Compare the result of a query with a number and return a message

Question

Hello,
I have the following query in oracle 9i:
SELECT COUNT(*)
FROM hourly_files
WHERE date_received = TO_DATE((SELECT TO_CHAR(SYSDATE - INTERVAL '1' DAY,'DDMMYYYY')
FROM DUAL), 'DDMMYYYY');
This will produce a count of the required rows
I need to compare the output number with another hardcoded number (threshold) and print an appropriate message e.g.
if the output of the above query is 18000 and the threshold number is set to 20000, then output a meesage:
Number of files received less than 2000
Any help will be much appreciated !
Thank you.

Answer 1

SQL> ed
Wrote file afiedt.buf
  1  SELECT CASE WHEN COUNT(*) >5 THEN 'Number is > than 5'
  2              WHEN COUNT(*) <1 THEN 'Its less than 1'
  3  ELSE 'Its in between'
  4  END
  5  FROM emp
  6* WHERE deptno=20
SQL> /
CASEWHENCOUNT(*)>5
Its in between
SQL> SELECT COUNT(*) FROM emp
  2  WHERE deptno=10;
  COUNT(*)
         3