Confusion about make Thread running(waiting online)

Question

the code like this
class a implements Runnable{
public void run(){
while(true){};
class App {
public static void main(String arg[]){
a mya=new a();
(new Thread(mya)).start();
(new Thread(mya)).start();
the two thread will run simultaneously .
could u tell me what's the order and step the two thread become runnable and then run.
why the two thread could run simultaneously?
They are the same priority and one is busy enough not to let others to run.
but actually they did run simultaneously.
why one thread could become runnable state and then running automaticatically!

Answer 1

I can't really understand your problem, but i think it this here:
A runnable class should look like this:
class myThread implements Runnable {
Thread thisThread
myThread () {
thisThread = new Thread(this);
thisThread.start();
public void run () {
while (Thread.currentThread() == this) {
//Do anything
class App {
public static void main (String a[]) {
(new myThread).start();
(new myThread).start();
This program will generate two threads, and as it's the sense of threads the will run simultaneously.
if you call start() of a thread, this will start the thread and goto next line, while the tread calls his run().
But where is the problem????