How to add date with month after convert number to month?
How to add date with month after convert number to month?
Month Date Result
24 21/11/09 24*(21/11/09)
I want to add both the column and result should be 21/11/11
Thanks
Nihar
Hmm,
Because, you are using YYYY for '09'.
SQL> ed
Wrote file afiedt.buf
1* select to_char(to_date('10/01/09','DD/MM/RRRR'),'DD/MM/YYYY') from dual
SQL> /
TO_CHAR(TO
10/01/2009
SQL> ed
Wrote file afiedt.buf
1* select to_char(to_date('10/01/09','DD/MM/YYYY'),'DD/MM/YYYY') from dual
SQL> /
TO_CHAR(TO
10/01/0009Or with Add_months
SQL> ed
Wrote file afiedt.buf
1* select to_char(add_months(to_date('10/01/09','DD/MM/YYYY'),36),'DD/MM/YYYY') from dual
SQL> /
TO_CHAR(AD
10/01/0012
SQL> ed
Wrote file afiedt.buf
1* select to_char(add_months(to_date('10/01/09','DD/MM/RRRR'),36),'DD/MM/YYYY') from dual
SQL> /
TO_CHAR(AD
10/01/2012-Arun
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As the questions states, how do I average data with 78,74,73 and 55 points respectively and obtain an array of 78 points?
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Thank you.
Attachments:
average4.vi 40 KBThe add function is polymorphic. It accepts arrays as well as numerics, but you need to understand one thing about array operations in LV. Operations performed on arrays of different sizes will always (I think) work based on the smallest array. For example, if you auto index 2 arrays of different sizes into a for loop, the number of times the loop will run will be the size of the small array. The same is true here - when you wire 2 arrays of different sizes to the add function, only the first N elements of the larger array get processed. The rest are dumped. That's why you get 55 elements.
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The bottom part is your algorithm, only cleaned up. Note how much easier it would be to read now. You should always write clean code. Also, note that I have changed the representation on some of the data from DBL to I32. This is because this is the representation the array function work with and your code had the DBLs coerced for no reason.
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Try to take over the world!
Attachments:
average4MOD.vi 63 KB
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