Compare firts count for second count the doc.inventory

Hello,
I need of the SAP transaction to compare first and second count,in the process the inventory management.
In module MM.
tks,
Danilo Araujo

incorporate mapping logic such that for every 999 item records create new IDoc node
check with this UDF for IDoc node mapping, item records will be input to UDF
int count = a.length;
int k=999;
result.addValue("");
for(int i=0;i<count;i++)
      if (i>=k){
          result.addValue(""); // if records > 999, add IDoc node
          k=k+999;
Do rest of the mapping accordingly

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Search Result is showing Blank Title for some of the doc Files

Hi,
I am doing Search on SharePoint 2010 with the search scope set to one of the document library , But the search result is showing different results for different doc files. I can analyse three type of output from the search result:
1) for some records Title is shown correct.
2) for some files , Title is shown with keyword "Title:<Actual Title>"
3) and in some docs its hsowing Just the keyword "Title:" in place of actual title
I am not able to understand why the result is behaving like this.
Any assistance will be really appreciable .
Thanks in advance

In Central Administration in the Search Service in Managed Properties look for 'Title'. You will see that Title is populated from a number of properties on a document, some properties are given higher priority then others. That could be a clue.
Also, what type of document are you crawling a PDF, word document, etc? For PDFs you have to install a special iFilter and you need to be aware sometimes the properties on the actual PDF in adobe are used.
I sugest: Try to make sure you give your documents a title in SharePoint and that you rank that property as the #1 property in Central Admin that the Managed property 'Title' uses.

Compare 2 IDOCS for duplicate

Hi,
Please any one can help me to compare 2 IDOCS for duplication (all the data records only).
Thanks in advance.

Hi Sandeep,
Welcome To SDN!!.
Refer the theard
https://forums.sdn.sap.com/click.jspa?searchID=13274282&messageID=2854327
Regards
Kiran Sure

Count the number of docs

Hello,
Is there anyway that we can aount the number of documents when we run a query..Like can we introduce any key figure in the query whose function will be to count the number of docs.PLease let me know.
thanks

Hi,
In Infocubes, DSO's there will be a Keyfigure called as Number of Records.
You can use that KF in your Query as Restricted Key Kigure.
For eg : You need the total count of employees
Then you need to the use the KF no.of records with the 0employee char.
Hope this will helps you ....
Thanks and Regards
Ashwin

Counting the number of lines for each procedure in a package

Hi,
I would like to write a query on USER_SOURCE that can display the number of code lines for each procedure/function in a package.
Is it possible to write such a query? Maybe by using analytical functions?
for example in the following example i would like to count the lines between "PROCEDURE proc1 IS" and "END proc1;" and between "PROCEDURE proc2 IS" and "END proc2;"
SQL> select text from user_source where name='PKG_TEST' and type='PACKAGE BODY';
TEXT
PACKAGE BODY PKG_TEST IS
PROCEDURE proc1 IS
BEGIN
    update t1 set EDITION_NAME = 'AAAAAAA';
    commit;
END proc1;
PROCEDURE proc2 IS
BEGIN
   update t1 set EDITION_NAME = 'AAAAAAA';
    commit;
END proc2;
END PKG_TEST;thanks for helping

onedbguru wrote:
Hopefully some idiot manager isn't trying to use this sort of thing to base their decisions on developer productivity. If so, they ARE idiots. Number of code lines NEVER, EVER, EVER!!! translates into an efficient application. If I were paid by the line, my code would look like:
select
1
from
dual
Based on the idiocy of this method of determining "performance" I would get paid $5.00 at $1.00/line. And trust me, I saw this back in the 80's and 90's and saw similar idiotic code and had to clean up the mess. Most of it wasn't efficient code to start with let alone the number of lines generated.Or the other extreme, when the PHB firmly believed that execution efficiency was gained by reducing the number of lines of code. So instead of nicely formatted, easy to read code:
      *GET NEXT ORDER NUMBER
            EXEC SQL
                 SELECT (MAX(ORDER_NUM) + 1)
                 INTO   :NEXT-NUM:IND-NULL
                 FROM   PART_ORDER
            END-EXEC.
            IF IND-NULL < 0
              MOVE 1 TO NEXT-NUM.
            EXEC SQL
                 INSERT
                 INTO    PART_ORDER
                        (ORDER_NUM,
                         ORIGIN_LOC,
                         ORDER_TYPE,
                         ORDER_STAT,
                         CREAT_TIME)
                 VALUES (:NEXT-NUM,
                         :LOC, 'R', 'O',
                         CURRENT TIMESTAMP)
               END-EXEC.
            MOVE NEXT-NUM TO MASK0.
            PERFORM HEADER-PROC THRU HEADER-EXIT.
        CREATE-ORDER-EXIT. EXIT.                                                     You got this:
       *GET NEXT ORDER NUMBER
        EXEC SQL SELECT (MAX(ORDER_NUM) + 1) INTO :NEXT-NUM:IND-NULL FROM
        PART_ORDER END-EXEC. IF IND-NULL < 0 MOVE 1 TO NEXT-NUM. EXEC SQL INSERT
        INTO PART_ORDER (ORDER_NUM, ORIGIN_LOC, ORDER_TYPE, ORDER_STAT,
        CREAT_TIME) VALUES (:NEXT-NUM, :LOC, 'R', 'O', CURRENT TIMESTAMP)
        END-EXEC. MOVE NEXT-NUM TO MASK0. PERFORM HEADER-PROC THRU HEADER-EXIT.
        CREATE-ORDER-EXIT. EXIT.                 Oh, wait! See the same thing all the time in this forum ... not because someone thinks fewer lines = faster code, but simply because people are sloppy.
INSERT INTO PART_ORDER(ORDER_NUM,ORIGIN_LOC,ORDER_TYPE,ORDER_STAT,CREAT_TIME) VALUES (:NEXT-NUM,:LOC, 'R', 'O',CURRENT TIMESTAMP) ;

CTE for Count the Binary Tree nodes

i have the table structure like this :
Create table #table(advId int identity(1,1),name nvarchar(100),Mode nvarchar(5),ReferId int )
insert into #table(name,Mode,ReferId)values('King','L',0)
insert into #table(name,Mode,ReferId)values('Fisher','L',1)
insert into #table(name,Mode,ReferId)values('Manasa','R',1)
insert into #table(name,Mode,ReferId)values('Deekshit','L',2)
insert into #table(name,Mode,ReferId)values('Sujai','R',2)
insert into #table(name,Mode,ReferId)values('Fedric','L',3)
insert into #table(name,Mode,ReferId)values('Bruce','R',3)
insert into #table(name,Mode,ReferId)values('paul','L',4)
insert into #table(name,Mode,ReferId)values('walker','R',4)
insert into #table(name,Mode,ReferId)values('Diesel','L',5)
insert into #table(name,Mode,ReferId)values('Jas','R',5)
insert into #table(name,Mode,ReferId)values('Edward','L',6)
insert into #table(name,Mode,ReferId)values('Lara','R',6)
select *from #table
How do i write the CTE for count the Binary tree nodes on level basis. Here is the example,
now,what i want to do is if i'm going to calculate the Count of the downline nodes.which means i want to calculate for '1' so the resultset which i'm expecting
count level mode
1 1 L
1 1 R
2 2 L
2 2 R
4 3 L
2 3 R
How do i acheive this,i have tried this
with cte (advId,ReferId,mode,Level)
as
select advId,ReferId,mode,0 as Level from #table where advid=1
union all
select a.advId,a.ReferId,a.mode ,Level+1 from #table as a inner join cte as b on b.advId=a.referId
select *From cte order by Level
i hope its clear. Thank you

See Itzik Ben-Gan examples for the subject
REATE TABLE Employees
empid int NOT NULL,
mgrid int NULL,
empname varchar(25) NOT NULL,
salary money NOT NULL,
CONSTRAINT PK_Employees PRIMARY KEY(empid),
CONSTRAINT FK_Employees_mgrid_empid
FOREIGN KEY(mgrid)
REFERENCES Employees(empid)
CREATE INDEX idx_nci_mgrid ON Employees(mgrid)
SET NOCOUNT ON
INSERT INTO Employees VALUES(1 , NULL, 'Nancy' , $10000.00)
INSERT INTO Employees VALUES(2 , 1 , 'Andrew' , $5000.00)
INSERT INTO Employees VALUES(3 , 1 , 'Janet' , $5000.00)
INSERT INTO Employees VALUES(4 , 1 , 'Margaret', $5000.00)
INSERT INTO Employees VALUES(5 , 2 , 'Steven' , $2500.00)
INSERT INTO Employees VALUES(6 , 2 , 'Michael' , $2500.00)
INSERT INTO Employees VALUES(7 , 3 , 'Robert' , $2500.00)
INSERT INTO Employees VALUES(8 , 3 , 'Laura' , $2500.00)
INSERT INTO Employees VALUES(9 , 3 , 'Ann' , $2500.00)
INSERT INTO Employees VALUES(10, 4 , 'Ina' , $2500.00)
INSERT INTO Employees VALUES(11, 7 , 'David' , $2000.00)
INSERT INTO Employees VALUES(12, 7 , 'Ron' , $2000.00)
INSERT INTO Employees VALUES(13, 7 , 'Dan' , $2000.00)
INSERT INTO Employees VALUES(14, 11 , 'James' , $1500.00)
The first request is probably the most common one:
returning an employee (for example, Robert whose empid=7)
and his/her subordinates in all levels.
The following CTE provides a solution to this request:
WITH EmpCTE(empid, empname, mgrid, lvl)
AS
-- Anchor Member (AM)
SELECT empid, empname, mgrid, 0
FROM Employees
WHERE empid = 7
UNION ALL
-- Recursive Member (RM)
SELECT E.empid, E.empname, E.mgrid, M.lvl+1
FROM Employees AS E
JOIN EmpCTE AS M
ON E.mgrid = M.empid
SELECT * FROM EmpCTE
Using this level counter you can limit the number of iterations
in the recursion. For example, the following CTE is used to return
all employees who are two levels below Janet:
WITH EmpCTEJanet(empid, empname, mgrid, lvl)
AS
SELECT empid, empname, mgrid, 0
FROM Employees
WHERE empid = 3
UNION ALL
SELECT E.empid, E.empname, E.mgrid, M.lvl+1
FROM Employees as E
JOIN EmpCTEJanet as M
ON E.mgrid = M.empid
WHERE lvl < 2
SELECT empid, empname
FROM EmpCTEJanet
WHERE lvl = 2
As mentioned earlier, CTEs can refer to
local variables that are defined within the same batch.
For example, to make the query more generic, you can use
variables instead of constants for employee ID and level:
DECLARE @empid AS INT, @lvl AS INT
SET @empid = 3 -- Janet
SET @lvl = 2 -- two levels
WITH EmpCTE(empid, empname, mgrid, lvl)
AS
SELECT empid, empname, mgrid, 0
FROM Employees
WHERE empid = @empid
UNION ALL
SELECT E.empid, E.empname, E.mgrid, M.lvl+1
FROM Employees as E
JOIN EmpCTE as M
ON E.mgrid = M.empid
WHERE lvl < @lvl
SELECT empid, empname
FROM EmpCTE
WHERE lvl = @lvl
Results generated thus far might be returned (but are not guaranteed to be),
and error 530 is generated. You might think of using the MAXRECURSION option
to implement the request to return employees who are two levels below
Janet using the MAXRECURSION hint instead of the filter in the recursive member
WITH EmpCTE(empid, empname, mgrid, lvl)
AS
SELECT empid, empname, mgrid, 0
FROM Employees
WHERE empid = 1
UNION ALL
SELECT E.empid, E.empname, E.mgrid, M.lvl+1
FROM Employees as E
JOIN EmpCTE as M
ON E.mgrid = M.empid
SELECT * FROM EmpCTE
OPTION (MAXRECURSION 2)
WITH EmpCTE(empid, empname, mgrid, lvl, sortcol)
AS
SELECT empid, empname, mgrid, 0,
CAST(empid AS VARBINARY(900))
FROM Employees
WHERE empid = 1
UNION ALL
SELECT E.empid, E.empname, E.mgrid, M.lvl+1,
CAST(sortcol + CAST(E.empid AS BINARY(4)) AS VARBINARY(900))
FROM Employees AS E
JOIN EmpCTE AS M
ON E.mgrid = M.empid
SELECT
REPLICATE(' | ', lvl)
+ '(' + (CAST(empid AS VARCHAR(10))) + ') '
+ empname AS empname
FROM EmpCTE
ORDER BY sortcol
(1) Nancy
| (2) Andrew
| | (5) Steven
| | (6) Michael
| (3) Janet
| | (7) Robert
| | | (11) David
| | | | (14) James
| | | (12) Ron
| | | (13) Dan
| | (8) Laura
| | (9) Ann
| (4) Margaret
| | (10) Ina
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
MS SQL optimization: MS SQL Development and Optimization
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Large scale of database and data cleansing
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Scheduling does not take the factory calendar for counting the workdays

I am scheduling my jobs in CPS 8 and I have imported my Factory calenders also. When using Factory calendars for scheduling the jobs for the 6th working day of every month, Its does not count the Saturday as a working day, where as the calendar I am using has Working day on Saturday.
Why is it so? And is there a way to solve this ?
Please suggest. Any help is appreciated.

Hi All,
I have used this same logic for scheduling jobs scheduling for the nth work days of every month.
But I have a job, where it is required to be scheduled on the 5th workday of a month and it is submitted once in every 6 months.
When I schedule it for every month, it works fine. But when I use a submit frame to submit it for once in every 6 months, it does not work.
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Madhu

Program (PL/SQL) for count the registers of all tables in a schema

Hi...
I create a little program , for count the registers of all tables in the schema...
If you need , send me your email...
Atte
Hector

Hi,
You can create a script by yourself by executing the script mentioned below:
Connect as sys or system....
SQL> spool test.sql
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Hi everybody.
I need a BADI for enter inventory count without doc. ref. Do anybody know some?
Thank you very much

Please. Any idea?
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Reports for Count the number of External Candidate Registration - ERecruitment

Dear Experts
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Cannot find an overload for "PeopleManager" and the argument count: "1".

Every time getting following error
Cannot find an overload for “PeopleManager” and the argument count: “1”.
at following line
$people = New-Object Microsoft.SharePoint.Client.UserProfiles.PeopleManager($context)
I am referring userprofile dll from 16 hive...

Hi,
Can you provide the complete script in use for a further research? It would make others easier to find out the root cause of this issue.
Here is a working demo which works in my environment, you can take it for a try:
#Specify tenant admin and URL
$User = "[email protected]"
#Configure Site URL and User
$SiteURL = "https://tenant.sharepoint.com/sites/mysite"
#Add references to SharePoint client assemblies and authenticate to Office 365 site - required for CSOM
Add-Type -Path "C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\16\ISAPI\Microsoft.SharePoint.Client.dll"
Add-Type -Path "C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\16\ISAPI\Microsoft.SharePoint.Client.Runtime.dll"
Add-Type -Path "C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\16\ISAPI\Microsoft.SharePoint.Client.UserProfiles.dll"
$Password = Read-Host -Prompt "Please enter your password" -AsSecureString
$Creds = New-Object Microsoft.SharePoint.Client.SharePointOnlineCredentials($User,$Password)
#Bind to Site Collection
$Context = New-Object Microsoft.SharePoint.Client.ClientContext($SiteURL)
$Context.Credentials = $Creds
#Identify users in the Site Collection
$Users = $Context.Web.SiteUsers
$Context.Load($Users)
$Context.ExecuteQuery()
#Create People Manager object to retrieve profile data
$PeopleManager = New-Object Microsoft.SharePoint.Client.UserProfiles.PeopleManager($Context)
Foreach ($User in $Users)
$UserProfile = $PeopleManager.GetPropertiesFor($User.LoginName)
$Context.Load($UserProfile)
$Context.ExecuteQuery()
If ($UserProfile.Email -ne $null)
Write-Host "User:" $User.LoginName -ForegroundColor Green
$UserProfile.UserProfileProperties
Write-Host ""
Thanks
TechNet Community Support
Please remember to mark the replies as answers if they help, and unmark the answers if they provide no help. If you have feedback for TechNet Support, contact
[email protected]

Counting the number of occurences in a table column

Hi All
I have a table with a column that contains approx. 5000 6-digit codes. A number of these codes are duplicted in the column, and I want to count the number of occurences of each code. The column looks a bit like -
WCID
940042
920012
940652
940199
188949
155146
155196
174196
152148
151281
196209
174015
182163
195465
195318
182008
189589
150675
There can be mulitple instances of each WCID and I need to count the number of instances of each. I also have access to another table that also has a column of each WCID, but only once - ie no multiple instances. The second table is identical except that there are only single instances of each WCID.
I thought I could either loop through on the table to be counted, from 100000 to 999999 and count each occurence that way, but it would be very inefficient. The other way I thought would be to perhaps select a WCID from the unique table, count the occurence of that, select the next WCID from the unique table, count that and so on, however I'm not sure how to do it in PL/SQL. Perhaps select the WCID from the unique table into a cursor, loop through that and compare it with the original table and count the instances?
I hope this makes some sense, any help would be really appreciated
Thanks
Bill

Hi, Bill,
That sounds like a job for GROUP BY:
SELECT    wcid
,         COUNT (*)       AS num_found
FROM      table_x
GROUP BY wcid
ORDER BY wcid
I hope that answers your question.
If not, post CREATE TABLE and INSERT statements for a little sample data, and the results you want from that data.

Did I make a mistake upgrading to ML? Count the costs!

Talk about your string of circumstances. All I really needed was to eliminate hum from the soundtrack of an oral-history video recording. The simplest solution seemed to be to update iMovie. I was using '09, which has virtually no capability to edit audio.
Well, when I tried to download iMovie '11 I learned that it would not work with Snow Leopard. Since I'd been considering upgrading for some time (but NOT read any fine print), I back-tracked and downloaded Mountain Lion. Then I downloaded and installed iMovie '11.
THEN, I noticed thosse funny marks in my dock. When I tried these icons I got the dreaded message "You can't open the application [AppName] because PowerPC applications are no longer supported."
Apps effected: Adobe CS2; Adobe Bridge; Microsoft Office (2004); Epson Scan.
This was brand-new news to me. I have tried to find out what if anything I can do about the loss of these apps (everyone of them legally-purchased items), and apparently I'm just without alternatives. Current version of CS6, about $600. Cheapest MS Office, $80. This is a BAD TRADE for a $20 OS upgrade!
And Epson Scan? There's one for the books. Epson sends me to the Apple Store, saying that is the only place to get an upgrade. Apple Store sees no problems, and informs me that there are no upgrades available or needed. System Preferences/Print & Scan sees the scanner, so that's not the problem.
About the internal optical drive: Before the OSX upgrade, the drive was working nominally. I know, because I burned a number of disks within the last week or two. Now? The drive appears to recognize music CDs, but it WILL NOT recognize blank disk media. I have tried both Toast Titanium 7 (most recent) and since that wouldn't work I tried OSX's native disk burning function. In neither case will the drive admit that it has a blank disk inserted. I just ruminates for 15-20 seconds and spits the disk out.
I also have an older Plextor external optical drive. But Apple Support itself gives completely mixed counsel regarding whether or not Mountain Lion can be used with an external optical drive. One place says it will work; another place tells you to use a networked computer's optical drive (!); many other places say an external drive won't work at all. Hey Apple, make up your mind!
Now, I'm sure somewhere in fine legal print they informed me that PowerPC apps would no longer work with ML. But that information was well-hidden, and did not surface in any professional reviews I read. So these behaviors were a complete surprise to me, and not the pleasant sort.
Needless to say, I'm left feeling really ill-used by Apple. Sure, I've got an up-to-date operating system, but now I'm left counting the costs. And so should you. The technically-oriented in this community will perhaps sneer at my naivete. But you need to recognize that not all Apple clients are technically up to your standards. Give us a break!! [I myself have been using PCs intensively since the second-generation IBM PC in the late 1970's.]
I'm ticked. In case it's not obvious. And feeling let down by Apple. And I've been a cheer-leader for them for many years.

I feel your pain! This happened to me with I replaced my dead iMac G5 with a new Mac Mini in August, 2011 and did not do my usual due diligence on Lion!
Try Apple's Image Capture application, provided for free in the Applications folder with your Epson. I use it all the time for my Epson Artisan 810.
Toast 7 is way too old; I think they are up to 11 or 12 now. But you should be able to burn discs from the Finder in any event.
Which iMac do you have; check the Model Identifier in About this Mac, More Info, System Report.
Since my Mac Mini has no optical drive, I use one that I purchased for $39 from Fry's some years ago to get the ability to burn DL DVDs and it seems to run fine in Lion with Toast 10.
Here is a "canned" answer I give for many in your situation. Study all of this and respond with more information so we can guide you to your solution:
Unfortunately you got caught up in the minor miracle of Rosetta. Originally licensed by Apple when it migrated from the PowerPC CPU platform that it had used from the mid-1990's until the Intel CPU platform in 2006, Rosetta allowed Mac users to continue to use their library of PPC software transparently in emulation.
However, Apple's license to continue to use this technology expired with new releases of OS X commencing with Lion (and now Mountain Lion). While educational efforts have been made over the last 6 years, the fact is that Rosetta was SO successful that many users were caught unaware UNTIL they upgraded to Lion or Mountain Lion.
Workarounds:
1. If your Mac will support it, restore OS X Snow Leopard;
2. If your Mac will support it, partition your hard drive or add an external hard drive and install Snow Leopard into it and use the "dual-boot" method to choose between your PowerPC software or Lion/Mt. Lion;
3. Upgrade your software to Intel compatible versions if they are available, or find alternative software that will open your data files, modify them and save them;
4. Install Snow Leopard Server (with Rosetta) into Parallels or VMWare Fusion for concurrent use of your PowerPC applications with Lion or Mt. Lion:
[click on image to enlarge]
Apple has now restarted to sell Snow Leopard Server at a 95% discount over its original price: only $19.99 + sales tax & shipping; telephone orders only, call 800-MYAPPLE (800-692-7753) - Apple Part Number: MC588Z/A
NOTE: Computer games with complex, 3D or fast motion graphics may not work well or at all in virtualization.
I am surprised that the professional reviews did not mention the lack of Rosetta in Mountain Lion.
When one similarly frustrated poster here on this forum expressed his sentiment that Apple should have posted a big red flag about Mountain Lion not having Rosetta, I pulled out my PowerPC version of Photoshop and created the image above!

Is there a way to count the number of times an array moves from positive to negative?

I have an array of values, and I need to find the number of times that the array changes signs (from positive to negative, or vice versa). In other words from a graphical standpoint, how many times a certain line crosses the x-axis. Counting the number of times the array equals zero does not help however, because the array does not always equal exactly zero when it crosses the axis (ie, the points could move from .1 to -.1).
Thanks for you help. Feel free to email me at [email protected] I only have lv 5.1.1 so if you attach any files, they cannot be version 6.0.

Attached is a VI showing the # of Pos and Neg numbers in an array, with 0 considered as non-Pos. It is easily modifiable to other parameters - including using the X-axis value as your compare point versus only Zero.
This is a modified VI from LV (Separate Array.vi)
Compare this with your other responses to find the best fit.
Doug
Attachments:
arraysizesposneg.vi ‏40 KB

Compare firts count for second count the doc.inventory

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