Convert number to alphabet
hi
i need help in converting number to alphabet
for example 4 to D, 2 to B, etc
thank you for helping
best regards
andors
private String Number2String(int number, bool isCaps)
Char c
= (Char)((isCaps ? 64 : 96) + number);
return c.ToString();
No point in doing - 1.
If you want 0 to be A then start at 65 for caps, 97 for lower.
Edit:
After some messing around, I've come up with the perfect method:
public static string numberToAlpha(long number, bool isLower = false)
string returnVal = "";
char c = isLower ? 'a' : 'A';
while (number >= 0)
returnVal = (char)(c + number % 26) + returnVal;
number /= 26;
number--;
return returnVal;
Similar Messages
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Convert number to letter of alphabet?
Hi,
Is there a LabWindows function for converting a number to an alphabet equivalent?
I was trying something like this...
char getLetterOfAlphabetByNum(int number){
//test if alpha
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DebugPrintf ("Error converting number to letter. Non-alphabetic.");
else{
//take decimal and convert to ascii
statusReturned=Fmt (&letter, "%s<%d", number);
if(statusReturned<0)
DebugPrintf ("Error converting number to letter!\n");
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Thanks!
Solved!
Go to Solution.It seems to me that you could simplify your code this way:
//number of alphabet to letter
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number += 64;
//test if alpha
if (!isalpha (number)) {
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return 0;
return (char)number;
I excluded the test for printable characters as is it overcome by test for alphabetic.
Also, be warned that passing numbers from 33 to 58 returns lowercase letters.
Proud to use LW/CVI from 3.1 on.
My contributions to the Developer Zone Community
If I have helped you, why not giving me a kudos? -
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Dear All
Some can help me
I want to convert below MS-SQL query in oracle 10g. please help me.
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--- Hey John... I just did it and saw your hint now !!! -
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I want to add both the column and result should be 21/11/11
Thanks
NiharHmm,
Because, you are using YYYY for '09'.
SQL> ed
Wrote file afiedt.buf
1* select to_char(to_date('10/01/09','DD/MM/RRRR'),'DD/MM/YYYY') from dual
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Wrote file afiedt.buf
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Wrote file afiedt.buf
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10/01/2012-Arun -
Hi,
I want to convert number in words and get the output through a query.
For example :if the value in row is 1311 then I want the query to return it like one thousand three hundreds and eleven.
Any help is highly appreciated.
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SQL> select to_char(to_date(0,'J'), 'JSP') as converted_form from dual;
select to_char(to_date(0,'J'), 'JSP') as converted_form from dual
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SQL> Better to build function as showed by Tom Kyte in the link given earlier.
Nicolas. -
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Thanks,
Ashwini KHi,
Please refer below links.
http://satyaobieesolutions.blogspot.in/2013/06/dateformat-converting-using-evaluate.html
http://satyaobieesolutions.blogspot.in/2013/06/date-format-change.html
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Program or FM to convert number of days into a CalDay format (ddmmyyy)
Hi ABAP friends,
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VenkatThanks Pranaam.
Two things:
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2. My requirement is actually reverse as you explained. I can certainly hard code the starting date: 01011900, but here the input should be the number of days. and I need the date (date2 in your ex.) based on the no. of days entered.
I found another FM which does exist in my BW system. That is: FIMA_DAYS_AND_MONTHS_AND_YEARS
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How to convert number field into time
Hi
I have made a form for storing of private dialed calls from different extensions. To store call duration i have assigned a number field which is storing following type of data
1.34
1.19
37.29
1.47
In above mentioned data decimals are seconds and left side is minutes.
Now the requirement is that if second is > 30 then 1 minute should be added in minutes else 30 seconds should appear instead of original seconds.
Please Help!>
To store call duration i have assigned a number field which is storing following type of data
In above mentioned data decimals are seconds and left side is minutes.
>
Please provide info about the form in which you RECEIVE the data. Do you receive the data in MM.SS format like you say you are storing it?
If not, why are you storing it this way?
Unless you have some reason to STORE the data differently just store it the way you got it. That way you won't lose any precision and you can manipulate it any way you need to for display purposes.
If you receive START_TIME and END_TIME then store both of those. Don't calculate and store duration; you will lose END_TIME and if you later need to calculate duration to a different precision you won't be able to.
Where is the data being stored? Oracle?
Write a simple function to convert a duration to minutes and seconds using the '>30' rule you have. Then if the rule changes you can write a new function or modify the existing one and the data itself doesn't have to change. -
Hello.
I'm new at this stuff and need a hand with a function.
I have a Customer table that has a Date set as a number.
When I drag this field on to the report I get the following: 20,071,101.00
Which makes complete sense since it is a number field.
How do I convert this field to a date format?
I tried the following:
cDateTime ({CUS.DATESTART})
Unfortunately, I'm doing something wrong as it is providing me with the following error:
Error: Dates must be between year 1 and year 9999
What am I doing wrong?
Perhaps there is a much easier method then trying to create function...
Thanks in advance for your assistance.
StephaneHello Raghavendra.
Your solution has provided my answer.
I will provide my final solution for others to view:
Date(tonumber(left(totext({CUS.DATESTART},'##'),4)),tonumber(mid(totext({CUS.DATESTART},'##'),5,2)),tonumber(right(totext({CUS.DATESTART},'##'),2)))
Notice how I substituted the actual date with the field(number).
Here is reported field: 01/11/2007
Note: my field value at this point was equal to CUS.DATESTART = 20,071,101.00
Thank you very much for your quick assistance.
Stephane
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