1 DEF GHI
         1 JKL
         1 DEF GHI
         1 JKL
         1 DEF
         1 GHI
         1 JKL
         2 MNO
        ID STRING
         3
12 rows selected.
SQL> SY.

Turning parts of a string into rows in another table

I need to extract unit codes that are stored in a string into rows in a new table as below
From:
Set_cd sequence_number rule_text
KP106A 15432 {1234,4567,8910,1567}
To:
Set_cd sequence_number unit
KP106A 15432 1234
KP106A 15432 4567
KP106A 15432 8910
KP106A 15432 1567
The strings will be of varying lengths but the layout will always be the same with the curley brackets and commas.
Any ideas please?
Thanx
Rob.
Edited by: Rob Mc on Sep 23, 2009 2:38 PM

Something like this ->
satyaki>
satyaki>select * from v$version;
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Prod
PL/SQL Release 10.2.0.1.0 - Production
CORE    10.2.0.1.0      Production
TNS for Linux: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - Production
Elapsed: 00:00:00.03
satyaki>
satyaki>
satyaki>with ta_tab
2 as
3    (
4      select 'KP106A' set_cd, 15432 sequence_number, '{1234,4567,8910,1567}' rule_text from dual
5    )
6 select set_cd,
7         sequence_number,
8         REGEXP_SUBSTR (replace(replace(rule_text,'{',''),'}',''), '[^,]+', 1, level) rule_part
9 from ta_tab
10 connect by level <= (
11                         select length(regexp_replace(replace(replace(rule_text,'{',''),'}',''),'[^,]*'))+1
12                        from ta_tab
13                      );
SET_CD SEQUENCE_NUMBER RULE_PART
KP106A           15432 1234
KP106A           15432 4567
KP106A           15432 8910
KP106A           15432 1567
Elapsed: 00:00:01.02
satyaki>
satyaki>Regards.
Satyaki De.

[svn:osmf:] 15983: Updating VideoQoSPluginMetadataSynthesizer to create comma separated string values for all of the available keys .

Revision: 15983
Revision: 15983
Author:   [email protected]
Date:     2010-05-10 04:47:46 -0700 (Mon, 10 May 2010)
Log Message:
Updating VideoQoSPluginMetadataSynthesizer to create comma separated string values for all of the available keys.
Modified Paths:
    osmf/trunk/apps/samples/plugins/VideoQoSPlugin/src/org/osmf/qos/VideoQoSPluginMetadataSyn thesizer.as

Rob:
"but the sad thing is, that managers will most likely respond with a "This used to be fast in MSSQL, but now it isn't any more in Oracle. Oracle is so slow ...""
On the bright side, it sounds like most of the database calls are implemented as stored procedures, so there is an opportunity to do it right (in Oracle terms) in the stored procedures.
I did a similar conversion a while back, converting bad SQLServer procedures to good Oracle procedures. Everyone said "Oracle is much faster that SQLServer"
John

Look Up For Comma Separated Strings

Hi,
How to look up for comma separated string from livecycle forms manager ??
Plz gimme an idea on this.
Raghava Kumar V.S.S.

Hi
My point is that the more detailed you ask your question, the more likely you are to get an answer.
Those of us who monitor these newsgroups also appreciate you doing as much of your own research as possible, before asking us for help - we're more likely to spend our own (personal and valuable) time helping you, if we know that you've spent your own time doing research, and you've still not been able to solve the problem.
I look forward to your next question :-)
Howard

Is there an easy way to convert a long string into an array?

I can convert a long string into a 1-d array by parsing and using build array, but I would like to know if there is a function to make this easier.
For example:
from/   aaaaaaaabbbbbbbbccccccccdddddddd         (string of ascii)
to/       an array that is 1-d with each element having eight characters
          aaaaaaaa
          bbbbbbbb
          cccccccc
          dddddddd
Thank you.
Solved!
Go to Solution.

Try something like this:
(If you can guarantee that the string length is an integer multiple of 8, you an drop the two triangular modes in the upper left. )
Message Edited by altenbach on 03-14-2010 06:40 PM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
ChopString.png ‏9 KB

Converting a binary string into a JPEG image in Crystal Reports 2008

Hi Gang
Iu2019m having problems converting a binary string into an image in Crystal Reports 2008
I have JPEG images stored in ECC. ECC stores the data in binary format.
Iu2019m using the ECC function module SKWF_PHIO_CONTENT_ACCESS_GET to retrieve the data. This function module has an export table, FILE_CONTENT_BINARY, which returns several lines of data. Each line contains a maximum of 1,024 characters.
When I drop the T_ FILE_CONTENT_BINARY.LINE field into my Crystal Report detail section, I wind up with a report that displays all the lines in FILE_CONTENT_BINARY table. (in my case, 19 lines are displayed.)
I created a formula to collect all the data into a single string.
whileprintingrecords;
stringvar data:= data & {SKWF_PHIO_CONTENT_ACCESS_GET.T_FILE_CONTENT_BINARY.LINE}
I added the formula to the detail section and itu2019s doing a great job collecting the data.
I then inserted a picture object in the report footer, opened the format editor, navigated to the u201Cpictureu201D tab, and inserted a formula for the u201Cgraphics locationu201D.
whileprintingrecords;
stringvar data:=data;
data
My clever idea turned out to be a disappointment . . . . my picture object is blank.
Does anyone have a solution for converting a binary string into a JPEG image?

Save the JPEG in a format CR supports. Refer to the help file for the file types.

Passing comma separated string to stored procedure

Hi,
There is thread with same query I created earlier and that was answered. That solution worked if I pass comma separated string containing IDs. But due to changes in the logic, I have to pass usernames instead of userIDs. I tried to modify the solution provided to use with this.
Following the link to previous post :
Re: Passing comma separated string to stored procedure
------Package-------
TYPE refcurQID IS REF CURSOR;
TYPE refcurPubs IS REF CURSOR;
procedure GetAllPersonalQueue (p_user_name in nvarchar2, TestQID OUT Test.refcurQID
, TestPubs OUT Test.refcurPubs);
------Package-------
------Package Body-------
PROCEDURE GetAllPersonalQueue (p_user_name in nvarchar2, TestQID OUT Test.refcurQID, TestPubs OUT Test.refcurPubs) as
BEGIN
Open TestQID for
select id from cfq where name in (p_user_name);
Open TestPubs for
SELECT qid FROM queues WHERE qid in(
select id from cfq where name in (p_user_name));
END GetAllPersonalQueue;
------Package Body-------
Thanks in advance
Aditya

Hi,
I modified the query as per the solution provided by isotope, after which the logic changed and I am passing username instead of userID in comma separated string.
Following is the changes SP, which does not throw any error, but no data is returned.
PROCEDURE GetAllPersonalQueue (p_user_name in nvarchar2, TestQID OUT Test.refcurQID, TestPubs OUT Test.refcurPubs
) is
--local variable
strFilter varchar2(100);
BEGIN
Open TestQID for
select id, name from cfq where name in
select regexp_substr(p_user_name||',','[a-z]+[0-9]+',1,level)
from dual
connect by level <= (select max(length(p_user_name)-length(replace(p_user_name,',')))+1
from dual)
Open TestPubs for
SELECT qid FROM queues WHERE qid in(
select id from cfq where name in
select regexp_substr(p_user_name||',','[a-z]+[0-9]+',1,level)
from dual
connect by level <= (select max(length(p_user_name)-length(replace(p_user_name,',')))+1
from dual)
END GetAllPersonalQueue;
Edited by: adityapawar on Feb 27, 2009 8:38 AM

How to split a delimited string into rows

Hi Everyone,
I have a field in my EMPLOYEE table named "OLD_USER_IDS" which stores all the old system ID's that the employee was once assigned to. This field is comma separated like so: "USERID1,USERID2,USERID3". My question is: how can I write a SELECT query that splits each individual User ID into its own row?
For example:
EMP_ID USER_ID
10 USERID1
10 USERID2
12 USERID3
15 USERID4
15 USERID5
15 USERID6
Thank You
-Sam

I think you should search this forum first for similar questions. I keep track of some interesting stuffs posted in this forum in a file, and from that
WITH t AS (SELECT 'USER1,USER2,USER3' str FROM DUAL
select substr(str,
                    decode(level,
                           1,
                           1,
                           instr(str, ',', 1, level - 1) + 1),
                    decode(instr(str, ',', 1, level),
                           0,
                           length(str),
                           instr(str, ',', 1, level) -
                           decode(level,
                                  1,
                                  0,
                                  instr(str, ',', 1, level - 1)) - 1)) the_value
        from (select str from t)
      connect by level <=
                 length(str) - length(replace(str, ',')) + 1;

Using a comma seprated string as rows

i hv a column in which i store comma seprated name, i have to show them as rows in a report..
plz help

As with most things, it depends greatly on your Oracle version (you should always post this information).
In release 11 here's a neat method.
http://laurentschneider.com/wordpress/2009/07/select-from-column-separated-list.html
In release 10 there's REGEXP
http://nuijten.blogspot.com/2009/07/splitting-comma-delimited-string-regexp.html
And it looks like you've been given a pre-10 answer already.

Converting comma separated string into rows

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