Comparing 2 one dimentional array

I have master list and a child list. Need to check whether the values in the child list exist in the master list. Please provide me a code to do this efficiently

If your arrays are really nested tables then check out the SUBMULTISET condition or the MULTISET INTERSECT operator.
Joe Fuda
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  • One Dimentional Array Problem

    Write an application that inputs five numbers, each of which is between 10 and 100, in inclusive. As each number is read, display it only if it is not a duplicate of a number already used. Provide for the "worst case," in which all five numbers are different. Use the smallest array to solve this problem. Display the complete set of unique values input after the user inputs each new value.
    What I have so far is this only...
    int array[] = {32, 18, 64, 18, 35};
    System.out.printf("%s%8s\n", "Index", "Value");
         for(int counter = 0; counter < array.length; counter++){
              System.out.println("  " + counter + "       " + array[counter]);
         }Someone please help me with this... it's due tomrow and I have no clue how to check if same number has been entered and return the value of 0 for it.

    yeah i know it does
    everything works
    i just had to switch up 2 values because it was giving me a reversed solution
    that array[k] into j, also i just switched all the variables into the common i use a lot.
    public class Duplication {
          * Method main
          * @param args
         public void duplicate(){
              int array[] = {32, 18, 64, 18, 64};
              System.out.printf("%s%8s\n", "Index", "Value");
              for (int counter1 = 0; counter1 < array.length; counter1++){
                   for (int counter2 = 0; counter2 < array.length; counter2++){
                        if ((array[counter1] == array[counter2]) && (counter2 != counter1)){
                             array[counter2] = 0;
                   System.out.printf("%3d%9d\n", counter1, array[counter1]);
         public static void main(String[] args) {
              Duplication dupe = new Duplication();
              dupe.duplicate();
    }Once again, thank you so much

  • Multi-dimentional array

    I have an multi dimentional array
    it has 5 columns and 8 rows
    A B C D E
    F G H I J
    K L M N O
    P Q R S T
    U V W X Y
    etc
    if i remove the row beginning [1][0]
    how can I get all the ones passed that row to shuffle up to fill the gap?
    A B C D E
    K L M N O
    P Q R S T
    U V W X Y
    ends up as
    A B C D E
    K L M N O
    P Q R S T
    U V W X Y
    Code would be lovely, I am new to this programming lark and I am not sure i like it :'(

    This is something done best (as previously suggested) with collections. Look into the tutorial and APIs for ArrayList and such. However, if you need to use arrays, here is a program that does (rather poorly I would think...)
    public class MultiArrayTest {
        public static void printData(char[][] data, int numRows, int numCols) {
             for (int r = 0; r < numRows; r++) {
                  for (int c = 0; c < numCols; c++){
                       System.out.print("" + data[r][c] + " ");
                  System.out.println(" ");
              System.out.println(" ");
        public static int deleteRow(char[][] data, int row, int maxRows, int maxCols) {
             for (int r = (row-1); r < (maxRows-1); r++){
                  for (int c = 0; c < maxCols; c++) {
                       data[r][c] = data[r+1][c];
             return maxRows-1;
         public static void main(String[] args) {
              char[][] data = { {'A', 'B', 'C', 'D', 'E'},
                                 {'F', 'G', 'H', 'I', 'J'},
                                 {'K', 'L', 'M', 'N', 'O'},
                                 {'P', 'Q', 'R', 'S', 'T'},
                                 {'U', 'V', 'W', 'X', 'Y'} };
              int maxRows = 5;
              int maxCols = 5;
              printData(data, maxRows, maxCols);
              maxRows = deleteRow(data,3,maxRows,maxCols);
              printData(data, maxRows, maxCols);
    }

  • How to compare 1000 X 512 arrays

    Hello there,
    I have problem with comparing large amount of arrays. I have 1000 x 512 arrays. That means i have 1000 lines and each line contain 512 elements. I want to compare this 512 elements of each line and short out same one. how can i do? In result i want only the filtered one that means if out of 1000 line if 200 line are same then i want only 800 arrays that means 800 X 512
    Thanx in advance,
    dipen

    Is the 2D array sorted (i.e. are the duplicate rows next to each other)?
    Is the duplicate row always the same or can you have several different rows that are duplicate?
    What is the datatype of the array?
    No matter what, this seems like an easy task. Can you attach a VI containing typical data?
    LabVIEW Champion . Do more with less code and in less time .

  • Deleting row of zero in one dim array

    In my application, I am using the first column of the table as a selection from the combo box. The table is converted to one dimension array of 200 rows and 1 column, Some of the rows have zero value which is visible in the combo box selection , I need to remove the rows containig zero before linking to combo pbox can it be possible
    With regards
    anusree

    Hi,
    Please find attached the VI doing what tst has explained
    The For-loop indexes each element from the Input Array, Insert the element into the new array if it is a non-zero.
    If it is a zero, simply shift the array without any insertion.
    Cheers!
    Ian F
    Since LabVIEW 5.1... 7.1.1... 2009, 2010
    依恩与LabVIEW
    LVVILIB.blogspot.com
    Attachments:
    Remove 0s from array.vi ‏23 KB

  • I just updated to 5.7 and the exported files are blurry. I compared the ones I exported before the change and they are fine. I have not change any settings.

    I just updated to 5.7 and the exported files are blurry. I compared the ones I exported before the change and they are fine. I have not change any settings.

    I don't understand your last paragraph.
    "The home page also has a full bar ..." What does "full bar" mean? " ... instead of the tray it had before."  What does "tray" mean?
    Anyway, you might try Settings > General > Reset > Reset Home Screen Layout
    I guess that cannot make things any worse.

  • Sort two one dimensional arrays

    I am having trouble sorting two one dimensional arrays. The first array is int type with ID numbers. I use a bubble sort to sort those. The other array is a string array of video titles. When the first int type array of ID numbers sort, I want the second string type array to follow it. I have tried many things and I can not get it to work properly. Here is what I have for now without the string sort. Can someone help me?
    public class Video
         public static void main(String[] args)
         int[] numID = {168, 397, 102, 39, 239};
         String[] videoTitle = {"Godzilla", "Superman", "Hannibal", "Star Wars", "Men In Black"};
         System.out.println("Here are your selections:");
         System.out.println();
    System.out.print(numID[0]);
         System.out.println("\t" +videoTitle[0]);
         System.out.print(numID[1]);
         System.out.println("\t" +videoTitle[1]);
         System.out.print(numID[2]);
         System.out.println("\t" +videoTitle[2]);
         System.out.print(numID[3]);
         System.out.println("\t" +videoTitle[3]);
         System.out.print(numID[4]);
         System.out.println("\t" +videoTitle[4]);
         System.out.println();
    System.out.println();
    //Sorting ID numbers in ascending order
         int a;
         int b;
         int temp;
    for (a = 0; a < (numID.length - 1); ++a)
         for(b = 0; b < (numID.length - 1); ++b)
              if(numID[b] > numID[b + 1])
                             temp = numID;
                             numID[b] = numID[b + 1];
                             numID[b + 1] = temp;
              System.out.println("Here are your selections in ascending order:");
              System.out.println();
         System.out.print(numID[0]);
              System.out.println("\t" +videoTitle[0]);
              System.out.print(numID[1]);
              System.out.println("\t" +videoTitle[1]);
              System.out.print(numID[2]);
              System.out.println("\t" +videoTitle[2]);
              System.out.print(numID[3]);
              System.out.println("\t" +videoTitle[3]);
              System.out.print(numID[4]);
              System.out.println("\t" +videoTitle[4]);
              System.out.println();
         System.out.println();

    There are ways to do that, of which the simplest would be to switch entries in both arrays at the same time. But since Java is an object-oriented language, the better way to do it would be to make a Video object containing a number and a title, put those objects in an array, and sort the objects.

  • To make one larger array using other two arrays

    Hi,
    I have two one dimensional arrays, using these two arrays as index need to create another larger one dimensional array.
    like : if two one dimensional arrays namely X and Y, then X and Y should go as index for the final array.
    Please help.
    Thank you

    kathyayini wrote:
    I have two one dimensional arrays, using these two arrays as index need to create another larger one dimensional array.
    like : if two one dimensional arrays namely X and Y, then X and Y should go as index for the final array.
    Please help.I second jverd, but you might want to look at Arrays.copy() and System.arrayCopy().
    Winston

  • Initialize a multi-dimentional array at declaration

    Is there any way I can initialize a multi-dimentional array at declaration.
    Is it possible to do the following in a single line?
               Vector vClicks[] = new Vector[2];
                vCliks[0] = new Vector();
                vClicks[1] = new Vector();I need to globally initialize it and then used it randomly in different methods.
    Thanks
    Message was edited by:
    getusama

    Is there any way I can initialize a multi-dimentional
    array at declaration.
    Is it possible to do the following in a single line?
    Vector vClicks[] = new Vector[2];
    vCliks[0] = new Vector();
    vClicks[1] = new Vector();
    I need to globally initialize it and then used it
    randomly in different methods.
    Thanks
    Message was edited by:
    getusama
    Vector [] v = {new Vector(), new Vector()};~Tim
    Message was edited by:
    SomeoneElse

  • Is it better to make multiple arrays of data or one big array and access it many times?.

    I am going to acquire up to 5 samples per second of 50 channels over 30 minutes then average ten of the channels and generate a report.  There are other bits of information needed to complete my task and graphs.  Would it be "faster" for the PC to have one large 4d array with all the information or faster to make several separate arrays?  Would it be more reliable to have one or many(fewer code lockups)?
    Also,
    Yes, I do mean to be using labview.  I expected this crowd to have a different perspective (and I could not find LV blog).
    For each channel, I want to scale per 6 other variables per channel(nominal high, mid, low, and reading high, mid low)  So there is the channels and time, then there is the calibration values, then there is the calibrated readings.  If I put all that along with my test information in one large matrix, it would be simpler for me to remember where in the matrix each item is, but if it is in several matrixies then the "active" matrix is smaller while the other information is not used.
    The sales rep for NI was indicating the computer power is much higher than I am used to.  (I have not started programming yet, I am preparing for a huge project on a "new"(2 year old)PC.)  I am trying to understand just how much power I am missing from my days of gwbasic, Q-basic and our current Visual Basic 6.0 running on XP.  This matrix question is new to me.
    Solved!
    Go to Solution.

    I don't see where you are getting 4 dimentions for your array.  I only see 2: channel and sample.
    From what you are describing, I would put any "support" information for a channel into a cluster.  So you should have an array of clusters to contain your support data.
    There are only two ways to tell somebody thanks: Kudos and Marked Solutions
    Unofficial Forum Rules and Guidelines

  • How to compare rows in 2D array?

    Hi,
    I have a 2D array of binary.
    - I want to compare all rows against each other.
    - Two rows should be compared if they have only one different element.
    - The result of comparison should be a row with the different element assigned as 2 (or any number different from 0, 1).
    - Continue to compare the result rows against each other.
    - Repeat it until no row can be compare (those final rows should be presented).
    Any idea will be appreciated!
    Solved!
    Go to Solution.

    sangquang wrote:
    I have a 2D array of binary.
    "Binary" is not a type. deep down, everything is binary one way or another. What do you actually have?
    sangquang wrote:
    - Two rows should be compared if they have only one different element.
    You have your oder of operations mixed up! You need to compare them first before you know if they have different elements.
    sangquang wrote:
    - The result of comparison should be a row with the different element assigned as 2 (or any number different from 0, 1).
    Please explain
    sangquang wrote:
    - Repeat it until no row can be compare (those final rows should be presented).
    Presented how? To the user? Does that mean all the result of the earlier row comparisons should not be presented? Why not?
    You post makes very little sense. Please attach a simple VI that contains a simple example of your 2D array (make current value default before saving). Then tell us what kind of result you would expect.
    LabVIEW Champion . Do more with less code and in less time .

  • Comparing data from an array

    Hi all
    I have a little problem regarding the use of arrays and obtaining the integer value from an index of one of the columns. I need to implement a program that reads data from serial ports. There are four serial ports and it is assumed that independant sets of data will be retrieved from each of these. I need my program to continuously loop and check to see if the data has changed at any of the serial ports (i've got this part working). The way it can be manually determined is if the file is opened and at the top of the data there is the error number which is incremented every time the data is changed. I have put the data into a 2D array for later use and have then put just the first column into a single array in the hope of bein
    g able to convert it to an integer or some form that can be compared. I need the highest error number for each peripheral to be stored (probably need separate loops/case for each serial port? - multitasking?) and when the data is next sent, i need to be able to compare it to see if the error number has changed and if it hasn't just continue looping and if it has make the new value the highest (in which case the rest of the data needs to manipulated and automatically updated in the database). I have been thrown head first into this project and to this date had only been a casual Labview programmer (V6i)
    Can anyone help?
    Ive attached the snippet that is for comapring the data only if anyone can build upon it (or scrap it!)
    Thanks
    Ridge
    Attachments:
    Array.vi ‏31 KB

    To compare the error is easy,attached is a little modification to your vi with shift register and Array max and min function. I'm not sure if this is the only problem.
    Attachments:
    Array[1].vi ‏38 KB

  • How to use XSLT for mapping feild names one by one to array element

    I have a XSLT case to map all the attributes feild name(not value) which has no child to the target, which is array loop.
    I give an sample below.
    source:
    <Items xmlns="http://www.example.org/sample">
    <SourceSystem>SourceSystem2573</SourceSystem>
    <TimeStamp>2010-01-17T20:54:08.234</TimeStamp>
    <Item>
    <ID>2574</ID>
    <Type>2575</Type>
    <Name>2576</Name>
    </Item>
    </Items>
    source XSD like:
         <element name="Items" type="tns:ItemsType"></element>
         <complexType name="ItemsType">
              <sequence>
                   <element name="SourceSystem" type="string" maxOccurs="1"
                        minOccurs="1">
                   </element>
                   <element name="TimeStamp" type="dateTime" maxOccurs="1"
                        minOccurs="1">
                   </element>
                   <element name="Item" type="tns:ItemType"
                        maxOccurs="unbounded" minOccurs="1">
                   </element>
    </sequence>
         </complexType>
    <complexType name="ItemType">
              <sequence>
                   <element name="ID" type="string" maxOccurs="1"
                        minOccurs="1">
                   </element>
                   <element name="Type" type="string" maxOccurs="1"
                        minOccurs="1">
                   </element>
    <element name="Name" type="string" maxOccurs="1"
                        minOccurs="1">
                   </element>
    </sequence>
         </complexType>
    target need to be like:
    <ns1:AttributesCollection>
    <ns1:Attributes>
    <ns1:fieldname>SourceSystem</ns1:fieldname>
    </ns1:Attributes>
    <ns1:Attributes>
    <ns1:fieldname>TimeStamp</ns1:fieldname>
    </ns1:Attributes>
    <ns1:Attributes>
    <ns1:fieldname>ID</ns1:fieldname>
    </ns1:Attributes>
    <ns1:Attributes>
    <ns1:fieldname>Type</ns1:fieldname>
    </ns1:Attributes>
    <ns1:Attributes>
    <ns1:fieldname>Name</ns1:fieldname>
    </ns1:Attributes>
    </ns1:AttributesCollection>
    target XSD:
    <xs:element name="AttributesCollection" type="AttributesCollection"/>
    <xs:complexType name="AttributesCollection">
    <xs:sequence>
    <xs:element name="Attributes" type="Attributes" minOccurs="0" maxOccurs="unbounded"/>
    </xs:sequence>
    </xs:complexType>
    <xs:complexType name="Attributes">
    <xs:sequence>
    <xs:element name="fieldname" minOccurs="0">
    <xs:simpleType>
    <xs:restriction base="xs:string">
    <xs:maxLength value="100"/>
    </xs:restriction>
    </xs:simpleType>
    </xs:element>
    </xs:sequence>
    </xs:complexType>
    I know we can use local-name() to get the tag/field name,
    but I have not idea how to get these leaf field names one by one and then mapping to every array elements.
    I tried whole day but no successful
    Does anyone have some idea?
    Thanks very much!
    Keith
    Edited by: user1065212 on 17-Jan-2010 22:50
    Edited by: user1065212 on 17-Jan-2010 22:53
    Edited by: user1065212 on 17-Jan-2010 22:59

    can you paste source xsd and the correct xml output, the current one isn't really valid
    <ID>2574</TotalNumOfItems>

  • How do i output multiple arrays from a case structure to create one larger array

    I currently have a vi that has one hardware input that i needed to take a measurement then be moved and take a similar measurement at a different point.  To accomplish this i used a while loop inside a case structure.  The while loop takes the measurement  and finds the numbers i need while the case structure is changed per the new measurement location.  I want to take the data points i have created in each case and output them into a single table.  I assumed to do this the best way would be to get the data from each case into its own built array and build a larger array but I cant get the information out of the case structure so that it all inputs at different places.
    thanks for your help
    Attachments:
    Array.vi ‏30 KB

    Hi Ross,
    attached you will find a solution for your table building problem.
    I would suggest thinking about program design - having the same case content in several cases doesn't make sense. I also would not want my user to press several stop buttons depending on choosen measurement...
    Best regards,
    GerdW
    CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
    Kudos are welcome
    Attachments:
    Array.vi ‏45 KB

  • How to read a text delimited file using 2 dimentional array in java ??

    hi,
    I am new to java programming.. I have to do a task where in i have to read a text delimeted file in an array.. For example.. If the file is as follows
    Name place Value
    adi goa 20
    shri mumbai 30
    riya bangalr 45
    I want it to be read in java so as to get an array[row][columns]
    This is something i am currently upto, but cant get any further.
    import java.io.BufferedReader;
    import java.io.FileReader;
    public class generateGML{
    public static void main(String[] argv)
    throws Exception{
    BufferedReader fh = new BufferedReader(new FileReader("filename.txt"));
    String s;
    while ((s=fh.readLine())!=null){
    String[] columns = s.split("\t");
    String name = columns[0];
    String place = columns[1];
    String value = columns[2];
    It reads columns,But I want it two dimentionally,as in something like matrix[row_num][column_num].
    Can anyone please suggest me..

    You could do the following:
    String[][] array = new String[rows][];
    int row_num = 0;
    while ((s=fh.readLine())!=null) {
       array[row_num++] = s.split("\t");
    }However, you need to know ahead of time how many rows to allocate. If you allocate more than needed, you'll need to copy to a new array, or you'll need to keep track of how much is actually populated. If you allocate less than needed, you'll get an ArrayIndexOutOfBoundsException.
    Another (likely better) approach is:
    Do you really need it as a 2-dimensional array? Can you make a List of objects that have a name, place, and value? Then you don't need to know how big of a list to allocate ahead of time, assuming you use a list that grows itself (like ArrayList or LinkedList). Your code would be much easier to read if you could say:
    String name = list.get(10).getName();instead of
    String name = array[10][0];

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