Converting a String to a Number

Hi All,
I am facing an issue in converting a string to number. I have tried with tonumber() but its throwing error. The string list is as below:
101,414.61
1,129,635.54
1,036.25
1,119.33
1,129,635.54
Note:- Plz check that comma separation is there in between numbers and also have decimal point.
Kindly help me in this......................
Regards,
Arun Krishnan.G

Thanks for the reply........
But the Syntax of ToNumber() will not support this format.........
While I use this I am getting Syntax error...............
Regards,
Arun Krishnan.G

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Help with how to convert a string to a number ??

Hi All,
I am having problem converting a string to number.
Looks like my to_number function is not working.
Help is very much appreciated.
My query is below, and I know my problem is in my inner query.
I am getting the following error:
what am I doing wrong ? and how should I fix it.
If there is a better approach, please share it.
ORA-01722: invalid number
01722. 00000 - "invalid number"
*Cause:
*Action:
SELECT
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FROM
    (SELECT OBJECT_NAME,
      SESSION_ID,
      TIMESTAMP,
      TO_NUMBER(FIELD1) REQUISITION_ID, -- I believe here is the problem
      TO_NUMBER(FIELD2) WEEK_GROUP,     -- here as well
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      TO_NUMBER(FIELD5) AI_ASGN      -- here
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GROUP BY OBJECT_NAME,
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    WEEK_GROUP,
    APTITUDE_AREA,
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Are you sure Field1, Field2, Field4 and Field5 contain a number information in all rows?
If there is a non numeric String in your Field<x> columns in any row the error will occor.

Using scan from string to convert a string into a number

I wanted to use scan from string to change a string into a decimal number, but when the string is, for example, 9.14123E-2 it just returns 10. How can I get it to return .00914 or 9.14E-2(as a number not a string). Would there be something easier than scan from string? I'm using labview 5.1. Thank you!

Hello,
May be you can checkout the attached example.
Perkash Mohan Lal
Institute of Semiconductor Technology
Technical University Braunschweig
Attachments:
string_conversion_1.vi ‏44 KB

How to convert a string list to number list

Hi
I have a table1 that codeid is a number(2)
and other table2 that obtain the codeidlist in a varchar2(50) where I save the codeid that I selected from table 1, I can be one o more : 1,2,4,5 etc.
I wanna make this but It gives an error: Invalid Number
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if you want to get rid of the connect by level
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with code_list as
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MODEL RETURN UPDATED ROWS
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   MEASURES (codelidlistt)
   RULES
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                           1,
                           ITERATION_NUMBER + 1))
select *
from table1
where codeid not in (select list from code_list )Edited by: pollywog on Apr 11, 2011 1:03 PM

Converting String to the Number

Dear Members,
I'm new to OAF.
I have a requirement in which I need to convert a string to the number.
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Regards.

Please import oracle.jbo.domain.Number;
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try
Number numValue = new Number (stringVal);
catch(SQLException e)
e.printStackTrace();
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Hi,
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Did you try:
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How do I know if I can convert a String value to an int value or not?

Hi,
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Encephalopathic wrote
Again, why?One of the problems (have been dued) in my codelab asks us to write a class as follow
Write a class definition of a class named 'Value' with the following:
a constructor accepting a single integer paramter
a constructor with no parameters
a method 'setVal' that accepts a single parameter,
a boolean method, 'wasModified' that returns true if setVal was ever called for the object.
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Convert a String to Decimal Format in European format

Hi Experts,
I am having a string as a context type for a input field, where the user can enter the Price, I need to convert the same into European format "###.###,00", I am using this below code to convert the string to decimal format
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String Str1 = wdContext.currentvn_temptable.getVa_TempUnitPrice();
Locale mylocale = Locale.GERMAN;
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wdComponentAPI.getMessageManager().reportSuccess("Unit Price" + " " + pattern + " " + output);
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Hello!
Try to change your pattern to this one
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How to convert a string value to date

Dear All,
I am new to powershell script, i was trying to store a Ad user password set date to a variable add, add a number of days to get the expire date.
but when i try to convert the variable to date value, I am getting the error as below.
Please help me......
PS C:\script> $passwordSetDate = (get-aduser user1 -properties * | select PasswordLastSet)
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PasswordLastSet
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Cannot find an overload for "ParseExact" and the argument count: "3".
At line:1 char:1
+ $a = [datetime]::ParseExact($passwordSetDate,"MM/dd/yyyy HH:MM:SS", $null)
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : NotSpecified: (:) [], MethodException
+ FullyQualifiedErrorId : MethodCountCouldNotFindBest
PS C:\script> $a = [datetime]::ParseExact($passwordSetDate,"MM/dd/yyyy HH:MM:SS", $null)

Dear All,
I am new to powershell script, i was trying to store a Ad user password set date to a variable add, add a number of days to get the expire date.
but when i try to convert the variable to date value, I am getting the error as below.
Please help me......
PS C:\script> $passwordSetDate = (get-aduser user1 -properties * | select PasswordLastSet)
PS C:\script> $passwordSetDate
PasswordLastSet
7/15/2014 8:17:24 PM
PS C:\script> $a = [datetime]::ParseExact($passwordSetDate,"MM/dd/yyyy HH:MM:SS", $null)
Cannot find an overload for "ParseExact" and the argument count: "3".
At line:1 char:1
+ $a = [datetime]::ParseExact($passwordSetDate,"MM/dd/yyyy HH:MM:SS", $null)
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
+ CategoryInfo : NotSpecified: (:) [], MethodException
+ FullyQualifiedErrorId : MethodCountCouldNotFindBest
PS C:\script> $a = [datetime]::ParseExact($passwordSetDate,"MM/dd/yyyy HH:MM:SS", $null)
In your post you ask how to convert a string value to a date. The value returned from the Get-AdUser is already a date. It does not need to be converted.
Bill has sshown one way to convert a date to a string and there are other methods. You need to clarify your question.
If you are really trying ot convert strings to dates then you can start with this:
[datetime]'01/21/1965 13:33:23'
Most date strings aer autodetected by the class.
¯\_(ツ)_/¯

Problem in converting the String to Date with time zone GMT

Hi,
When I tried to convert the string 12/05/2009 to Date, the time zone is set to BST.On the other hand, for the date 12/12/2009, the time zone is set to GMT. What should I do to get the time zone as GMT all the time.?
SimpleDateFormat formatter = new SimpleDateFormat("dd/MM/yyyy");
String dateString = "12/05/2009";
System.out.println(myDate.toString());

I think you are all missing the point. java.util.Date objects always alway always store the date as the number of milliseconds since 1/1/1970 UTC so the only TimeZone they have its the implicit UTC. When you use the Date.toString() method the toString() method gets the default time zone from your environment and formats the data accordingly. This means that the same Date object will, by default, produce a different result for France and Australia and the US.
So, if you have the date "12/5/2009" as a String then to convert it to a java.util.Date you must specify what TimeZone is implied. If it is your system time zone then you can just create a SimpleDateFormat object with the correct format and then use the parse() method to create the java.util.Date object and this will automatically be converted to UTC. If the date String represents some other time zone then you must explicitly set the time zone of the SimpleDateFormat object before parsing the string.
The same approach applies when converting a java.util.Date object to a String. If you want anything other than your system time zone then you must explicitly tell the SimpleDateFormat what time zone you want the result formatted for.

How do I convert a string, and use a string as a property?

I have an array in the following format:
{ownsCar: 'true', ownsBike: 'true', ownsHouse: 'true'}
{ownsCar: 'false', ownsBike: 'true', ownsHouse: 'true'}
{ownsCar: 'true', ownsBike: 'false', ownsHouse: 'true'}
etc ............
And I need to test against each item e.g.
if...
myDataGrid[myItem].ownsCar == Object(myCheckbox).label
... then
if...
myDataGrid[myItem].ownsBike == Object(myCheckbox).label
... then
if...
myDataGrid[myItem].ownsHouse == Object(myCheckbox).label
... then
But I need to build my application where the property (e.g. "ownsCar", "ownsBike", "ownsHouse") is a variable such as:
if...
myDataGrid[myItem].myProperty == Object(myCheckbox).label
... then
I would like to loop through my Array, counting the number of items, and then use each item as a property.
How would I convert the string (e.g. "ownsCar") into a property "myProperty" ???
Many thanks in advance
Chris

Thanks, but my problem is that I won't know what my property will be.
E.g. they could be...
{svnsdkvnsdklvnsdklv: 'true', seuAfnwfnw: 'true', asfwseionf: 'true', etc.................}
and there could be lots of them.
I need to have myObject[N], where N is a variable property for each of the items taken from a variable length array
so...
ownsCar is represented by myObject.[N]
ownsHouse is represented by myObject.[N+1]
ownsBike is represented by myObject.[N+2]
etc
(sorry, this is so difficult to explain when I dont know what the answer is)

Convert hexadecimal output to decimal (number)

I am reading hexadecimal format from the output of the VISA read block and I want to convert it to the decimal preferably exponential format.
Example of what I read is 76 00 02 (in dec: 7.600 E+2).
I know there is "type cast" block that converts nicelly but I am not sure what to specify for a type input.
Can you show me how to apply this type cast block for in my VI so that it converts hex string (76 00 02) into exponential string/number (7.600 E+2)?
I attached my VI so it is more clear.
Thanks everybody,
Pedja
Attachments:
MultiGauge.vi ‏64 KB

Coop wrote:
> I am reading hexadecimal format from the output of the VISA read block
> and I want to convert it to the decimal preferably exponential format.
> Example of what I read is 76 00 02 (in dec: 7.600 E+2).
> I know there is "type cast" block that converts nicelly but I am not
> sure what to specify for a type input.
> Can you show me how to apply this type cast block for in my VI so that
> it converts hex string (76 00 02) into exponential string/number
> (7.600 E+2)?
Looking at your code I see that you have not a hexadecimal string coming
back but instead a binary string. The fact that you display the string
as hexadecimal in the string indicator is just showing you the ASCII
codes of the string characters as hexadecimal numbers.
The funct
ion From Hexadecimal String expects a clear text string with
hexadecimal characters but that is something entirely different from a
binary string you choose to display as hexadecimal numbers.
An example: the binary string 7600 02 you receive from the device is in
fact the character 'v', a null character and a 02 character (or in ASCII
terms a start of text character).
So assuming your example is right (which I have to admit seems very
strange and therefore suspicious to me) you would have to do something
more like included example. But as I said I have little understanding
why the hexadecimal interpretation of the binary values should
correspond to the decimal value you want to have!
Also as you can see there is not really clear where the 00 character
belongs to. The two methods where it is either part of the multiplier or
the exponent both produce the same result for this particular example.
Which one is right if any, should be tested.
Rolf Kalbermatter
Rolf Kalbermatter
CIT Engineering Netherlands
a division of Test & Measurement Solutions
Attachments:
Binary_(Hex)_to_Decimal_Numeric.vi ‏51 KB

Converting a String to a Number

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