Command line parameters and path problem

Question

hello ....
I have to execute an application from my java program. My application called "AIMSS" takes 2 command line parameters. Now, when i mention those parameters with complete path to my executeable, windows reports that "unable to open the shortcut". Below is what i am trying:
private static final String WIN_PATH = "rundll32";
private static final String WIN_FLAG  "url.dll,FileProtocolHandler";
private String cmd = null;
private String url = null;
public void runMyFileWithMessage(String msg)
    try
url = "C:\\Program Files\\Raytheon\\AIMSS 4.0\\Runtime\\Standard\\aimss40.exe" + " AAAVIETM 3457";
             cmd = WIN_PATH + " " + WIN_FLAG + " " + url;
             System.out.println(url);
             Runtime.getRuntime().exec(cmd);
        catch(IOException io)
            System.out.println("AIMSS problem. Below is the Stack Trace.");
            io.printStackTrace();
    }Although, when i tried to run the executeable from Start->Run, by giving it same complete path and 2 arguments, it runs fine. Any help would be greatly appreciated.
Raheel.

Answer 1

Passing multiple paramters in a String to exec() doesn't work. Use the exec method that takes a String array instead and pass the call and each parameter in as a separate String.
Off the top of my head (check the api) it will be something like
String[] cmd = {"C:\\Program Files\\Raytheon\\AIMSS 4.0\\Runtime\\Standard\\aimss40.exe","AAAVIETM", "3457"};
Runtime.getRuntime().exec(cmd);