Convert xml string into xml file?

Hi,
I got a method that returns an JDom Element object.
Then I use the JDOM Element toString method() to change it into xml string.
Now, I need to convert it into actual xml file.
How to I do it?
Thanks.

Hi,
If you got an xml string, just write it to an ordinary file. Look at FileWriter.
/Kaj

Similar Messages

Convert XML string into XML

Hi All,
Can you please let me know for any sample code in xslt/java mapping for converting XML string into XML. We use SAP Pi 7.0
My XML string starts like this
<?xml version="1.0" encoding="UTF-8" ?>
- <ns0:MT_ReceiverFileStructure <namespace>"><Output><?xml version="1.0" encoding="ISO-8859-9"?><?xml-stylesheet type="text/xsl" href="<xsl>"?><Tarih_Date Tarih="11.09.2014" Date="09/11/2014>
Thanks,
Pavithra

Thanks Praveen. It worked.
However, the xml i have is an extract from a exchange rate URL and it has the reference to a xsl in it as below
<?xml version="1.0" encoding="ISO-8859-9"?><?xml-stylesheet type="text/xsl" href="<ABC.xsl>"?>.
So there is an error in sxmb_moni. Is it possible to remove this.

REG: WRITE XML STRING INTO XML FILE

Hi All, I have a XML FILE on PC. I get a xml string from my server.
My Task: I want to append the xml string coming from the server into the existing xml file at a particular Node. Given below is my code :
String xmlString = baos.toString();
                  DocumentBuilder db4XMLString = docBuilderFactory.newDocumentBuilder();
                  InputSource inStream = new InputSource();
                  inStream.setCharacterStream(new StringReader(xmlString));
                  Document doc4XMLString = db4XMLString.parse(inStream);
                  Node root4XMLString = doc4XMLString.getElementsByTagName("epg").item(0);
                  doc.appendChild(doc.importNode(root4XMLString, true));
                  File file = new File(Constant.XMLFILEPATH);
                  Result result = new StreamResult(file.toURI().getPath());
                  Source source = new DOMSource(doc);
                  Transformer xformer = TransformerFactory.newInstance().newTransformer();
                  xformer.transform(source, result);But, wen i run my application I get following exception:
The markup in the document following the root element must be well-formed.
org.xml.sax.SAXParseException: The markup in the document following the root element must be well-formed.
at org.apache.xerces.parsers.DOMParser.parse(Unknown Source)
at org.apache.xerces.jaxp.DocumentBuilderImpl.parse(Unknown Source)
Is that my XML string is not well formed. Is it so then please let me how to convert my xml string into well formed XML data.
Please help me out.
Thanking You.

There are many reasons why xmlString could be not well formed. There is no magic recipe for making it well formed: just look at it and see why it is not parseable.
Note that this line:
String xmlString = baos.toString();can be problematic if you have non ASCII-7 characters in your XML document. baos could then contain a byte representation of these characters in one particular encoding, but, since you use the .toString() method that relies on the default encoding of your system, you can end up with a mismatch and garbage in your XML.

How to convert Java string into XML one?

With SAX I can parse an xml file, but I should create xml file by hands.
Ok, it's simple, but how to encode java string into XML constant
like "Hello & goodby" into "Hello & goodby" ?
Is there a standard method for such special xml characters?

If you are creating your XML "by hand" then just make sure your hands know that you have to do that. It isn't difficult to write a Java method to do it, if "by hand" means "in Java code". Otherwise your XML is not well-formed. And as far as I know there is no package that takes ill-formed XML and fixes it up.

Insert XML String into XML file at a certain position

Hello,
I have this xml string:
<jdbc-driver-params>
<url>jdbc:oracle:thin:@localhost:1521:mydb</url>
<driver-name>oracle.jdbc.OracleDriver</driver-name>
<properties>
<property>
<name>user</name>
<value>myuser</value>
</property>
</properties>
<password-encrypted>myuser</password-encrypted>
</jdbc-driver-params>and i need to insert it into an xml file at a certain position (as child for a node)
The xml file looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<jdbc-data-source xmlns="http://www.bea.com/ns/weblogic/90"
    xmlns:sec="http://www.bea.com/ns/weblogic/90/security"
    xmlns:wls="http://www.bea.com/ns/weblogic/90/security/wls"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.bea.com/ns/weblogic/920 http://www.bea.com/ns/weblogic/920.xsd">
    <name>myDB</name>
    <jdbc-data-source-params>
        <global-transactions-protocol>OnePhaseCommit</global-transactions-protocol>
    </jdbc-data-source-params>
</jdbc-data-source>And this is how I would like to get it in the end:
<?xml version='1.0' encoding='UTF-8'?>
<jdbc-data-source xmlns="http://www.bea.com/ns/weblogic/90" xmlns:sec="http://www.bea.com/ns/weblogic/90/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:wls="http://www.bea.com/ns/weblogic/90/security/wls" xsi:schemaLocation="http://www.bea.com/ns/weblogic/920 http://www.bea.com/ns/weblogic/920.xsd">
<name>mydb</name>
<jdbc-driver-params>
    <url>jdbc:oracle:thin:@localhost:1521:myDB</url>
    <driver-name>oracle.jdbc.OracleDriver</driver-name>
    <properties>
      <property>
        <name>user</name>
        <value>myuser</value>
      </property>
    </properties>
    <password-encrypted>myuser</password-encrypted>
</jdbc-driver-params>
<jdbc-connection-pool-params>
    <test-table-name>SQL SELECT 1 FROM DUAL</test-table-name>
</jdbc-connection-pool-params>
<jdbc-data-source-params>
    <global-transactions-protocol>OnePhaseCommit</global-transactions-protocol>
</jdbc-data-source-params>
</jdbc-data-source>So, I obtain the node for the given xml string, the jdbc-data-source node from the xml file and i attempt the appendChild. The problem is that nothing really gets inserted into the xml file.
Someone, any idea?
My code:
try
               DOMParser parser = new DOMParser();
               parser.parse(xmlFileName);
               Document doc = parser.getDocument(); // the document we will insert node into
               Node root = doc.getElementsByTagName("jdbc-data-source").item(0);
               //get XML string node
               DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
               DocumentBuilder db = factory.newDocumentBuilder();
               InputSource inStream = new InputSource();
               inStream.setCharacterStream(new StringReader(xmlString));
               Document doc4XMLString = db.parse(inStream);
               Node rootXMLString = doc4XMLString.getElementsByTagName("jdbc-driver-params").item(0);
               root.appendChild(doc.importNode(rootXMLString, true));
               return true;
          catch (Exception e)
               e.printStackTrace();
          }Thanks,
johnny
Edited by: smeag0l on Aug 6, 2008 5:08 PM
Edited by: smeag0l on Aug 6, 2008 5:43 PM

Well, you helped me again :-) Thank you very much!
Here is how the code should look:
                        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
               DocumentBuilder db4XMLFile = factory.newDocumentBuilder();
               Document doc4XMLFile = db4XMLFile.parse(xmlFileName);
               Node root4XMLFile = doc4XMLFile.getElementsByTagName(rootNodeName).item(0);
               DocumentBuilder db4XMLString = factory.newDocumentBuilder();
               InputSource inStream = new InputSource();
               inStream.setCharacterStream(new StringReader(xmlString));
               Document doc4XMLString = db4XMLString.parse(inStream);
               Node root4XMLString = doc4XMLString.getElementsByTagName(xmlStringNodeName).item(0);
               root4XMLFile.appendChild(doc4XMLFile.importNode(root4XMLString, true));
               File file = new File(xmlFileName);
                        Result result = new StreamResult(file.toURI().getPath());
               Source source = new DOMSource(doc4XMLFile);
               Transformer xformer = TransformerFactory.newInstance().newTransformer();
                  xformer.transform(source, result);

How to convert a string into xml file

Hi,
i have a string . the string contain fully formated xml data. i mean my string like below
<?xml version="1.0"?>
<PARTS>
   <TITLE>Computer Parts</TITLE>
   <PART>
      <ITEM>Motherboard</ITEM>
      <MANUFACTURER>ASUS</MANUFACTURER>
      <MODEL>P3B-F</MODEL>
      <COST> 123.00</COST>
   </PART>
   <PART>
......................i want to convert it into an xml file
can u help me?
thank u

Thank you Paul Clapham,
and sorry ..
i have some other doubt.. regarding xml
i want to post an XML file from one server(Server_1) to other server.(Server_2)
To generate an xml file i used DOM in Server_1.
using xml.transform , StringWriter i converted it into String.
I post the string to another server and there i will parse it.
for that i write the code like below in servlet in server_1
<form name=fn action=http://localhost:8080/server_2/parseXMl.do method=post>
<input type=hidden name=xmlFile value="+Xmlstring+">
<input type=submit >is this process is correct?
Some of the turorial told that use web-services/XML-RPC
but i new to both..
I want to complete it using my knowledge only/
Is it possible to do it?
Or any other alternative?
can help me?

XML: How to convert xml string into Node/Document

I have a string in xml form.
<name>
<first/>
<second/>
</name>
I want to convert this string into DOM Node or Document.
How can I do this?
Any help or pointer?
TIA
Sachin

Try this :
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(new org.xml.sax.InputSource(new StringReader(strXml)));Hope this helps.

Convert XML string into DOM

Hi all,
I have a question here regarding converting XML string into a DOM document.
How can I do this in Java?
The Document.Parse() methods do not have one that takes in String as its parameter.
I'm not sure what is the best way to do this in Java.
Any help is greatly appreciated.
Thank you in advance.
regards,
Sean

Convert XML String to Document with StringReader.
String xmlString;
DocumentBuilderFactory factory =
            DocumentBuilderFactory.newInstance();
            DocumentBuilder builder = factory.newDocumentBuilder();
   Document         document = builder.parse(new InputSource(new StringReader(xmlString)));

Convert string into XML inside BPEL

Hello ,
How to convert string into xml format ? And make element and define attribute inside it ??

There are several problems with your input:
1. Your xml is not well-formed because the attribute values should be enclosed withing double " quotes and not single ' quotes;
2. You use a prefix (sml) for the folowing part but you dont define the namespace:
<ids>
<VID ID="new"/>
<data>
<*sml:*attr name="std">
<sml:value></sml:value>
</sml:attr>
<sml:attr name="xde">
<sml:value></sml:value>
</sml:attr>
</data>
</ids>
Complete message should be:
<ids xmlns:sml="somenamespace">
<VID ID="new"/>
<data>
<sml:attr name="std">
<sml:value></sml:value>
</sml:attr>
<sml:attr name="xde">
<sml:value></sml:value>
</sml:attr>
</data>
</ids>
3. Do you assign this expression to a variable that is based on the schema of your message you want to parse
Regards,
Melvin
* TIP Answer the question as helpful or correct if it helps you , so that someone else will be knowing that this solution helped you or worked for you and also it gives points to the person who answers the question. *

Convert XML string into an abap format date and time

Hi,
Does anyone know of a method or a function module in ABAP which converts XML string into an abap format date and time.
Here is a part of the xml that I want to convert.
<ns2:EventDateTime>2009-07-02T10:13:45+10:00</ns2:EventDateTime>
<ns2:EventMessageTransmissionDateTime>2009-07-02T10:13:45.987+10:00</ns2:EventMessageTransmissionDateTime>
Currently EventDateTime and EventMessageTransmissionDateTime are type XSDDATETIME_Z and these are converted to proper dates and times. We will be changing these fields to a STRING instead of XSDDATETIME_Z. The reason for this is to make the field more versatile. The customer would be receiving dates with Zulu (2009-09-23T12:00:00Z), with offsets (2009-09-23T12:00:00+10:00/-10:00) and just local timestamp (2009-09-23T12:00:00). With this, we need to make the date fields as string
to be able to accept the various date formats (esp. the local timestamp).
I am looking for a standard function module or method that will convert the xml string to a proper date and time abap format.
Would appreciate anyone's help!
Thanks.
Edited by: eunice ocson on Jul 13, 2009 1:49 AM
Edited by: eunice ocson on Jul 13, 2009 1:50 AM
Edited by: eunice ocson on Jul 13, 2009 1:51 AM
Edited by: eunice ocson on Jul 13, 2009 1:51 AM

Hi Eunice
Use the FM 'SMUM_XML_PARSE'
for more info
[Convert XML string to ABAP|XML String to ABAP or GUI]
hope it helps you.
Thanks!!

How to convert database table into xml file

Hi.
How to convert database table into XML file in Oracle HTML DB.
Please let me know.
Thanks.

This not really a specific APEX question... but I search the database forum and found this thread which I think will help
Exporting Oracle table to XML
If it does not I suggest looking at the database forum or have a look at this document on using the XML toolkit
http://download-east.oracle.com/docs/html/B12146_01/c_xml.htm
Hope this helps
Chris

Conversion of xml string to xml file

To convert xml string to xml file in java i used
Document XMLDoc=DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(new InputSource(new StringReader("<root><main>Title</main></root&g t;")));
But it is showing an error as InputSource cannot be resolved
How to rectify this

I assume you mean there is a compiler error? (It helps if you explain your problem instead of just giving a vague description of it.) It sounds like you have to import InputSource. You do know about the import statements that go at the beginning of a Java class, don't you?

A class to format an XML string into indented xml code

I am looking for a class or a piece of code to format an XML string into indented xml code
for example: an XML string as follows
<servlet><servlet-name>Login</servlet-name>servlet-class>ucs.merch.client.system.LoginServlet</servlet-class></servlet><servlet-mapping><servlet-name>Login</servlet-name>
to format into :
<servlet>
<servlet-name>Login</servlet-name>
<servlet-class>ucs.merch.client.system.LoginServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Login</servlet-name>
<url-pattern>/Login</url-pattern>
</servlet-mapping>
e-mail : [email protected]

Xerces has a class called OutputFormat
If you have your XML document in memory, you can format it using the method setIndenting(true) on the OutputFormat class. The following is an example:
assuming xmlDoc is our document and fileName is the name of the file we wish to write to:
OutputFormat format = new OutputFormat(xmlDoc);
// setup output file name
PrintWriter printwriter = new PrintWriter(new FileWriter(fileName, false));
// construct an XMLSerializer for writing the document
XMLSerializer serializer = new XMLSerializer( printwriter, format );
// Ensure output is indented correctly...
format.setIndenting(true);
// set serializer as a DOM Serializer
serializer.asDOMSerializer();
// serialize the document
serializer.serialize(xmlDoc);
hope this helps!
Rob.

How to get an xml string into a Document w/o escaping mark-up characters?

Hi,
I am using one of the latest xerces using Java. I am pretty sure I am using xerces-2.
I have an existing Document and I am trying to add more content to it. The new content itself is xml string. I am trying to insert this xml string into the document using document.createTextNode. I am able to insert, but somewhere it is escaping the mark-up characters (<,>,etc). When I convert the document into String, I can see, for example, <userData> instead of <userData>.
There is an alternative option to accomplish this by creating a new document with this xml string, get the root element, import this element into my document. Execution time for this procedure is very high - means, this is very bad in terms of time-wise performance.
Can any help on how to accomplish this (bringing an xml string into a document without escaping mark-up characters) in time-efficient way.

So you want to treat the contents of the string as XML rather than as text? Then you have to parse it.
Or if your reason for asking is just that you don't like the look of escaped text, then use a CDATA section to contain the text.

Converting webi reports into Xml

Hi all ,
Can we convert the BO Edge 3.1 Webi reports into XML Format?
Pls suggest me a solution and if we can convert, pls describe the procedure to be followed inorder to convert the reports into xml files?
Thanks in advance,
Thanks & regards,
Amrita.B

Hello,
While this is not possible (directly) for the entire report, you could do one of the following:
1. If you're on SP2 (or higher), you could publish Webi Report Content as a web service. There is more information in the pdf at http://help.sap.com/businessobject/product_guides/boexir31SP2/en/xi31_sp2_webi_rich_en.pdf (pg 304) .
2. Use QAAWS to publish queries used in the report as web services.
Best,
Srinivas

Convert xml string into xml file?

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